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ESO Y4A · Physics and Chemistry
Energy · Waves: light and sound

Sound

You put music on through a speaker and feel the casing vibrate if you rest your hand on it. That vibration pushes the air, the air pushes your eardrum, and your brain interprets it as sound. Without air (or some other medium) there would be nothing to push: that is why explosions cannot be heard in space.

Before you start, make sure you know: Uniform rectilinear motion (3rd ESO)
Before you start, make sure you know: The kinetic-molecular theory (2nd ESO)

Sound is a longitudinal mechanical wave

If you touch the membrane of a speaker or a ringing bell with your fingertip, you feel a continuous tingling that stops as soon as the sound dies away: how does that invisible vibration travel across the room until it reaches your ears?

Animation of a longitudinal sound wave emitted by a vibrating speaker: the zones of compression and expansion of the air move to the right while each particle only oscillates back and forth; the particle highlighted in pink shows that it does not travel along. speaker zones of compressed air and zones of expanded air
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In a laboratory, an electric bell is suspended inside a glass bell jar, and the air is gradually removed. The figure shows the experimental setup. a) Describe what is…

In a laboratory, an electric bell is suspended inside a glass bell jar, and the air is gradually removed. The figure shows the experimental setup.

air leaves pump bell bell jar
  1. a) Describe what is heard as the air leaves.
  2. b) What does this experiment demonstrate about what sound needs in order to travel?
  3. c) Why do two astronauts on the surface of the Moon talk to each other by radio even when standing next to each other?
Solve
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Sound travels through air as a series of compressed and rarefied regions that move from the source to the ear. The figure shows these regions of compression and…

Sound travels through air as a series of compressed and rarefied regions that move from the source to the ear. The figure shows these regions of compression and rarefaction.

compression rarefaction v
  1. a) Does the air travel from the loudspeaker to your ear, or does it only oscillate around its position?
  2. b) Considering the direction in which the air oscillates relative to the direction in which the wave travels, is sound a transverse or longitudinal wave? Justify your answer.
  3. c) Describe how you would model it using a stretched spring on a table.
Solve

The qualities of sound

A referee's whistle gives out a sharp, piercing blast, whereas a tractor engine produces a deep, low rumble: which physical quantities make our brain distinguish so clearly between such different sounds?

Lower the frequency and the wave becomes lower in pitch; raise the amplitude and the sound would be louder (although the ear does not "see" the wave, this is how the air vibrates).

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The loudspeaker at the sports centre is $68\ \text{m}$ away from where you are, as shown in the figure. How long does it take for the sound to reach your ears? Given…

The loudspeaker at the sports centre is $68\ \text{m}$ away from where you are, as shown in the figure.

loudspeaker you 68 m t = ? v = 340 m/s

How long does it take for the sound to reach your ears? Given data: sound travels through air at $340\ \text{m/s}$.

Solve
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On a guitar, the first string (the thinnest) vibrates open at $330\ \text{Hz}$ and the sixth (the thickest) at $82,5\ \text{Hz}$. a) Which of the two strings sounds…

On a guitar, the first string (the thinnest) vibrates open at $330\ \text{Hz}$ and the sixth (the thickest) at $82,5\ \text{Hz}$.

  1. a) Which of the two strings sounds higher-pitched?
  2. b) Which wave quantity determines the pitch (high or low) of a sound?
  3. c) In what unit is this quantity measured?
Solve
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You shout in front of a court wall and hear the echo $0,5\ \text{s}$ later, as shown in the figure. a) Explain the path travelled by the sound from when it left your…

You shout in front of a court wall and hear the echo $0,5\ \text{s}$ later, as shown in the figure.

wall d = ? t = 0,5 s v = 340 m/s
  1. a) Explain the path travelled by the sound from when it left your mouth until you heard it.
  2. b) Calculate how far away the wall is. (Sound travels at $340\ \text{m/s}$.)
Solve

The speed of sound in different media

During a storm, lightning lights up the sky instantly, but the thunder rumbles several seconds later: why do they not arrive together if both phenomena happen at the same moment?

Horizontal bar chart comparing the speed of sound: air 340 m/s, water 1500 m/s and steel more than 5000 m/s; the denser the medium, the faster the sound. Speed of sound in different media Air (gas) 340 m/s Water (liquid) 1500 m/s Steel (solid) more than 5000 m/s Particles further apart more tightly packed
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Fireworks explode $1700\ \text{m}$ from your house. How long does it take for you to hear the bang after seeing the flash? (Sound travels at $340\ \text{m/s}$.)

Fireworks explode $1700\ \text{m}$ from your house. How long does it take for you to hear the bang after seeing the flash? (Sound travels at $340\ \text{m/s}$.)

Solve
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A whistle emits a sound of $340\ \text{Hz}$ in air, where sound travels at $340\ \text{m/s}$. a) Calculate its wavelength. b) Another whistle emits at double the…

A whistle emits a sound of $340\ \text{Hz}$ in air, where sound travels at $340\ \text{m/s}$.

  1. a) Calculate its wavelength.
  2. b) Another whistle emits at double the frequency, $680\ \text{Hz}$: calculate its wavelength.
  3. c) Explain, using $v = \lambda \cdot f$, how the wavelength of a sound changes when its frequency increases in the same medium.
Solve
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A hiker shouts in front of a distant rock face and hears the echo $3\ \text{s}$ later. a) How far away is the wall? (Sound travels at $340\ \text{m/s}$.) b) They walk…

A hiker shouts in front of a distant rock face and hears the echo $3\ \text{s}$ later.

  1. a) How far away is the wall? (Sound travels at $340\ \text{m/s}$.)
  2. b) They walk $170\ \text{m}$ towards the rock face and shout again: how long does the echo take now?
  3. c) Explain why the time has decreased in the same proportion as the distance.
Solve

The human ear, decibels and noise

Sound spectrum by frequency: infrasounds below 20 Hz, the human audible range between 20 Hz and 20 000 Hz, and ultrasounds above 20 000 Hz. Audible range: 20 Hz – 20 000 Hz infrasounds (< 20 Hz) ultrasounds (> 20 000 Hz) audible 20 Hz 20 000 Hz increasing frequency
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A ship's sonar sends an ultrasound pulse towards the seabed and the echo returns $0,4\ \text{s}$ later, as shown in the figure. Sound travels through water at…

A ship's sonar sends an ultrasound pulse towards the seabed and the echo returns $0,4\ \text{s}$ later, as shown in the figure. Sound travels through water at $1500\ \text{m/s}$.

ship pulse echo seabed h = ? t = 0,4 s v = 1500 m/s
  1. a) What is the depth under the ship?
  2. b) Why does sonar use ultrasound instead of audible sound?
  3. c) If the ship sails to an area where the seabed is at $600\ \text{m}$, how long will it take for the echo to return?
Solve
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There is a rule of thumb for thunderstorms: "every $3\ \text{s}$ between the lightning and the thunder means $1\ \text{km}$ of distance". a) Check the rule by…

There is a rule of thumb for thunderstorms: "every $3\ \text{s}$ between the lightning and the thunder means $1\ \text{km}$ of distance".

  1. a) Check the rule by calculating what distance sound travels in $3\ \text{s}$ ($v_{\text{sound}} = 340\ \text{m/s}$).
  2. b) What error does the rule make, in metres and as a percentage? Do you find this acceptable for everyday use?
  3. c) The rule assumes that light arrives instantaneously: calculate how long light from the lightning actually takes to travel $1\ \text{km}$ ($c = 3\cdot10^{8}\ \text{m/s}$) and justify whether this assumption is reasonable.
Solve

Summary

See all the exercises in this section