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BAC2 ss · Mathematics
Linear programming · Constraints

Linear inequalities and systems of linear inequalities

A catering company has to decide how many basic menus ($x$) and how many premium menus ($y$) to prepare for an event: the budget, the number of cooks available and the capacity of the hall impose several conditions on $x$ and $y$ at the same time. Each condition is a linear inequality in two unknowns; all of them together form a system. This section reviews how each piece is solved — the half-plane of an inequality, the region of a system — because on that region you will build, in the next sections, linear programming: choosing the best point from among all the possible ones.

Before you start, make sure you know: Systems of inequalities (1st Bachillerato)
Before you start, make sure you know: Inequalities in two unknowns (4th ESO)

The half-plane of a linear inequality

Representation of the solution half-plane of the inequality 2x+3y ≤ 12, with the solid boundary line, the point P on the boundary and the point Q outside the solution. 2x+3y=12 P(3,2) ✓ Q(5,5) ✗
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Represent on the plane the solution half-plane of the inequality $2x + 3y \leq 12$ and check algebraically whether the points $A(3, 2)$ and $B(2, 5)$ belong to it. What…

Represent on the plane the solution half-plane of the inequality $2x + 3y \leq 12$ and check algebraically whether the points $A(3, 2)$ and $B(2, 5)$ belong to it. What special feature does the point $A$ have with respect to the boundary line?

You can do it on paper and send a photo with your answer.

Solve
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Represent the set of points in the plane satisfying $y \geq 2x - 1$. Explain how you decide which half-plane to shade and whether the line $y = 2x - 1$ belongs to the…

Represent the set of points in the plane satisfying $y \geq 2x - 1$. Explain how you decide which half-plane to shade and whether the line $y = 2x - 1$ belongs to the solution or not.

Solve

Systems of inequalities: the intersection of half-planes

Graphical representation of the triangular feasible region formed by the intersection of x ≥ 0, y ≥ 0 and x + y ≤ 5, with its vertices highlighted. x+y=5 x≥0, y≥0, x+y≤5
Practice★☆☆Not started
Represent the solution region of the system formed by $x \geq 0$, $y \geq 0$ and $x + y \leq 5$. What geometric shape is obtained? State its vertices.

Represent the solution region of the system formed by $x \geq 0$, $y \geq 0$ and $x + y \leq 5$. What geometric shape is obtained? State its vertices.

Solve
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Represent the solution region of the system formed by $x \geq 0$, $y \geq 0$, $x + y \leq 6$ and $x \leq 4$. Calculate the coordinates of all its vertices and state what…

Represent the solution region of the system formed by $x \geq 0$, $y \geq 0$, $x + y \leq 6$ and $x \leq 4$. Calculate the coordinates of all its vertices and state what type of polygon it is.

Solve

Setting up the system from a problem statement

The most important step — and the one that goes wrong most often in exams — is translating a text correctly into inequalities. Each condition in the statement ("no more than", "at least", "at most") becomes an inequality with $\leq$ or $\geq$.

Summary table showing the equivalence between everyday expressions and the mathematical inequality symbols. "no more than" / "at most" → ≤ "at least" / "at minimum" → ≥ x ≥ 0, y ≥ 0 (always implicit)
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A sports clothing shop is preparing its spring order: let $x$ be the number of technical t-shirts and $y$ be the number of hoodies it will order. Due to warehouse space,…

A sports clothing shop is preparing its spring order: let $x$ be the number of technical t-shirts and $y$ be the number of hoodies it will order. Due to warehouse space, it cannot receive more than $40$ garments in total, and the supplier requires it to order at least $10$ t-shirts. Write the system of inequalities that captures all these conditions.

Solve
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The figure shows the solution region of a system of inequalities and four points marked on it, as shown in the figure. Decide graphically which points are solutions to…

The figure shows the solution region of a system of inequalities and four points marked on it, as shown in the figure.

0 1 2 3 4 5 6 x 1 2 3 4 5 6 y P(2, 3) Q(3, 4) R(4, 2) S(5, 1)

Decide graphically which points are solutions to the system and confirm your answer by checking each point algebraically in the system $x + 2y \leq 10$, $3x + y \leq 15$, $x \geq 0$, $y \geq 0$.

Solve

Systems with a parameter

Some university entrance exam problems introduce a parameter into one of the constraints and ask how the region changes depending on its value. The strategy is the same: draw the region for a couple of specific values of the parameter and observe which line moves.

Representation of a feasible region bounded by a moving horizontal line y=k for different values of the parameter. y=k (small k) y=k (large k)
Practice★★★Not started
Consider the system formed by $x \geq 0$, $y \geq 0$, $x + y \leq 4$ and $y \leq k$, where $k > 0$ is a parameter. a) Represent the region for $k = 6$ and for $k = 2$.…

Consider the system formed by $x \geq 0$, $y \geq 0$, $x + y \leq 4$ and $y \leq k$, where $k > 0$ is a parameter.

  • a) Represent the region for $k = 6$ and for $k = 2$.

  • b) Determine for which values of $k$ the solution region is a quadrilateral and for which it is a triangle, justifying your answer.

Solve

Back to the start: each limit of the catering company (capacity, cooks, budget) is expressed as a linear inequality; their intersection delimits the polygonal region that contains all the feasible combinations of menus $(x,y)$.

Summary

See all the exercises in this section