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Trigonometry · Trigonometry

Law of Sines

Before you start, make sure you know: Right triangles (Secondary Year 3)
Before you start, make sure you know: Reduction to the first quadrant and the fundamental identity (Secondary Year 3)

Until now you could only solve right triangles. But a surveyor measuring the distance to an island from two points on the Gulf of Mexico coast, or an engineer checking a cable car's cable, almost never has a right angle. You need a tool that works with any triangle: the law of sines. By the end you'll be able to decide, from just a few pieces of data, whether a triangle exists and how many there are.

The law and the circumscribed circle

In any triangle $ABC$, each side is proportional to the sine of its opposite angle, and that ratio is the diameter of the circle that passes through all three vertices.

Triangle inscribed in a circumscribed circle with vertices A, B, C on the circle and their opposite sides a, b, c marked. A B C a b c
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In a triangle $ABC$, the angles $A = 45^\circ$ and $B = 60^\circ$ are known, as well as the length of side $a = 12$ cm. Calculate the length of side $b$ using the sine…

In a triangle $ABC$, the angles $A = 45^\circ$ and $B = 60^\circ$ are known, as well as the length of side $a = 12$ cm. Calculate the length of side $b$ using the sine rule.

Solve
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In any triangle, side $c$ measures $24$ cm and the opposite angle $C$ measures $30^\circ$. Calculate the radius $R$ of the circumcircle of this triangle.

In any triangle, side $c$ measures $24$ cm and the opposite angle $C$ measures $30^\circ$. Calculate the radius $R$ of the circumcircle of this triangle.

Solve
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A triangle $PQR$ has angles $P = 50^\circ$ and $Q = 75^\circ$. If side $r = 20$ m, calculate the length of side $p$.

A triangle $PQR$ has angles $P = 50^\circ$ and $Q = 75^\circ$. If side $r = 20$ m, calculate the length of side $p$.

Solve

Finding an angle: the ambiguous case

When the unknown is an angle (you know two sides and an angle opposite one of them), solving for the sine can give two solutions: an acute angle and its supplement, because $\operatorname{sin}(180^\circ-x)=\operatorname{sin}x$.

Ambiguous case with A of 30°, b of 14 cm, and a of 10 cm: the opposite side, with its endpoint fixed at C, meets the base at B₁ and at B₂, showing the two possible triangles with the same angle A and the same given sides. A 30° C B₁ B₂
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Given a triangle $ABC$ in which sides $a = 15$ cm and $b = 10$ cm and the obtuse angle $A = 120^\circ$ are known, determine the value of angle $B$.

Given a triangle $ABC$ in which sides $a = 15$ cm and $b = 10$ cm and the obtuse angle $A = 120^\circ$ are known, determine the value of angle $B$.

Solve
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Determine whether it is possible to construct a triangle $ABC$ with the following data: $a = 8$ cm, $b = 14$ cm, and $A = 45^\circ$. Justify your answer mathematically…

Determine whether it is possible to construct a triangle $ABC$ with the following data: $a = 8$ cm, $b = 14$ cm, and $A = 45^\circ$. Justify your answer mathematically using the sine rule.

Solve
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In triangle $ABC$, sides $a = 10$ cm, $b = 14$ cm, and angle $A = 30^\circ$ are known. Calculate the two possible values for angle $B$ and the corresponding lengths of…

In triangle $ABC$, sides $a = 10$ cm, $b = 14$ cm, and angle $A = 30^\circ$ are known. Calculate the two possible values for angle $B$ and the corresponding lengths of side $c$ for each case.

30° A C B₂ B₁ b = 14 a = 10 a = 10
Solve
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In the construction of a triangle $ABC$, side $a = 10$ cm and angle $A = 45^\circ$ are fixed. Side $b$ has a variable length $x$ cm. Determine, giving reasons, the…

In the construction of a triangle $ABC$, side $a = 10$ cm and angle $A = 45^\circ$ are fixed. Side $b$ has a variable length $x$ cm. Determine, giving reasons, the strict interval of real values of $x$ for which there exist exactly two distinct triangles satisfying these conditions simultaneously.

Solve

Triangulation: distances from two angles

In surveying and navigation, you measure an easy-to-reach distance (the baseline) and two angles from its endpoints. With that you can calculate the distance to an inaccessible point.

Triangulation with two stations A and B 50 km apart measuring angles of 40° and 65° toward a ship S. 40° 65° A B S 50 km
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Two coastguard stations, $A$ and $B$, are separated by a distance of $50$ km along a straight coastline. A ship $S$ emits a distress signal. Station $A$ detects the…

Two coastguard stations, $A$ and $B$, are separated by a distance of $50$ km along a straight coastline. A ship $S$ emits a distress signal. Station $A$ detects the signal forming an angle of $40^\circ$ with the coastline, while station $B$ detects it with an angle of $65^\circ$. Calculate the straight-line distance from each station to the ship.

A B S 50 km 40° 65° d₁ d₂
Solve
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A cable car ascends in a straight line from a base station $A$ to the summit $C$ of a mountain. From a point $D$, situated $200$ m behind $A$ in the same horizontal…

A cable car ascends in a straight line from a base station $A$ to the summit $C$ of a mountain. From a point $D$, situated $200$ m behind $A$ in the same horizontal plane, the angle of elevation to $C$ is $22^\circ$. From station $A$, the angle of elevation to the summit is $35^\circ$. Calculate the length of the cable car wire $AC$ by solving triangle $ADC$.

D A C 200 m 22° 35° cable
Solve
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An aircraft flies in a straight line at a constant altitude. A stationary observer on the ground initially spots it with an angle of elevation of $30^\circ$. Exactly…

An aircraft flies in a straight line at a constant altitude. A stationary observer on the ground initially spots it with an angle of elevation of $30^\circ$. Exactly $10$ seconds later, the aircraft, flying directly towards the observer's vertical line, is spotted with an angle of elevation of $45^\circ$. If the constant speed of the aircraft is $600$ km/h, calculate its altitude by solving the triangle formed by the observer and the two positions of the aircraft using the sine rule.

Solve

Area, polygons, and combined problems

The law of sines is also useful for regular polygons (they are divided into isosceles triangles from the center) and for areas when you know one side and the two angles touching it. Remember that the area of a triangle is $\frac12 ab\operatorname{sin}C$, with $C$ the angle between sides $a$ and $b$.

Triangular lot with angles of 60° and 75° at the ends of a 120 m side. 60° 75° 120 m
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Calculate the perimeter of a regular heptagon (a 7-sided polygon) inscribed in a circle of radius $R = 10$ cm. Use the law of sines on the isosceles triangles formed…

Calculate the perimeter of a regular heptagon (a 7-sided polygon) inscribed in a circle of radius $R = 10$ cm. Use the law of sines on the isosceles triangles formed from the center of the polygon.

Solve
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A triangular plot of land has two angles measuring $60^\circ$ and $75^\circ$. The side between these two angles is bounded by a straight wall measuring $120$ m.…

A triangular plot of land has two angles measuring $60^\circ$ and $75^\circ$. The side between these two angles is bounded by a straight wall measuring $120$ m. Calculate the total area of the plot.

Solve
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The slope of a mountain has a constant inclination of $15^\circ$ relative to the horizontal plane. Two points $A$ and $B$ are on the slope, with $B$ situated $50$ m…

The slope of a mountain has a constant inclination of $15^\circ$ relative to the horizontal plane. Two points $A$ and $B$ are on the slope, with $B$ situated $50$ m further up than $A$ along the slope. A vertical telecommunications pole is installed at point $B$. From point $A$, the angle of elevation to the top of the pole is $42^\circ$ measured from the horizontal. Calculate the exact height of the pole.

15° 42° A B C 50 m h
Solve

Identities that help you prove things

For proofs you need two trigonometry tools. You will use them as formulas; here they are just a reminder.

Proofs with the law of sines

An important skill in Pensamiento Matemático is proving identities. The key: from the law of sines, $a=2R\operatorname{sin}A$, $b=2R\operatorname{sin}B$, $c=2R\operatorname{sin}C$. This way, a side is exchanged for a sine and vice versa.

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In a triangle $ABC$, the proportion $\frac{a}{\sin A} = 24$ holds. If the sum of the angles $A + B = 120^\circ$ and side $a = 12\sqrt{3}$ cm, determine the exact length…

In a triangle $ABC$, the proportion $\frac{a}{\sin A} = 24$ holds. If the sum of the angles $A + B = 120^\circ$ and side $a = 12\sqrt{3}$ cm, determine the exact length of side $c$.

Solve
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In a triangle $ABC$, angle $A$ is exactly twice angle $B$ ($A = 2B$). Prove, using the sine rule and double-angle trigonometric identities, that the lengths of the sides…

In a triangle $ABC$, angle $A$ is exactly twice angle $B$ ($A = 2B$). Prove, using the sine rule and double-angle trigonometric identities, that the lengths of the sides satisfy the relation $a = 2b \cos B$.

Solve
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Prove that the radius $R$ of the circumcircle of a triangle $ABC$ is directly related to the area of triangle $S$ by the formula: $R = \frac{a \times b \times c}{4S}$…

Prove that the radius $R$ of the circumcircle of a triangle $ABC$ is directly related to the area of triangle $S$ by the formula:

$R = \frac{a \times b \times c}{4S}$

(Hint: Express the area of the triangle using the sine of one of its angles and combine it with the sine rule).

Solve
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In a triangle $ABC$, the lengths of sides $a$, $b$, and $c$ are in arithmetic progression, satisfying the relation $2b = a + c$. Prove that the sines of the opposite…

In a triangle $ABC$, the lengths of sides $a$, $b$, and $c$ are in arithmetic progression, satisfying the relation $2b = a + c$. Prove that the sines of the opposite angles maintain an analogous relation: $\sin A + \sin C = 2 \sin B$.

Solve

Back to the beginning: with one side measured on the coast and two angles, the law of sines gives the distance to the island; and if the sine you solve for exceeds $1$, you know that triangle doesn't exist.

Summary

See all the exercises in this section