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Chemical reactions · The fundamental laws of chemistry

Quantitative calculations in everyday life

A fertiliser label, a laboratory analysis or the technical data sheet of a medicine almost never gives the chemical formula of what it contains: it gives percentages. "NPK 15-15-15", "ibuprofen 75,7 % C", "ore with 80 % richness". Knowing how to translate those percentages into real masses, and the reverse process, going from a composition to the formula of the compound, is one of the most widely used skills in applied chemistry.

Before you start, make sure you know: The mole and molar mass (4th ESO)
Before you start, make sure you know: Percentages (1st ESO)

The percentage composition of a compound

When $100\ \text{g}$ of pure water is broken down by electrolysis, you always obtain $11{,}1\ \text{g}$ of hydrogen and $88{,}9\ \text{g}$ of oxygen, no matter where the water comes from: how can we predict this fixed proportion mathematically from its chemical formula?

Segmented bar diagram showing the molar mass of water (18 g/mol) split between hydrogen (11,1 %) and oxygen (88,9 %). H: 11,1 % O: 88,9 % H₂O: 18 g/mol split between H and O
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Calculate the percentage composition of water, $\text{H}2\text{O}$ (atomic masses: $\text{H} = 1\ \text{u}$; $\text{O} = 16\ \text{u}$). Check that the two percentages…

Calculate the percentage composition of water, $\text{H}_2\text{O}$ (atomic masses: $\text{H} = 1\ \text{u}$; $\text{O} = 16\ \text{u}$). Check that the two percentages add up to $100\ \%$.

Solve
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Ammonia, $\text{NH}3$, is the raw material for the nitrogenous fertiliser industry. Calculate its mass percentage of nitrogen (atomic masses: $\text{N} = 14\ \text{u}$;…

Ammonia, $\text{NH}_3$, is the raw material for the nitrogenous fertiliser industry. Calculate its mass percentage of nitrogen (atomic masses: $\text{N} = 14\ \text{u}$; $\text{H} = 1\ \text{u}$).

Solve
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The marble used in worktops is calcium carbonate, $\text{CaCO}3$. Calculate its percentage composition (atomic masses: $\text{Ca} = 40\ \text{u}$;…

The marble used in worktops is calcium carbonate, $\text{CaCO}_3$. Calculate its percentage composition (atomic masses: $\text{Ca} = 40\ \text{u}$; $\text{C} = 12\ \text{u}$; $\text{O} = 16\ \text{u}$).

Solve

Richness or purity of a raw material

Bar representing 50 kg of ore: 80 % (40 kg) is iron(III) oxide, the useful substance, and 20 % (10 kg) is impurities or gangue that contribute no iron. Ore: 50 kg (100 %) 80 % Fe₂O₃ 20 % 40 kg of Fe₂O₃ (useful) 10 kg impurities (gangue) pure substance
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A bag of fertiliser from an agricultural warehouse has the label "NPK $15$-$15$-$15$" printed on it, indicating $15\ \%$ by mass of nitrogen, $15\ \%$ of phosphorus(V)…

A bag of fertiliser from an agricultural warehouse has the label "NPK $15$-$15$-$15$" printed on it, indicating $15\ \%$ by mass of nitrogen, $15\ \%$ of phosphorus(V) oxide, and $15\ \%$ of potassium oxide.

  1. a) Explain what the three numbers on the label mean.
  2. b) If the bag contains $20\ \text{kg}$ of fertiliser, how many kilograms of each nutrient does it provide?
Solve
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An iron ore arrives at the steelworks with a purity of $80\ \%$ in iron(III) oxide. a) How many kilograms of iron(III) oxide are in $50\ \text{kg}$ of ore? b) What does…

An iron ore arrives at the steelworks with a purity of $80\ \%$ in iron(III) oxide.

  1. a) How many kilograms of iron(III) oxide are in $50\ \text{kg}$ of ore?
  2. b) What does the remaining $20\ \%$ refer to?
Solve
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A mine supplies an iron ore with a purity of $80\ \%$ iron(III) oxide, $\text{Fe}2\text{O}3$ (atomic masses: $\text{Fe} = 56\ \text{u}$; $\text{O} = 16\ \text{u}$). a)…

A mine supplies an iron ore with a purity of $80\ \%$ iron(III) oxide, $\text{Fe}_2\text{O}_3$ (atomic masses: $\text{Fe} = 56\ \text{u}$; $\text{O} = 16\ \text{u}$).

  1. a) Calculate the percentage by mass of iron in the pure oxide.
  2. b) How many kilograms of iron can be obtained, at most, from one tonne ($1\,000\ \text{kg}$) of this ore?
Solve

From composition to the empirical formula

Laboratory analysis of $100\ \text{mg}$ of an unknown pure substance shows that it contains $40{,}0\ \text{mg}$ of carbon, $6{,}7\ \text{mg}$ of hydrogen and $53{,}3\ \text{mg}$ of oxygen: what method allows us to work out the chemical formula of the compound from these percentages by mass?

Vertical flow diagram with three steps for calculating the empirical formula: convert percentage to mass in 100 grams, go from grams to moles and divide by the smallest number of moles. % → g take 100 g of sample g → mol ÷ molar mass of each element ÷ smallest by the smallest no. of moles
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Glucose has the molecular formula $\text{C}6\text{H}{12}\text{O}6$. a) What is its empirical formula? Explain what information each of the two formulas gives. b) Give an…

Glucose has the molecular formula $\text{C}_6\text{H}_{12}\text{O}_6$.

  1. a) What is its empirical formula? Explain what information each of the two formulas gives.
  2. b) Give an example of a compound whose empirical and molecular formulas coincide and explain why this occurs.
Solve
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The analysis of a laboratory moisturiser shows a percentage composition of $40,0\ \%$ of carbon, $6,7\ \%$ of hydrogen, and $53,3\ \%$ of oxygen (atomic masses:…

The analysis of a laboratory moisturiser shows a percentage composition of $40,0\ \%$ of carbon, $6,7\ \%$ of hydrogen, and $53,3\ \%$ of oxygen (atomic masses: $\text{C} = 12\ \text{u}$; $\text{H} = 1\ \text{u}$; $\text{O} = 16\ \text{u}$).

  1. a) Calculate the moles of each element present in $100\ \text{g}$ of the compound.
  2. b) Deduce its empirical formula.
Solve
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Vitamin C (ascorbic acid) in food supplements has a percentage composition of $40,9\ \%$ carbon, $4,5\ \%$ hydrogen and $54,5\ \%$ oxygen, and its molar mass is…

Vitamin C (ascorbic acid) in food supplements has a percentage composition of $40,9\ \%$ carbon, $4,5\ \%$ hydrogen and $54,5\ \%$ oxygen, and its molar mass is $176\ \text{g/mol}$ (atomic masses: $\text{C} = 12\ \text{u}$; $\text{H} = 1\ \text{u}$; $\text{O} = 16\ \text{u}$).

  1. a) Determine its empirical formula. Hint: if the molar ratios are not integers, multiply them all by the same number until you get simple integers.
  2. b) Determine its molecular formula.
  3. c) A tablet contains $500\ \text{mg}$ of vitamin C: how many moles of vitamin C is this? Express the result to three significant figures.
Solve

From the empirical formula to the molecular formula

A CH₂ unit of 14 g/mol is repeated k = 3 times and forms the C₃H₆ molecule of 42 g/mol. CH₂ 14 g/mol × k = 42/14 = 3 14 g/mol 14 g/mol 14 g/mol C₃H₆ · 42 g/mol
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A gaseous hydrocarbon has a percentage composition of $85,7\ \%$ carbon and $14,3\ \%$ hydrogen, and its molar mass is $42\ \text{g/mol}$ (atomic masses:…

A gaseous hydrocarbon has a percentage composition of $85,7\ \%$ carbon and $14,3\ \%$ hydrogen, and its molar mass is $42\ \text{g/mol}$ (atomic masses: $\text{C} = 12\ \text{u}$; $\text{H} = 1\ \text{u}$).

  1. a) Determine its empirical formula.
  2. b) Determine its molecular formula. What additional piece of data was needed compared to the previous part?
Solve
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A liquid hydrocarbon found in petrol has a percentage composition of $85,7\ \%$ carbon and $14,3\ \%$ hydrogen, and its molar mass is $70\ \text{g/mol}$ (atomic masses:…

A liquid hydrocarbon found in petrol has a percentage composition of $85,7\ \%$ carbon and $14,3\ \%$ hydrogen, and its molar mass is $70\ \text{g/mol}$ (atomic masses: $\text{C} = 12\ \text{u}$; $\text{H} = 1\ \text{u}$).

  1. a) Determine its empirical formula and the molar mass of that empirical formula.
  2. b) Determine its molecular formula and check that it is consistent with the given molar mass.
  3. c) Explain why percentage analysis alone can never distinguish between two compounds with the same empirical formula.
Solve
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A gas sold in cylinders for cooking has a density of $1,96\ \text{g/L}$ at standard temperature and pressure (molar volume under these conditions: $22,4\ \text{L/mol}$)…

A gas sold in cylinders for cooking has a density of $1,96\ \text{g/L}$ at standard temperature and pressure (molar volume under these conditions: $22,4\ \text{L/mol}$) and a percentage composition of $81,8\ \%$ carbon and $18,2\ \%$ hydrogen (atomic masses: $\text{C} = 12\ \text{u}$; $\text{H} = 1\ \text{u}$).

  1. a) Calculate its molar mass from the density and the molar volume.
  2. b) Determine its empirical formula.
  3. c) Determine its molecular formula and identify which gas it is.
Solve

Back to the start: In a $25\ \text{kg}$ sack of NPK 15-15-15 fertiliser, the richness of $15\ \%$ shows that it contains $25 \cdot 0{,}15 = 3{,}75\ \text{kg}$ of usable nitrogen, directly translating the commercial percentage into real mass.

Summary

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