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Secondary 1 · Mathematics
Numbers · Divisibility

Prime Numbers and Prime Factorization

In the school cooperative, $13$ students want to form equal rows for a Physical Education exercise, but they can only line up in one row of $13$ or each one alone. With $12$ students, on the other hand, there are many ways: $2 \times 6$, $3 \times 4$, $1 \times 12$... What is different about $13$ and $12$? The answer lies in their divisors.

Prime and Composite Numbers

Graphical comparison of rectangles: 7 only allows one row of 1 by 7, while 12 allows arrangements of 1 by 12, 2 by 6, and 3 by 4. 7 (prime) 1 × 7 — only one way 12 (composite) 1×12 2×6 3×4
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In PE class, the teacher wants to arrange the $13$ students into perfect rows and columns for an exercise (for example, $2$ rows of $6$ people). a) Why can they not do…

In PE class, the teacher wants to arrange the $13$ students into perfect rows and columns for an exercise (for example, $2$ rows of $6$ people).

  1. a) Why can they not do this with $13$ students in any way other than a single row of $13$?
  2. b) What type of number is $13$ based on its factors?
3 4 12 = 3 × 4 1 left over! 13 = 3 × 4 + 1 1 13 13 = 1 × 13
Solve
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Classify the following numbers in the table according to whether they are prime (they only have two factors: $1$ and themselves) or composite (they have more than two…

Classify the following numbers in the table according to whether they are prime (they only have two factors: $1$ and themselves) or composite (they have more than two factors):

$11, 14, 19, 21, 23, 27, 31, 33$

Prime Numbers Composite Numbers
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The Sieve of Eratosthenes

More than $2{,}000$ years ago, Eratosthenes came up with a "filter" to find all the primes up to a given number: you cross out the multiples of each prime you find, and what survives is prime.

Number grid for the Sieve of Eratosthenes, for crossing out successive multiples and isolating the prime numbers. 1 2 3 4 5 6 7 8 9 10 in gray: crossed out as a multiple of 2, 3, or 5 (and 1, separately) in color: surviving primes → 2, 3, 5, 7

The sieve step by step

  1. Write the numbers from 2 to 30. The 1 is left out because it is not prime.

  2. Circle the smallest number that is not yet circled or crossed out.

  3. Cross out its multiples greater than itself, without crossing out the circled number.

  4. Repeat steps 2 and 3 until every number is circled or crossed out. The circled numbers are the primes.

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At a card collectors' convention, the display stands are numbered from $10$ to $25$. The organisers want to highlight stands with a prime number using an orange sign.…

At a card collectors' convention, the display stands are numbered from $10$ to $25$. The organisers want to highlight stands with a prime number using an orange sign. Write the list of all stand numbers that should have an orange sign.

STAND 10 STAND 11 STAND 12 STAND 13 STAND 14 STAND 15 STAND 16 STAND 17 STAND 18 STAND 19 STAND 20 STAND 21 STAND 22 STAND 23 STAND 24 STAND 25 Orange sign (Prime Number) To check
Solve
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The Sieve of Eratosthenes works like a filter that lets only prime numbers through. If we pour the numbers from $1$ to $10$ into the filter, explain why the number $1$…

The Sieve of Eratosthenes works like a filter that lets only prime numbers through. If we pour the numbers from $1$ to $10$ into the filter, explain why the number $1$ is not considered prime and why the number $9$ gets trapped in the filter for composite numbers.

Input: 1 to 10 1 Discarded Neither prime nor composite 4 6 8 10 9 Trapped Is composite 9 = 3² 7 5 3 2 Prime Numbers Pass the filter
Solve
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Classify the following numbers as prime or composite, justifying your answer using the divisibility rules. For the composite numbers, state at least one divisor other…

Classify the following numbers as prime or composite, justifying your answer using the divisibility rules. For the composite numbers, state at least one divisor other than $1$ and the number itself:

$47, 51, 67, 87, 91, 101$

Solve
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In a math class, the teacher says that to find out if a number less than $100$ is prime, it is sufficient to check that it is not divisible by $2, 3, 5$ and $7$. Explain…

In a math class, the teacher says that to find out if a number less than $100$ is prime, it is sufficient to check that it is not divisible by $2, 3, 5$ and $7$.

Explain why there is no need to check if it is divisible by $11$ or by other larger prime numbers. Apply this idea to check if the number $97$ is prime.

Solve
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To check whether the number $601$ is prime, a student claims that they only need to divide it by the prime numbers less than $25$. a) Justify why the student has chosen…

To check whether the number $601$ is prime, a student claims that they only need to divide it by the prime numbers less than $25$.

  1. a) Justify why the student has chosen the number $25$ as a limit.
  2. b) Carry out the necessary divisions following their reasoning and determine whether $601$ is prime or composite.
  3. c) What is the largest prime number you would have to test to know if $1009$ is prime?
Solve

Prime Factorization

Every composite number can be written as a product of prime numbers: they are the "building blocks" it is made of.

Vertical bar layout of the prime factorization of 120, giving two cubed times three times five. 1202 602 302 153 55 1 120 = 2³ · 3 · 5

You can also use a factor tree: you split the number into two factors and keep splitting each one until every branch ends in a prime. The result is the same.

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Look at the following "division tower" (prime factorisation) and identify the missing numbers in the blank spaces so that it is correct:

Look at the following "division tower" (prime factorisation) and identify the missing numbers in the blank spaces so that it is correct:

60 30 5 1 2 3 5 ÷2
Solve
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Find the prime factorisation of the number $40$ using the vertical line method and express the result as a product of powers.

Find the prime factorisation of the number $40$ using the vertical line method and express the result as a product of powers.

Solve
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Find out which number it is in each case by working out the powers and multiplying the factors: a) $2^2 \times 3 \times 5 = $ b) $2 \times 3^3 = $ c) $3^2 \times 11 = $

Find out which number it is in each case by working out the powers and multiplying the factors:

  1. a) $2^2 \times 3 \times 5 = $
  2. b) $2 \times 3^3 = $
  3. c) $3^2 \times 11 = $
Solve
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The number $12$ can be represented in a rectangular shape in several ways (for example, $2 \times 6$ or $3 \times 4$). However, a prime number can only form a single…

The number $12$ can be represented in a rectangular shape in several ways (for example, $2 \times 6$ or $3 \times 4$). However, a prime number can only form a single row.

Look at the drawing and find the prime factorisation of the total number of dots forming the rectangle:

Hint: Both sides of the rectangle are prime
Solve
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Find the prime factorisation of the following numbers using the vertical line method. Express the final result using powers where possible: a) $180$ b) $252$ c) $450$

Find the prime factorisation of the following numbers using the vertical line method. Express the final result using powers where possible:

  1. a) $180$
  2. b) $252$
  3. c) $450$
Solve
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Fill in the blanks in this factor tree for the number $120$. Remember that each branch must end in a prime number for the factorisation to be complete. Then write the…

Fill in the blanks in this factor tree for the number $120$. Remember that each branch must end in a prime number for the factorisation to be complete. Then write the final result using powers.

120 12 ? ? 4 ? ? ? ? 120 =
Solve
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Sometimes, to factorize numbers ending in zero, we can use mental "shortcuts". For example, we know that $10 = 2 \times 5$, so each trailing zero contributes a factor…

Sometimes, to factorize numbers ending in zero, we can use mental "shortcuts". For example, we know that $10 = 2 \times 5$, so each trailing zero contributes a factor $2$ and a factor $5$.

Factorize the following numbers using this trick to save steps in the vertical line (you can remove each trailing zero at once by writing $2 \times 5$ on the right):

  1. a) $1,200$
  2. b) $4,500$
  3. c) $18,000$
Diagram of the shortcut: a trailing zero breaks down into the factors 2 and 5 SHORTCUT 0 2 5 Each trailing zero contributes a 2 and a 5
Solve
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In the math lab, an incomplete prime factorization has been left on the board. Help reconstruct it knowing that the original number is less than $500$. Calculate the…

In the math lab, an incomplete prime factorization has been left on the board. Help reconstruct it knowing that the original number is less than $500$.

X < 500 X Y 25 5 1 2 P 5 5

Calculate the value of the original number $X$, the intermediate quotient $Y$ and the prime factor $P$ knowing that $P$ is the smallest possible prime number that makes $X$ a multiple of $3$.

Solve

Divisors from the Factorization

With the factorization you can find all the divisors by combining the factors, without testing them one by one.

Combining the powers of the prime factors to obtain all the divisors of a number. N = 2² · 13 1 2 4 13 26 52 powers of 2 × 1 o × 13
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Find all the factors of the number $N$ knowing that its prime factorisation is $N = 2^2 \times 13$. Is $N$ a composite or prime number? Justify your answer based on the…

Find all the factors of the number $N$ knowing that its prime factorisation is $N = 2^2 \times 13$. Is $N$ a composite or prime number? Justify your answer based on the definition of these types of numbers.

Solve
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Find all the factors of the following numbers using their prime factorisation. Show the process of combining factors: a) $28$ b) $42$

Find all the factors of the following numbers using their prime factorisation. Show the process of combining factors:

  1. a) $28$
  2. b) $42$
Solve
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Find the smallest number that has exactly $6$ factors, knowing that only the first two prime numbers appear in its prime factorisation. Explain your reasoning by…

Find the smallest number that has exactly $6$ factors, knowing that only the first two prime numbers appear in its prime factorisation. Explain your reasoning by analysing the exponents in its factorisation.

N = 2ᵃ · 3ᵇ (a+1) · (b+1) = 6 6 factors in total 1 N Pairs multiplying to N
Solve
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A natural number $N$ has the following property: its prime factorisation is of the form $2^a \times 3^b$. We know that if we multiply $N$ by $2$, its number of factors…

A natural number $N$ has the following property: its prime factorisation is of the form $2^a \times 3^b$. We know that if we multiply $N$ by $2$, its number of factors increases by $3$, and if we multiply it by $3$, its number of factors increases by $4$.

Calculate the value of the exponents $a$ and $b$, and find the number $N$.

Solve

GCF and LCM with Factorization

Factorization also helps you compare two numbers. Let's take $A = 2^3 \cdot 3^2 \cdot 5$ and $B = 2^2 \cdot 3 \cdot 7$.

The LCM solves "how often do they coincide" problems. For example: two buses leave a terminal together, one every $6$ minutes and the other every $10$. Since $6 = 2 \cdot 3$ and $10 = 2 \cdot 5$, the LCM is $2 \cdot 3 \cdot 5 = 30$: they coincide every $30$ minutes. And if you group a number in sixes and in tens and there is always the same amount left over, that number is the LCM (or a multiple of it) plus the amount left over.

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Marta has a collection of old coins. If she groups them $6$ by $6$, she has $3$ left over. If she groups them $10$ by $10$, she also has $3$ left over. Knowing that she…

Marta has a collection of old coins. If she groups them $6$ by $6$, she has $3$ left over. If she groups them $10$ by $10$, she also has $3$ left over.

Knowing that she has more than $50$ coins but fewer than $80$, exactly how many coins does Marta have in her collection? (Hint: relate the problem to the concept of least common multiple).

Solve
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Given the numbers $A = 2^4 \times 3^2 \times 5 \times 11$ and $B = 2^3 \times 3^4 \times 7$. Without calculating the numerical value of $A$ or $B$, answer giving…

Given the numbers $A = 2^4 \times 3^2 \times 5 \times 11$ and $B = 2^3 \times 3^4 \times 7$.

Without calculating the numerical value of $A$ or $B$, answer giving reasons:

  1. a) Is the product $A \times B$ divisible by $55$?
  2. b) Is the product $A \times B$ a multiple of $54$?
  3. c) What is the prime factorisation of the number resulting from $M.C.D.(A, B)$?
Solve

Back to the beginning: the $13$ students can only form one row because $13$ is prime (its only divisors are $1$ and $13$); $12$ is composite and has $6$ divisors ($1, 2, 3, 4, 6$, and $12$), which is why there are so many ways to organize them.

Summary

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