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Secondary 1 · Mathematics
Numbers · Divisibility

Greatest Common Factor

In the school workshop there are two wooden strips, $36$ cm and $48$ cm long. You want to cut them into pieces of the same length, as long as possible and with no wood left over. How long should each piece be? That length is the greatest common factor.

What the G.C.F. is

Lists of the factors of 12 and 18 with their common factors highlighted and 6 marked as the greatest common factor. factors of 121, 2, 3, 4, 6, 12 factors of 181, 2, 3, 6, 9, 18 common 1, 2, 3, 6 M.C.D.(12, 18) = 6

The most direct method, for small numbers: write all the factors of each number and keep the largest of the common ones.

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Work out in your head the $MCD$ of the following pairs of numbers. These are small numbers where you can identify the highest common factor at a glance: a) $MCD(4, 8)$…

Work out in your head the $MCD$ of the following pairs of numbers. These are small numbers where you can identify the highest common factor at a glance:

  1. a) $MCD(4, 8)$
  2. b) $MCD(5, 10)$
  3. c) $MCD(7, 14)$
  4. d) $MCD(10, 20)$

What do all these results have in common?

Solve
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Find all the divisors of the numbers $12$ and $18$. Then, state which are the common divisors and point out which of them is the Greatest Common Divisor (GCD). You can…

Find all the divisors of the numbers $12$ and $18$. Then, state which are the common divisors and point out which of them is the Greatest Common Divisor (GCD).

You can use a diagram like the one in the figure: write the divisors of each number in each circle and, in the area where they overlap, the ones that are common.

Diagram of two overlapping circles, one for the divisors of 12 and another for the divisors of 18, empty to be filled inDivisors of 12Divisors of 18Common area
Solve

Finding the G.C.F. with prime factors

With large numbers, listing factors is slow. It is faster to break the numbers down into prime factors.

Diagram of finding the G.C.F. by prime factorization, taking the common factors with the smallest exponent. A = 2² · 3 · 5B = 2 · 3² 5 is not in B → it doesn't count of 2² and 2¹, the smaller is 2¹ M.C.D.(A, B) = 2 · 3 = 6
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Look at the prime factorisations of these two numbers and find their $MCD$: $A = 2^{2} \times 3 \times 5$ $B = 2 \times 3^{2}$ Remember the rule: "For the HCF, we take…

Look at the prime factorisations of these two numbers and find their $MCD$:

  • $A = 2^{2} \times 3 \times 5$

  • $B = 2 \times 3^{2}$

Remember the rule: "For the HCF, we take the common factors raised to the lowest power".

Solve
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Calculate the Highest Common Factor ($M.C.D.$) of the following sets of numbers using prime factorisation: a) $48$ and $72$ b) $30, 45$ and $60$ c) $120$ and $150$

Calculate the Highest Common Factor ($M.C.D.$) of the following sets of numbers using prime factorisation:

  1. a) $48$ and $72$
  2. b) $30, 45$ and $60$
  3. c) $120$ and $150$
Solve
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Look at the following prime factorisations of three numbers and, without performing the multiplications, state their $\text{HCF}$: $A = 2^3 \times 3^2 \times 5$…

Look at the following prime factorisations of three numbers and, without performing the multiplications, state their $\text{HCF}$:

$A = 2^3 \times 3^2 \times 5$

$B = 2^2 \times 3^3$

$C = 2^2 \times 3^2 \times 7$

Solve

Relatively prime numbers

Prime factorizations of 14 and 15: they share no prime factors and their G.C.F. is 1. 14 = 2 · 7 15 = 3 · 5 no common prime→ M.C.D.(14, 15) = 1 14 and 15 are relatively prime, even though neither of them is prime
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Two numbers are said to be coprime if their only common factor is $1$. Check whether the following pairs of numbers are coprime by calculating their $M.C.D.$: a) $14$…

Two numbers are said to be coprime if their only common factor is $1$. Check whether the following pairs of numbers are coprime by calculating their $M.C.D.$:

  1. a) $14$ and $15$
  2. b) $22$ and $33$
  3. c) $21$ and $25$
Solve

Simplifying fractions with the G.C.F.

Another use of the G.C.F.: simplifying a fraction in a single step. If you divide the numerator and the denominator by their G.C.F., you get the fraction in lowest terms, which can't be simplified any further.

Why does it work? Dividing the top and bottom by the same number doesn't change the value of the fraction. And since you use the greatest common factor, after dividing the two numbers no longer share any factor, that is, they are relatively prime.

Practice★★☆Not started
Two numbers are said to be coprime if their only common factor is $1$. Check whether the following pairs of numbers are coprime by calculating their $M.C.D.$: a) $14$…

Two numbers are said to be coprime if their only common factor is $1$. Check whether the following pairs of numbers are coprime by calculating their $M.C.D.$:

  1. a) $14$ and $15$
  2. b) $22$ and $33$
  3. c) $21$ and $25$
Solve

Problems about sharing into equal parts

When you have to group or share several quantities into equal groups, as large as possible and with nothing left over, the G.C.F. is the tool to use.

Sharing 45 and 60 books onto equal shelves of 15 books each. 45 books 15 15 15 60 books 15 15 15 15 each shelf: 15 books (G.C.F.)
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In the technology workshop, the students have two wooden battens measuring $36$ cm and $48$ cm in length. They need to cut them into pieces of the same length, with this…

In the technology workshop, the students have two wooden battens measuring $36$ cm and $48$ cm in length. They need to cut them into pieces of the same length, with this length being the maximum possible.

  1. a) What will be the length of each piece?
  2. b) How many pieces will they get in total from the two battens?
Solve
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In a library, they want to organise $45$ adventure books and $60$ science fiction books on shelves so that each shelf has the same number of books and this number is the…

In a library, they want to organise $45$ adventure books and $60$ science fiction books on shelves so that each shelf has the same number of books and this number is the maximum possible.

  1. a) How many books will they put on each shelf?
  2. b) How many shelves will they use for the adventure books and how many for the science fiction books?
Solve
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A community day has been organized at the school. There are $54$ 7th grade students and $42$ 8th grade students. They want to form teams (all from the same class or…

A community day has been organized at the school. There are $54$ 7th grade students and $42$ 8th grade students. They want to form teams (all from the same class or mixed, as the homeroom teacher decides) on condition that all teams in the school have exactly the same number of people and that this number is as large as possible without anyone being left over.

  1. a) How many students will be in each team?
  2. b) How many 7th grade teams and how many 8th grade teams will be formed?
Solve
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For a food bank, a supermarket donates $36$ tins of pulses, $48$ cartons of milk and $60$ bags of rice. They want to prepare the maximum possible number of identical…

For a food bank, a supermarket donates $36$ tins of pulses, $48$ cartons of milk and $60$ bags of rice. They want to prepare the maximum possible number of identical bags to distribute, such that each bag contains the same number of items of each type.

  1. a) What is the maximum number of bags they can prepare?
  2. b) What will each bag contain?
Solve

Harder problems

Sometimes the G.C.F. is hidden. These are the ideas to look for.

  • Largest possible squares that cover a rectangle: the side is the $G.C.F.$ of the two sides. To find how many squares there are, work out how many fit along the length and along the width, and multiply.

  • Posts at the same distance around a perimeter: the distance is the $G.C.F.$ of the sides. The number of posts is the perimeter divided by that distance (on a closed outline, there are as many posts as segments).

  • A number that leaves remainder $r$ when dividing $a$ and $b$: if it leaves remainder $r$, then it divides $a - r$ and $b - r$ exactly. Find the $G.C.F.(a - r,\ b - r)$. The divisor must be greater than $r$.

  • Finding a number with a given G.C.F.: the number must contain the factors of the G.C.F. and must not share any extra factor with the other number.

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Make up two distinct natural numbers, $a$ and $b$, such that the following condition is met: $M.C.D.(a, b) = 12$ Reason your answer by showing the prime factorisation of…

Make up two distinct natural numbers, $a$ and $b$, such that the following condition is met:

$M.C.D.(a, b) = 12$

Reason your answer by showing the prime factorisation of the chosen numbers.

Solve
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A street artist wants to design a mural on a rectangular wall measuring $210$ cm high by $165$ cm wide. For her design, she wants to divide the whole wall into equal…

A street artist wants to design a mural on a rectangular wall measuring $210$ cm high by $165$ cm wide. For her design, she wants to divide the whole wall into equal squares, such that these are as large as possible and she does not have to cut any pieces.

  1. a) What must be the length of the side of each square to cover the entire wall?
  2. b) How many squares will the mural have in total?
165 cm 210 cm MURAL x x ?
Solve
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A gardener wants to surround a rectangular vegetable patch $90$ meters long and $126$ meters wide with fence posts. The owner of the patch has asked him to place a post…

A gardener wants to surround a rectangular vegetable patch $90$ meters long and $126$ meters wide with fence posts. The owner of the patch has asked him to place a post at each corner and for the distance between consecutive posts to always be the same and as large as possible.

  1. a) What distance should he leave between each post?
  2. b) How many posts will he need in total to surround the entire perimeter of the vegetable patch?
Vegetable patch d = maximum distance 126 m 90 m d d
Solve
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We are looking for the largest possible number that, when dividing the numbers $159$ and $195$, leaves a remainder of $3$ units in both cases. Reason through the steps…

We are looking for the largest possible number that, when dividing the numbers $159$ and $195$, leaves a remainder of $3$ units in both cases. Reason through the steps you follow to find it using the concept of Highest Common Factor.

Solve
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We know that the Greatest Common Divisor of two numbers is $12$ and that one of those numbers is $48$. If the other number is greater than $50$ but less than $70$: a)…

We know that the Greatest Common Divisor of two numbers is $12$ and that one of those numbers is $48$. If the other number is greater than $50$ but less than $70$:

  1. a) Find what that second number is.
  2. b) Justify your answer using prime factorisation.
Solve

Back to the beginning: $36 = 2^2 \times 3^2$ and $48 = 2^4 \times 3$, so $G.C.F.(36, 48) = 2^2 \times 3 = 12$ cm. Each piece measures $12$ cm, and you get $3$ pieces from the first strip and $4$ from the second.

Summary

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