Infinite Limits and Limits at Infinity
A stationery shop orders T-shirts printed for Buen Fin. It pays a fixed cost of $\$3{,}000$ plus $\$20$ for each T-shirt, so the average cost per piece is $CP(x) = \dfrac{20x + 3000}{x}$. If it prints just 1 T-shirt, that average is huge. If it prints thousands, what does it get close to? Answering this takes two kinds of limit: when $x$ approaches a point and the function shoots up, and when $x$ grows without bound.
Infinite limit at a point: vertical asymptote
When the denominator of a rational function is zero at $x_0$ and the numerator is not, the function shoots up near $x_0$.
Tables also work when the limit is a number. For $f(x)=\dfrac{x^2-1}{x-1}$ the function is not defined at $x=1$, but $f(0.9)=1.9$, $f(0.99)=1.99$, $f(1.01)=2.01$, $f(1.1)=2.1$: the values approach $2$. The limit describes what value the function approaches, not the value it takes at the point.
To read limits on a graph, follow the curve with your finger from the left and from the right of the point: an open circle means that point does not belong to the function, but the limit is still read from the height the curve reaches. If both sides reach the same height, that is the limit. If they do not match, the overall limit does not exist.
Look at the graph of the function $f(x)$ and determine the value of the one-sided limits as the variable $x$ approaches $x = 2$, that is, $\lim_{x \to 2^-} f(x)$ and…
Look at the graph of the function $f(x)$ and determine the value of the one-sided limits as the variable $x$ approaches $x = 2$, that is, $\lim_{x \to 2^-} f(x)$ and $\lim_{x \to 2^+} f(x)$. From your observation, explain whether the overall limit $\lim_{x \to 2} f(x)$ exists.
In the graph, the open circle indicates that this point does not belong to the function, and the filled dot does belong to it.
Complete the following table of values for the function $f(x) = \frac{x^2 - 1}{x - 1}$ and intuitively estimate the value of the limit $\lim_{x \to 1} f(x)$. Explain…
Complete the following table of values for the function $f(x) = \frac{x^2 - 1}{x - 1}$ and intuitively estimate the value of the limit $\lim_{x \to 1} f(x)$. Explain why, even though the function is not defined at $x = 1$, we can still talk about its limit at that point.
| $x$ | 0.9 | 0.99 | 0.999 | 1,001 | 1.01 | 1.1 |
|---|---|---|---|---|---|---|
| $f(x)$ |
Given the function $f(x) = \frac{4}{x - 3}$, study its behavior as $x$ approaches $3$ from both sides. To do so, calculate: a) $\lim_{x \to 3^-} f(x)$ b)…
Given the function $f(x) = \frac{4}{x - 3}$, study its behavior as $x$ approaches $3$ from both sides. To do so, calculate:
- a) $\lim_{x \to 3^-} f(x)$
- b) $\lim_{x \to 3^+} f(x)$
State whether the function has any vertical asymptote and write its equation.
Limits at infinity of polynomials
What happens to a function when $x$ grows without bound? In a polynomial, the highest-degree term rules: the others become insignificant.
For example, with $x=1{,}000$ in $x^2-5x$: $x^2=1{,}000{,}000$ and $5x=5{,}000$. The second term barely matters.
For the sign: $x^n$ with $n$ even is positive at both ends, and with $n$ odd it has the sign of $x$. Then multiply by the sign of $a_n$.
Calculate the following limits at infinity for the given polynomial functions. Remember that the term of highest degree is the one that determines the end behavior of…
Calculate the following limits at infinity for the given polynomial functions. Remember that the term of highest degree is the one that determines the end behavior of the function:
- a) $\lim_{x \to +\infty} (-x^3 + 5x^2 + 2)$
- b) $\lim_{x \to -\infty} (2x^4 - 3x + 1)$
- c) $\lim_{x \to -\infty} (x^5 + x^2)$
Imagine that the daily profit of a new specialty café, in pesos, follows the function $B(t) = 2t^2 - 10t + 50$, where $t$ is the time in months since its opening. What…
Imagine that the daily profit of a new specialty café, in pesos, follows the function $B(t) = 2t^2 - 10t + 50$, where $t$ is the time in months since its opening. What will happen to the profit if the café keeps operating indefinitely? Calculate $\lim_{t \to +\infty} B(t)$ and interpret the result in the context of the problem.
Limits at infinity of rational functions
In a fraction of polynomials, the only thing that matters when $x\to\pm\infty$ is comparing the degree of the numerator with that of the denominator.
If the exponent of the numerator is larger, the graph has no horizontal asymptote. For example, $\dfrac{x^2+10}{x-5}$ grows without bound as $x\to+\infty$ and tends to $-\infty$ as $x\to-\infty$ (branches that open up, not leveling off).
Analyse the degree of the numerator and the denominator to determine the value of the following limits at infinity without carrying out complex operations: a)…
Analyse the degree of the numerator and the denominator to determine the value of the following limits at infinity without carrying out complex operations:
- a) $\lim_{x \to +\infty} \frac{5x^2 - 3x}{2x^2 + 1}$
- b) $\lim_{x \to +\infty} \frac{x + 7}{x^2 - 4}$
- c) $\lim_{x \to +\infty} \frac{x^3 - 1}{100x^2 + 5}$
A market study analyzes the evolution of the number of users of a new messaging app, measured in thousands, by means of the function $U(t) = \dfrac{40t + 10}{2t + 5}$,…
A market study analyzes the evolution of the number of users of a new messaging app, measured in thousands, by means of the function $U(t) = \dfrac{40t + 10}{2t + 5}$, where $t$ represents the time in months since its launch. The figure shows the graph of this function.
- a) Analyze what happens to the number of users around the third month. To do so, calculate the following limit, showing your reasoning:
- b) Determine the long-term behavior of the app. Is there a maximum value that the number of users approaches? Interpret the result in terms of horizontal asymptotes.
Calculate the following limits at infinity using the comparison of dominant terms and explain their graphical meaning (whether they tend to a specific value or display…
Calculate the following limits at infinity using the comparison of dominant terms and explain their graphical meaning (whether they tend to a specific value or display parabolic branches):
- a) $\lim_{x \to +\infty} \dfrac{3x^3 - 5x + 2}{1 - 2x^3}$
- b) $\lim_{x \to -\infty} \dfrac{x^2 + 10}{x - 5}$
- c) $\lim_{x \to +\infty} \dfrac{\sqrt{x^4 + 3x}}{5x^2 - 1}$
Finding parameters from limits
Many problems give the limit and ask for a constant. Two ideas are used:
-
At infinity: if there is a horizontal asymptote $y=L$, the quotient of the leading coefficients must equal $L$.
-
At a point with a finite limit and denominator $0$: the numerator must also be zero at that point. If not, the limit would be infinite.
Calculate the values of $a$ and $b$ so that the following limit equalities hold: a) $\lim_{x \to +\infty} \dfrac{ax^2 + 5x}{3x^2 - 2} = 4$ b)…
Calculate the values of $a$ and $b$ so that the following limit equalities hold:
- a) $\lim_{x \to +\infty} \dfrac{ax^2 + 5x}{3x^2 - 2} = 4$
- b) $\lim_{x \to 1} \dfrac{x^2 + bx - 3}{x - 1} = 4$ (Note: For the limit to be finite at a point that makes the denominator zero, the numerator must also be zero).
Given the rational function $f(x) = \dfrac{x^2 - kx}{x^2 - 4}$: a) Find the value of the parameter $k \in \mathbb{R}$ so that the function has a removable discontinuity…
Given the rational function $f(x) = \dfrac{x^2 - kx}{x^2 - 4}$:
- a) Find the value of the parameter $k \in \mathbb{R}$ so that the function has a removable discontinuity at $x = 2$.
- b) For the value of $k$ found in the previous part, study the behavior of the function as $x$ tends to $-2$. What type of limit do you obtain? Justify whether a vertical asymptote exists by calculating the one-sided limits:
Consider the rational function $f(x) = \frac{ax^2 + bx + 2}{x^2 - 4}$. Determine the values of the real parameters $a$ and $b$ knowing that the function has a horizontal…
Consider the rational function $f(x) = \frac{ax^2 + bx + 2}{x^2 - 4}$. Determine the values of the real parameters $a$ and $b$ knowing that the function has a horizontal asymptote at $y = 2$ and that a finite limit exists at the point $x = 2$. Once the parameters are found, calculate the value of this limit at $x = 2$ and discuss the behavior of the function as $x$ tends to $-2$.
Extension: the indeterminate form $\infty-\infty$ with roots, the conjugate
When a subtraction tends to $\infty-\infty$ and a root appears, you multiply and divide by the conjugate to eliminate the root with a difference of squares.
That is why in the drone exercise, the height $H(t)=\sqrt{t^2+8t}-t$ levels off at a finite value, even though each term grows without bound. Two infinities that are subtracted do not automatically give $0$: it depends on how fast each one grows.
A forest surveillance drone follows a flight path whose height in meters above sea level is given by the expression $H(t) = \sqrt{t^2 + 8t} - t$, where $t$ is the time…
A forest surveillance drone follows a flight path whose height in meters above sea level is given by the expression $H(t) = \sqrt{t^2 + 8t} - t$, where $t$ is the time in minutes since it began its patrol.
Calculate the limit of the height as time tends to infinity:
$$\lim_{t \to +\infty} (\sqrt{t^2 + 8t} - t)$$At what height does the drone stabilize its flight in the long term? Resolve the indeterminate form by multiplying by the conjugate.
Calculate the value of the following limit involving a difference of irrational functions at infinity:…
Calculate the value of the following limit involving a difference of irrational functions at infinity:
$\lim_{x \to +\infty} \left( \sqrt{4x^2 + 5x - 1} - \sqrt{4x^2 - 3x + 2} \right)$
Explain with reasons why we cannot simply say that the result is $0$ when subtracting two infinities of the same order.
Extension: growth hierarchy, exponential, power, and logarithm
When an exponential, a power, and a logarithm compete, you do not need algebra: a fixed hierarchy decides which one wins.
At $-\infty$ the picture changes: $a^x\to0$ (with $a>1$), so an exponential becomes negligible and often gives horizontal asymptotes.
The same trick explains a limited-growth model: in $P(t)=\dfrac{100e^{0.5t}}{k+e^{0.5t}}$, dividing by $e^{0.5t}$ leaves $\dfrac{100}{ke^{-0.5t}+1}\to100$: the population levels off at $100$ million, which is its maximum capacity.
In a biotechnology laboratory, the population of a strain of bacteria (in millions) grows according to the model: $$P(t) = 15 + \frac{100t^2}{t^2 + 200}$$ where…
In a biotechnology laboratory, the population of a strain of bacteria (in millions) grows according to the model:
$$P(t) = 15 + \frac{100t^2}{t^2 + 200}$$where $t \ge 0$ is the time in hours.
- a) What is the initial population of bacteria ($t=0$)?
- b) Calculate $\lim_{t \to +\infty} P(t)$. What does this value represent for the colony of bacteria?
- c) Compare the order of infinity of the numerator and the denominator in the fraction. If the growth were $100t^3$ instead of $100t^2$, would the long-term behavior change? Justify your answer using limits.
Analyze the asymptotic behavior of the function $g(x) = \frac{2^{x+1} + 5}{2^x - 8}$. To do so: a) Calculate the limits as $x \to +\infty$ and as $x \to -\infty$. What…
Analyze the asymptotic behavior of the function $g(x) = \frac{2^{x+1} + 5}{2^x - 8}$. To do so:
- a) Calculate the limits as $x \to +\infty$ and as $x \to -\infty$. What horizontal asymptotes does it have?
- b) Identify the point where the denominator vanishes and study the one-sided limits at that point to determine whether there is a vertical asymptote.
Calculate the value of the following limit, comparing orders of infinity and resolving the resulting indeterminate form:…
Calculate the value of the following limit, comparing orders of infinity and resolving the resulting indeterminate form:
$\lim_{x \to +\infty} \frac{x^{100} + 3^x}{\log_2(x^5) + e^x}$
Justify your answer based on the hierarchy of growth of exponential, polynomial (power) and logarithmic functions. Would the result change if the limit were towards $-\infty$? Reason your answer.
Extension: the number $e$ and notable limits
An indeterminate form $1^\infty$ appears when the base tends to $1$ and the exponent to $\infty$. It is resolved with the number $e$.
Two other limits that are used: $\displaystyle\lim_{x\to0}\dfrac{\sin x}{x}=1$ and $\displaystyle\lim_{x\to0}\dfrac{\ln(1+x)}{x}=1$ (with $x$ in radians). From this it follows, for example, that $\dfrac{\ln(1+x^2)}{x}\approx\dfrac{x^2}{x}=x\to0$ as $x\to0$.
Find the values of $k$ so that the following limit based on the structure of the number $e$ is equal to $e^6$:…
Find the values of $k$ so that the following limit based on the structure of the number $e$ is equal to $e^6$:
$\lim_{x \to +\infty} \left( \frac{x^2 + kx + 1}{x^2 - 2x + 3} \right)^{2x}$
Show all intermediate steps, including resolving the indeterminate form $1^\infty$.
Given the piecewise function: $f(x) = \begin{cases} \frac{\ln(1+x^2)}{x} & \text{if } x < 0 \\ \frac{a \times \sin(x)}{x} + b & \text{if } x > 0 \end{cases}$ Calculate…
Given the piecewise function:
$f(x) = \begin{cases} \frac{\ln(1+x^2)}{x} & \text{if } x < 0 \\ \frac{a \times \sin(x)}{x} + b & \text{if } x > 0 \end{cases}$
Calculate the values of $a$ and $b$ so that the one-sided limits exist at $x=0$, the limit from the left is equal to $0$ and the limit from the right is equal to $5$. Is it possible to define $f(0)$ so that the function is continuous at that point?
Extension: formal definition with neighborhoods
"$f(x)$ approaches $L$" is made precise as follows: for any distance $\varepsilon>0$ you are given, you can find a distance $\delta>0$ such that, if $0<|x-x_0|<\delta$, then $|f(x)-L|<\varepsilon$.
For a line with slope $m$ the pattern is always $\delta=\varepsilon/|m|$.
Use the formal definition of a limit based on neighbourhoods to prove that the limit of the function $f(x) = \frac{3x - 1}{2}$ as $x$ tends to $3$ is equal to $4$. To do…
Use the formal definition of a limit based on neighbourhoods to prove that the limit of the function $f(x) = \frac{3x - 1}{2}$ as $x$ tends to $3$ is equal to $4$. To do so, given an $\varepsilon > 0$, find an expression for $\delta$ in terms of $\varepsilon$ that satisfies the condition:
$0 < |x - 3| < \delta \implies |f(x) - 4| < \varepsilon$