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ESO Y4A · Mathematics
coordinate geometry · Coordinate geometry

The midpoint of a segment

A cable car needs a support tower exactly halfway between the base station and the summit. That "halfway point" has a name: the midpoint of the segment. And since it is just another point, it can also be calculated using coordinates.

Before you start, make sure you know: Operations with integers (2nd ESO)
Before you start, make sure you know: First-degree equations (2nd ESO)

The midpoint formula

Segment on the Cartesian plane joining points A and N, with its midpoint M marked at the centre. A(7, −1) N(−3, 9) M
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When determining the midpoint $M$ of the segment with endpoints $C(-4, 2)$ and $D(6, 8)$, a classmate subtracted the coordinates of the endpoints and divided by two:…

When determining the midpoint $M$ of the segment with endpoints $C(-4, 2)$ and $D(6, 8)$, a classmate subtracted the coordinates of the endpoints and divided by two: $M\left(\frac{6 - (-4)}{2}, \frac{8 - 2}{2}\right) = (5, 3)$. Correct this common error and find the correct coordinates of the midpoint.

Solve
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Calculate the coordinates of the midpoint of the line segment with endpoints $A(4, -2)$ and $B(-6, 8)$.

Calculate the coordinates of the midpoint of the line segment with endpoints $A(4, -2)$ and $B(-6, 8)$.

Solve

Finding the missing endpoint

If you know one endpoint $A$ and the midpoint $M$, you can work out the other endpoint $B$: since $M$ is the mean of $A$ and $B$, then $B = 2M - A$.

Segment showing the endpoint A and the midpoint M, used to deduce the position of the unknown endpoint B. A M B = 2M − A
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Point $M(1, 1)$ is the midpoint of the segment with endpoints $A(-2, 3)$ and $B$. Calculate the coordinates of endpoint $B$.

Point $M(1, 1)$ is the midpoint of the segment with endpoints $A(-2, 3)$ and $B$. Calculate the coordinates of endpoint $B$.

Solve
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A bridge structure features a diagonal beam running from anchor $A(2, 1)$ to node $B(14, 9)$, expressed in metres. A strain sensor needs to be installed exactly at the…

A bridge structure features a diagonal beam running from anchor $A(2, 1)$ to node $B(14, 9)$, expressed in metres. A strain sensor needs to be installed exactly at the centre of the beam. Calculate the coordinates of the sensor.

X Y A(2,1) B(14,9) SENSOR (?)
Solve

Symmetry about a point

Point A reflected about the centre Q to obtain its symmetric point A' at the same distance. A Q A' samedistance samedistance
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Find the coordinates of the reflection of $P(5, -2)$ in point $Q(0, 4)$.

Find the coordinates of the reflection of $P(5, -2)$ in point $Q(0, 4)$.

Solve

Applications: diagonals and centres

The midpoint lies behind many geometric properties: the centre of a circle is the midpoint of any of its diameters; in a parallelogram, the two diagonals intersect at their common midpoint.

Parallelogram with its two diagonals intersecting exactly at their common midpoint. A B C D
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The line segment joining points $P(-4, 7)$ and $Q(8, 3)$ is the diameter of a circle. Calculate the coordinates of the centre of the circle and the exact length of its…

The line segment joining points $P(-4, 7)$ and $Q(8, 3)$ is the diameter of a circle. Calculate the coordinates of the centre of the circle and the exact length of its radius.

Solve
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Three of the vertices of a parallelogram $ABCD$ are $A(-1, -2)$, $B(4, -1)$ and $C(5, 3)$. Knowing that the diagonals of a parallelogram bisect each other, calculate the…

Three of the vertices of a parallelogram $ABCD$ are $A(-1, -2)$, $B(4, -1)$ and $C(5, 3)$. Knowing that the diagonals of a parallelogram bisect each other, calculate the coordinates of the fourth vertex $D$.

Solve
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Given any quadrilateral with vertices at $A(-4, 2)$, $B(2, 6)$, $C(6, 0)$ and $D(0, -6)$, calculate the coordinates of the midpoints of its four sides. Then, prove…

Given any quadrilateral with vertices at $A(-4, 2)$, $B(2, 6)$, $C(6, 0)$ and $D(0, -6)$, calculate the coordinates of the midpoints of its four sides. Then, prove mathematically that the new quadrilateral formed by joining these midpoints is always a parallelogram.

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Summary

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