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Real numbers · Real numbers

The real number line

A laboratory instrument never gives "the" exact value: it gives a range. Expressing that range unambiguously (as an interval, as a neighbourhood or as an inequality) is the language you will use constantly in physics, chemistry and technology.

Before you start, make sure you know: Intervals, rays and neighbourhoods (4th ESO)
Before you start, make sure you know: Inequalities in one unknown (4th ESO)

Intervals and inequalities

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Express as an interval and as an inequality the set of real numbers that are greater than or equal to $-3$ and strictly less than $5$.

Express as an interval and as an inequality the set of real numbers that are greater than or equal to $-3$ and strictly less than $5$.

Solve
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Write as an interval the set of real numbers satisfying the condition $|x| \le 7$.

Write as an interval the set of real numbers satisfying the condition $|x| \le 7$.

Solve

Neighbourhoods: E(a, r)

Graphical representation on the real number line of an open neighbourhood with centre a and radius r, lying between a - r and a + r. r r a−r a a+r
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Express the neighbourhood $E(-1, 3)$ as a numerical interval and describe it using an absolute value inequality.

Express the neighbourhood $E(-1, 3)$ as a numerical interval and describe it using an absolute value inequality.

Solve
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Given the open interval $(2, 8)$, express it in neighbourhood notation, explicitly indicating its centre $a$ and its radius $r$.

Given the open interval $(2, 8)$, express it in neighbourhood notation, explicitly indicating its centre $a$ and its radius $r$.

Solve

Distance between two points on the line

Representation of the concept of distance between two points on the real number line using the absolute value of their difference. A = −4,5 B = 2,3 d(A,B) = |A−B| = 6,8
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Calculate the distance on the number line between points $A = -4,5$ and $B = 2,3$, and express the mathematical operation using absolute value notation.

Calculate the distance on the number line between points $A = -4,5$ and $B = 2,3$, and express the mathematical operation using absolute value notation.

Solve
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State which of the following real numbers belong to the interval $[-1, \pi)$: $-1,01$, $-1$, $3,14$, $\frac{22}{7}$, $\sqrt{10}$.

State which of the following real numbers belong to the interval $[-1, \pi)$:

$-1,01$, $-1$, $3,14$, $\frac{22}{7}$, $\sqrt{10}$.

Solve

Operations with intervals: union, intersection, complement

Comparison on the real number line of the half-open interval [-3, 4) with its complement, formed by the union of two disjoint rays. I = [−3, 4) −3 4 (−∞,−3) [4,+∞)
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Given the sets $A = (-\infty, 2]$, $B = (-1, 5)$ and $C = [0, +\infty)$, calculate $(A \cap B) \cup C$ and express the result as a single numerical interval.

Given the sets $A = (-\infty, 2]$, $B = (-1, 5)$ and $C = [0, +\infty)$, calculate $(A \cap B) \cup C$ and express the result as a single numerical interval.

Solve
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Consider the interval $I = [-3, 4)$. Determine the complementary set $\mathbb{R} \setminus I$ and express it as the union of two intervals.

Consider the interval $I = [-3, 4)$. Determine the complementary set $\mathbb{R} \setminus I$ and express it as the union of two intervals.

Solve

Inequalities: from linear to quadratic

Graphical representation of the sign of an upward-opening parabola that crosses the horizontal axis at two roots, showing positive values at the ends and negative values in the middle interval. x₁ x₂ + − + x < x₁sign + x₁ < x < x₂sign − x > x₂sign +
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Solve the inequality $|2x - 5| \le 3$ and represent the solution set as an interval.

Solve the inequality $|2x - 5| \le 3$ and represent the solution set as an interval.

Solve
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Express as a union of intervals the set of all real numbers satisfying the quadratic inequality $x^2 - 4x - 5 > 0$.

Express as a union of intervals the set of all real numbers satisfying the quadratic inequality $x^2 - 4x - 5 > 0$.

Solve

Back to the start: If a laboratory sensor measures $25{,}0\text{ ^\circ C}$ with an uncertainty of $0{,}2\text{ ^\circ C}$, its range is described with complete precision as the neighbourhood $E(25;\, 0{,}2)$, the inequality $|T - 25| < 0{,}2$ or the interval $(24{,}8;\, 25{,}2)$.

Summary

See all the exercises in this section