Back to homeMathematics · 3rd ESO · Change subject
Start for free
ESO Y3 · Mathematics
Proportionality · Proportionality

Ratios and proportions

A "16:9" screen, a "1:300 000" map, a recipe with "2 of flour for every 1 of water"… These are all ratios: ways of comparing two quantities by dividing. They are the basis of proportionality, which you will meet everywhere: prices, recipes, plans, speeds.

Before you start, make sure you know: Ratio and proportion (2nd ESO)
Before you start, make sure you know: Fractions. Equivalent fractions (2nd ESO)

Ratio between two quantities

In a class with 12 girls and 18 boys, the ratio of girls to boys is $\frac{12}{18} = \frac{2}{3}$: for every 2 girls there are 3 boys.

Diagram of groups of girls and boys illustrating the ratio of twelve to eighteen simplified to two to three. … ×6 12 girls18 boys ratio 12 : 18 = 2 : 3

Scales

A scale is the ratio between a measurement on the drawing and the real measurement. A scale of $1 : 300\,000$ means that 1 cm on the map is $300\,000$ cm = 3 km in real life.

Scale plan showing the correspondence between a distance on paper and the real distance. 1 cm map 1 : 300 000 1 cm on the map = 300 000 cm in real life = 3 000 m = 3 km
Practice★☆☆Not started
Calculate the value of the ratio of each pair of quantities and interpret the result: a) $3\ \text{kg}$ of cherries cost $10,50\ \text{€}$. b) A gravel cyclist covers…

Calculate the value of the ratio of each pair of quantities and interpret the result:

  1. a) $3\ \text{kg}$ of cherries cost $10,50\ \text{€}$.
  1. b) A gravel cyclist covers $95\ \text{km}$ in $4\ \text{h}$.
  1. c) A bottle contains $2\ \text{L}$ and a drum, $25\ \text{L}$.
Solve
Practice★☆☆Not started
Two metal rods measure $8\ \text{dm}$ and $12\ \text{dm}$. a) Calculate the ratio of the length of the first to the second, and simplify it. b) Calculate the ratio of…

Two metal rods measure $8\ \text{dm}$ and $12\ \text{dm}$.

  1. a) Calculate the ratio of the length of the first to the second, and simplify it.
  1. b) Calculate the ratio of the second to the first.
  1. c) How are the two ratios obtained related to each other? Does this always happen?
Solve
Practice★☆☆Not started
A road map is drawn to a scale of $1 : 300.000$. a) Explain the meaning of this ratio. b) What real-life distance is represented by $5\ \text{cm}$ on the map? c) Two…

A road map is drawn to a scale of $1 : 300.000$.

  1. a) Explain the meaning of this ratio.
  1. b) What real-life distance is represented by $5\ \text{cm}$ on the map?
  1. c) Two towns are $21\ \text{km}$ apart in reality. How far apart are they on the map?
Solve

Proportions

Cross-multiplication diagram for a proportion checking the equality of extremes and means. 34 = 912 extremes: 3 · 12 = 36 means: 4 · 9 = 36 36 = 36 → it is a proportion

Finding the missing term

Thanks to that property, if you know three terms you can find the fourth (the fourth proportional):

$$\frac{x}{4} = \frac{9}{12} \ \Rightarrow\ 12x = 36 \ \Rightarrow\ x = 3$$

And if the means are equal, $\frac{a}{x} = \frac{x}{b}$, then $x^2 = ab$: $x = \sqrt{ab}$ is the mean proportional. For example, between 4 and 9: $x = \sqrt{36} = 6$.

Practice★☆☆Not started
Check, by calculating the product of the extremes and the product of the means, whether the following pairs of ratios form a proportion: a) $\frac{6}{4}$ and…

Check, by calculating the product of the extremes and the product of the means, whether the following pairs of ratios form a proportion:

  1. a) $\frac{6}{4}$ and $\frac{15}{10}$
  1. b) $\frac{5}{8}$ and $\frac{7}{12}$
  1. c) $\frac{2,5}{4}$ and $\frac{5}{8}$
Solve
Practice★☆☆Not started
Find the fourth proportional in each case: a) $\frac{x}{4} = \frac{9}{12}$ b) $\frac{5}{x} = \frac{15}{21}$ c) $\frac{8}{6} = \frac{20}{x}$

Find the fourth proportional in each case:

  1. a) $\frac{x}{4} = \frac{9}{12}$
  1. b) $\frac{5}{x} = \frac{15}{21}$
  1. c) $\frac{8}{6} = \frac{20}{x}$
Solve
Practice★★☆Not started
Find the mean proportional in each case, that is, the positive value of $x$ that satisfies the continuous proportion: a) $\frac{x}{4} = \frac{25}{x}$ b)…

Find the mean proportional in each case, that is, the positive value of $x$ that satisfies the continuous proportion:

  1. a) $\frac{x}{4} = \frac{25}{x}$
  1. b) $\frac{3}{x} = \frac{x}{27}$
  1. c) $\frac{x}{2} = \frac{50}{x}$
Solve

Summary

See all the exercises in this section