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Equations · Systems of equations

Methods of solution

In 4th ESO you solved systems of two equations with two unknowns by substitution, equating or elimination. In Bachillerato those same three methods are still the foundation, but the systems get more complicated: exponentials, logarithms, roots and fractions appear, and sometimes there are three unknowns instead of two. The key idea never changes: reduce the system to something you already know how to solve.

Before you start, make sure you know: Systems of linear equations (4th ESO)
Before you start, make sure you know: Systems of non-linear equations (4th ESO)

Review: substitution, equating and elimination

Summary diagram with the fundamental idea of the methods of substitution, equating and elimination. Substitution: solve for one unknown and substitute Equating: solve for the same unknown twice Elimination: add equations after adjusting coefficients
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Solve the following system of linear equations using the elimination method: $3x - 2y = 7$ $5x + 4y = 8$

Solve the following system of linear equations using the elimination method:

$3x - 2y = 7$

$5x + 4y = 8$

Solve
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Solve the following non-linear system of equations using the substitution method: $x - y = 2$ $x^2 + y^2 = 10$

Solve the following non-linear system of equations using the substitution method:

$x - y = 2$

$x^2 + y^2 = 10$

Solve

Choosing the method according to the form of the system

There is no single "best" method: there is one that is more convenient for each system. If one unknown is almost already isolated, use substitution. If the two equations look very similar, use equating or elimination.

Diagram for choosing the most suitable algebraic method according to the structure of the system. x already isolated→ substitution same unknown→ equating similar coefficients→ elimination
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Find the value of the unknowns $x$, $y$, $z$ in the following system of linear equations, which is already in echelon form: $2x - y + 3z = 14$ $3y - z = 5$ $2z = 8$

Find the value of the unknowns $x$, $y$, $z$ in the following system of linear equations, which is already in echelon form:

$2x - y + 3z = 14$

$3y - z = 5$

$2z = 8$

Solve

Exponentials and logarithms: change of variable

Transformation of an exponential system into a linear system by equating exponents with the same base. 2x+y = 32 = 25 3x−y = 9 = 32 I equate the exponents x + y = 5 x − y = 2 linear system
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Solve the following exponential system of equations by expressing both sides of each equation as powers with the same base: $2^{x+y} = 32$ $3^{x-y} = 9$

Solve the following exponential system of equations by expressing both sides of each equation as powers with the same base:

$2^{x+y} = 32$

$3^{x-y} = 9$

Solve
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Apply the definition of a logarithm to set up an equivalent linear system and solve the following system of equations: $\log_2(x + y) = 3$ $x - 2y = 2$

Apply the definition of a logarithm to set up an equivalent linear system and solve the following system of equations:

$\log_2(x + y) = 3$

$x - 2y = 2$

Solve

Radicals and algebraic fractions

Transformation of a logarithmic system into an algebraic system by applying the properties of logarithms. √x + √y = 5 , x − y = 5 1 solve for x = y + 5 2 substitute 3 square both sides, carefully

In a system with algebraic fractions it is useful to call $u=\dfrac{1}{x}$, $v=\dfrac{1}{y}$ if each unknown appears only in denominators: the system then becomes linear again in $u$, $v$.

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Find the solution to the following system of equations involving radical expressions: $\sqrt{x} + \sqrt{y} = 5$ $x - y = 5$

Find the solution to the following system of equations involving radical expressions:

$\sqrt{x} + \sqrt{y} = 5$

$x - y = 5$

Solve
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Solve the following system of equations containing algebraic fractions, clearly stating the initial restrictions on the unknowns: $\frac{2}{x} + \frac{3}{y} = 2$…

Solve the following system of equations containing algebraic fractions, clearly stating the initial restrictions on the unknowns:

$\frac{2}{x} + \frac{3}{y} = 2$

$\frac{4}{x} - \frac{1}{y} = \frac{1}{6}$

Solve

When there are three unknowns

With three unknowns and three equations, substitution and equating become slow and it is easy to make mistakes. Elimination, applied in an orderly way, is the basis of Gaussian elimination: eliminating unknowns one by one until the system is left in "echelon form", like the one in the warning above.

Transformation of a system of three equations with three unknowns into an echelon-form system by orderly elimination. x + y + z = 6 x − y + 2z = 5 x + y − z = 0 → x + y + z = 6 2z = 6 −2y + z = −1
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Apply Gaussian elimination to transform and solve the following system of three linear equations in three unknowns: $x + y + z = 6$ $x - y + 2z = 5$ $x + y - z = 0$

Apply Gaussian elimination to transform and solve the following system of three linear equations in three unknowns:

$x + y + z = 6$

$x - y + 2z = 5$

$x + y - z = 0$

Solve
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Solve the following system of linear equations using Gaussian elimination and state whether it is a consistent independent system: $2x - y + 3z = 1$ $x + 2y - z = 4$…

Solve the following system of linear equations using Gaussian elimination and state whether it is a consistent independent system:

$2x - y + 3z = 1$

$x + 2y - z = 4$

$4x - y + z = 2$

Solve

Summary

See all the exercises in this section