Properties of probabilities
You already know what an event is and how events are combined. Now it is time to put numbers on them consistently: you cannot assign just any probability to any event, because there are some minimum rules that every assignment of probabilities must satisfy. From those rules we derive the formulas you will use constantly: the one for the complement and the one for the union.
Kolmogorov's axioms
A video game developer is analysing the probability of obtaining rare items from a loot box. The possible outcomes are: "Common Item" ($C$), "Rare Item" ($R$) and "Epic…
A video game developer is analysing the probability of obtaining rare items from a loot box. The possible outcomes are: "Common Item" ($C$), "Rare Item" ($R$) and "Epic Item" ($E$). State whether the following probability assignment is valid according to Kolmogorov's axioms and justify your answer:
$P(C) = 0,65$
$P(R) = 0,20$
$P(E) = 0,25$
Probability of the complementary event
In a study on mobile app usage among teenagers, it has been determined that the probability of a student having a video editing app installed is $P(V) = 0,35$. Calculate…
In a study on mobile app usage among teenagers, it has been determined that the probability of a student having a video editing app installed is $P(V) = 0,35$. Calculate the probability that a student chosen at random does not have this app installed.
In a box of materials for a technology project there are 50 resistors. It is known that some are $100\ \Omega$ ($A$) and others are $220\ \Omega$ ($B$), and some are new…
In a box of materials for a technology project there are 50 resistors. It is known that some are $100\ \Omega$ ($A$) and others are $220\ \Omega$ ($B$), and some are new and others used. One resistor is drawn at random. If $P(A) = 0,6$ and events $A$ and $B$ are complementary, determine:
- a) The probability of drawing a $220\ \Omega$ resistor.
- b) What is the value of $P(A \cap B)$? Justify your answer based on the relationship between complementary events.
Probability of the union
The third axiom only covers incompatible events. For events that can overlap, we have to subtract the intersection, since otherwise it would be counted twice.
For the graduation trip, Year 13 students must choose between three possible destinations: Mojácar, Mallorca or Tenerife. It is known that the probability of them…
For the graduation trip, Year 13 students must choose between three possible destinations: Mojácar, Mallorca or Tenerife. It is known that the probability of them choosing Mojácar is $P(M) = 0,42$ and that of choosing Mallorca is $P(L) = 0,38$. Given that the events are mutually exclusive (they can only choose one destination), calculate:
- a) The probability that the students travel to Mojácar or Mallorca.
- b) The probability that they choose neither of these two destinations and go to Tenerife.
Let $X$ and $Y$ be two events such that $P(X) = 0,25$ and $P(Y) = 0,55$. Given that these events are mutually exclusive, calculate the probability that: a) Event $X$ or…
Let $X$ and $Y$ be two events such that $P(X) = 0,25$ and $P(Y) = 0,55$. Given that these events are mutually exclusive, calculate the probability that:
- a) Event $X$ or event $Y$ occurs.
- b) Event $X$ does not occur.
- c) $X$ and $Y$ occur at the same time.
Observe the following Venn diagram representing the probabilities of different regions for two events $M$ and $N$ in a sample space $E$. From the data in the diagram,…
Observe the following Venn diagram representing the probabilities of different regions for two events $M$ and $N$ in a sample space $E$.
From the data in the diagram, calculate the following probabilities:
- a) $P(M \cup N)$
- b) $P(M - N)$, that is, the probability of $M$ occurring but not $N$.
- c) $P(\bar{M} \cup \bar{N})$ using de Morgan's Laws.
- d) Are events $M$ and $N$ mutually exclusive? Justify your answer.
Combining De Morgan with the properties: diagrams with data
Many problems give the probability that "neither of the two events occurs" and ask for that of the union (or the other way round). Here De Morgan's laws are combined with the union formula.
Consider events $A$ and $B$ associated with a random experiment. If we know that $P(A) = 0,5$, $P(B) = 0,4$ and that the probability of neither $A$ nor $B$ occurring is…
Consider events $A$ and $B$ associated with a random experiment. If we know that $P(A) = 0,5$, $P(B) = 0,4$ and that the probability of neither $A$ nor $B$ occurring is $P(\bar{A} \cap \bar{B}) = 0,3$, apply de Morgan's Laws to find the probability of the union, $P(A \cup B)$.
Let $A$ and $B$ be two events associated with a random experiment. It is known that the probability that neither of them occurs is $P(\bar{A} \cap \bar{B}) = 0,2$.…
Let $A$ and $B$ be two events associated with a random experiment. It is known that the probability that neither of them occurs is $P(\bar{A} \cap \bar{B}) = 0,2$. Furthermore, it is known that $P(A) = 0,5$ and $P(B) = 0,4$.
Calculate, giving reasons, the following probabilities:
- a) $P(A \cup B)$
- b) $P(A \cap B)$
- c) $P(\bar{A} | B)$
- d) Determine whether events $A$ and $B$ are independent.
In a study on social media use among Year 13 students, two platforms are analysed: InstaPlus* (event $A$) and TikToker* (event $B$). It is known that the probability of…
In a study on social media use among Year 13 students, two platforms are analysed: InstaPlus (event $A$) and TikToker (event $B$). It is known that the probability of a student using at least one of the two is $0,8$. Furthermore, the probability of using the first but not the second is $0,3$. If it is known that the probability of using both platforms is half the probability of using neither of them, calculate:
- a) The probability that a student, chosen at random, uses the TikToker platform.
- b) Are events $A$ and $B$ independent? Justify your answer mathematically by comparing $P(A \cap B)$ with the product of their individual probabilities.
- c) Calculate the probability that they use only one of the two platforms.