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Chemical reactions · Gases and solutions

Solutions and their properties

In 4th ESO you measured concentration in percentages and in grams per litre. In a real chemistry laboratory, however, what matters almost always is not how many grams there are, but how many particles (molecules or ions) there are, because it is the particles that react, that cross a membrane, or that lower the freezing point of the water in a car's radiator in the middle of winter. That is why in Bachillerato concentration is expressed mainly in moles per litre: molarity.

Before you start, make sure you know: Solutions (4th ESO)
Before you start, make sure you know: Calculations with moles (4th ESO)

Molarity: concentration in moles per litre

If you dissolve $58{,}5\ \text{g}$ of common salt (NaCl) in water and $180\ \text{g}$ of glucose ($\text{C}_6\text{H}_{12}\text{O}_6$) in another beaker, the balance shows very different masses, yet both containers hold the same amount of substance ($1\ \text{mol}$ of NaCl units and $1\ \text{mol}$ of glucose molecules; however, when dissolved, the NaCl separates into $2\ \text{mol}$ of ions): how can we express concentration so as to compare the real number of molecules or ions present per litre, and not just their mass?

Volumetric flask with one litre of solution made up to the mark and four solute particles, illustrating molarity as moles per litre. Molarity: moles of solute per litre 4 solute particles in 1 L (each particle = 1 mol) 1 L graduation mark solute particles M = 4 mol / 1 L = 4 mol/L
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In the laboratory, $0,5\ \text{mol}$ of sodium chloride is dissolved in water to make $2\ \text{L}$ of solution. a) Write down the formula for molarity. b) Calculate the…

In the laboratory, $0,5\ \text{mol}$ of sodium chloride is dissolved in water to make $2\ \text{L}$ of solution.

  1. a) Write down the formula for molarity.
  2. b) Calculate the molarity of the solution.
Solve
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A solution of sodium hydroxide, $\text{NaOH}$, is $0,4\ \text{M}$. Data: molar mass of $\text{NaOH}$, $40\ \text{g/mol}$. a) How many moles of $\text{NaOH}$ are in…

A solution of sodium hydroxide, $\text{NaOH}$, is $0,4\ \text{M}$. Data: molar mass of $\text{NaOH}$, $40\ \text{g/mol}$.

  1. a) How many moles of $\text{NaOH}$ are in $250\ \text{mL}$ of that solution?
  2. b) How many grams of $\text{NaOH}$ is this?
Solve
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You are asked to prepare $200\ \text{mL}$ of a $1\ \text{M}$ solution of potassium chloride, $\text{KCl}$. Given: molar mass of $\text{KCl}$, $74,5\ \text{g/mol}$. a)…

You are asked to prepare $200\ \text{mL}$ of a $1\ \text{M}$ solution of potassium chloride, $\text{KCl}$. Given: molar mass of $\text{KCl}$, $74,5\ \text{g/mol}$.

  1. a) How many moles of $\text{KCl}$ do you need?
  2. b) What mass should you weigh?
  3. c) Describe the complete laboratory procedure, naming the apparatus (balance, beaker, volumetric flask…) and the moment when it is made up to the mark.
Solve

Parts per million: very small concentrations

One kilogram of water, equivalent to a million milligrams, shown as a bar; a very thin strip at the end represents 1 mg of solute, that is, 1 ppm. 1 kg of water (= 1 000 000 mg) 1 mg of solute = 1 ppm 1 ppm = 1 mg per kg of solution
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The legal limit of nitrates in drinking water is $50\ \text{ppm}$, i.e. $50\ \text{mg}$ of nitrate per kilogram of water. a) How many milligrams of nitrate, at most, can…

The legal limit of nitrates in drinking water is $50\ \text{ppm}$, i.e. $50\ \text{mg}$ of nitrate per kilogram of water.

  1. a) How many milligrams of nitrate, at most, can a container with $5\ \text{kg}$ of water contain?
  2. b) In the laboratory, $50\ \text{ppm}$ is often taken as $50\ \text{mg/L}$: explain what is being assumed about the density of water for both ways of expressing it to coincide.
Solve
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Analysis of a spring finds $30\ \text{mg}$ of dissolved fluoride per $2\ \text{kg}$ of water. The recommended limit for drinking water is $1,5\ \text{ppm}$. a) Express…

Analysis of a spring finds $30\ \text{mg}$ of dissolved fluoride per $2\ \text{kg}$ of water. The recommended limit for drinking water is $1,5\ \text{ppm}$.

  1. a) Express the fluoride concentration of the spring in ppm.
  2. b) Does it exceed the limit? How many times does it exceed it?
Solve

Diluting and mixing molar solutions

In the laboratory, commercial acids are supplied very concentrated (such as hydrochloric acid at $37\ \% \approx 12\ \text{M}$), but for practical work low concentrations such as $0{,}1\ \text{M}$ or $0{,}5\ \text{M}$ are almost always needed: what exact volume of solvent must you add to lower the concentration without altering the amount of solute?

Dilution of 10 mL of 2 M HCl: 90 mL of water are added in a volumetric flask up to the 100 mL mark, giving 0,2 M HCl with the same number of solute particles, 0,02 mol. State 1 Concentrated HCl State 2 Dilute HCl M₁ = 2 M V₁ = 10 mL + 90 mL of water made up to 100 mL graduation mark M₂ = 0,2 M V₂ = 100 mL total volume solute particles (the same in both containers) n = M₁·V₁ = 2 M · 0,010 L = 0,02 mol = M₂·V₂
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$10\ \text{mL}$ of a hydrochloric acid solution, $\text{HCl}$, $2\ \text{M}$ are taken and water is added to make up $100\ \text{mL}$ of solution. Observe the diagram of…

$10\ \text{mL}$ of a hydrochloric acid solution, $\text{HCl}$, $2\ \text{M}$ are taken and water is added to make up $100\ \text{mL}$ of solution. Observe the diagram of the dilution.

10 mL HCl 2 M + water 100 mL M₂ = ?
  1. a) How many moles of $\text{HCl}$ did the initial $10\ \text{mL}$ contain?
  2. b) Calculate the molarity of the diluted solution.
  3. c) Verify that the relationship $M_1\cdot V_1=M_2\cdot V_2$ is satisfied and explain which quantity is conserved in a dilution.
Solve
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A laboratory has nitric acid, $\text{HNO}3$, $4\ \text{M}$ and needs to prepare $500\ \text{mL}$ of $0,8\ \text{M}$ solution. a) Apply the relationship…

A laboratory has nitric acid, $\text{HNO}_3$, $4\ \text{M}$ and needs to prepare $500\ \text{mL}$ of $0,8\ \text{M}$ solution.

  1. a) Apply the relationship $M_1\cdot V_1=M_2\cdot V_2$ to calculate the volume of concentrated acid that needs to be measured.
  2. b) Describe how to safely prepare the dilution: what apparatus is used and why the acid is added to the water and not the other way round.
Solve
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In an analytical laboratory, $100\ \text{mL}$ of $0,5\ \text{M}$ $\text{NaCl}$ solution are mixed with $300\ \text{mL}$ of $1,5\ \text{M}$ $\text{NaCl}$ solution. Assume…

In an analytical laboratory, $100\ \text{mL}$ of $0,5\ \text{M}$ $\text{NaCl}$ solution are mixed with $300\ \text{mL}$ of $1,5\ \text{M}$ $\text{NaCl}$ solution. Assume that the volumes are additive. The diagram shows the mixture.

100 mL NaCl 0,5 M + 300 mL NaCl 1,5 M 400 mL M = ?
  1. a) Calculate the moles of salt provided by each solution.
  2. b) Calculate the molarity of the resulting mixture.
  3. c) Explain why the result is not $1\ \text{M}$, the mean of the two initial concentrations.
Solve

Colligative properties: what matters is how many particles there are

Freezing temperature scale: pure water freezes at 0 °C, the 0,5 M salt solution freezes lower down and the 1 M salt solution freezes lower still. Freezing temperature T 0 °C pure water 0,5 M salt 1 M salt freezes at 0 °C freezes lower down freezes lower still depression
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The colligative properties of solutions depend on the number of dissolved solute particles and not on their nature. a) Order from lowest to highest freezing point: pure…

The colligative properties of solutions depend on the number of dissolved solute particles and not on their nature.

  1. a) Order from lowest to highest freezing point: pure water, $0,5\ \text{M}$ salt solution, and $1\ \text{M}$ salt solution. Explain your answer.
  2. b) Order those same three samples from lowest to highest boiling point.
  3. c) Does it affect these orderings whether the solute is salt or sugar? Explain what it means for them to be colligative properties.
Solve
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Two compartments are separated by a semipermeable membrane, which allows water to pass through but not glucose. In one there is a $0,1\ \text{M}$ glucose solution and in…

Two compartments are separated by a semipermeable membrane, which allows water to pass through but not glucose. In one there is a $0,1\ \text{M}$ glucose solution and in the other a $1\ \text{M}$ solution. The diagram shows the initial situation.

net flow of water: ? water glucose semipermeable membrane 0,1 M glucose 1 M glucose
  1. a) Explain what osmosis is.
  2. b) Predict which way the water will pass through the membrane and justify your answer.
  3. c) What difference will be observed between the two compartments over time?
  4. d) What is osmotic pressure? State what would need to be done to prevent this flow of water.
Solve
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Red blood cells are surrounded by a semipermeable membrane and contain an aqueous medium with dissolved salts and proteins. a) Explain why saline or intravenous fluid…

Red blood cells are surrounded by a semipermeable membrane and contain an aqueous medium with dissolved salts and proteins.

  1. a) Explain why saline or intravenous fluid injected into a vein must be isotonic, that is, have a solute concentration similar to that of blood. Which colligative phenomenon is involved?
  2. b) Predict what would happen to red blood cells if the IV fluid were much more dilute than blood: which way would water flow and what risk would there be?
  3. c) What if it were much more concentrated? Justify your answer in the same way.
Solve

Summary

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