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derivatives · Derivatives

Differentiation Rules

Before you start, make sure you know: Logarithms (High School Year 2 (semesters 3 and 4))

Regina owns a taco stand and knows that her profit depends on how many orders she sells. She wants to know how much her profit changes if she sells one more order, and she doesn't want to compute a limit every time. In this section you will see the rules that turn the derivative into a fast, mechanical calculation, for costs, profits, social media users, and much more.

From the definition to the rules: the four steps

The average rate of change of $f$ on $[a, b]$ is $\dfrac{f(b)-f(a)}{b-a}$. The derivative $f'(x)$ is the instantaneous rate of change: what is left of that average rate when the interval gets smaller and smaller. To compute it from scratch you follow the four-step rule.

It works, but it's long. The following rules give you the same result in one line.

Practice★☆☆Not started
A content creator has observed that the number of views of one of their videos on a social network follows the function $f(t) = t^2 + 20t + 100$, where $t$ is the time…

A content creator has observed that the number of views of one of their videos on a social network follows the function $f(t) = t^2 + 20t + 100$, where $t$ is the time in hours since it was published.

Calculate the Average Rate of Change (A.R.O.C.) of the number of views in the interval $[1, 4]$. Interpret the result obtained in the context of the problem.

1 2 3 4 5 t (h) 125 150 175 200 225 f(t) f(1) f(4) Δt = 3 Δf = ? A.R.O.C. = ? f(t) = t² + 20t + 100
Solve

Basic rules: constant, power, sum

From the limit in the four steps you get these rules, which you will use all the time.

We will also use two derivatives that you should already know: $(e^x)' = e^x$ and $(\ln x)' = \dfrac{1}{x}$.

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Calculate the derivative of the following polynomial functions using the basic rules of differentiation: a) $f(x) = 5x^3 - 2x^2 + 7x - 10$ b)…

Calculate the derivative of the following polynomial functions using the basic rules of differentiation:

  1. a) $f(x) = 5x^3 - 2x^2 + 7x - 10$
  1. b) $g(x) = \frac{1}{4}x^4 + \frac{2}{3}x^3 - 5$
  1. c) $h(x) = x^5 - \sqrt{2}x$
Solve
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The total cost (in pesos) of manufacturing $x$ units of a custom sneaker model is given by the function $C(x) = 10x^2 + 200x + 4\,000$. a) Calculate the marginal cost…

The total cost (in pesos) of manufacturing $x$ units of a custom sneaker model is given by the function $C(x) = 10x^2 + 200x + 4\,000$.

  1. a) Calculate the marginal cost function $C'(x)$.
  1. b) Find the marginal cost when 20 units are produced and interpret what this value means for the company.
Solve

The product rule

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Given the function $f(x) = (3x - 5) \times e^x$, find its derivative by applying the product rule. Simplify the result by factorising where possible.

Given the function $f(x) = (3x - 5) \times e^x$, find its derivative by applying the product rule. Simplify the result by factorising where possible.

Solve

The quotient rule

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Calculate the derivative of the following rational function using the quotient rule: $$f(x) = \frac{2x + 3}{x - 1}$$ State for which values of $x$ the derivative of this…

Calculate the derivative of the following rational function using the quotient rule:

$$f(x) = \frac{2x + 3}{x - 1}$$

State for which values of $x$ the derivative of this function does not exist, based on its domain.

Solve

Tangent line and normal line

The derivative $f'(a)$ is the slope of the tangent line at $x = a$. With the slope and the point $(a, f(a))$ you can write the line.

If the point is not on the curve, you can't start with $f(P)$. Call $a$ the $x$-coordinate of the point of tangency and require that the tangent at $a$ pass through $P$.

Parabola y = x² with its two tangent lines at x = 2 and x = -2, which pass through the point (0, -4) P(0, -4) (2, 4) (-2, 4) y = x²
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Find the equation of the tangent line to the graph of the function $f(x) = x^2 - 4x + 1$ at the point with abscissa $x = 3$. The figure shows the graph of $f$ and the…

Find the equation of the tangent line to the graph of the function $f(x) = x^2 - 4x + 1$ at the point with abscissa $x = 3$.

The figure shows the graph of $f$ and the point $P$ on the curve with that abscissa.

Parabola f(x) = x² − 4x + 1 with the point P(3, −2) marked on the curvexyO12341−2P(3, −2)f(x) = x² − 4x + 1
Solve
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Given the function $f(x) = \dfrac{x^2 + k}{x - 1}$, calculate the value of the constant $k$ knowing that the gradient of the tangent line to the graph of $f(x)$ at the…

Given the function $f(x) = \dfrac{x^2 + k}{x - 1}$, calculate the value of the constant $k$ knowing that the gradient of the tangent line to the graph of $f(x)$ at the point with abscissa $x = 2$ is equal to $-3$. Once $k$ has been found, write the complete equation of this tangent line.

Solve
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Consider the curve $y = x^3 - 6x^2 + 4$ and the line $r: y = -9x + 2$. a) Find the points of the curve at which the tangent line is parallel to the line $r$. b) Write…

Consider the curve $y = x^3 - 6x^2 + 4$ and the line $r: y = -9x + 2$.

  1. a) Find the points of the curve at which the tangent line is parallel to the line $r$.
  1. b) Write the equations of the tangent lines to the curve at those points.
Solve
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Find the equations of the tangent lines to the curve $f(x) = x^2 - 4x + 3$ that pass through the external point $P(2, -5)$. Hint: Remember that point $P$ does not…

Find the equations of the tangent lines to the curve $f(x) = x^2 - 4x + 3$ that pass through the external point $P(2, -5)$.

Hint: Remember that point $P$ does not necessarily lie on the graph of the function. You should write the gradient of the tangent line at a generic point $(a, f(a))$ and equate it to the gradient of the line connecting that point to $P$.

Solve

Composite functions: the chain rule

A composite function is a function inside another one, like $\sqrt{4x+1}$ or $(3x^2-1)^5$. This topic has its own page; here is what you need.

Roots are easier to differentiate as fractional powers: $\sqrt[3]{u^2} = u^{2/3}$, so its derivative is $\frac23 u^{-1/3}u'$.

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Given the function $f(x) = \sqrt{x^2 + 9}$, calculate its derivative using the chain rule. Once obtained, find the value of the gradient of the tangent line to the curve…

Given the function $f(x) = \sqrt{x^2 + 9}$, calculate its derivative using the chain rule. Once obtained, find the value of the gradient of the tangent line to the curve at the point $x = 4$.

x y x=4 f(4) f(x) = √(x² + 9) Tangent line dx dy m = f'(4)
Solve

Exponentials and logarithms

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Apply the chain rule to find the derivative of the following composite functions: a) $f(x) = (2x^2 + 1)^4$ b) $g(x) = \ln(5x - 2)$ c) $h(x) = e^{3x^2}$

Apply the chain rule to find the derivative of the following composite functions:

  1. a) $f(x) = (2x^2 + 1)^4$
  1. b) $g(x) = \ln(5x - 2)$
  1. c) $h(x) = e^{3x^2}$
Solve
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Calculate the derivative of the following functions using the rules of differentiation, simplifying the final result whenever possible: a)…

Calculate the derivative of the following functions using the rules of differentiation, simplifying the final result whenever possible:

  1. a) $f(x) = \sqrt[3]{(5x^2 - 1)^2}$
  1. b) $g(x) = \ln\left(\dfrac{x^2 + 3}{x - 2}\right)$ (use the properties of logarithms before differentiating).
  1. c) $h(x) = 3^{x^2} \times (2x + 5)$
Solve

Combinations: costs, profits, and growth

In real problems several rules get mixed. Identify the outermost operation (sum, product, quotient, composition) and work inward. Simplify at the end.

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A cosmetics company has estimated that the daily profit (in hundreds of pesos) generated by the sale of a new facial serum follows the function…

A cosmetics company has estimated that the daily profit (in hundreds of pesos) generated by the sale of a new facial serum follows the function $B(t) = 20t \times e^{-0.2t}$, where $t$ is the time in months since its launch. The figure shows the graph of $B(t)$ and marks the point corresponding to $t=5$.

  1. a) Obtain the expression of the function $B'(t)$, which represents the rate of change of the profit.
  1. b) Calculate the value of the derivative 5 months after its launch and interpret the result obtained in economic terms.
Graph of the function B(t) = 20t·e^(-0,2t) for t between 0 and 16 months, with the point with abscissa t = 5 marked5101510203040t (months)B (hundreds of $)B(t)
Solve
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Consider the function $f(x) = \dfrac{e^{2x}}{x^2 + 1}$. a) Calculate its derivative $f'(x)$, simplifying the expression as much as possible. b) Determine whether there…

Consider the function $f(x) = \dfrac{e^{2x}}{x^2 + 1}$.

  1. a) Calculate its derivative $f'(x)$, simplifying the expression as much as possible.
  1. b) Determine whether there is any point where the curve has a horizontal tangent (zero gradient). If so, state the coordinates of that point.
Solve
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A biotechnology company has modeled the total production cost (in thousands of pesos) of a new drug using the function: $$C(x) = \sqrt{x^2 + 9} + \ln(x+1)$$ where $x$ is…

A biotechnology company has modeled the total production cost (in thousands of pesos) of a new drug using the function:

$$C(x) = \sqrt{x^2 + 9} + \ln(x+1)$$

where $x$ is the number of batches produced.

  1. Calculate the marginal cost function $C'(x)$.

  2. Determine the rate at which the cost changes when exactly 4 batches are being produced.

Solve

Piecewise functions: continuity and differentiability

A piecewise function changes formula at a point $x = c$. For it to be differentiable at $c$, the curve can't have jumps or "corners."

Practice★★☆Not started
Determine the values of the parameters $a$ and $b$ so that the following function is continuous and differentiable across the set of real numbers $\mathbb{R}$:…

Determine the values of the parameters $a$ and $b$ so that the following function is continuous and differentiable across the set of real numbers $\mathbb{R}$:

$f(x) = \begin{cases} ax^2 + 3x & \text{if } x \le 2 \\ \dfrac{b}{x} + 1 & \text{if } x > 2 \end{cases}$

Solve
Practice★★★Not started
Given the following piecewise function, determine the values of the parameters $a$ and $b$ so that the function is differentiable across its entire domain (especially at…

Given the following piecewise function, determine the values of the parameters $a$ and $b$ so that the function is differentiable across its entire domain (especially at the boundary point $x = 1$):

$$f(x) = \begin{cases} a \times e^{x-1} + 2x^2 & \text{if } x \le 1 \\ \frac{x^2 + b}{x} & \text{if } x > 1 \end{cases}$$ 0 x y x = 1 f₁(x) f₂(x) y = 2x - 2
Solve

Logarithmic differentiation

Functions like $x^x$ or $(x^2+1)^{\ln x}$ are not "pure" powers or exponentials, so no row of the table works.

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Apply the technique of logarithmic differentiation to find the expression for the derivative of: $f(x) = (x^2 + 1)^{\ln(x)}$

Apply the technique of logarithmic differentiation to find the expression for the derivative of:

$f(x) = (x^2 + 1)^{\ln(x)}$

Solve

Successive derivatives

The derivative of $f'$ is called the second derivative $f''$; the derivative of $f''$ is $f'''$, and so on: $f^{(n)}$ is the derivative of order $n$. The second derivative measures how the slope changes, and you will use it to tell whether the curve is concave up ($f''>0$) or concave down ($f''<0$).

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Given the function $f(x) = x^2 \times \ln(x)$, calculate: a) The first derivative $f'(x)$. b) The second derivative $f''(x)$. c) The equation of the normal line to the…

Given the function $f(x) = x^2 \times \ln(x)$, calculate:

  1. a) The first derivative $f'(x)$.
  1. b) The second derivative $f''(x)$.
  1. c) The equation of the normal line to the graph at the point with abscissa $x = e$. (Remember that the normal line is perpendicular to the tangent at the point of contact).
1 2 3 4 5 2 4 6 8 0 x y e e² f(x) = x²·ln(x) Tangent Normal
Solve
Practice★★★Not started
Given the rational function $f(x) = \frac{1}{2x - 3}$, obtain a general expression for its nth derivative, $f^{(n)}(x)$. To do this, calculate the 1st, 2nd, 3rd, and 4th…

Given the rational function $f(x) = \frac{1}{2x - 3}$, obtain a general expression for its nth derivative, $f^{(n)}(x)$.

To do this, calculate the 1st, 2nd, 3rd, and 4th order derivatives, identify the pattern in numbers and signs, and write it in terms of $n$ and the factorial $n!$.

Solve

Critical points and the second derivative

A local maximum or minimum of a differentiable function occurs where the tangent is horizontal: $f'(a) = 0$.

When there are unknown parameters, each piece of data gives an equation. "The curve passes through $P$" gives $f(x_P) = y_P$. "There is an extremum at $x_P$" gives $f'(x_P) = 0$.

And if you are asked for the maximum growth rate, it is not the maximum of the function but that of its derivative $N'$. So you look for $N''(t) = 0$.

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Determine the values of $a, b \in \mathbb{R}$ so that the function $f(x) = \dfrac{ax + b}{x^2 - 4}$ has a relative extremum at the point $P(0, -1)$. Once you have found…

Determine the values of $a, b \in \mathbb{R}$ so that the function $f(x) = \dfrac{ax + b}{x^2 - 4}$ has a relative extremum at the point $P(0, -1)$. Once you have found the parameters, use the second derivative to confirm whether it is a maximum or a minimum.

Solve
Practice★★★Not started
The number of active users on a new social network (in millions) follows a logistic growth model given by the function: $$N(t) = \frac{100}{1 + 9e^{-0.5t}}$$ where $t$…

The number of active users on a new social network (in millions) follows a logistic growth model given by the function:

$$N(t) = \frac{100}{1 + 9e^{-0.5t}}$$

where $t$ is the time in months since its launch.

  1. Find the function $N'(t)$ representing the growth rate of the social network.

  2. In which month is the user growth rate at its maximum?

Hint: You must find the maximum of the derivative function $N'(t)$, which involves calculating the second derivative $N''(t)$ and setting it equal to zero.

Solve

Back to the beginning: Regina's profit, $U(x)$, changes by approximately $U'(x)$ pesos when she sells one more order. Now you know how to compute $U'(x)$ with the rules, even when $U$ combines products, quotients, or exponentials.

Summary

See all the exercises in this section