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BAC2 ss · Mathematics
Statistics · Inference

Survey technical specifications and critical reading

Every published survey, electoral or otherwise, comes (or should come) with some small print: the technical specifications. Without them, a headline such as "60 % reject..." means nothing: you need to know who was asked, how many people were asked, and what the margin of error is. This section applies everything covered in confidence intervals to reading, and picking apart, a real survey.

Before you start, make sure you know: Approximating the binomial using the normal distribution (1st Bachillerato CCSS)
Before you start, make sure you know: The normal distribution (1st Bachillerato CCSS)

What technical specifications are

Diagram of a survey's technical specifications showing population, sample, sampling error and confidence level. Population: electoral roll (650.000) Sample: 1.200 interviews Sampling error: ± 2,8 % Confidence: 95,5 %
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An election poll publishes the following methodology sheet: "Target population: electoral roll of the province ($650.000$ people). Sample: $1.200$ interviews. Margin of…

An election poll publishes the following methodology sheet: "Target population: electoral roll of the province ($650.000$ people). Sample: $1.200$ interviews. Margin of error: $\pm 2,8\ \%$. Confidence level: $95,5\ \%$".

  • a) Explain what each of the four items of data means.

  • b) What is the relationship between the confidence level and the certainty that the true result lies within the margin of error?

Solve

The margin of error and what it depends on

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A survey on reading habits gives $34\ \%$ daily readers, with a margin of error of $\pm 3\ \%$ and a confidence level of $95 \%$. a) Between which values does the true…

A survey on reading habits gives $34\ \%$ daily readers, with a margin of error of $\pm 3\ \%$ and a confidence level of $95 \%$.

  • a) Between which values does the true percentage of daily readers lie, at that confidence level?

  • b) A headline claims: "Exactly $34$ out of every $100$ people read daily". Correct the headline so that it is honest.

Solve
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The methodology sheet of an opinion poll states: "Target population: $2.400.000$ voters. Sample: $2.400$ random interviews. Margin of error: $\pm 2\ \%$. Confidence…

The methodology sheet of an opinion poll states: "Target population: $2.400.000$ voters. Sample: $2.400$ random interviews. Margin of error: $\pm 2\ \%$. Confidence level: $95\ \%$".

  • a) Interpret each piece of data in the methodology sheet.

  • b) Explain qualitatively why the margin of error depends on the sample size and hardly at all on the population size.

  • c) The poll gives $21\ \%$ to one party and $22\ \%$ to another. Can it be claimed that the second party is ahead? Justify your answer using the margin of error.

Solve

Unrepresentative samples and bias

Diagram comparing the selection of a representative random sample with a sample with selection bias within a population. real population "those who respond" (bias)
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An online newspaper runs the headline: "$60\ \%$ of young people reject the council's new app". In the small print, it reads: survey of $80$ users of a municipal…

An online newspaper runs the headline: "$60\ \%$ of young people reject the council's new app". In the small print, it reads: survey of $80$ users of a municipal services complaint forum.

  • a) Point out all the methodological issues with this headline (sample selection, size, and bias).

  • b) Using the margin of error formula $E = 1,96 \cdot \sqrt{\frac{0,5 \cdot 0,5}{n}}$, estimate the margin of error that even a random sample of that size would have.

  • c) Rewrite the headline honestly.

Solve
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To find out about library usage in a secondary school with $900$ students, $50$ students from a single year group—those in the study hall during the first period—are…

To find out about library usage in a secondary school with $900$ students, $50$ students from a single year group—those in the study hall during the first period—are surveyed.

  • a) Identify which element of the methodology sheet is flawed: the target population, the sample, or the calculation of error?

  • b) Explain why the sample is not representative and propose how to select it correctly.

Solve

Comparing results within the margin of error

Number line representation of two overlapping confidence intervals for proportions of 21 % and 22 % with an error of ± 2 %. A: 21% ± 2% they overlap B: 22% ± 2% 19%20%21%22%23%24%
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True or false, justifying your answer: "If a survey was conducted with $1.200$ people and a confidence level of $95\ \%$, its result coincides exactly with the true…

True or false, justifying your answer: "If a survey was conducted with $1.200$ people and a confidence level of $95\ \%$, its result coincides exactly with the true value for the entire population."

Solve
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Two surveys on the same population and in the same week give different results for the same event: the first estimates $38\ \%$ with a margin of error of $\pm 2\ \%$…

Two surveys on the same population and in the same week give different results for the same event: the first estimates $38\ \%$ with a margin of error of $\pm 2\ \%$ (sample of $2.500$ people) and the second, $34\ \%$ with a margin of error of $\pm 4,5\ \%$ (sample of $450$ people), both at a $95\ \%$ confidence level.

  • a) Write down the intervals in which the true value would lie according to each survey and check that they overlap.

  • b) Using the formula for margin of error, explain why the second has a much larger margin.

  • c) If a headline reads "The surveys contradict each other", is it correct? Justify your answer.

Solve

Designing a survey: sample size and your own technical specifications

Practice★★★Not started
You want to estimate the percentage of students in your city ($25.000$ students) who eat a proper breakfast, with a maximum margin of error of $\pm 3\ \%$ and a…

You want to estimate the percentage of students in your city ($25.000$ students) who eat a proper breakfast, with a maximum margin of error of $\pm 3\ \%$ and a confidence level of $95 \%$.

  • a) Calculate the sample size required in the worst-case scenario ($p = q = 0,5$), using $n = \frac{1,96^2 \cdot 0,25}{E^2}$.

  • b) Describe the population (universe) and a sampling procedure that guarantees representativeness.

  • c) Write out the full methodology sheet (factsheet) of your study as it would appear published.

Solve

Back to the start: If a headline claims that "$60\,\%$ reject...", immediately look for the technical specifications: with a representative sample of $n = 1.000$ people the error is $\pm 3{,}1\,\%$ (true rejection between $56{,}9\,\%$ and $63{,}1\,\%$), but with only $100$ people the error would rise to $\pm 10\,\%$ and an absolute majority would no longer be certain.

Summary

See all the exercises in this section