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BAC1 ss · Mathematics
Functions · Limits

Limits at a point

You already know what it means for a function to have a limit at a point. Now it is time to calculate it precisely in specific cases: sometimes substituting is enough, sometimes you have to factorise, and sometimes it is worth using a table before tackling the algebra.

Before you start, make sure you know: Factorising and the Ruffini rule (4th ESO)
Before you start, make sure you know: Algebraic fractions (4th ESO)

Direct substitution

If the function is defined and "well-behaved" (a polynomial, a rational function whose denominator does not vanish, a root with a positive argument...) at the point, the limit is calculated simply by substituting.

Diagram of the direct substitution rule for calculating limits when no indeterminate forms appear. lim(x→a) f(x) = f(a) if substituting x=a gives no indeterminate form
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Calculate the following limits by direct substitution into the expression of the function: a) $\lim_{x \to -1} (x^3 - 3x^2 + 4)$ b) $\lim_{x \to 0} \frac{2x + 5}{x - 3}$…

Calculate the following limits by direct substitution into the expression of the function:

  1. a) $\lim_{x \to -1} (x^3 - 3x^2 + 4)$
  1. b) $\lim_{x \to 0} \frac{2x + 5}{x - 3}$
  1. c) $\lim_{x \to 4} \sqrt{x + 5}$
Solve
Practice★☆☆Not started
A market study indicates that the daily profits of a new coffee shop, in euros, follow the function $B(t) = t^2 + 5t - 10$, where $t$ is the time in months since its…

A market study indicates that the daily profits of a new coffee shop, in euros, follow the function $B(t) = t^2 + 5t - 10$, where $t$ is the time in months since its opening. Calculate the limit of the profits as time tends to $3$ months ($t \to 3$).

Solve

Estimating limits with a table of values

Before calculating algebraically, a table of values very close to the point — from both sides — lets you guess where the function is heading. It is especially useful when direct substitution gives $\frac00$.

Practice★☆☆Not started
Given the function $f(x) = \frac{x^2 - 1}{x - 1}$, complete the following table of values to approximate the limit of the function as $x$ tends to $1$. What value does…

Given the function $f(x) = \frac{x^2 - 1}{x - 1}$, complete the following table of values to approximate the limit of the function as $x$ tends to $1$. What value does the function appear to approach?

$x \to 1^-$ $f(x)$ $x \to 1^+$ $f(x)$
$0,9$ $1,1$
$0,99$ $1,01$
$0,999$ $1,001$
Solve
Practice★★☆Not started
A content creator has observed that the growth of followers on their channel during the first hour of a livestream follows the function $f(x) = \frac{x^2 - 25}{x - 5}$,…

A content creator has observed that the growth of followers on their channel during the first hour of a livestream follows the function $f(x) = \frac{x^2 - 25}{x - 5}$, where $x$ is the time in minutes. However, right at minute $x = 5$, the platform suffered a small technical error and did not record data.

Estimate the value that the number of followers approaches as time approaches $5$ minutes by completing the following table of values and calculating the limit:

$x$ $4,9$ $4,99$ $4,999$ $5,001$ $5,01$ $5,1$
$f(x)$

$\lim_{x \to 5} \frac{x^2 - 25}{x - 5}$

Solve

The indeterminate form $\frac00$: factorise and simplify

When the numerator and denominator are polynomials that vanish at the same point $a$, both have the factor $(x-a)$. By factorising and cancelling that factor, the indeterminate form disappears.

Flow diagram of the method for resolving the indeterminate form zero over zero by factorising and cancelling common factors. P(x) = (x−a)·Q₁(x) if P(a)=0, the factor (x−a) can always be taken out
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Given the piecewise-defined function: $$f(x) = \begin{cases} 2x + 1 & \text{if } x < 1 \\ x^2 + 2 & \text{if } x \geq 1 \end{cases}$$ Calculate the one-sided limits at…

Given the piecewise-defined function:

$$f(x) = \begin{cases} 2x + 1 & \text{if } x < 1 \\ x^2 + 2 & \text{if } x \geq 1 \end{cases}$$

Calculate the one-sided limits at the boundary point:

  1. a) $\lim_{x \to 1^-} f(x)$
  1. b) $\lim_{x \to 1^+} f(x)$

Does the limit $\lim_{x \to 1} f(x)$ exist? Justify your answer.

Solve
Practice★★☆Not started
Calculate the value of the following limit by resolving the indeterminate form by factorising polynomials: $\lim_{x \to -2} \frac{x^3 + 3x^2 + 2x}{x^2 - x - 6}$

Calculate the value of the following limit by resolving the indeterminate form by factorising polynomials:

$\lim_{x \to -2} \frac{x^3 + 3x^2 + 2x}{x^2 - x - 6}$

Solve

The conjugate with roots

If the indeterminate form $\frac00$ appears together with a root, multiplying and dividing by the conjugate turns the root into a square and removes the problem.

Difference of two squares identity applied to a binomial with a square root to find the conjugate. (√A − B)(√A + B) = A − B² multiplying by the conjugate "removes" the root in the numerator
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Solve the following limit using the conjugate product method to eliminate the radical from the numerator: $\lim_{x \to 4} \frac{\sqrt{x+5} - 3}{x - 4}$

Solve the following limit using the conjugate product method to eliminate the radical from the numerator:

$\lim_{x \to 4} \frac{\sqrt{x+5} - 3}{x - 4}$

Solve

Vertical asymptote or removable discontinuity?

When the denominator vanishes at $x=a$, everything depends on whether the numerator also vanishes there: if it does, the common root cancels and there may be no asymptote; if it does not, there is a genuine vertical asymptote with infinite limits.

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Given the rational function $f(x) = \frac{2x^2 - 8}{x^2 - 4x + 4}$, study its behaviour as $x$ approaches $2$. To do so, calculate the one-sided limits:…

Given the rational function $f(x) = \frac{2x^2 - 8}{x^2 - 4x + 4}$, study its behaviour as $x$ approaches $2$.

To do so, calculate the one-sided limits:

$\lim_{x \to 2^-} f(x)$ and $\lim_{x \to 2^+} f(x)$

Explain, based on the results, whether the function has a vertical asymptote or a removable discontinuity at that point.

Solve
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In a biology laboratory, the concentration of a toxin in a bacterial culture is studied. The concentration $C$ in parts per million (ppm) with respect to the temperature…

In a biology laboratory, the concentration of a toxin in a bacterial culture is studied. The concentration $C$ in parts per million (ppm) with respect to the temperature $x$ in degrees Celsius follows the function:

$C(x) = \frac{x^2 - 4x + 3}{x^2 - 1}$

Calculate the limiting concentration as the temperature tends to $1^\circ\text{C}$. Is the concentration defined at exactly that temperature? Justify your answer by analysing the domain and the limit at that point.

Solve
Practice★★★Not started
Consider the rational function $R(x) = \frac{x^2 - m}{x^2 - 5x + 6}$. a) Determine the value of $m$ so that the function has a removable discontinuity at $x = 2$. b) For…

Consider the rational function $R(x) = \frac{x^2 - m}{x^2 - 5x + 6}$.

  1. a) Determine the value of $m$ so that the function has a removable discontinuity at $x = 2$.
  1. b) For that value of $m$, calculate $\lim_{x \to 2} R(x)$.
  1. c) What happens to the limit of the function at $x = 3$ for the value of $m$ found in part a)? Calculate the one-sided limits at $x = 3$ and describe the behavior of the infinite branches of the function near that line.
Solve

Summary

See all the exercises in this section