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Chemical reactions · The fundamental laws of chemistry

Laws of Mass and Stoichiometric Relationships

Antoine Lavoisier weighed everything. Before him, chemists described reactions with words ("the metal is calcined", "the air is spoiled"); he put them on a balance, before and after, and discovered something that seems obvious today but that changed chemistry for ever back then: the total weight does not shift by a single gram. From that balance, and from two other equally precise observations, came the three laws that you will use throughout this block every time you balance an equation or calculate a reactant.

Before you start, make sure you know: Law of conservation of mass (Lavoisier) (3rd ESO)
Before you start, make sure you know: Law of definite proportions (Proust) (3rd ESO)

The law of conservation of mass

If you burn a log in a fireplace, the ashes left behind weigh much less than the original wood; on the other hand, if you heat steel wool in air, the oxidised residue weighs more than the starting metal: where does the mass that seems to disappear go, or where does the mass that is gained come from?

Two-pan balance in equilibrium: on the left the reactants and on the right the products have the same mass the balance stays level reactants products m reactants m products
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We dissolve an effervescent tablet of $3\ \text{g}$ in a beaker of $100\ \text{g}$ of water. When the bubbling stops, the whole system weighs $102,5\ \text{g}$. Observe…

We dissolve an effervescent tablet of $3\ \text{g}$ in a beaker of $100\ \text{g}$ of water. When the bubbling stops, the whole system weighs $102,5\ \text{g}$. Observe the diagram of the process:

before 3 g + 100 g after 102,5 g gas: ? escapes into the air
  1. a) What mass of gas has escaped into the air?
  2. b) Does this result contradict the law of conservation of mass? Reason your answer.
Solve
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When a candle is weighed on a balance before and after being left to burn for a while, we find that the whole system has lost mass. The diagram shows what happens: a)…

When a candle is weighed on a balance before and after being left to burn for a while, we find that the whole system has lost mass. The diagram shows what happens:

O₂ from the air CO₂ and H₂O escape into the air the balance reads less
  1. a) Does this mean that matter has been destroyed? Explain what has actually happened.
  2. b) How would you design the experiment to check that the total mass is conserved?
Solve
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In a kiln, $10\ \text{g}$ of calcium carbonate decomposes due to heat, producing $5,6\ \text{g}$ of calcium oxide and $4,4\ \text{g}$ of carbon dioxide, as summarised in…

In a kiln, $10\ \text{g}$ of calcium carbonate decomposes due to heat, producing $5,6\ \text{g}$ of calcium oxide and $4,4\ \text{g}$ of carbon dioxide, as summarised in the diagram:

calcium carbonate 10 g calcium oxide 5,6 g carbon dioxide 4,4 g +
  1. a) Check that the law of conservation of mass is obeyed.
  2. b) If $25\ \text{g}$ of calcium carbonate decomposes, what mass of each product will be obtained? Which second law of chemical combination are you applying?
Solve

The law of definite proportions

Two water samples of different size, a small flask and a large beaker, with bars showing the same mass ratio of hydrogen to oxygen, 1 : 8 sample A H : O = 1 : 8 H O sample B H : O = 1 : 8 H O the same proportion, wherever it comes from
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In a laboratory, two samples of copper(II) oxide from different sources are analysed. Sample A contains $3,97\ \text{g}$ of copper and $1,00\ \text{g}$ of oxygen; Sample…

In a laboratory, two samples of copper(II) oxide from different sources are analysed. Sample A contains $3,97\ \text{g}$ of copper and $1,00\ \text{g}$ of oxygen; Sample B contains $11,91\ \text{g}$ of copper and $3,00\ \text{g}$ of oxygen.

  1. a) Calculate the ratio $\frac{\text{masa de cobre}}{\text{masa de oxígeno}}$ in each sample.
  2. b) Could they be the same compound? Which law of chemical combination guarantees this?
Solve
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A sample of $15,9\ \text{g}$ of copper(II) oxide contains $12,7\ \text{g}$ of copper and $3,2\ \text{g}$ of oxygen. a) What mass of oxygen will be combined with…

A sample of $15,9\ \text{g}$ of copper(II) oxide contains $12,7\ \text{g}$ of copper and $3,2\ \text{g}$ of oxygen.

  1. a) What mass of oxygen will be combined with $25,4\ \text{g}$ of copper in another sample of the same oxide?
  2. b) What will be the total mass of that second sample?
Solve
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A company buys industrial copper(II) oxide and suspects that it arrives with impurities. Pure oxide combines copper and oxygen in the ratio of $63,5\ \text{g}$ of copper…

A company buys industrial copper(II) oxide and suspects that it arrives with impurities. Pure oxide combines copper and oxygen in the ratio of $63,5\ \text{g}$ of copper for every $16\ \text{g}$ of oxygen. Analysis of a $10,0\ \text{g}$ sample of the product received shows that it contains only $7,6\ \text{g}$ of copper.

  1. a) Calculate what mass of copper a sample of $10,0\ \text{g}$ of pure copper(II) oxide should contain.
  2. b) Is the product received pure? Justify your answer using the law of definite proportions.
  3. c) Assuming that the impurity does not contain copper, estimate the purity of the product as a percentage.
Solve

The law of multiple proportions

Nitrogen and oxygen form several oxides: for a fixed $14\ \text{g}$ of nitrogen, we find compounds with $8\ \text{g}$, $16\ \text{g}$, $24\ \text{g}$, $32\ \text{g}$ and $40\ \text{g}$ of oxygen. Why does oxygen not combine in any continuous proportion, but in exact, proportional jumps?

Comparison of the masses of oxygen in carbon monoxide and carbon dioxide for a fixed amount of carbon O = 4 g CO O = 8 g CO₂ same mass of C (3 g) ratio of O: 4 : 8 = 1 : 2
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Carbon forms two gaseous oxides. In one of them, $3\ \text{g}$ of carbon combines with $4\ \text{g}$ of oxygen; in the other, $3\ \text{g}$ of carbon combines with…

Carbon forms two gaseous oxides. In one of them, $3\ \text{g}$ of carbon combines with $4\ \text{g}$ of oxygen; in the other, $3\ \text{g}$ of carbon combines with $8\ \text{g}$ of oxygen, as shown in the figure:

oxide 1 3 g of C + 4 g of O oxide 2 3 g of C + 8 g of O
  1. a) Calculate the ratio between the two masses of oxygen that combine with the same mass of carbon.
  2. b) Which law of chemical combination do these data illustrate, and who stated it?
Solve
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Nitrogen forms several oxides. Fixing the mass of nitrogen at $14\ \text{g}$, the masses of combined oxygen are $16\ \text{g}$ in nitrogen monoxide, $32\ \text{g}$ in…

Nitrogen forms several oxides. Fixing the mass of nitrogen at $14\ \text{g}$, the masses of combined oxygen are $16\ \text{g}$ in nitrogen monoxide, $32\ \text{g}$ in nitrogen dioxide, and $40\ \text{g}$ in dinitrogen pentoxide.

  1. a) Express the ratio $16 : 32 : 40$ as a ratio of simple integers.
  2. b) State the law of chemical combination that these data predict and explain its meaning.
Solve
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Chlorine forms four oxides: $\text{Cl}2\text{O}$, $\text{Cl}2\text{O}3$, $\text{Cl}2\text{O}5$, and $\text{Cl}2\text{O}7$ (atomic masses: $\text{Cl} = 35,5\ \text{u}$;…

Chlorine forms four oxides: $\text{Cl}_2\text{O}$, $\text{Cl}_2\text{O}_3$, $\text{Cl}_2\text{O}_5$, and $\text{Cl}_2\text{O}_7$ (atomic masses: $\text{Cl} = 35,5\ \text{u}$; $\text{O} = 16\ \text{u}$).

  1. a) Calculate the mass of oxygen that combines with $71\ \text{g}$ of chlorine in each of the four oxides.
  2. b) Check that these masses are in the ratio of simple integers $1 : 3 : 5 : 7$.
  3. c) Predict what mass of oxygen would combine with $71\ \text{g}$ of chlorine in a hypothetical oxide $\text{Cl}_2\text{O}_9$ and state in your own words the law you have used.
Solve

From the laws of mass to stoichiometry

Taken together, the three laws are the reason why a balanced chemical equation is not just a writing convention: it is a statement about mass proportions that can be checked with a balance, and that makes it possible to predict how much reactant is needed or how much product will be obtained in any reaction, however large or small.

Synthesis of water: two H₂ molecules and one O₂ molecule give two H₂O molecules, and a balanced scale shows that 4 g + 32 g of reactants weigh the same as 36 g of water 4 g H₂ + 32 g O₂ fixed proportion 36 g H₂O conservation of mass 4 g 32 g 36 g
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The industrial synthesis of ammonia is summarised as follows: $28\ \text{g}$ of nitrogen reacts with $6\ \text{g}$ of hydrogen to yield $34\ \text{g}$ of ammonia. a)…

The industrial synthesis of ammonia is summarised as follows: $28\ \text{g}$ of nitrogen reacts with $6\ \text{g}$ of hydrogen to yield $34\ \text{g}$ of ammonia.

  1. a) What mass of hydrogen is needed to react with $56\ \text{g}$ of nitrogen?
  2. b) What mass of ammonia will then be produced?
  3. c) State which two laws of chemical combination you have applied and in which part.
Solve
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$10\ \text{g}$ of hydrogen and $64\ \text{g}$ of oxygen are introduced into a closed reactor to produce water. The stoichiometric ratio by mass is $1\ \text{g}$ of…

$10\ \text{g}$ of hydrogen and $64\ \text{g}$ of oxygen are introduced into a closed reactor to produce water. The stoichiometric ratio by mass is $1\ \text{g}$ of hydrogen for every $8\ \text{g}$ of oxygen.

  1. a) Determine which reactant is used up first and justify your answer with a calculation.
  2. b) Calculate the mass of water formed and the mass of the remaining reactant.
  3. c) Check that the total mass inside the reactor before and after the reaction is the same. Which law requires this?
Solve
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In a lime kiln, $200\ \text{g}$ of limestone (pure calcium carbonate) is heated to obtain $112\ \text{g}$ of quicklime (calcium oxide) and $88\ \text{g}$ of carbon…

In a lime kiln, $200\ \text{g}$ of limestone (pure calcium carbonate) is heated to obtain $112\ \text{g}$ of quicklime (calcium oxide) and $88\ \text{g}$ of carbon dioxide.

  1. a) Check that mass is conserved in the process.
  2. b) Express the stoichiometric mass ratio calcium carbonate : calcium oxide : carbon dioxide using integers.
  3. c) Predict what mass of quicklime and carbon dioxide $500\ \text{g}$ of limestone will produce, indicating which two laws of chemical combination make this prediction possible.
Solve

Summary

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