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ESO Y4A · Mathematics
Algebra · Polynomials

The Remainder Theorem

Imagine that your training app calculates how many calories you have burned using a polynomial formula, and you want to know the result after exactly two hours, without having to rebuild the whole table of earlier values. The remainder theorem does just that with polynomials: it gives you the remainder of a division without dividing, using a single substitution.

Before you start, make sure you know: Polynomial division (3rd ESO)
Before you start, make sure you know: Polynomials (2nd ESO)

The remainder theorem

Concept diagram of the remainder theorem: it links the remainder of dividing P(x) by (x - a) with the numerical value P(a), and shows that a is a root if the result is 0. divide P(x) by (x − a) remainder of P(x) : (x − a) = P(a) if it equals 0 a is a root
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Find the remainder of the division of the polynomial $P(x) = 3x^4 - 2x^3 + 5x - 7$ by $x - 2$ without performing the division.

Find the remainder of the division of the polynomial $P(x) = 3x^4 - 2x^3 + 5x - 7$ by $x - 2$ without performing the division.

Solve
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Calculate the remainder of dividing $U(x) = \frac{1}{2}x^3 - x^2 + 3x - \frac{5}{2}$ by $x - 2$ without dividing using Ruffini's rule.

Calculate the remainder of dividing $U(x) = \frac{1}{2}x^3 - x^2 + 3x - \frac{5}{2}$ by $x - 2$ without dividing using Ruffini's rule.

Solve

Remainders with $x + a$: watch the sign

Dividing by $x + a$ is the same as dividing by $x - (-a)$, so the value you substitute is not $a$, but $-a$.

Concept diagram showing how a divisor of the form x + a is rewritten as x - (-a) to see that the value to substitute into the polynomial is -a. rewrite the divisor x + 1 = x − (−1) compare with x − a substitute a = −1 the remainder is P(−1)
Practice★☆☆Not started
Calculate the remainder of dividing the polynomial $S(x) = -x^5 + 3x^2 - 4$ by $x + 1$ by applying the remainder theorem.

Calculate the remainder of dividing the polynomial $S(x) = -x^5 + 3x^2 - 4$ by $x + 1$ by applying the remainder theorem.

Solve
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Find the remainder of dividing $V(x) = 4x^6 - 3x^4 + 2x^2 - 1$ by $x + 1$ by evaluating the polynomial at the appropriate value.

Find the remainder of dividing $V(x) = 4x^6 - 3x^4 + 2x^2 - 1$ by $x + 1$ by evaluating the polynomial at the appropriate value.

Solve

Zero remainder: the link with roots

The most important case of the theorem is when the remainder is exactly $0$.

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Determine, using the remainder theorem, whether the polynomial $R(x) = 2x^3 - 5x^2 + x + 2$ is divisible by $x - 2$.

Determine, using the remainder theorem, whether the polynomial $R(x) = 2x^3 - 5x^2 + x + 2$ is divisible by $x - 2$.

Solve
Practice★☆☆Not started
Check using the remainder theorem whether $x = -2$ is a root of the polynomial $T(x) = x^4 + 3x^3 - 2x^2 + 12$.

Check using the remainder theorem whether $x = -2$ is a root of the polynomial $T(x) = x^4 + 3x^3 - 2x^2 + 12$.

Solve

Finding a parameter for a given remainder

When a polynomial has an unknown letter (a parameter) and you are told what remainder it must give when divided by $(x-a)$, the theorem turns the problem into a simple equation: substitute, set the result equal to the required remainder and solve.

Step diagram for finding a parameter: evaluate the polynomial at x = a, set P(a) equal to the required remainder R and solve for the parameter k. P(x) with parameter k required remainder = R P(a) = R solve for k
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Calculate the value of the parameter $k$ so that the remainder of dividing the polynomial $P(x) = x^3 - kx^2 + 5x - 2$ by $x - 3$ is equal to $10$.

Calculate the value of the parameter $k$ so that the remainder of dividing the polynomial $P(x) = x^3 - kx^2 + 5x - 2$ by $x - 3$ is equal to $10$.

Solve
Practice★★☆Not started
Find the value of $a$ so that the polynomial $Q(x) = 2x^4 + ax^3 - 3x^2 + 5x - a$ is divisible by $x + 2$.

Find the value of $a$ so that the polynomial $Q(x) = 2x^4 + ax^3 - 3x^2 + 5x - a$ is divisible by $x + 2$.

Solve
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Determine the value of $b$ knowing that dividing the polynomial $R(x) = 3x^3 + bx^2 - 2x + 4$ by $x - 1$ gives the same remainder as dividing it by $x + 2$.

Determine the value of $b$ knowing that dividing the polynomial $R(x) = 3x^3 + bx^2 - 2x + 4$ by $x - 1$ gives the same remainder as dividing it by $x + 2$.

Solve

Several conditions at once

Some problems give two or more conditions about remainders, with two unknown parameters: each condition becomes an equation, and you solve the system.

Diagram of the process for finding two parameters: each division condition gives a linear equation, and both are solved as a system. condition 1 → equation 1 condition 2 → equation 2 system unknowns a, b
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The daily revenue of a shop, in hundreds of euros, is approximated by the polynomial $I(x) = -x^3 + 12x^2 - 20x + c$, where $x$ is the number of days elapsed. If the…

The daily revenue of a shop, in hundreds of euros, is approximated by the polynomial $I(x) = -x^3 + 12x^2 - 20x + c$, where $x$ is the number of days elapsed. If the remainder of dividing $I(x)$ by $x - 5$ is $80$, find the value of the constant term $c$ using the remainder theorem.

Solve
Practice★★★Not started
The design of a sports car bodywork profile is mathematically modelled using a polynomial $D(x) = x^4 + ax^3 + bx^2 - 4x + 4$. To ensure optimal aerodynamics, the…

The design of a sports car bodywork profile is mathematically modelled using a polynomial $D(x) = x^4 + ax^3 + bx^2 - 4x + 4$. To ensure optimal aerodynamics, the polynomial must be divisible by $x - 2$ and leave a remainder of $15$ when divided by $x + 1$. Set up a system of equations using the remainder theorem and calculate the values of $a$ and $b$.

X D(x) 2 D(2)=0 −1 15 D(−1)=15 D(x)
Solve

Back to the start: To find out how many calories you have burned after exactly two hours without rebuilding the table, you just need to calculate the numerical value by substituting $x = 2$ into the app's polynomial formula.

Summary

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