Definition of the derivative of a function at a point
You are riding the Metrobús along Insurgentes and the speedometer reads 40 km/h "at this instant." But no time passes in an instant: how can you calculate a speed if there is no interval? You already know the average rate of change between two points; if you move the second point closer to the first, that average settles on a number. That number is the derivative, and here you will learn to calculate it rigorously using limits.
The limit of the difference quotient
The average rate of change of $f$ between $a$ and $a+h$ is $\dfrac{f(a+h)-f(a)}{h}$: it is the slope of the secant line. If $h$ gets smaller and smaller, we look for the number it approaches.
To calculate it we follow the four-step rule:
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Write $f(a+h)$.
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Subtract $f(a)$ (with parentheses).
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Divide by $h$ and simplify.
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Find the limit as $h\to 0$.
Find the instantaneous rate of change (derivative) of the function $f(x) = 3x - 5$ at the point with x-coordinate $x = 1$, applying the limit of the difference quotient.
Find the instantaneous rate of change (derivative) of the function $f(x) = 3x - 5$ at the point with x-coordinate $x = 1$, applying the limit of the difference quotient.
Using the definition of derivative by means of the limit $f'(a) = \lim_{h \to 0} \frac{f(a+h) - f(a)}{h}$, calculate the value of $f'(2)$ for the function…
Using the definition of derivative by means of the limit $f'(a) = \lim_{h \to 0} \frac{f(a+h) - f(a)}{h}$, calculate the value of $f'(2)$ for the function $f(x) = x^2 + 3$.
The distance covered by an object in free fall on a fictitious planet is given by $s(t) = 4t^2$, where $s$ is measured in meters and $t$ in seconds. Calculate the…
The distance covered by an object in free fall on a fictitious planet is given by $s(t) = 4t^2$, where $s$ is measured in meters and $t$ in seconds. Calculate the instantaneous velocity at $t = 3$ s applying the definition of derivative as a limit.
Two forms of the definition
This form is convenient when the numerator can be factored.
When there are square roots, you multiply by the conjugate to resolve the indeterminate form.
Given the function $f(x) = 2x^2 - x$, use the alternative expression of the definition $f'(a) = \lim_{x \to a} \frac{f(x) - f(a)}{x - a}$ to find the derivative at the…
Given the function $f(x) = 2x^2 - x$, use the alternative expression of the definition $f'(a) = \lim_{x \to a} \frac{f(x) - f(a)}{x - a}$ to find the derivative at the point $a = -1$.
Using the definition of derivative by means of limits, calculate $f'(3)$ for the rational function $f(x) = \frac{1}{x - 1}$.
Using the definition of derivative by means of limits, calculate $f'(3)$ for the rational function $f(x) = \frac{1}{x - 1}$.
Find the derivative of the radical function $f(x) = \sqrt{x + 5}$ at the point $x = 4$, applying the definition of derivative as a limit and multiplying by the conjugate…
Find the derivative of the radical function $f(x) = \sqrt{x + 5}$ at the point $x = 4$, applying the definition of derivative as a limit and multiplying by the conjugate to resolve the indeterminate form.
Calculate the derivative of the function $f(x) = \sqrt{x^2 + 3}$ at the point $x = 1$ using exclusively the definition of derivative as a limit. Show all the algebraic…
Calculate the derivative of the function $f(x) = \sqrt{x^2 + 3}$ at the point $x = 1$ using exclusively the definition of derivative as a limit. Show all the algebraic steps necessary to resolve the indeterminate form.
The derivative as a function and as a rate of change
If instead of a fixed point $a$ you use a generic point $x$, the result is an expression in $x$: the derivative function.
$$f'(x) = \lim_{h\to0}\frac{f(x+h)-f(x)}{h}$$The derivative measures the instantaneous rate of change: velocity if $f$ is position, marginal cost if $f$ is cost, heating rate if $f$ is temperature.
A cyclist in a velodrome covers a distance given by the function $d(t) = t^2 + 5t$ (measured in meters, with $t$ in seconds). Calculate their instantaneous speed at…
A cyclist in a velodrome covers a distance given by the function $d(t) = t^2 + 5t$ (measured in meters, with $t$ in seconds). Calculate their instantaneous speed at $t = 2$ seconds using strictly the definition of derivative by limits.
In a technology component factory, the total cost of producing $q$ units is given by the function $C(q) = 2\,000 + 40q + 2q^2$ in pesos. Determine the marginal cost (the…
In a technology component factory, the total cost of producing $q$ units is given by the function $C(q) = 2\,000 + 40q + 2q^2$ in pesos. Determine the marginal cost (the derivative of the cost function) when exactly $q = 20$ units are produced, by solving the limit of the formal definition of derivative.
The altitude of an agricultural observation drone follows the equation $h(t) = -5t^2 + 20t + 2$, with height $h$ expressed in meters and time $t$ in seconds. Using the…
The altitude of an agricultural observation drone follows the equation $h(t) = -5t^2 + 20t + 2$, with height $h$ expressed in meters and time $t$ in seconds. Using the definition of derivative by means of the limit for a general point $t$, obtain the velocity function $v(t) = h'(t)$ and determine at what exact instant the drone reaches its maximum height (when its velocity is zero).
Calculate, using the definition of derivative with the limit for a general point $x$, the derivative function $f'(x)$ of $f(x) = x^3 - 3x$. Then, use the result obtained…
Calculate, using the definition of derivative with the limit for a general point $x$, the derivative function $f'(x)$ of $f(x) = x^3 - 3x$. Then, use the result obtained to find the points on the curve where the tangent line is completely horizontal.
The temperature $T$ (measured in degrees Celsius) of a computer processor as a function of time $t$ (in minutes) after starting an intensive calculation process is given…
The temperature $T$ (measured in degrees Celsius) of a computer processor as a function of time $t$ (in minutes) after starting an intensive calculation process is given by the expression $T(t) = \frac{4t}{t^2 + 1} + 30$. Calculate the instantaneous rate of heating (the derivative) at exactly $t = 2$ minutes, evaluating step by step the limit of the definition of derivative.
Using the general definition of derivative $f'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h}$, prove step by step that the derivative function of…
Using the general definition of derivative $f'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h}$, prove step by step that the derivative function of $f(x) = \frac{1}{\sqrt{x}}$ is exactly $f'(x) = -\frac{1}{2x\sqrt{x}}$ for any value of $x > 0$.
One-sided derivatives and corner points
If the difference quotient is calculated only with $h\to0^+$ or only with $h\to0^-$, you get the one-sided derivatives $f'(a^+)$ and $f'(a^-)$.
For piecewise-defined functions, you first check continuity and then calculate the one-sided derivatives, each with its own formula.
Prove, by explicitly calculating the one-sided limits of the difference quotient, that the absolute value function $f(x) = |x - 3|$ is not differentiable at the point…
Prove, by explicitly calculating the one-sided limits of the difference quotient, that the absolute value function $f(x) = |x - 3|$ is not differentiable at the point $x = 3$.
The attached graph shows a continuous function that has a sharp corner. Define analytically an absolute value function that corresponds to this graph and prove…
The attached graph shows a continuous function that has a sharp corner. Define analytically an absolute value function that corresponds to this graph and prove rigorously, by calculating the one-sided limits of the difference quotient, why the function is not differentiable at $x = 2$.
Determine whether the following piecewise function is differentiable at $x = 2$, first checking its continuity and then applying the definition of one-sided derivatives:…
Determine whether the following piecewise function is differentiable at $x = 2$, first checking its continuity and then applying the definition of one-sided derivatives:
$f(x) = \begin{cases} x^2 & \text{if } x \le 2 \\ 4x - 4 & \text{if } x > 2 \end{cases}$
Given the function $f(x) = x|x|$, prove using the definition of derivative by calculating the one-sided limits of the difference quotient that the function is smooth…
Given the function $f(x) = x|x|$, prove using the definition of derivative by calculating the one-sided limits of the difference quotient that the function is smooth (differentiable) at $x = 0$, and find the exact value of $f'(0)$.
Differentiability and continuity
A useful fact: even functions
A function is even if it satisfies $f(-x)=f(x)$ for all $x$: its graph is symmetric about the $y$-axis. $x^2$, $x^4$, and $|x|$ are even. To check it, replace $x$ with $-x$ and verify that the expression does not change: $(-x)^2=x^2$.
If $f$ is even, in the difference quotient at $0$, $q(h)=\dfrac{f(h)-f(0)}{h}$, we have $f(-h)=f(h)$, so $q(-h)=\dfrac{f(h)-f(0)}{-h}=-q(h)$. That is, the quotient changes sign when $h$ is replaced by $-h$.
Determine the exact values of the parameters $a$ and $b$ so that the piecewise function…
Determine the exact values of the parameters $a$ and $b$ so that the piecewise function
$f(x) = \begin{cases} ax^2 + b & \text{if } x < 1 \\ \frac{1}{x} & \text{if } x \ge 1 \end{cases}$
is differentiable at $x = 1$. You must justify your answer by applying the definition of continuity and evaluating the limits of the one-sided derivatives using the difference quotient.
Suppose $f(x)$ is an even function (that is, it satisfies $f(-x) = f(x)$ for all real numbers $x$) and is known to be differentiable at the point with x-coordinate…
Suppose $f(x)$ is an even function (that is, it satisfies $f(-x) = f(x)$ for all real numbers $x$) and is known to be differentiable at the point with x-coordinate $x = 0$. Prove analytically, using the definition of derivative by means of the limit $\lim_{h \to 0} \frac{f(h) - f(0)}{h}$, that $f'(0) = 0$ must necessarily hold.
Using the definition to find the tangent line
A constant function, such as $f(x)=7$, has $\dfrac{7-7}{h}=0$: its derivative is $0$ and its tangent is the horizontal line itself.
Tangents parallel to a given line
Two nonvertical lines are parallel if they have the same slope: $m_1=m_2$. So, if you are asked for the tangents to a curve that are parallel to $y=mx+b$, you look for the points where $f'(x)=m$.
Calculate the derivative of the constant function $f(x) = 7$ at the point $x = 5$ applying the formal definition with the limit. Briefly explain the geometrical meaning…
Calculate the derivative of the constant function $f(x) = 7$ at the point $x = 5$ applying the formal definition with the limit. Briefly explain the geometrical meaning of the result obtained.
Find the equation of the tangent line to the curve $f(x) = x^2$ at the point with x-coordinate $x = 2$. To do this, first calculate the gradient $m = f'(2)$ using the…
Find the equation of the tangent line to the curve $f(x) = x^2$ at the point with x-coordinate $x = 2$. To do this, first calculate the gradient $m = f'(2)$ using the definition of derivative by means of the limit.
Find the equation of the tangent line to the function $f(x) = \frac{x}{x + 2}$ at the origin. You must calculate the gradient by evaluating the limit of the definition…
Find the equation of the tangent line to the function $f(x) = \frac{x}{x + 2}$ at the origin. You must calculate the gradient by evaluating the limit of the definition of derivative at $x = 0$.
Find the equations of all the tangent lines to the curve $f(x) = x^3 - x$ that are strictly parallel to the line with equation $y = 2x + 1$. To solve this, you must…
Find the equations of all the tangent lines to the curve $f(x) = x^3 - x$ that are strictly parallel to the line with equation $y = 2x + 1$. To solve this, you must first obtain the general expression for the gradient $f'(x)$ applying the definition of derivative by limits.
The quarterly profit of a renewable energy company as a function of its investment $x$ (in millions of pesos) follows a quadratic model of the form $B(x) = -ax^2 + bx$.…
The quarterly profit of a renewable energy company as a function of its investment $x$ (in millions of pesos) follows a quadratic model of the form $B(x) = -ax^2 + bx$. Given that maximum profit is reached with an exact investment of $10$ million pesos and that this maximum profit amounts to $500$ million, deduce the values of the constants $a$ and $b$. Subsequently, prove using the definition of derivative by limits that the instantaneous rate of change at that point satisfies $B'(10) = 0$.
Go back to the beginning: the Metrobús speedometer shows the limit of the average speed as the interval shrinks to zero, that is, the derivative of position.