DNA Replication
When you scrape your knee playing baseball, the skin cells divide to close the wound. Each new cell needs a complete and exact copy of the DNA. How does the cell copy almost three billion letters without making almost any mistakes? This section explains the molecular machinery behind that copying, using the bacterium as a model because it is the best understood, and then pointing out what changes in a eukaryotic cell. At the end you will come back to this question.
Replication is semiconservative
When DNA from bacteria labeled with $^{15}\text{N}$ is centrifuged after a single division in a medium with $^{14}\text{N}$, no completely heavy or completely light DNA appears, only a single band of intermediate density. How is the original material distributed among the daughter cells?
What does it mean that DNA replication is semi-conservative? Explain it in your own words, indicating how the two daughter DNA molecules are formed.
What does it mean that DNA replication is semi-conservative? Explain it in your own words, indicating how the two daughter DNA molecules are formed.
At what point in the cell cycle is DNA replicated and why is it essential for replication to occur before cell division begins?
At what point in the cell cycle is DNA replicated and why is it essential for replication to occur before cell division begins?
Before the famous Meselson and Stahl experiment, there were three theoretical models to explain DNA replication: semiconservative, conservative, and dispersive. Imagine…
Before the famous Meselson and Stahl experiment, there were three theoretical models to explain DNA replication: semiconservative, conservative, and dispersive. Imagine that you perform this experiment by culturing E. coli bacteria for many generations in a medium with heavy nitrogen ($^{15}\text{N}$) until all their DNA is labelled, and then you transfer them to a medium with light nitrogen ($^{14}\text{N}$).
- a) Deduce what types of DNA molecules (heavy $^{15}\text{N}\text{-}^{15}\text{N}$, hybrid $^{15}\text{N}\text{-}^{14}\text{N}$, or light $^{14}\text{N}\text{-}^{14}\text{N}$) and in what percentages would appear in the density gradient after one and after two generations if replication were:
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Strictly conservative.
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Strictly dispersive.
- b) Reason in a justified manner which of these two alternative models was ruled out already with the analysis of the first-generation DNA and which obligatorily required waiting for the second generation to be refuted.
The replication fork
Notice that the complementarity A↔T and G↔C decides which nucleotide goes into each position. That is the principle behind the copy.
Name the main enzyme that synthesises the new strand of DNA during replication and explain its basic function and in which direction (5'→3' or 3'→5') it adds nucleotides.
Name the main enzyme that synthesises the new strand of DNA during replication and explain its basic function and in which direction (5'→3' or 3'→5') it adds nucleotides.
Name the enzyme that opens the DNA double helix at the replication fork and explain what mechanical problem appears in the molecule ahead of the fork (supercoiling) and…
Name the enzyme that opens the DNA double helix at the replication fork and explain what mechanical problem appears in the molecule ahead of the fork (supercoiling) and what type of enzyme solves it.
Explain the role of the RNA primer at the start of replication and reason why DNA polymerase cannot initiate a new strand from scratch.
Explain the role of the RNA primer at the start of replication and reason why DNA polymerase cannot initiate a new strand from scratch.
Leading strand and lagging strand
If dividing cells are given a brief radioactive pulse, part of the new DNA appears in very long molecules, but another part is isolated in tiny fragments of about a thousand nucleotides. If the fork moves in only one direction, why is one of the two strands made in pieces?
At a replication fork, one of the new strands (A) is synthesized continuously, moving toward the fork, while the other (B) is synthesized in fragments, moving away from…
At a replication fork, one of the new strands (A) is synthesized continuously, moving toward the fork, while the other (B) is synthesized in fragments, moving away from it. Indicate which of the new strands (A or B) is the leading strand and which is the lagging strand, and explain why one is synthesized continuously and the other in Okazaki fragments, referring to the direction in which DNA polymerase operates.
Place the following stages of replication in order and justify the chosen order: joining of fragments by DNA ligase, unwinding of the double helix by helicase, synthesis…
Place the following stages of replication in order and justify the chosen order: joining of fragments by DNA ligase, unwinding of the double helix by helicase, synthesis of nucleotides by DNA polymerase, removal of primers, formation of Okazaki fragments.
Name the enzyme that synthesises the RNA primers during replication and explain why each Okazaki fragment needs its own primer while the leading strand only needs one at…
Name the enzyme that synthesises the RNA primers during replication and explain why each Okazaki fragment needs its own primer while the leading strand only needs one at the start.
Once the RNA primers of the lagging strand have been removed, what are the gaps filled with and which enzyme then seals the chain? Explain why the lagging strand takes…
Once the RNA primers of the lagging strand have been removed, what are the gaps filled with and which enzyme then seals the chain? Explain why the lagging strand takes longer to be completed than the leading strand.
To analyze the synthesis of new DNA strands during replication, a pulse-chase assay is performed in a bacterial culture: cells are exposed to radioactive thymidine…
To analyze the synthesis of new DNA strands during replication, a pulse-chase assay is performed in a bacterial culture: cells are exposed to radioactive thymidine ($[^3\text{H}]\text{-thymidine}$) during an ultrashort pulse of $5$ seconds and then transferred to a medium with an excess of non-radioactive thymidine (chase) for $5$ minutes. Following alkaline lysis and denaturation, the DNA strands are separated by density gradient centrifugation. a) Predict and justify what size pattern of radioactive fragments (small ones of about $1000$-$2000$ nucleotides or high-molecular-weight ones) will be observed at the end of the pulse ($5$ s) and how it will change after the chase ($5$ min). b) If the same assay is performed in a mutant strain with thermally blocked DNA ligase, predict the result after the $5$-minute chase and justify your answer. c) Reason why this experiment refutes the hypothesis that both strands are synthesized continuously.
The fidelity of the copy
Nucleotides arrive as triphosphates (dATP, dGTP, dCTP, dTTP). The energy to form the bond in the chain comes from the breaking of two of their three phosphates, so the cell does not need to supply another energy source for each joining step.
During replication, which nucleotide will be inserted opposite an adenine of the template strand? And opposite a guanine? Explain which property of the DNA structure…
During replication, which nucleotide will be inserted opposite an adenine of the template strand? And opposite a guanine? Explain which property of the DNA structure makes it possible for the copy to be faithful.
The nucleotides incorporated into the new strand arrive as triphosphates (dATP, dGTP, dCTP, dTTP). Explain where the cell obtains the energy needed to form the bonds of…
The nucleotides incorporated into the new strand arrive as triphosphates (dATP, dGTP, dCTP, dTTP). Explain where the cell obtains the energy needed to form the bonds of the growing chain.
Chemical analysis of the DNA of a species shows that $30\ \%$ of its bases are adenine. State, with reasoning, the percentages of thymine, guanine and cytosine, and…
Chemical analysis of the DNA of a species shows that $30\ \%$ of its bases are adenine. State, with reasoning, the percentages of thymine, guanine and cytosine, and explain what consequence this complementarity relationship has for DNA replication.
In a laboratory, a mutant strain of Escherichia coli* is obtained that has an alteration in DNA polymerase III: its polymerization rate in the $5'\to 3'$ direction…
In a laboratory, a mutant strain of Escherichia coli is obtained that has an alteration in DNA polymerase III: its polymerization rate in the $5'\to 3'$ direction remains intact, but it has completely lost its $3'\to 5'$ exonuclease activity. a) Predict and justify what effect this mutation will have on copying fidelity and on the spontaneous mutation rate per cell division. b) If this strain is cultured in the presence of 2-aminopurine (a base analog that can mispair with cytosine), reason whether the mutation fixation rate will be higher, lower, or equal to that of the wild-type strain. c) Justify at the molecular level why the proofreading activity must remove the mismatched nucleotide in the $3'\to 5'$ direction before continuing with the addition of the next nucleotide.
DNA replication achieves extraordinary fidelity thanks to three successive barriers: the pairing specificity of DNA polymerase (an error of $1$ in every $10^5$…
DNA replication achieves extraordinary fidelity thanks to three successive barriers: the pairing specificity of DNA polymerase (an error of $1$ in every $10^5$ nucleotides), $3'\to 5'$ exonuclease proofreading (final error of $1$ in every $10^7$), and the post-replicative mismatch repair system (final error of $1$ in every $10^9$). a) A cell line from hereditary colorectal cancer (Lynch syndrome) exhibits a mutation rate $100$ times higher than normal, even though its DNA polymerases have intact polymerase and exonuclease activities. Deduce and justify what mechanism is failing in these cells. b) To correct an error after the passage of the fork, the repair system must distinguish the template (old) strand from the newly synthesized one. Reason how the cellular machinery discriminates between both strands to avoid replacing the base on the original strand. c) If a mismatch error (for example, a guanine incorrectly paired with a thymine) escapes all correction systems and the cell goes through two complete rounds of cell division, deduce what proportion of the final daughter DNA molecules will carry the permanently fixed mutation.
Special features of eukaryotic replication
The DNA of a human cell is almost two meters long and its polymerases move much more slowly than those of a bacterium, yet the cell replicates its whole genome in about eight hours. What strategy allows linear chromosomes to duplicate so quickly without degrading at the ends?
| Bacterium | Human cell | |
|---|---|---|
| Shape of the DNA | circular | linear |
| Origins of replication | one | hundreds or thousands |
| Ends (telomeres) | none | yes, they shorten |
After replication, each eukaryotic chromosome consists of two sister chromatids with identical DNA sequences, joined at the centromere. They separate during mitosis (in anaphase), and each daughter cell receives one.
Return to the beginning: the cell copies almost three billion letters with few errors because each base pairs only with its complement, the polymerase corrects its own mistakes, and there are repair systems that act afterward. And it does so quickly because it opens many origins of replication at the same time.
How many replication forks are formed from a single origin of replication and in which direction do they advance? Explain the advantage of eukaryotic chromosomes having…
How many replication forks are formed from a single origin of replication and in which direction do they advance? Explain the advantage of eukaryotic chromosomes having many origins of replication.
State two differences between the replication of a bacterial chromosome and that of a human chromosome, considering the shape of the DNA and the number of origins of…
State two differences between the replication of a bacterial chromosome and that of a human chromosome, considering the shape of the DNA and the number of origins of replication.
The DNA polymerase of E. coli adds about $1000$ nucleotides per second at each fork. Calculate how long it will take, at a minimum, to replicate its circular chromosome…
The DNA polymerase of E. coli adds about $1000$ nucleotides per second at each fork. Calculate how long it will take, at a minimum, to replicate its circular chromosome of $4.6$ million base pairs if it is replicated from a single origin bidirectionally, and comment on the result by comparing it with the generation time of the bacterium (about $20$ minutes).
After replication, each chromosome is made up of two sister chromatids. Explain what relationship the DNA sequences of both chromatids bear to each other, why they…
After replication, each chromosome is made up of two sister chromatids. Explain what relationship the DNA sequences of both chromatids bear to each other, why they remain joined for a time and at what moment of cell division they separate.
Two human cell cultures are compared in the laboratory: normal dermal fibroblasts and cancer cells from a lung carcinoma cell line. Average telomere length is monitored…
Two human cell cultures are compared in the laboratory: normal dermal fibroblasts and cancer cells from a lung carcinoma cell line. Average telomere length is monitored over the course of $60$ population doublings. The fibroblasts enter replicative senescence at doubling $40$ with progressive telomeric shortening, whereas the cancer cells proliferate continuously and maintain their telomere length intact. a) Justify at the molecular level why conventional replication machinery cannot complete the $5'$ end of the lagging strand after the removal of the last RNA primer (the "end replication problem"). b) A therapy is designed that introduces into the tumor cells a synthetic oligonucleotide complementary to the template RNA of human telomerase ribonucleoprotein (hTR). Predict and justify what effect this treatment will have on telomerase activity, telomere length, and the long-term viability of the tumor cells.
Eukaryotic DNA polymerase adds about $50$ nucleotides per second and an average human chromosome can have $150$ million base pairs. a) Calculate how long it would take…
Eukaryotic DNA polymerase adds about $50$ nucleotides per second and an average human chromosome can have $150$ million base pairs. a) Calculate how long it would take to replicate that chromosome if there were only one origin of replication at its center. b) Explain how the eukaryotic cell solves this speed problem. c) Reason what advantages and what risks the strategy of using many origins of replication has.
Going further: ligase and labeling pulses
Two experimental ideas help with reasoning. First: if newly made DNA is labeled with a short pulse of radioactive thymidine, the first things to be labeled are small fragments of $1000$-$2000$ nucleotides (Okazaki); with longer pulses, that radioactivity moves to large fragments because ligase joins them. This proves that synthesis is semidiscontinuous: continuous in one strand and discontinuous in the other.
Second: in the leading strand, ligase also acts, because the strand is started at many origins and the stretches from each origin must be joined. If ligase fails, both strands are left with breaks, not just the lagging strand.
A thermosensitive yeast mutant for the gene encoding DNA ligase I is isolated. At $25\text{ }^\circ\text{C}$ the yeast divides normally, but when cultured at…
A thermosensitive yeast mutant for the gene encoding DNA ligase I is isolated. At $25\text{ }^\circ\text{C}$ the yeast divides normally, but when cultured at $37\text{ }^\circ\text{C}$ the enzyme is inactivated and the cell arrests its cell cycle before entering mitosis. a) A student claims: "At $37\text{ }^\circ\text{C}$, only the lagging strand will have breaks because Okazaki fragments are formed on it; the leading strand will be a single, perfectly continuous chain from one end of the chromosome to the other." Refute this statement, taking into account the presence of multiple replication origins (replicons) per linear chromosome. b) Specify the exact type of chemical bond that cannot be sealed in the absence of ligase (indicating the terminal $3'$ and $5'$ chemical groups) and reason why DNA polymerases cannot carry out this sealing reaction on their own. c) Justify why the presence of unsealed breaks in the double helix activates a cell cycle checkpoint, preventing mitosis.
To verify whether replication is continuous or discontinuous, researchers carry out pulse labelling with tritiated thymidine for $5$, $15$, and $60$ seconds in bacteria.…
To verify whether replication is continuous or discontinuous, researchers carry out pulse labelling with tritiated thymidine for $5$, $15$, and $60$ seconds in bacteria. After denaturing the DNA, they analyse the size of the radioactive strands by centrifugation. At $5$ seconds, they only detect short fragments ($1000$–$2000$ nucleotides), but as the labelling time increases, the radioactivity progressively shifts toward high-molecular-weight fragments. a) Reason why this result supports that replication occurs in a semi-discontinuous manner rather than continuously on both strands. b) Predict and justify what result would have been obtained in the three measurements if both strands were synthesised continuously from the replication origin. c) Explain the unavoidable molecular cause (structural and enzymatic) why the cell is forced to synthesise one of the two strands based on small fragments.