Characteristics of functions
Analysing a function completely means always answering the same questions: where is it defined?, where does it cross the axes?, where is it positive or negative?, what values can it take? and does it have any symmetry? In Bachillerato these questions are combined in more complex functions than in ESO.
Domain with several restrictions at once
Determine the domain of the rational function $f(x) = \frac{x-1}{x^2-9}$.
Determine the domain of the rational function $f(x) = \frac{x-1}{x^2-9}$.
Find the domain of the function $f(x) = \sqrt{\frac{x+1}{x-3}}$.
Find the domain of the function $f(x) = \sqrt{\frac{x+1}{x-3}}$.
Determine the domain of the function $f(x) = \ln(x^2 - 4x + 3)$.
Determine the domain of the function $f(x) = \ln(x^2 - 4x + 3)$.
Intercepts and sign analysis
Determine the intervals in which the function $q(x) = -3x + 12$ is positive and those in which it is negative.
Determine the intervals in which the function $q(x) = -3x + 12$ is positive and those in which it is negative.
Find the axis intercepts and study the sign of the rational function $g(x) = \frac{x^2-4}{x-1}$.
Find the axis intercepts and study the sign of the rational function $g(x) = \frac{x^2-4}{x-1}$.
Range of a function
State the range of the quadratic function $r(x) = x^2 + 4$.
State the range of the quadratic function $r(x) = x^2 + 4$.
Find the inverse function of $f(x) = \frac{2x-5}{x+1}$ and use it to determine the range of the function $f(x)$.
Find the inverse function of $f(x) = \frac{2x-5}{x+1}$ and use it to determine the range of the function $f(x)$.
Symmetry: even and odd functions
Determine analytically whether the function $h(x) = \frac{x^3}{x^2+1}$ is even, odd or has no symmetry.
Determine analytically whether the function $h(x) = \frac{x^3}{x^2+1}$ is even, odd or has no symmetry.
Prove analytically that the function $f(x) = \ln\left(\frac{1-x}{1+x}\right)$ is odd and determine its domain.
Prove analytically that the function $f(x) = \ln\left(\frac{1-x}{1+x}\right)$ is odd and determine its domain.