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Chemical bonding and structure of matter · Chemical bonding

Stability of atoms and ions

Apart from the noble gases, almost no element is found in nature as single atoms: metallic sodium, chlorine gas and the oxygen in the air always end up combined or paired with other atoms. The reason is always the same: an isolated atom is almost never the lowest-energy form possible, and matter spontaneously tends towards that minimum energy.

Before you start, make sure you know: Electron configuration (4th ESO)
Before you start, make sure you know: Subatomic particles and isotopes (2nd ESO)

Why atoms bond

If you bring metallic sodium into contact with chlorine gas, they react violently, giving off light and heat until they form common salt ($\text{NaCl}$), a substance so stable that to separate it back into its elements you have to melt it and pass electricity through it: why do isolated atoms prefer to group together, and what force holds them together?

Graph of potential energy against the distance between two atoms: at very short distances the energy rises because of the repulsion between nuclei, at large distances it tends to that of the separate atoms, and in between there is a well of minimum energy, which corresponds to the bonded atoms; the depth of the well is the bond energy. Potential energy Distance between the atoms Bond energy repulsion between nuclei 2 separate atoms bonded atoms: minimum energy

The depth of the well in this curve (the difference between the separated atoms and the minimum) is the bond energy: the energy that has to be supplied to separate the atoms again.

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Isolated atoms are rarely found in nature: except for noble gases, elements occur forming compounds or metals. a) Explain what it means for an atom to be "stable" and…

Isolated atoms are rarely found in nature: except for noble gases, elements occur forming compounds or metals.

  1. a) Explain what it means for an atom to be "stable" and what atoms gain by bonding with one another.
  2. b) What happens to the energy of the system when atoms form a bond? Does it increase or decrease?
Solve
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The octet rule guides the chemistry of most elements. a) State it in your own words. b) Which electrons in the atom does it refer to? c) What configuration do atoms…

The octet rule guides the chemistry of most elements.

  1. a) State it in your own words.
  2. b) Which electrons in the atom does it refer to?
  3. c) What configuration do atoms reach when they satisfy it? Give an example of an element that already possesses it naturally.
Solve
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Neon ($Z = 10$) is used in illuminated signs because it is a completely inert gas: it does not react with anything. a) Write its electron configuration. b) How many…

Neon ($Z = 10$) is used in illuminated signs because it is a completely inert gas: it does not react with anything.

  1. a) Write its electron configuration.
  2. b) How many electrons does it have in its outer shell?
  3. c) Explain, from this configuration, why noble gases do not form compounds under normal conditions.
Solve

From atom to ion: cations and anions

Adjust the electrons in this Bohr model of sodium: with $11$ protons and $11$ electrons you have the neutral atom; lower them to $10$ and you get the $\text{Na}^+$ ion, with the same valence shell as neon.

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When sodium combines with chlorine, each sodium atom loses an electron and becomes the $\text{Na}^+$ ion. The diagram represents the loss of the electron. a) Define what…

When sodium combines with chlorine, each sodium atom loses an electron and becomes the $\text{Na}^+$ ion. The diagram represents the loss of the electron.

Na Na atom loses 1 electron Na +1 Na ion
  1. a) Define what a cation is and what an anion is.
  2. b) State the sign of the charge for each type of ion.
  3. c) Is the $\text{Na}^+$ ion a cation or an anion? Reason your answer.
Solve
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Magnesium ($Z = 12$) reacts by losing electrons and forming the $\text{Mg}^{2+}$ ion. a) How many electrons does each magnesium atom lose? b) How many electrons does the…

Magnesium ($Z = 12$) reacts by losing electrons and forming the $\text{Mg}^{2+}$ ion.

  1. a) How many electrons does each magnesium atom lose?
  2. b) How many electrons does the formed ion have in total?
  3. c) Write the process as a half-equation: $\text{Mg} \rightarrow \text{Mg}^{2+} + \ldots$ (complete the number of electrons released).
Solve
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The chlorine ($Z = 17$) in swimming pool water acts as a disinfectant and, when reacting, each atom gains an electron forming the $\text{Cl}^{-}$ ion. a) How many…

The chlorine ($Z = 17$) in swimming pool water acts as a disinfectant and, when reacting, each atom gains an electron forming the $\text{Cl}^{-}$ ion.

  1. a) How many electrons does the chloride ion have?
  2. b) Is it a cation or an anion?
  3. c) What is its net electrical charge? Justify your answer by counting protons and electrons.
Solve
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A particle contains $12$ protons and $10$ electrons. a) Calculate its net charge. b) Is it a neutral atom, a cation or an anion? c) Identify the element and write the…

A particle contains $12$ protons and $10$ electrons.

  1. a) Calculate its net charge.
  2. b) Is it a neutral atom, a cation or an anion?
  3. c) Identify the element and write the symbol of the ion.
Solve

Predicting the most stable ion

Shell model: sodium (2, 8, 1) loses its single valence electron and becomes Na⁺ (2, 8), with the neon configuration; chlorine (2, 8, 7) gains an electron and becomes Cl⁻ (2, 8, 8), with the argon configuration. Sodium (Z = 11): metal, 1 valence e⁻ 11+ e⁻ loses 1 e⁻ instead of gaining 7 11+ + Na: 2, 8, 1 1 extra e⁻ Na⁺: 2, 8 Ne configuration Chlorine (Z = 17): non-metal, 7 valence e⁻ 17+ gap e⁻ gains 1 e⁻ instead of losing 7 17+ − Cl: 2, 8, 7 1 e⁻ missing Cl⁻: 2, 8, 8 Ar configuration
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Chlorine ($Z = 17$) and argon ($Z = 18$) are neighbours in the periodic table. a) Write the electron configuration of the chlorine atom and that of the $\text{Cl}^{-}$…

Chlorine ($Z = 17$) and argon ($Z = 18$) are neighbours in the periodic table.

  1. a) Write the electron configuration of the chlorine atom and that of the $\text{Cl}^{-}$ ion.
  2. b) Compare the configuration of the chloride ion with that of the argon atom: what do you observe?
  3. c) Using this result, explain why chlorine tends to gain an electron when it reacts.
Solve
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The aluminium ($Z = 13$) in soft drink cans and the sulphur ($Z = 16$) in matches are very different elements, but both form stable ions. a) Write the electron…

The aluminium ($Z = 13$) in soft drink cans and the sulphur ($Z = 16$) in matches are very different elements, but both form stable ions.

  1. a) Write the electron configuration of each atom.
  2. b) Predict the most stable ion that each will form by applying the octet rule.
  3. c) Write the configuration of each ion and name the noble gas whose configuration it matches.
Solve
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To abbreviate configurations, noble gas notation is used: that of potassium ($Z = 19$) is written as $[\text{Ar}]\ 4s^1$. a) Write its full electron configuration,…

To abbreviate configurations, noble gas notation is used: that of potassium ($Z = 19$) is written as $[\text{Ar}]\ 4s^1$.

  1. a) Write its full electron configuration, without abbreviating.
  2. b) How many valence electrons does potassium have?
  3. c) Which ion will it form most easily? Write its configuration and explain why it is exceptionally stable.
Solve

Isoelectronic species and the size of ions

In crystallographic measurements, the radius of the $\text{O}^{2-}$ ion is $140\text{ pm}$ whereas that of the $\text{Mg}^{2+}$ cation is barely $72\text{ pm}$, even though both have exactly the same 10 electrons: why do two species with identical electron shells have such different sizes?

Scale comparison of the radius of the isoelectronic ions O²⁻ (8 protons), Na⁺ (11) and Mg²⁺ (12), all with 10 electrons: the radius decreases as the number of protons increases. O²⁻ 8 protons Na⁺ 11 protons Mg²⁺ 12 protons 140 pm 102 pm 72 pm more protons → smaller radius Same 10 electrons, very different sizes
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These species seem very different: $\text{N}^{3-}$, $\text{O}^{2-}$, $\text{F}^{-}$, $\text{Na}^{+}$, $\text{Mg}^{2+}$, and $\text{Al}^{3+}$. Data: $Z(\text{N}) = 7$,…

These species seem very different: $\text{N}^{3-}$, $\text{O}^{2-}$, $\text{F}^{-}$, $\text{Na}^{+}$, $\text{Mg}^{2+}$, and $\text{Al}^{3+}$. Data: $Z(\text{N}) = 7$, $Z(\text{O}) = 8$, $Z(\text{F}) = 9$, $Z(\text{Na}) = 11$, $Z(\text{Mg}) = 12$, $Z(\text{Al}) = 13$.

  1. a) Calculate the number of electrons in each species.
  2. b) What do all of them have in common?
  3. c) Explain what it means for them to be isoelectronic and state which noble gas they are isoelectronic with.
Solve
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When converting into an ion, an atom changes in size: the radius of the sodium atom is $186\ \text{pm}$ and that of the $\text{Na}^{+}$ ion is $102\ \text{pm}$; that of…

When converting into an ion, an atom changes in size: the radius of the sodium atom is $186\ \text{pm}$ and that of the $\text{Na}^{+}$ ion is $102\ \text{pm}$; that of the chlorine atom is $99\ \text{pm}$ and that of the $\text{Cl}^{-}$ ion is $181\ \text{pm}$. The four sizes are compared to scale in the figure.

Na 186 pm Na +1 102 pm Cl 99 pm Cl −1 181 pm
  1. a) Write the electron configurations of the two atoms and the two ions.
  2. b) Explain why the cation is much smaller than the atom from which it originates.
  3. c) Explain why the anion is much larger than its atom.
Solve
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The species $\text{O}^{2-}$, $\text{F}^{-}$, $\text{Na}^{+}$, and $\text{Mg}^{2+}$ all have $10$ electrons, but their radii are $140\ \text{pm}$, $133\ \text{pm}$,…

The species $\text{O}^{2-}$, $\text{F}^{-}$, $\text{Na}^{+}$, and $\text{Mg}^{2+}$ all have $10$ electrons, but their radii are $140\ \text{pm}$, $133\ \text{pm}$, $102\ \text{pm}$, and $72\ \text{pm}$, respectively. The figure compares the four radii to scale.

O −2 140 pm F −1 133 pm Na +1 102 pm Mg +2 72 pm
  1. a) Explain why, for the same number of electrons, the size of the species depends on the number of protons in the nucleus.
  2. b) Order the four species from largest to smallest radius and relate that order to their atomic number.
  3. c) Without further data, predict which will have a larger radius between the $\text{N}^{3-}$ ion and the $\text{Al}^{3+}$ ion, and justify your prediction.
Solve

Why there is a limit: ionisation energy

To remove the first electron from sodium takes $496\text{ kJ/mol}$, but removing the second requires $4562\text{ kJ/mol}$ (almost ten times more), which prevents the $\text{Na}^{2+}$ ion from existing: why does the energy required shoot up all at once after losing a specific number of electrons?

This model represents the $\text{Mg}^{2+}$ ion: only two complete shells remain. Try to imagine (without touching it) how much more it would cost to remove a third electron from that inner shell, which already has a noble-gas structure: that is why magnesium never forms $\text{Mg}^{3+}$.

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These are the energies required to remove successive electrons from a magnesium atom ($Z = 12$): $E_1 = 738\ \text{kJ/mol}$, $E_2 = 1451\ \text{kJ/mol}$, and…

These are the energies required to remove successive electrons from a magnesium atom ($Z = 12$): $E_1 = 738\ \text{kJ/mol}$, $E_2 = 1451\ \text{kJ/mol}$, and $E_3 = 7733\ \text{kJ/mol}$. The figure represents the three energies.

E (kJ/mol) 2000 4000 6000 8000 738 1451 7733 E1 E2 E3
  1. a) Locate between which ionisations the large jump occurs and justify it using the electron configuration of magnesium.
  2. b) Explain why magnesium forms the $\text{Mg}^{2+}$ ion and never $\text{Mg}^{3+}$ in its compounds.
  3. c) Predict, reasoning from their configurations, between which ionisations the large jump will appear in sodium ($Z = 11$) and in aluminium ($Z = 13$).
Solve
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Removing an electron from a neon atom costs $2081\ \text{kJ/mol}$, but removing it from the $\text{Na}^{+}$ ion, which has exactly the same electron configuration, costs…

Removing an electron from a neon atom costs $2081\ \text{kJ/mol}$, but removing it from the $\text{Na}^{+}$ ion, which has exactly the same electron configuration, costs $4562\ \text{kJ/mol}$. In contrast, it costs a neutral sodium atom only $496\ \text{kJ/mol}$ to lose its $3s$ electron. The figure compares the three ionisation energies.

E (kJ/mol) 1000 2000 3000 4000 5000 2081 4562 496 Ne Na (+1) Na
  1. a) Explain why it is harder to ionise $\text{Na}^{+}$ than $\text{Ne}$ if both have the same electrons.
  2. b) Using the data, reason why sodium easily forms the $\text{Na}^{+}$ ion but never appears as $\text{Na}^{2+}$ in chemical compounds.
  3. c) Connect your answers to the idea of noble gas configuration stability.
Solve

Summary

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