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BAC2 ss · Mathematics
Determinants · Determinants

Determinants of order 2

To every square matrix we can assign a single number that sums up very useful information about it: whether it has an inverse, whether its rows are "independent", and what area it generates. For $2\times2$ matrices, this number is found with a very simple calculation.

Before you start, make sure you know: Quadratic equations (1st Bachillerato)
Before you start, make sure you know: Vectors. Definitions (1st Bachillerato)

The determinant of a 2×2 matrix

Mnemonic for the 2×2 determinant, with the leading diagonal as a solid line and the other diagonal dashed and subtracted a b c d + a·d − b·c

The product of the leading diagonal (solid) is added; the product of the other diagonal (dashed) is subtracted. The determinant is written $|A|$ or $\det(A)$, and the matrix can also be drawn between vertical bars instead of brackets.

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Calculate the value of the following 2nd-order determinants, paying special attention to the use of negative signs: a) $\begin{vmatrix} 5 & -3 \\ 2 & 4 \end{vmatrix}$ b)…

Calculate the value of the following 2nd-order determinants, paying special attention to the use of negative signs:

  1. a) $\begin{vmatrix} 5 & -3 \\ 2 & 4 \end{vmatrix}$
  1. b) $\begin{vmatrix} -1 & -6 \\ 0 & 7 \end{vmatrix}$
  1. c) $\begin{vmatrix} 10 & 15 \\ 2 & 3 \end{vmatrix}$
2nd-order determinants a) 5 −3 2 4 = ? b) −1 −6 0 7 = ? c) 10 15 2 3 = ? Main Diag. - Anti-Diag. = ?
Solve
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Find the value of the determinant of the matrix $A$ when it contains simple fractions. This type of calculation is common when working with allocation coefficients in…

Find the value of the determinant of the matrix $A$ when it contains simple fractions. This type of calculation is common when working with allocation coefficients in economics problems:

$A = \begin{pmatrix} \frac{1}{2} & 4 \\ \frac{1}{4} & 6 \end{pmatrix}$

Solve

Determinants with an unknown

A determinant can also contain a letter instead of a number. By setting the result equal to a given value, you get an equation, usually linear or quadratic, which you solve as usual.

Diagram showing the care needed with signs when subtracting a negative product on the other diagonal x 5 2 8 = 8x − 10 = 14
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Determine the value of the unknown $x$ so that the following equality holds, where the result of the determinant is a known integer value:…

Determine the value of the unknown $x$ so that the following equality holds, where the result of the determinant is a known integer value:

$\begin{vmatrix} x & 5 \\ 2 & 8 \end{vmatrix} = 14$

Solve
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Consider the matrix $A = \begin{pmatrix} x+1 & 2 \\ x & x-1 \end{pmatrix}$. Determine the real values of $x$ for which the determinant of the matrix is equal to $6$.

Consider the matrix $A = \begin{pmatrix} x+1 & 2 \\ x & x-1 \end{pmatrix}$. Determine the real values of $x$ for which the determinant of the matrix is equal to $6$.

Solve

Singular matrices and regular matrices

Visual comparison between the parallelogram with area of a regular matrix and the collapsed line with no area of a singular matrix |A| ≠ 0 — regular |A| = 0 — singular

Look at the diagram: if the determinant is not $0$, the two rows of $A$ generate a parallelogram with a non-zero area; if it is $0$, the two rows are proportional and the parallelogram is "flattened" into a line, with no area. That is why a singular matrix has no inverse: there is no way to "undo" a transformation that collapses the plane onto a line.

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Given the matrix depending on the real parameter $m$: $$A(m) = \begin{pmatrix} m^2 - 9 & m + 3 \\ m - 3 & 2 \end{pmatrix}$$ a) Calculate the value of its determinant in…

Given the matrix depending on the real parameter $m$:

$$A(m) = \begin{pmatrix} m^2 - 9 & m + 3 \\ m - 3 & 2 \end{pmatrix}$$
  1. a) Calculate the value of its determinant in terms of $m$.
  2. b) Determine all values of $m$ for which the matrix does not have an inverse (singular matrix).
  3. c) If $m = 0$, calculate the determinant of the inverse matrix $A^{-1}$ using the properties of determinants, without finding the inverse matrix explicitly.
Solve
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In a matrix encryption system, a key matrix $K$ of order 2 is used. For the system to be secure and allow decryption, the matrix $K$ must be invertible. The following…

In a matrix encryption system, a key matrix $K$ of order 2 is used. For the system to be secure and allow decryption, the matrix $K$ must be invertible. The following matrix is proposed:

$$K = \begin{pmatrix} k-2 & -3 \\ -2 & k \end{pmatrix}$$
  1. a) Calculate the values of $k$ that make the system insecure (that is, such that $K$ has no inverse).
  2. b) If it is known that the determinant of the key matrix must be equal to $10$ to comply with a specific security standard, calculate the possible values of $k$.
Solve

The determinant as the area of a parallelogram

Parallelogram determined by two vectors in the Cartesian plane, whose area equals the modulus of the determinant u v Area
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A determinant of order 2 can represent the area of a parallelogram defined by two vectors in the plane. Calculate the absolute value of the determinant formed by the…

A determinant of order 2 can represent the area of a parallelogram defined by two vectors in the plane. Calculate the absolute value of the determinant formed by the vectors $\vec{u} = (4, 1)$ and $\vec{v} = (2, 5)$ to find that area:

$Área = \left| \begin{vmatrix} 4 & 2 \\ 1 & 5 \end{vmatrix} \right|$

Parallelogram with one vertex at the origin, whose sides are the vectors u(4, 1) and v(2, 5), drawn on axes with 30 pixels per unitxy04125u(4, 1)v(2, 5)Area
Solve
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In designing a logo for a new tech startup, a designer uses a parallelogram defined by the vectors $\vec{u} = (a, 1)$ and $\vec{v} = (2, a)$. It is known that the area…

In designing a logo for a new tech startup, a designer uses a parallelogram defined by the vectors $\vec{u} = (a, 1)$ and $\vec{v} = (2, a)$. It is known that the area of this parallelogram is given by the modulus of the determinant of the matrix formed by both vectors.

Calculate the value of the parameter $a$ so that the area of the logo is $3$ square units.

X Y a 1 2 a u=(a,1) v=(2,a) Area = 3 u²
Solve

Summary

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