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ESO Y4A · Mathematics
Geometry and trigonometry · Trigonometry

Trigonometric ratios in the right-angled triangle

How do you measure the height of a building without climbing it, or the gradient of a ramp without laying a ruler on it? The answer lies in right-angled triangles: one angle and one side are enough to find out everything else. This is the first time you are meeting this tool, so let's take it step by step.

Before you start, make sure you know: Pythagoras' theorem (2nd ESO)
Before you start, make sure you know: Similar triangles (2nd ESO)

From similar triangles to a constant ratio

Draw several right-angled triangles with the same acute angle $\alpha$ but different sizes. They are all similar (same angles), so the ratios between their corresponding sides are always the same number, however large or small the triangle is.

Three nested similar right-angled triangles with the same acute angle, showing that the ratio between the opposite side and the hypotenuse does not depend on the size of the triangle. α small medium large opposite / hypotenuse = always the same number
Practice★☆☆Not started
Look at the right-angled triangle in the figure. a) Write, as fractions, the ratios $\sen\ \alpha$, $\cos\ \alpha$ and $\tg\ \alpha$ of the marked angle. b) Write these…

Look at the right-angled triangle in the figure.

α 4 3 5
  1. a) Write, as fractions, the ratios $\sen\ \alpha$, $\cos\ \alpha$ and $\tg\ \alpha$ of the marked angle. b) Write these same ratios for the other acute angle. What relationship do you observe between them?
Solve

Sine, cosine and tangent

In a right-angled triangle, fix an acute angle $\alpha$. Each side has a name according to its position relative to $\alpha$: the hypotenuse, the opposite side (the one that does not touch $\alpha$) and the adjacent side (the one that does touch it, other than the hypotenuse).

Right-angled triangle with the acute angle alpha marked and its sides identified as hypotenuse, opposite and adjacent. α adjacent opposite hypotenuse
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In the right-angled triangle in the figure, the legs measure $6$ cm and $8$ cm. a) Calculate the hypotenuse. b) Find the three trigonometric ratios of the marked angle…

In the right-angled triangle in the figure, the legs measure $6$ cm and $8$ cm.

β 6 cm 8 cm ?
  1. a) Calculate the hypotenuse. b) Find the three trigonometric ratios of the marked angle $\beta$.
Solve
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In the triangle in the figure, the hypotenuse measures $10$ cm and angle $\alpha$ is $30^\circ$. Calculate the length of the side opposite $\alpha$. (Given:…

In the triangle in the figure, the hypotenuse measures $10$ cm and angle $\alpha$ is $30^\circ$.

30° 10 cm ?

Calculate the length of the side opposite $\alpha$. (Given: $\sen\ 30^\circ = 0{,}5$.)

Solve
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The two shorter sides of a right-angled triangle each measure $4$ cm. a) What is the tangent of each of the acute angles? b) What are the measurements of these angles?…

The two shorter sides of a right-angled triangle each measure $4$ cm. a) What is the tangent of each of the acute angles? b) What are the measurements of these angles? Justify your answer without a calculator.

Solve

Going further: The fundamental relationships

Since sine and cosine come from the same right-angled triangle, they are not independent: they are linked by Pythagoras.

These relationships allow you to calculate all three ratios knowing only one of them, without measuring any side.

Right-angled triangle with hypotenuse 1 and sides sine and cosine of alpha, justifying the fundamental relationship using Pythagoras' theorem. cos α sen α 1 sen²α + cos²α = 1² (Pythagoras in the triangle with hypotenuse 1)
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Determine whether these statements about an acute angle $\alpha$ are true or false: a) "The sine of $\alpha$ can be greater than $1$." b) "The tangent of $\alpha$ can be…

Determine whether these statements about an acute angle $\alpha$ are true or false: a) "The sine of $\alpha$ can be greater than $1$." b) "The tangent of $\alpha$ can be greater than $1$." Justify both answers using the definition of the ratios in a right-angled triangle and give an example where applicable.

Solve
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For an acute angle $\alpha$, it is known that $\sen\ \alpha = 0{,}6$. Calculate $\cos\ \alpha$ and $\tg\ \alpha$ using trigonometric identities.

For an acute angle $\alpha$, it is known that $\sen\ \alpha = 0{,}6$. Calculate $\cos\ \alpha$ and $\tg\ \alpha$ using trigonometric identities.

Solve
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If $\tg\ \alpha = 2$ and $\alpha$ is acute, calculate $\sen\ \alpha$ and $\cos\ \alpha$.

If $\tg\ \alpha = 2$ and $\alpha$ is acute, calculate $\sen\ \alpha$ and $\cos\ \alpha$.

Solve

Going further: Special angles: 30°, 45° and 60°

There are three angles whose ratios can be calculated exactly, without a calculator, from very simple shapes.

Equilateral triangle of side 2 split by its height into two right-angled triangles with angles of 30° and 60°, sides 1 and root 3, and hypotenuse 2. side 2, height splits into two 60°-30°-90° triangles cut square: 45°-45°-90°
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The acute angles of a right-angled triangle are $35^\circ$ and $55^\circ$. Knowing that $\sen\ 35^\circ \approx 0{,}574$, find without a calculator the value of…

The acute angles of a right-angled triangle are $35^\circ$ and $55^\circ$. Knowing that $\sen\ 35^\circ \approx 0{,}574$, find without a calculator the value of $\cos\ 55^\circ$ and justify it using the definition of trigonometric ratios.

Solve
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a) Look at Panel A in the figure, where an equilateral triangle of side $2$ has been divided by an altitude, and deduce the exact values of $\sen 30^\circ$,…
  1. a) Look at Panel A in the figure, where an equilateral triangle of side $2$ has been divided by an altitude, and deduce the exact values of $\sen 30^\circ$, $\cos 30^\circ$, and $\tg 30^\circ$.
  1. b) Look at Panel B, where a square of side $1$ has been divided by a diagonal, and deduce the trigonometric ratios of $45^\circ$ ($\sen 45^\circ$, $\cos 45^\circ$, and $\tg 45^\circ$).
  1. c) Using the above and the relationships between complementary angles, complete the following table with the ratios of $30^\circ$, $45^\circ$, and $60^\circ$:
Angle $\sen$ $\cos$ $\tg$
$30^\circ$
$45^\circ$
$60^\circ$
Right triangles to deduce trigonometric ratios of 30°, 45°, and 60° A 60° 30° 1 √3 2 B 45° 1 1 √2
Solve
Practice★★★Not started
Calculate without a calculator, using the table of special angles: a) $\sen^2\ 30^\circ + \cos^2\ 60^\circ + \tg\ 45^\circ$. b)…

Calculate without a calculator, using the table of special angles: a) $\sen^2\ 30^\circ + \cos^2\ 60^\circ + \tg\ 45^\circ$. b) $\frac{\sen\ 60^\circ}{\cos\ 30^\circ} + \tg^2\ 30^\circ$.

Solve

Back to the beginning: To measure the height of the building, all you need to do is stand a known distance from its base (the adjacent side) and measure the angle of elevation $\alpha$ to the top: the height is that distance multiplied by $\tan\ \alpha$.

Summary

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