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ESO Y1 · Mathematics
Numbers · Decimal numbers

Approximation and rounding

A runner takes $12,45$ seconds. A set of scales shows $2,341$ kg of oranges. You almost never need all the digits: learning to round and truncate gives you exactly the number you need, without losing what matters.

Rounding and truncating

Try the slider and compare how many decimal places are kept.

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To carry out an experiment in Science class, we need to measure exactly $4,576$ grams of salt. Complete the following table by applying the two requested approximation…

To carry out an experiment in Science class, we need to measure exactly $4,576$ grams of salt. Complete the following table by applying the two requested approximation methods:

Approximation to hundredths Result
Truncation
Rounding
Solve
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Look at the following decimal numbers and round them to one decimal place (tenths): a) $3,14$ b) $9,68$ c) $0,45$ d) $1,03$

Look at the following decimal numbers and round them to one decimal place (tenths):

  1. a) $3,14$
  2. b) $9,68$
  3. c) $0,45$
  4. d) $1,03$
Solve
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Copy and complete the following table in your exercise book, finding the given approximations for the decimal number $n = 14,3728$. | Approximation to... | Truncation |…

Copy and complete the following table in your exercise book, finding the given approximations for the decimal number $n = 14,3728$.

Approximation to... Truncation Rounding
Tenths
Hundredths
Thousandths
Solve

Which one is closer to the real value?

Number line comparing the approximation of 7,428 to the nearest hundredth: truncation gives 7,42 with an error of 0,008, while rounding gives 7,43 with an error of less than 0,002. truncation(further away) rounding(closer) 7,427,43 7,428 0,0080,002

The rounding error is less than or equal to half a unit of the place value you round to. For example, 2,35 rounded to the nearest tenth is 2,4: the error is exactly 0,05. Truncation can be almost a whole unit of that place value away from the real value.

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A 100-metre sprinter has recorded a time of $12,45$ seconds on the stopwatch. If we want to express this time with a single decimal digit: a) Round to the nearest tenth.…

A 100-metre sprinter has recorded a time of $12,45$ seconds on the stopwatch. If we want to express this time with a single decimal digit:

  1. a) Round to the nearest tenth.
  2. b) Was it an upward or a downward approximation? Explain why you looked at the hundredths digit.

On the number line, the runner's time is marked with a point between $12,4$ and $12,5$, and each small mark represents $0,01$ s.

Number line between 12,4 and 12,5 with marks every 0,01 and a point at 12,4512,412,512,45Time in seconds (each small mark = 0,01 s)
Solve
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Approximate the number $\pi \approx 3,141592...$ in the following ways: a) By rounding to three decimal places (thousandths). b) By truncation to three decimal places…

Approximate the number $\pi \approx 3,141592...$ in the following ways:

  1. a) By rounding to three decimal places (thousandths).
  2. b) By truncation to three decimal places (thousandths).
  3. c) In which case is the result larger?
Solve
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A mathematics teacher calculates the average mark for an exam and gets $6,4782$. a) Approximate the mark to one decimal place by truncation. b) Approximate the mark to…

A mathematics teacher calculates the average mark for an exam and gets $6,4782$.

  1. a) Approximate the mark to one decimal place by truncation.
  2. b) Approximate the mark to one decimal place by rounding.
  3. c) Which of the two approximations is more favourable to the student? Why do you think school report cards usually use rounding instead of truncation?
Solve

Rounding in real life

Sometimes it is better to round in one direction only (always up or always down), not to the nearest value.

Example of rounding up in real life: for a garden with a perimeter of 15,66 metres, 16 metres of fencing are bought to make sure there is no shortage of material. Garden: sides of 4,56 m and 3,27 m Exact perimeter: 15,66 m Fencing in whole metres, rounding "up": 16 m (so there is no shortage)
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In a video game shop, the price of a poster is €$7,82$. If you only have one-euro coins and you want to know, approximately, how many whole euros it costs: On the number…

In a video game shop, the price of a poster is €$7,82$. If you only have one-euro coins and you want to know, approximately, how many whole euros it costs:

On the number line in the figure, the two long marks are two consecutive whole numbers (the ones marked with “?”) and each small mark is one tenth.

Number line between two unknown consecutive whole numbers, divided into ten parts, with the price 7,82 € marked7,82 €??
  1. a) Between which two whole numbers does the price lie?
  2. b) Which of the two numbers is it closer to? Round to the nearest unit.
Solve
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Imagine you are going to pay with a $20$ € note for a purchase that costs $14,23$ €. The cashier has no small cent coins and suggests rounding the price to the nearest…

Imagine you are going to pay with a $20$ € note for a purchase that costs $14,23$ €. The cashier has no small cent coins and suggests rounding the price to the nearest tenth of a euro (that is, to a multiple of $10$ cents, with a single decimal digit).

  1. a) What would the new rounded price be?
  2. b) How much money would the cashier give you back after the rounding?
Solve
Practice★★☆Not started
We want to put a protective fence around a small rectangular garden. When measuring with a digital tape measure, we find that the sides measure $4,56$ metres and $3,27$…

We want to put a protective fence around a small rectangular garden. When measuring with a digital tape measure, we find that the sides measure $4,56$ metres and $3,27$ metres.

4,56 m 3,27 m
  1. a) Calculate the perimetre of the garden.
  2. b) If the garden owner buys the fence from a DIY store that only sells in whole metres and always rounds up (rounding up to the nearest unit) to make sure there is enough material, how many metres of fencing will he buy?
Solve

Back to the beginning: If you approximate to the nearest tenth, the runner's time ($12,45$ s) rounds to $12,5$ s (it goes up because the hundredths digit is $5$), whereas the weight of the oranges ($2,341$ kg) rounds to $2,3$ kg (the hundredths digit is less than $5$).

Summary

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