Back to homeMathematics · 1st Bach. Social Sciences · Change subject
Start for free
BAC1 ss · Mathematics
Functions · Limits

Infinite branches of exponential and logarithmic functions

A video goes viral and its views grow faster every day: that is an exponential. The wifi signal gets weaker by less and less as you move away: also an exponential, but a decreasing one. And the popularity of a Google search grows quickly at first but more and more slowly later: that is a logarithm. All three situations have very characteristic infinite branches, different from the ones you already know in rational functions.

Before you start, make sure you know: Exponential functions (4th ESO)
Before you start, make sure you know: Logarithmic functions (4th ESO)

Exponentials at infinity: growing or dying out

The behaviour of $a^x$ at infinity depends only on whether the base $a$ is greater or less than $1$.

Practice★☆☆Not started
A mold colony grows in a Petri dish in a school laboratory. The area it covers, in $cm^2$, follows the model of an exponential function that depends on time $t$ in days:…

A mold colony grows in a Petri dish in a school laboratory. The area it covers, in $cm^2$, follows the model of an exponential function that depends on time $t$ in days: $M(t) = 2 \cdot 1,5^t$. The graph shows the function for $t$ between 0 and 6 days.

Graph of the exponential function M(t) = 2 · 1,5^t for t between 0 and 6 days, increasing and with M(0) = 21234564812162024t (days)M(t) (cm²)2

a) What value does the area covered by the mold approach if the colony keeps growing indefinitely? Express this fact using limit notation.

b) Look at the graph of the function and describe the type of infinite branch it presents when $t \to +\infty$.

Solve
Practice★☆☆Not started
The Wi-Fi signal strength in a coffee shop, measured in microwatts ($\mu$W), decreases as we move away from the antenna according to the function…

The Wi-Fi signal strength in a coffee shop, measured in microwatts ($\mu$W), decreases as we move away from the antenna according to the function $I(d) = 60 \cdot e^{-0,1d}$, where $d$ is the distance in metres.

a) Calculate the limit of the signal strength as the distance $d$ tends to $+\infty$.

b) What does the result obtained mean in the context of the problem? Is there a horizontal asymptote?

Solve
Practice★☆☆Not started
Find the horizontal asymptotes, if any, of the following functions by studying their limits at infinity: a) $f(x) = 5^{x} + 2$ b)…

Find the horizontal asymptotes, if any, of the following functions by studying their limits at infinity:

a) $f(x) = 5^{x} + 2$

b) $g(x) = \left(\frac{1}{2}\right)^{x} - 3$

Note: Remember to study the limit both as $x \to +\infty$ and as $x \to -\infty$.

Solve

Vertical asymptotes in exponentials and logarithms

The logarithm is only defined for positive arguments: at the end of the domain, where the argument approaches $0$, a vertical asymptote appears. Something similar happens if the exponent of an exponential blows up at a point.

Graph of the logarithmic function with a vertical asymptote at x equal to 4 and a slow-growth branch towards plus infinity x = 4 ln(x−4): vertical asymptote at the edge of the domain
Practice★☆☆Not started
Given the logarithmic function $f(x) = \ln(x - 4)$, find: a) The domain of the function. b) Study the behavior of the function as $x$ approaches $4$ from the right (…

Given the logarithmic function $f(x) = \ln(x - 4)$, find:

a) The domain of the function.

b) Study the behavior of the function as $x$ approaches $4$ from the right ($x \to 4^+$) and determine whether there is a vertical asymptote.

Solve
Practice★★☆Not started
Given the function $f(x) = e^{1/(x-3)}$, calculate the following one-sided limits: 1. $\lim_{x \to 3^-} f(x)$ 2. $\lim_{x \to 3^+} f(x)$ In light of the results,…

Given the function $f(x) = e^{1/(x-3)}$, calculate the following one-sided limits:

  1. $\lim_{x \to 3^-} f(x)$

  2. $\lim_{x \to 3^+} f(x)$

In light of the results, indicate whether there is a vertical asymptote at $x = 3$ and describe the behaviour of the function on each side of the point.

Solve

The logarithm grows, but very slowly

Unlike exponentials, the logarithm tends to $+\infty$ as $x\to+\infty$, but so slowly that it has no horizontal or vertical asymptote at that end: only a parabolic branch of very gentle growth.

Practice★☆☆Not started
A logistics company estimates that the maintenance cost of its fleet of lorries, in euros, follows the model $C(x) = 1500 + \log(x + 10)$, where $x$ is the number of…

A logistics company estimates that the maintenance cost of its fleet of lorries, in euros, follows the model $C(x) = 1500 + \log(x + 10)$, where $x$ is the number of kilometres driven.

Analyse the infinite branch of the function as the mileage increases indefinitely ($x \to +\infty$). Does the maintenance cost have a maximum limit or does it grow without bound?

Solve
Practice★☆☆Not started
Match each of the following limit expressions with the corresponding graphical feature of a logarithmic function $f(x) = \log_a(x)$ with $a > 1$: 1.…

Match each of the following limit expressions with the corresponding graphical feature of a logarithmic function $f(x) = \log_a(x)$ with $a > 1$:

  1. $\displaystyle \lim_{x \to 0^+} f(x) = -\infty$

  2. $\displaystyle \lim_{x \to +\infty} f(x) = +\infty$

A) The function has a slow-growing parabolic branch.

B) The function has a vertical asymptote at the y-axis.

Solve
Practice★★☆Not started
Analyse the behaviour of the function $g(x) = 2 + \frac{\ln(x)}{x}$ as the independent variable grows indefinitely ($x \to +\infty$). Explain whether the function has…

Analyse the behaviour of the function $g(x) = 2 + \frac{\ln(x)}{x}$ as the independent variable grows indefinitely ($x \to +\infty$).

Explain whether the function has any horizontal asymptote and represent it schematically on a coordinate axis.

Solve

Saturation models: the logistic horizontal asymptote

Many real phenomena level off at a limiting value. The temperature of a cooling body decays exponentially towards room temperature (Newton's law of cooling). Others, such as the users of an app or the spread of a piece of news, combine an exponential with a fraction and level off at a maximum value: this is the pattern of the logistic curve.

Practice★★☆Not started
A market study estimates that the number of subscribers to a new streaming platform, in thousands of people, follows the function…

A market study estimates that the number of subscribers to a new streaming platform, in thousands of people, follows the function $S(t) = \frac{120}{1 + 4 \cdot e^{-0,1t}}$, where $t$ is the time in months since its launch.

Determine the limit of subscribers that the platform will have "in the long term", that is, when $t \to +\infty$. What is this behaviour called from the point of view of the infinite branches of the function?

Solve
Practice★★☆Not started
In a chemistry lab, the temperature of a reaction (in $^\circ C$) is given by the function $T(t) = 20 + 80 \cdot e^{-0,5t}$, where $t$ is the time in minutes. The figure…

In a chemistry lab, the temperature of a reaction (in $^\circ C$) is given by the function $T(t) = 20 + 80 \cdot e^{-0,5t}$, where $t$ is the time in minutes. The figure shows the graph of the function during the first 10 minutes.

Graph of the temperature T(t) as a function of time t during the first 10 minutes, a decreasing curvet (min)T (°C)2468100255075100
  1. a) What is the initial temperature of the reaction?
  1. b) At what temperature will the mixture stabilize if we let a long time pass? Calculate $\lim_{t \to +\infty} T(t)$.
Solve
Practice★★★Not started
The impact of a digital marketing campaign for a new mobile app is measured by the number of daily active users, $U(t)$, in thousands, where $t$ is the time in days…

The impact of a digital marketing campaign for a new mobile app is measured by the number of daily active users, $U(t)$, in thousands, where $t$ is the time in days since launch. The model is given by the following function:

$$U(t) = \frac{120}{2 + 8e^{-0,15t}}$$

The figure shows the graph of $U(t)$ over the first 40 days.

Increasing graph of the active users U(t), in thousands, over the first 40 days, with the points at t = 0 and t = 20 marked 10 20 30 40 20 40 60 80 0 Time t (days) Users U(t) [thousands] U(0) = 12 U(20) ≈ 50

Analyze the long-term behavior of the user community by calculating $\lim_{t \to +\infty} U(t)$ and interpret the meaning of the horizontal asymptote you find. What would happen to the limit if the exponent were positive, that is, if $e^{0,15t}$ appeared instead of $e^{-0,15t}$? Justify your answer.

Solve

Comparing orders of growth: who wins at infinity?

When an exponential, a logarithm and a power of $x$ compete inside the same limit, there is a fixed hierarchy that decides the result without any further calculation.

Practice★★★Not started
In a class debate about rates of growth, a student claims that, since the numerator of the function $g(x) = \frac{x}{e^x}$ tends to infinity as $x \to +\infty$, the…

In a class debate about rates of growth, a student claims that, since the numerator of the function $g(x) = \frac{x}{e^x}$ tends to infinity as $x \to +\infty$, the function $g(x)$ cannot have a finite limit at infinity either.

Prove by calculating $\lim_{x \to +\infty} \frac{x}{e^x}$ whether the student is correct or not, comparing the rate of growth of the exponential function with that of the linear function. Does $g(x)$ have a horizontal asymptote? State its equation.

Solve
Practice★★★Not started
An educational content channel earns a monthly advertising income (in hundreds of euros) given by the function $R(x) = 50 \cdot \ln(x+1) - 0,5x$, where $x$ represents…

An educational content channel earns a monthly advertising income (in hundreds of euros) given by the function $R(x) = 50 \cdot \ln(x+1) - 0,5x$, where $x$ represents the months elapsed since its launch.

  1. a) Calculate $\lim_{x \to +\infty} R(x)$ by comparing the orders of magnitude of logarithmic growth versus linear growth.
  2. b) Is this a good model to represent the channel's long-term income? Justify your answer based on the infinite branch obtained.
R(x) = 50 · ln(x+1) - 0,5x Long term (x → +∞) Time (x months) Income R(x) 0 50 100 150 200 100 200 Maximum (x=99) - 0,5x Remaining R(x) y = 50 · ln(x+1) (Logarithmic Growth) y = 0,5x (Linear Growth) a) Limit Analysis Long-term magnitude: Linear vs Logarithmic lim x→+∞ R(x) = ? b) Long-term model Observe the infinite branch: ¿Es un buen modelo? ? ? Negative income?
Solve

Summary

See all the exercises in this section