Powers of rational numbers
A ball that rises to $\frac{2}{3}$ of its previous height on every bounce: after 4 bounces it will be at $\left(\frac{2}{3}\right)^4$ of its initial height. And on calculators you will see things like $10^{-3}$. Here you will learn what powers of fractions and negative indices mean.
Powers of a fraction
Raising a fraction to a power means raising the numerator and the denominator to that power:
$$\left(\frac{2}{5}\right)^3 = \frac{2}{5} \cdot \frac{2}{5} \cdot \frac{2}{5} = \frac{2^3}{5^3} = \frac{8}{125}$$A square tile with side $\frac{2}{5}$ m has an area of $\left(\frac{2}{5}\right)^2 = \frac{4}{25}$ m²: a square metre holds 25 little squares of side $\frac{1}{5}$ m, and the tile covers 4 of them.
Calculate the numerical value of the following powers. Remember to raise both the numerator and the denominator to the given exponent. Express the result as an…
Calculate the numerical value of the following powers. Remember to raise both the numerator and the denominator to the given exponent. Express the result as an irreducible fraction.
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$\left( \frac{2}{3} \right)^3$
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$\left( \frac{1}{5} \right)^2$
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$\left( \frac{3}{2} \right)^4$
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$\left( \frac{10}{7} \right)^0$
We have a small square tile for a mosaic. The side of the tile measures $\frac{2}{5}$ of a metre. Calculate the area occupied by this tile, expressing the result as a…
We have a small square tile for a mosaic. The side of the tile measures $\frac{2}{5}$ of a metre. Calculate the area occupied by this tile, expressing the result as a fraction.
Use the following visual diagram to help you:
Sometimes we confuse the size of fractions when we raise them to a power. Look at the following graph showing the unit, $\left(\frac{1}{2}\right)^1$ and…
Sometimes we confuse the size of fractions when we raise them to a power. Look at the following graph showing the unit, $\left(\frac{1}{2}\right)^1$ and $\left(\frac{1}{2}\right)^2$.
Based on the logic above, order the following powers from smallest to largest:
$$ \left( \frac{1}{3} \right)^2, \quad \left( \frac{1}{3} \right)^1, \quad \left( \frac{1}{3} \right)^3 $$Negative indices
Look at the table: each time the index goes down by one, the result is divided by the base. If we continue the pattern below 0, fractions appear.
Explore with base 2 or 10 and negative indices: the result gets tiny, but it never reaches 0 and never becomes negative.
In mathematics, we sometimes need to change the sign of the exponent to perform operations. Rewrite the following powers so that they have a positive exponent, inverting…
In mathematics, we sometimes need to change the sign of the exponent to perform operations. Rewrite the following powers so that they have a positive exponent, inverting the base when necessary. You do not need to calculate the final result, just express the transformed power.
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$\left( \frac{4}{5} \right)^{-2}$
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$\left( \frac{1}{3} \right)^{-4}$
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$5^{-3}$
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$\left( -\frac{2}{7} \right)^{-3}$
Calculate the value of the following powers by first converting them into powers with positive exponents. Remember that the result must be an irreducible fraction. a)…
Calculate the value of the following powers by first converting them into powers with positive exponents. Remember that the result must be an irreducible fraction.
- a) $(\frac{3}{5})^{-2}$
- b) $(\frac{-2}{3})^{-3}$
- c) $-( \frac{1}{4} )^{-2}$
- d) $(\frac{10}{3})^{-1}$
The sign of the result
You only need to look at the base and whether the index is even or odd:
| Base | Even index | Odd index |
|---|---|---|
| Positive | $+$ $\quad (2^4 = 16)$ | $+$ $\quad (2^3 = 8)$ |
| Negative | $+$ $\quad ((-2)^4 = 16)$ | $-$ $\quad ((-2)^3 = -8)$ |
With a negative index the same applies: $\left(-\frac{1}{2}\right)^{-3} = (-2)^3 = -8$.
Determine the sign (positive or negative) of the result of the following powers without carrying out the full calculation. Justify your answer based on whether the base…
Determine the sign (positive or negative) of the result of the following powers without carrying out the full calculation. Justify your answer based on whether the base is negative and whether the exponent is even or odd.
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$\left( -\frac{1}{2} \right)^4$
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$\left( -\frac{3}{4} \right)^3$
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$\left( \frac{5}{2} \right)^{-2}$
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$\left( -\frac{2}{3} \right)^{-5}$
Working with powers of fractions
All the properties from the previous section still hold with fractional bases and negative indices:
Use the properties of powers to simplify the following expressions. Leave your answer expressed as a single power (you do not need to calculate the final value). 1.…
Use the properties of powers to simplify the following expressions. Leave your answer expressed as a single power (you do not need to calculate the final value).
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$\left( \frac{3}{4} \right)^5 \cdot \left( \frac{3}{4} \right)^2$
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$\left( \frac{2}{5} \right)^7 : \left( \frac{2}{5} \right)^4$
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$\left( \frac{1}{2} \right)^3 \cdot \left( \frac{1}{2} \right)$
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$\left[ \left( \frac{5}{3} \right)^2 \right]^4$
Use the properties of powers to simplify the following expressions and write the result as a single power with a rational base. You do not need to calculate the final…
Use the properties of powers to simplify the following expressions and write the result as a single power with a rational base. You do not need to calculate the final value, only the simplified power.
- a) $(\frac{2}{7})^3 \cdot (\frac{2}{7})^5 : (\frac{2}{7})^{-2}$
- b) $[(\frac{1}{5})^2]^{-3} \cdot (\frac{1}{5})^4$
- c) $(\frac{2}{3})^4 \cdot (\frac{6}{5})^4$
We have a special rubber ball. Each time it bounces off the ground, it reaches a height that is $\frac{2}{3}$ of the previous height. If we drop the ball from a height…
We have a special rubber ball. Each time it bounces off the ground, it reaches a height that is $\frac{2}{3}$ of the previous height.
If we drop the ball from a height of 2 metres:
- a) Express as a power the height it reaches after the fourth bounce.
- b) Is that height greater or less than 0.3 metres? Justify your answer using the power calculation.
Back to the start: After 4 bounces, the ball reaches $\left(\frac{2}{3}\right)^4 = \frac{2^4}{3^4} = \frac{16}{81}$ of its initial height (less than $20\,\%$), and on the calculator screen $10^{-3} = \frac{1}{10^3} = \frac{1}{1000} = 0{,}001$.