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Equations · Algebra

Polynomials

In 4th ESO you already worked with polynomials: adding them, multiplying them and dividing them using Ruffini's rule. In 1st Bachillerato these tools become more general and more useful: they are used to model a company's profit, the path of a drone or the resistance of a circuit, and to solve high-degree equations that would otherwise be impossible to tackle. This section reviews the common ground and signals, in each part, where each idea is developed further.

Before you start, make sure you know: Operations with polynomials (4th ESO)
Before you start, make sure you know: Factorisation and Ruffini's rule (4th ESO)

Definition, degree and basic operations

A polynomial in $x$ is a sum of terms $a_n x^n + a_{n-1}x^{n-1} + \dots + a_1 x + a_0$, where the $a_i$ are real numbers (the coefficients) and the exponents are natural numbers. The degree is the highest exponent with a non-zero coefficient; $a_n$ is the leading coefficient and $a_0$ is the constant term.

To add or subtract polynomials, you collect like terms (terms of the same degree). To multiply, you apply the distributive property: each term of the first polynomial times each term of the second, and then collect like terms.

Step-by-step combined operation to subtract two polynomials after multiplying by a scalar. P(x) = 2x³ − 5x² + 3x − 1 Q(x) = −x³ + 4x² − 2x + 5 2P(x) − Q(x) = (4x³−10x²+6x−2) − (−x³+4x²−2x+5) = 5x³ − 14x² + 8x − 7
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Let $P(x) = 2x^3 - 5x^2 + 3x - 1$ and $Q(x) = -x^3 + 4x^2 - 2x + 5$ be polynomials. Calculate the polynomial resulting from the operation $2P(x) - Q(x)$ and express the…

Let $P(x) = 2x^3 - 5x^2 + 3x - 1$ and $Q(x) = -x^3 + 4x^2 - 2x + 5$ be polynomials. Calculate the polynomial resulting from the operation $2P(x) - Q(x)$ and express the result ordered in descending order of degree.

Solve

Division of polynomials

Dividing $D(x)$ by $d(x)$ gives a quotient $C(x)$ and a remainder $R(x)$ with $D(x)=d(x)\cdot C(x)+R(x)$, where the remainder always has a lower degree than the divisor (or is zero). The algorithm is the same as long division of numbers: you divide the highest-degree term, multiply and subtract, and repeat with what is left.

Classic layout of long Euclidean division of two polynomials, showing dividend, divisor, quotient and remainder. D(x) dividend = d(x) divisor · C(x) quotient + R(x) remainder degree of R(x) lowerthan the degree of d(x)
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Perform the following polynomial division and clearly indicate the quotient polynomial $C(x)$ and the remainder polynomial $R(x)$:…

Perform the following polynomial division and clearly indicate the quotient polynomial $C(x)$ and the remainder polynomial $R(x)$:

$(x^4 - 3x^3 + 2x^2 - x + 5) : (x^2 - x + 1)$

Solve
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In the division of the polynomial $P(x) = 2x^4 - x^3 + kx^2 - 3x + 5$ by $Q(x) = x^2 - x + 2$, find the value of the parameter $k$ so that the remainder of the division…

In the division of the polynomial $P(x) = 2x^4 - x^3 + kx^2 - 3x + 5$ by $Q(x) = x^2 - x + 2$, find the value of the parameter $k$ so that the remainder of the division is a constant number (that is, a polynomial of degree 0). What is the exact value of this remainder?

Solve

A shortcut when the divisor is $x-a$: Ruffini's rule

If the divisor has degree $1$ and is of the form $x-a$, there is no need to set up the long division: Ruffini's rule works only with the coefficients and is much quicker. The next section develops it in depth; here it is enough to recognise when it can be used.

Diagram of Ruffini's rule illustrating the successive additions and multiplications used to find the quotient and remainder. 3−25−7 −2 −616−42 3−821 −49 quotient: 3x² − 8x + 21remainder: −49
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Use Ruffini's rule to divide the polynomial $P(x) = 3x^4 - 2x^3 + 5x - 7$ by the binomial $x + 2$. State the quotient and the remainder.

Use Ruffini's rule to divide the polynomial $P(x) = 3x^4 - 2x^3 + 5x - 7$ by the binomial $x + 2$. State the quotient and the remainder.

Solve

Two shortcuts to find out whether $a$ is a root

Before dividing, it is worth knowing whether it is worthwhile: the remainder theorem says that the remainder of dividing $P(x)$ by $(x-a)$ is, directly, $P(a)$. And the factor theorem says that $(x-a)$ is a factor of $P(x)$ exactly when $P(a)=0$, that is, when $a$ is a root. Both are extended in the sections "Remainder theorem" and "Factorisation".

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Apply the Remainder Theorem to calculate the remainder of the division of the polynomial $P(x) = x^5 - 3x^4 + 2x^2 - 5x + 8$ by $x - 3$, without performing the full…

Apply the Remainder Theorem to calculate the remainder of the division of the polynomial $P(x) = x^5 - 3x^4 + 2x^2 - 5x + 8$ by $x - 3$, without performing the full division.

Solve
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Using the Factor Theorem, check whether the values $x = 2$ and $x = -1$ are roots of the polynomial $P(x) = x^3 - 2x^2 - x + 2$. Justify your answer by showing your…

Using the Factor Theorem, check whether the values $x = 2$ and $x = -1$ are roots of the polynomial $P(x) = x^3 - 2x^2 - x + 2$. Justify your answer by showing your calculations.

Solve

Back to the familiar: common factor, identities and fractions

Factorising starts just as it did in 4th ESO: common factor first, then the standard identities. And an algebraic fraction is simplified in the same way as a numerical fraction, by cancelling the factors that the numerator and denominator have in common.

Diagram of the ordered strategy for factorising polynomials: taking out a common factor, applying standard identities and using Ruffini's rule. 3x³ − 12x → 3x(x² − 4) → 3x(x − 2)(x + 2) common factor, then difference of squares
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Factorise out the common factor and use algebraic identities to fully factorise the polynomial $P(x) = 3x^3 - 12x$.

Factorise out the common factor and use algebraic identities to fully factorise the polynomial $P(x) = 3x^3 - 12x$.

Solve
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Simplify the following algebraic fraction as far as possible, factorising the numerator and the denominator first: $\frac{x^2 - 9}{x^2 + 6x + 9}$

Simplify the following algebraic fraction as far as possible, factorising the numerator and the denominator first:

$\frac{x^2 - 9}{x^2 + 6x + 9}$

Solve
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Perform the following multiplication of algebraic fractions and simplify the result: $\frac{2x}{x-1} \cdot \frac{x^2 - 1}{4x^2}$

Perform the following multiplication of algebraic fractions and simplify the result:

$\frac{2x}{x-1} \cdot \frac{x^2 - 1}{4x^2}$

Solve

Polynomials that model real problems

Many situations — profits, volumes, signals — are described by a polynomial with an unknown parameter. The conditions of the problem (a known value, an exact remainder) are translated into equations that allow us to find that parameter.

Diagram translating two conditions on a polynomial with parameters into a system of two linear equations. B(x) = −x³ + ax² + bx + 4 + B(1) = 0remainder of B(x) ÷ (x−2) = 2 two equations, two unknowns a, b
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The daily profits of a company, in thousands of euros, are modelled by the polynomial $B(x) = -x^3 + ax^2 + bx + 4$, where $x$ is the day of the week (from 1 to 7). It…

The daily profits of a company, in thousands of euros, are modelled by the polynomial $B(x) = -x^3 + ax^2 + bx + 4$, where $x$ is the day of the week (from 1 to 7). It is known that on day 1 the profit is zero. Furthermore, when dividing $B(x)$ by $x-2$, the remainder is $2$. Calculate the parameters $a$ and $b$, and factorise the polynomial to determine on which other day of the week the profit is exactly zero again.

Solve
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A packaging company designs open-topped rectangular boxes from a sheet of cardboard measuring $30 \text{ cm}$ by $20 \text{ cm}$. To do this, they cut squares of side…

A packaging company designs open-topped rectangular boxes from a sheet of cardboard measuring $30 \text{ cm}$ by $20 \text{ cm}$. To do this, they cut squares of side $x$ from each corner and fold up the edges. Express the volume $V(x)$ of the box as a polynomial in standard expanded form. Then, calculate the exact volume if squares of $x = 4 \text{ cm}$ are cut out.

x x x x 30 cm 20 cm
Solve
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The thermal expansion curve of a new polymer is approximated by a cubic polynomial $E(t) = at^3 + bt^2 + ct + d$. In laboratory tests, it was found that at temperatures…

The thermal expansion curve of a new polymer is approximated by a cubic polynomial $E(t) = at^3 + bt^2 + ct + d$. In laboratory tests, it was found that at temperatures $t = 1 \ ^\circ\text{C}$, $t = 2 \ ^\circ\text{C}$, and $t = -1 \ ^\circ\text{C}$, the expansion is zero. However, at $t = 0 \ ^\circ\text{C}$, the expansion is $2 \text{ mm}$. Determine the value of the coefficients $a, b, c, d$ of the polynomial.

Solve

Summary

See all the exercises in this section