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ESO Y4A · Physics and Chemistry
Matter · Amount of substance

Calculations with moles

A fire extinguisher, a butane cylinder and a helium balloon have something in common: to make them, you need to know exactly how many moles of gas fit inside. The mole is not just a theoretical idea: it is the tool engineers use to calculate real quantities.

Before you start, make sure you know: Atomic mass and molecular mass (2nd ESO)
Before you start, make sure you know: Standard form and significant figures (2nd ESO)

From mass to moles

In the laboratory, balances measure grams, but chemical reactions happen atom by atom: $18\ \text{g}$ of water contain one mole of molecules, but $18\ \text{g}$ of glucose are only a tenth of a mole. How do we convert the mass shown on the balance into the amount of substance that reacts?

A beaker of substance on a balance that reads in grams; dividing the mass by the molar mass M gives the number of moles, shown as blocks of M grams that are each equivalent to 1 mole. g mass (g) ÷ M M grams 1 mole M grams 1 mole M grams 1 mole moles (n)
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You have $36\ \text{g}$ of water in a glass. Knowing that the molar mass of water is $18\ \text{g/mol}$, calculate how many moles of water the glass contains.

You have $36\ \text{g}$ of water in a glass. Knowing that the molar mass of water is $18\ \text{g/mol}$, calculate how many moles of water the glass contains.

Solve
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In a laboratory, they weigh $58,5\ \text{g}$ of common salt, $\text{NaCl}$, whose molar mass is $58,5\ \text{g/mol}$. How many moles of salt have they weighed out?

In a laboratory, they weigh $58,5\ \text{g}$ of common salt, $\text{NaCl}$, whose molar mass is $58,5\ \text{g/mol}$. How many moles of salt have they weighed out?

Solve

From moles to mass

Diagram of the reverse conversion from moles to mass in grams by multiplying by the molar mass. moles (n) mass (g) × M
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A fire extinguisher contains $3\ \text{mol}$ of carbon dioxide. If the molar mass of $\text{CO}2$ is $44\ \text{g/mol}$, what mass of gas does the fire extinguisher…

A fire extinguisher contains $3\ \text{mol}$ of carbon dioxide. If the molar mass of $\text{CO}_2$ is $44\ \text{g/mol}$, what mass of gas does the fire extinguisher contain?

Solve
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In a pharmacy, they use $0,25\ \text{mol}$ of ethanol ($M = 46\ \text{g/mol}$) to prepare a disinfectant. What mass of ethanol have they used?

In a pharmacy, they use $0,25\ \text{mol}$ of ethanol ($M = 46\ \text{g/mol}$) to prepare a disinfectant. What mass of ethanol have they used?

Solve
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An iron nail weighs $5,6\ \text{g}$ (molar mass of iron: $56\ \text{g/mol}$). a) How many moles of iron atoms does the nail contain? b) How many atoms is this? (Given:…

An iron nail weighs $5,6\ \text{g}$ (molar mass of iron: $56\ \text{g/mol}$).

  1. a) How many moles of iron atoms does the nail contain?
  2. b) How many atoms is this? (Given: $N_{\text{A}} = 6,022\cdot10^{23}\ \text{mol}^{-1}$)
Solve

From moles to number of particles

A single sip of water contains more than $10^{23}$ molecules, an astronomical figure that is impossible to measure directly one by one. How do we group microscopic particles into manageable packets so that we can count them?

To go from moles to number of particles you multiply by Avogadro's number, and the other way you divide, just like with dozens. moles (n) particles (N) × NA ÷ NA NA = 6.022 · 10²³ particles per mole just as 1 dozen = 12: 2 dozen = 24 eggs 0.5 mol of glucose → 0.5 · 6.022·10²³ = 3.011·10²³ molecules
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A laboratory flask contains $0,5\ \text{mol}$ of glucose dissolved in water. How many molecules of glucose are in the flask? (Given:…

A laboratory flask contains $0,5\ \text{mol}$ of glucose dissolved in water. How many molecules of glucose are in the flask? (Given: $N_{\text{A}} = 6,022\cdot10^{23}\ \text{mol}^{-1}$)

Solve
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An electrical cable contains $2\ \text{mol}$ of copper atoms. How many copper atoms is this? (Given: $N_{\text{A}} = 6,022\cdot10^{23}\ \text{mol}^{-1}$)

An electrical cable contains $2\ \text{mol}$ of copper atoms. How many copper atoms is this? (Given: $N_{\text{A}} = 6,022\cdot10^{23}\ \text{mol}^{-1}$)

Solve
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When a soft drink is opened, $4,4\ \text{g}$ of $\text{CO}2$ escapes (molar mass: $44\ \text{g/mol}$). a) How many moles of gas have escaped? b) How many molecules is…

When a soft drink is opened, $4,4\ \text{g}$ of $\text{CO}_2$ escapes (molar mass: $44\ \text{g/mol}$).

  1. a) How many moles of gas have escaped?
  2. b) How many molecules is this? (Given: $N_{\text{A}} = 6,022\cdot10^{23}\ \text{mol}^{-1}$)
Solve

The volume of a mole of gas

If you measure, at standard conditions, the volume of $2\ \text{g}$ of $\text{H}_2$ ($1\ \text{mol}$), $32\ \text{g}$ of $\text{O}_2$ ($1\ \text{mol}$) and $44\ \text{g}$ of $\text{CO}_2$ ($1\ \text{mol}$), you will find that all three gases occupy exactly $22{,}4\ \text{L}$. Why do gases with such different masses and molecules occupy exactly the same space?

Two identical cubic containers of 22,4 litres, one with a mole of helium (single atoms) and the other with a mole of carbon dioxide (linear O=C=O molecules), with the same number of widely spaced particles and a lot of empty space between them. Standard conditions: 0 °C and 1 atm = 1 mol He 22,4 L 1 mol CO₂ 22,4 L C O
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Under standard conditions, that is, at $0\ \celsius$ and $1\ \text{atm}$ of pressure, one mole of any gas occupies $22,4\ \text{L}$, as shown in the diagram. A balloon…

Under standard conditions, that is, at $0\ \celsius$ and $1\ \text{atm}$ of pressure, one mole of any gas occupies $22,4\ \text{L}$, as shown in the diagram.

1 mol 22,4 L any gas 2 mol V = ? helium standard conditions: 0 °C · 1 atm

A balloon contains $2\ \text{mol}$ of helium. What volume does the gas occupy under standard conditions?

Solve
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An airtight bag contains $11,2\ \text{L}$ of air measured under standard conditions ($22,4\ \text{L/mol}$). How many moles of air are inside the bag?

An airtight bag contains $11,2\ \text{L}$ of air measured under standard conditions ($22,4\ \text{L/mol}$). How many moles of air are inside the bag?

Solve
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Natural gas, which is almost entirely methane, $\text{CH}4$ ($M = 16\ \text{g/mol}$), arrives through the pipes of many homes. a) How many moles of methane are in…

Natural gas, which is almost entirely methane, $\text{CH}_4$ ($M = 16\ \text{g/mol}$), arrives through the pipes of many homes.

  1. a) How many moles of methane are in $16\ \text{g}$?
  2. b) What volume would they occupy under standard conditions ($22,4\ \text{L/mol}$)?
Solve

Chaining the three routes together

Overall diagram of conversions that places the mole as the central node linking mass, number of particles and volume of gases. mass moles N V
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In the laboratory, a $0,25\ \text{mol}$ sample of an unknown gas weighs $11\ \text{g}$. a) Calculate the molar mass of the gas. b) Which gas could it be: methane,…

In the laboratory, a $0,25\ \text{mol}$ sample of an unknown gas weighs $11\ \text{g}$.

  1. a) Calculate the molar mass of the gas.
  2. b) Which gas could it be: methane, $\text{CH}_4$ ($M = 16\ \text{g/mol}$), or propane, $\text{C}_3\text{H}_8$ ($M = 44\ \text{g/mol}$)? Justify your answer.
Solve
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In the kitchen there are two bottles: one with $100\ \text{g}$ of water ($M = 18\ \text{g/mol}$) and another with $100\ \text{g}$ of ethyl alcohol or ethanol (…

In the kitchen there are two bottles: one with $100\ \text{g}$ of water ($M = 18\ \text{g/mol}$) and another with $100\ \text{g}$ of ethyl alcohol or ethanol ($M = 46\ \text{g/mol}$).

  1. a) Calculate how many moles are in each bottle, to one decimal place.
  2. b) Which of the two contains more molecules? Justify your answer.
  3. c) Without doing further calculations, explain what the molar mass of a substance would need to be like for $100\ \text{g}$ of it to contain more molecules than $100\ \text{g}$ of water.
Solve
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In the laboratory, a gas is collected in a container: a sample of $3,2\ \text{g}$ occupies $2,24\ \text{L}$ under standard conditions ($22,4\ \text{L/mol}$). a) How many…

In the laboratory, a gas is collected in a container: a sample of $3,2\ \text{g}$ occupies $2,24\ \text{L}$ under standard conditions ($22,4\ \text{L/mol}$).

  1. a) How many moles of gas are in the sample?
  2. b) Calculate the molar mass of the gas.
  3. c) Which gas is it: oxygen, $\text{O}_2$ ($M = 32\ \text{g/mol}$), or nitrogen, $\text{N}_2$ ($M = 28\ \text{g/mol}$)? Explain how you know.
Solve

Back to the beginning: To fill that helium balloon, whose gas is at a pressure close to atmospheric, you can convert its volume into moles ($n = V/22{,}4$, assuming standard conditions) and then calculate the mass in grams ($m = n \cdot M$). In the $\text{CO}_2$ extinguisher or the butane cylinder the gas is at high pressure and partly liquefied, so $22{,}4\ \text{L/mol}$ does not apply: engineers work with the mass and the molar mass ($n = m/M$) to know how many moles they inject.

Summary

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