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ESO Y3 · Mathematics
Linear and quadratic equations · Equations

Quadratic equations

A video game box has a square base of area 144 cm². How long is the side? You are looking for an $x$ such that $x^2 = 144$: this is a quadratic equation, because the unknown is squared. These equations can have two solutions, one or none, and there is a formula that solves them all.

Before you start, make sure you know: Linear equations (2nd ESO)
Before you start, make sure you know: Operations with integers (2nd ESO)

General form

Graphically, $y = ax^2 + bx + c$ is a parabola, and the solutions are the points where it crosses the x-axis. Change $a$, $b$ and $c$ and see how many crossing points there are:

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For each of the following quadratic equations, identify the coefficients $a$, $b$ and $c$ and state whether it is a complete or incomplete equation: a)…

For each of the following quadratic equations, identify the coefficients $a$, $b$ and $c$ and state whether it is a complete or incomplete equation:

  1. a) $x^2 - 5x + 6 = 0$
  2. b) $2x^2 - 32 = 0$
  3. c) $x^2 + 8x = 0$
  4. d) $3 - x^2 + 2x = 0$
Solve
Practice★☆☆Not started
Check, without solving the equation, whether the proposed values of $x$ are solutions to the equation $x^2 - 4x + 3 = 0$: a) $x = 1$ b) $x = 0$ c) $x = 3$ d) $x = -1$

Check, without solving the equation, whether the proposed values of $x$ are solutions to the equation $x^2 - 4x + 3 = 0$:

  1. a) $x = 1$
  2. b) $x = 0$
  3. c) $x = 3$
  4. d) $x = -1$
Solve

Incomplete equations

They are solved without the formula, and more quickly:

Diagram showing how to solve an incomplete equation with no constant term by taking out a common factor, splitting into two branches: x equals zero and the bracket equals zero. x · (x + 3) = 0 x = 0 x + 3 = 0 → x = −3 If a · b = 0, then a = 0 or b = 0. (No other product of two numbers gives 0.)
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Solve the following incomplete quadratic equations of the type $ax^2 + c = 0$. Remember that if the square root does not yield a real number, you must state so: a)…

Solve the following incomplete quadratic equations of the type $ax^2 + c = 0$. Remember that if the square root does not yield a real number, you must state so:

  1. a) $x^2 - 25 = 0$
  2. b) $3x^2 - 12 = 0$
  3. c) $x^2 + 16 = 0$
  4. d) $2x^2 = 50$
Solve
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Solve the following incomplete quadratic equations of the type $ax^2 + bx = 0$ by taking out a common factor: a) $x^2 - 7x = 0$ b) $2x^2 + 10x = 0$ c) $3x^2 = 6x$ d)…

Solve the following incomplete quadratic equations of the type $ax^2 + bx = 0$ by taking out a common factor:

  1. a) $x^2 - 7x = 0$
  2. b) $2x^2 + 10x = 0$
  3. c) $3x^2 = 6x$
  4. d) $x^2 + x = 0$
Solve
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The area of the square base of a video game storage box is $144\text{ cm}^2$. Calculate the length of the side of the base by setting up a quadratic equation.

The area of the square base of a video game storage box is $144\text{ cm}^2$. Calculate the length of the side of the base by setting up a quadratic equation.

x x Area 144 cm²
Solve

The quadratic formula

For any complete equation:

$$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$

The $\pm$ gives two solutions: one by adding the root and the other by subtracting it.

Complete quadratic formula with distinct colours highlighting the position of each coefficient: minus b, plus or minus the square root of the discriminant, and two a in the denominator. x = −b± b² − 4ac 2a change the sign of b discriminant Δ twice a ± → two solutions
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Apply the quadratic formula $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ to find the solutions to the following complete equations: a) $x^2 - 6x + 8 = 0$ b)…

Apply the quadratic formula $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ to find the solutions to the following complete equations:

  1. a) $x^2 - 6x + 8 = 0$
  2. b) $x^2 + x - 12 = 0$
Solve
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Solve the following quadratic equation by first simplifying the algebraic expressions through expanding the algebraic identities: $$(2x - 3)^2 - (x + 1)^2 = -5$$…

Solve the following quadratic equation by first simplifying the algebraic expressions through expanding the algebraic identities:

$$(2x - 3)^2 - (x + 1)^2 = -5$$

Remember that to apply the quadratic formula, you must first reduce the equation to the form $ax^2 + bx + c = 0$.

Solve

The discriminant: how many solutions?

What is inside the square root, $\Delta = b^2 - 4ac$, is called the discriminant and tells you how many solutions there are without solving:

Graphs of three parabolas illustrating the three cases of the discriminant: two points where it crosses the axis if positive, one point of tangency if zero, and no crossing if negative. Δ > 0two solutions Δ = 0one (repeated) Δ < 0none
$\Delta = b^2 - 4ac$ Solutions
$\Delta > 0$ Two distinct solutions
$\Delta = 0$ One (repeated) solution: $x = -\frac{b}{2a}$
$\Delta < 0$ No real solution (the square root of a negative does not exist)
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Calculate the value of the discriminant $\Delta = b^2 - 4ac$ for each equation and state whether it has two real solutions, a repeated root, or no real solutions (you do…

Calculate the value of the discriminant $\Delta = b^2 - 4ac$ for each equation and state whether it has two real solutions, a repeated root, or no real solutions (you do not need to calculate the solutions):

  1. a) $x^2 - 4x + 4 = 0$
  2. b) $x^2 + 2x + 5 = 0$
  3. c) $x^2 - 5x - 1 = 0$
Solve
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Study the discriminant ($\Delta = b^2 - 4ac$) of the following equations and determine, without solving them, how many real solutions each one has. Justify your answer…

Study the discriminant ($\Delta = b^2 - 4ac$) of the following equations and determine, without solving them, how many real solutions each one has. Justify your answer in each case:

  1. a) $x^2 - 6x + 9 = 0$
  2. b) $2x^2 + 3x + 5 = 0$
  3. c) $3x^2 - 4x - 2 = 0$

What value should the constant term take in equation a) so that it suddenly has no solution?

Solve
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Given the quadratic equation $x^2 - (k-2)x + k = 0$, determine what values the parameter $k$ must take so that the equation has a single real solution (a repeated root).

Given the quadratic equation $x^2 - (k-2)x + k = 0$, determine what values the parameter $k$ must take so that the equation has a single real solution (a repeated root).

Solve

Extension: biquadratic equations

In $x^4 - 13x^2 + 36 = 0$ only $x^4$ and $x^2$ appear. The trick is a change of variable: we call $t = x^2$ (so $x^4 = t^2$).

Flow diagram of the change of variable t = x²: x⁴ − 13x² + 36 becomes t² − 13t + 36, and undoing the change with x = ±√t gives the four solutions ±2 and ±3. x⁴ − 13x² + 36 t = x² t² − 13t + 36 x = ±√t ±2, ±3
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Biquadratic equations can be solved by using a substitution $t = x^2$. Use this technique to find the four real solutions of the following equation: $$x^4 - 13x^2 + 36 =…

Biquadratic equations can be solved by using a substitution $t = x^2$. Use this technique to find the four real solutions of the following equation:

$$x^4 - 13x^2 + 36 = 0$$
Solve

Quadratic problems

When solving a problem, discard the solutions that make no sense: a negative length, a number of people with decimals…

Flow diagram of a problem showing two algebraic solutions, twelve and minus thirteen, marking the first as valid and discarding the second because it is not a natural number. x(x + 1) = 156 x = 12 ✓ x = −13 ✗not a natural number
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If we add three times an integer to its square, we get zero as a result. What numbers could these be? Set up the equation and find the possible solutions.

If we add three times an integer to its square, we get zero as a result. What numbers could these be? Set up the equation and find the possible solutions.

Solve
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The product of two consecutive natural numbers is equal to their sum increased by $19$ units. What are these numbers?

The product of two consecutive natural numbers is equal to their sum increased by $19$ units. What are these numbers?

Solve
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We want to put a wooden frame of constant width $x$ around a rectangular photograph measuring $10\text{ cm}$ by $15\text{ cm}$. If we know that the total area (photo…

We want to put a wooden frame of constant width $x$ around a rectangular photograph measuring $10\text{ cm}$ by $15\text{ cm}$. If we know that the total area (photo plus frame) must be $300\text{ cm}^2$, what should the width $x$ of the frame be?

x x 10 cm 15 cm Photo Frame A = 300 cm²
Solve

Back to the start: In the video game box, $x^2 = 144 \Rightarrow x = \pm\sqrt{144} = \pm 12$; since a physical length cannot be negative, the side of the base measures exactly $12\text{ cm}$.

Summary

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