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ESO Y2 · Mathematics
Numbers · Natural numbers

Prime factorisation

$24$ boxes in a warehouse can be arranged in many ways: $2 \cdot 12$, $3 \cdot 8$, $4 \cdot 6\ldots$ But there is only one way to break it down into prime factors: it is its mathematical "fingerprint".

Before you start, make sure you know: Prime numbers and prime factorisation (1st ESO)
Before you start, make sure you know: Multiples, divisors and divisibility rules (1st ESO)

The fundamental theorem: a unique factorisation

Prime factorisation of the number 24 expressed as a repeated product and in powers: 2 cubed times 3. 24 = 2 · 2 · 2 · 3 = 2³ · 3 However hard you try, you will always arrive at the same prime factors.
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State which number corresponds to each of the following prime factorisations: a) $2^{2} \cdot 3 \cdot 5$ b) $2^{3} \cdot 7$ c) $3^{2} \cdot 11$

State which number corresponds to each of the following prime factorisations:

  1. a) $2^{2} \cdot 3 \cdot 5$
  1. b) $2^{3} \cdot 7$
  1. c) $3^{2} \cdot 11$
Solve
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Classify the following natural numbers into prime or composite. Remember that prime numbers are those that have only two factors: $1$ and themselves.…

Classify the following natural numbers into prime or composite. Remember that prime numbers are those that have only two factors: $1$ and themselves.

$14, 17, 21, 23, 27, 29, 33, 37$

Solve

The factor tree

A visual way to break a number down: you keep splitting the number into any two factors until every branch ends in a prime number.

Tree diagram for factorising the number 24, branching until it reaches the primes 2 and 3. 24 6 4 2 2 2 3 4 is not prime: keep dividing 24 = 2 · 3 · 2 · 2 = 2³ · 3
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Complete the following factor tree for the number $24$. You must find two numbers that multiply to give the level above, until all the numbers at the ends are prime.…

Complete the following factor tree for the number $24$. You must find two numbers that multiply to give the level above, until all the numbers at the ends are prime.

× × × 24 6 ? 2 3 ? ?

Finally, write down the factorisation of $24$ as a product of its prime factors.

Solve
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A video game designer wants to organise a virtual item warehouse. To do so, they need to know how many factors the number of available boxes has, which is $360$. a) Find…

A video game designer wants to organise a virtual item warehouse. To do so, they need to know how many factors the number of available boxes has, which is $360$.

  1. a) Find the prime factorisation of $360$.
  2. b) Using the rule of exponents (add one to each exponent in the factorisation and multiply them), calculate the total number of factors that $360$ has.
Solve

The vertical bar technique

The quickest method for large numbers: you repeatedly divide by the smallest possible prime until you reach $1$.

Vertical bar diagram showing the successive divisions of 60 by 2, 2, 3 and 5 until reaching 1. 602 302 153 55 1 60 = 2² · 3 · 5
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Fill in the blanks in the following prime factorisation of a number using the vertical line method: Write down the final result of the factorisation using powers.

Fill in the blanks in the following prime factorisation of a number using the vertical line method:

60 ? 15 5 1 2 2 ? 5

Write down the final result of the factorisation using powers.

Solve
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Find the prime factorisation of the following numbers. Express the final result as a product of powers: a) $36$ b) $45$ c) $80$

Find the prime factorisation of the following numbers. Express the final result as a product of powers:

  1. a) $36$
  1. b) $45$
  1. c) $80$
Solve

Using the factorisation to reason

Once you have factorised a number, you can answer questions about multiples and divisors without calculating its value.

Checking multiples and divisors from the prime factors of a number without calculating its total value. A = 2² · 3 · 7 multiple of 7? the 7 is there → yes divisible by 10 = 2·5? the 5 is missing → no
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Look at the prime factorisation of the following numbers: $A = 2^{2} \cdot 3 \cdot 7$ $B = 2 \cdot 3^{2} \cdot 5$ Without carrying out the multiplications, answer with…

Look at the prime factorisation of the following numbers:

$A = 2^{2} \cdot 3 \cdot 7$

$B = 2 \cdot 3^{2} \cdot 5$

Without carrying out the multiplications, answer with reasoning:

  1. a) Is the number $A$ a multiple of $7$?
  2. b) Is the number $B$ divisible by $10$? (Hint: see if it has the necessary factors to form $10$).
  3. c) Is the number $3$ a factor of $A$?
Solve
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A Physical Education teacher wants to organise their $28$ students into equal groups of more than $2$ people but fewer than $10$, so that no student is left over. Use…

A Physical Education teacher wants to organise their $28$ students into equal groups of more than $2$ people but fewer than $10$, so that no student is left over.

Use the prime factorisation of $28$ to find all possible ways to make the groups.

Solve

Summary

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