Work and power
In 3rd ESO you saw that a force does work when it manages to move something in its own direction: $W = F \cdot d$. But forces do not always pull in a straight line with the motion. A child dragging a cart with the rope at an angle, a lawnmower pushed by a handle held diagonally: here the force and the displacement form an angle, and the formula needs refining.
Revision: when the force and the displacement are in the same line
If you push with all your might against a heavy wardrobe but cannot move it from the spot, you end up exhausted, yet in physics we say you have not transferred any energy to the wardrobe: why does physics say there is no work if there is no displacement?
A worker pushes a pallet with a horizontal force of $150\ \text{N}$ and moves it $8\ \text{m}$ along the warehouse floor. Calculate the work done.
A worker pushes a pallet with a horizontal force of $150\ \text{N}$ and moves it $8\ \text{m}$ along the warehouse floor. Calculate the work done.
You place a box of books of $8\ \text{kg}$ on the top shelf of a cupboard, $1,5\ \text{m}$ above the floor (take $g = 10\ \text{m/s}^2$). a) What minimum force do you…
You place a box of books of $8\ \text{kg}$ on the top shelf of a cupboard, $1,5\ \text{m}$ above the floor (take $g = 10\ \text{m/s}^2$).
- a) What minimum force do you have to overcome to raise it?
- b) What work do you do against gravity?
When the force is at an angle: the cosine comes into play
When you pull a wheeled suitcase, if you hold the handle almost horizontal it moves along easily, but if you raise it almost vertical it is much harder to make it move forwards: how much of your force is really used depending on the angle?
A child pulls a cart with a rope that forms an angle of $60^\circ$ with the horizontal, exerting a force of $200\ \text{N}$, and drags it $10\ \text{m}$ (…
A child pulls a cart with a rope that forms an angle of $60^\circ$ with the horizontal, exerting a force of $200\ \text{N}$, and drags it $10\ \text{m}$ ($\cos 60^\circ = 0,5$), as shown in the figure.
Calculate the work done.
Aitana mows the lawn by pushing the lawnmower with a force of $80\ \text{N}$ applied to the handle, which forms an angle of $30^\circ$ with the horizontal (…
Aitana mows the lawn by pushing the lawnmower with a force of $80\ \text{N}$ applied to the handle, which forms an angle of $30^\circ$ with the horizontal ($\cos 30^\circ \approx 0,87$), and covers $20\ \text{m}$ of lawn, as shown in the figure.
- a) Calculate the work done.
- b) What work would have been done by pushing horizontally with the same force? What accounts for the difference?
Special cases: 0°, 90° and 180°
The work done by a force on a moving object is calculated as $W = F \cdot d \cdot \cos \alpha$, where $\alpha$ is the angle between the force and the displacement. You…
The work done by a force on a moving object is calculated as $W = F \cdot d \cdot \cos \alpha$, where $\alpha$ is the angle between the force and the displacement. You pull a trolley with the same force and over the same distance in three cases: with the rope horizontal ($\alpha = 0^\circ$), at an angle of $45^\circ$, and at an angle of $90^\circ$ ($\cos 0^\circ = 1$; $\cos 45^\circ \approx 0,71$; $\cos 90^\circ = 0$). The figure shows the three cases.
Order the three amounts of work done from greatest to least and justify your answer using the formula.
A worker pushes a container $12\ \text{m}$ along a warehouse floor with a horizontal force of $80\ \text{N}$, while friction opposes it with $45\ \text{N}$, as shown in…
A worker pushes a container $12\ \text{m}$ along a warehouse floor with a horizontal force of $80\ \text{N}$, while friction opposes it with $45\ \text{N}$, as shown in the figure. Remember that work done by a force opposing displacement is negative ($\alpha = 180^\circ$, $\cos 180^\circ = -1$).
- a) Calculate the work done by the worker.
- b) Calculate the work done by friction.
- c) What is the net work done on the container?
Power: the rate of transferring energy
The motor of a conveyor belt in a parcel distribution centre does $18000\ \text{J}$ of work in $60\ \text{s}$. Power is calculated as $P = W/t$. Calculate the power of…
The motor of a conveyor belt in a parcel distribution centre does $18000\ \text{J}$ of work in $60\ \text{s}$. Power is calculated as $P = W/t$. Calculate the power of the motor, in watts.
A drill has a power rating of $600\ \text{W}$ and operates for $2\ \text{min}$ ($1\ \text{kWh} = 3,6\cdot10^{6}\ \text{J}$). a) Express the time in seconds. b) Calculate…
A drill has a power rating of $600\ \text{W}$ and operates for $2\ \text{min}$ ($1\ \text{kWh} = 3,6\cdot10^{6}\ \text{J}$).
- a) Express the time in seconds.
- b) Calculate the work (energy) done.
- c) Express this energy in $\text{kWh}$.
The motor of a patio awning has a power rating of $40\ \text{W}$ and takes $15\ \text{s}$ to retract it. a) What work does it do? b) If the awning rises by…
The motor of a patio awning has a power rating of $40\ \text{W}$ and takes $15\ \text{s}$ to retract it.
- a) What work does it do?
- b) If the awning rises by $1,5\ \text{m}$, what average force does the motor exert?
The same work by different routes
A kayaker drags his kayak $40\ \text{m}$ across the sand by pulling a rope that forms an angle of $45^\circ$ with the horizontal, with a force of $50\ \text{N}$ (…
A kayaker drags his kayak $40\ \text{m}$ across the sand by pulling a rope that forms an angle of $45^\circ$ with the horizontal, with a force of $50\ \text{N}$ ($\cos 45^\circ \approx 0,71$). Friction with the sand opposes the motion with $20\ \text{N}$.
- a) Calculate the work done by the kayaker.
- b) Calculate the work done by friction (remember it is negative).
- c) What is the net work done on the kayak? How can you observe the effect of this net work?
To load a box of $60\ \text{kg}$ onto a lorry, whose bed is $1,2\ \text{m}$ above the ground, you can lift it vertically or push it up a frictionless ramp $3\ \text{m}$…
To load a box of $60\ \text{kg}$ onto a lorry, whose bed is $1,2\ \text{m}$ above the ground, you can lift it vertically or push it up a frictionless ramp $3\ \text{m}$ long (take $g = 10\ \text{m/s}^2$). The figure shows the two options.
- a) Calculate the work required in each case and explain why it is the same.
- b) Calculate the force that must be applied in each case.
- c) What is the advantage of using the ramp? What is the "cost" of using it?
Back to the beginning: with the lawnmower, pushing with the handle at an angle means that only the horizontal component of your force ($F \cdot \cos \alpha$) does work to move it forwards; the vertical component just presses the machine into the grass.