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Secondary 4 · Biology
Molecular genetics · From DNA to protein

Gene Expression

Before you start, make sure you know: Gene Expression (Secondary Year 2 (first cycle))
Before you start, make sure you know: DNA and RNA (Secondary Year 2 (first cycle))

The cells of your skin, your muscles, and your liver all have the same DNA, but each one makes its own proteins. Having a gene is not enough: it has to be used. This use, called gene expression, happens in two stages, transcription and translation, and forms what is known as the central dogma of biology: DNA → RNA → protein. A question for this whole section: if DNA never leaves the nucleus, how do its instructions get to the ribosomes, where proteins are made?

Transcription: from gene to messenger RNA

In eukaryotic cells, DNA stays inside the nucleus, but proteins are made in the cytoplasm. The cell solves this problem by making a working copy of the gene: messenger RNA.

Transcription in a eukaryotic cell: inside the nucleus, RNA polymerase opens the DNA double helix, travels along the template strand in the 3'→5' direction, and synthesizes a complementary mRNA in the 5'→3' direction; the 3' end stays attached to the polymerase and the 5' end separates first. The finished mRNA leaves through a nuclear pore into the cytoplasm, 5' end first, and binds to a ribosome. nucleus cytoplasm 3' 5' 5' 3' coding strand DNA: template strand (read 3'→5') promoter RNA polymerase moves mRNA being synthesized 5' 3' 3' finished mRNA exits to the cytoplasm mRNA 5' ribosome nuclear pore nuclear membrane

Notice how the mRNA grows: the 3' end is the one that gets longer, because that is where the polymerase adds nucleotides; the 5' end separates from the DNA first and is the one that goes out ahead toward the cytoplasm.

A gene is a segment of DNA that, when expressed, gives rise to a functional product: a protein (via mRNA) or a functional RNA, such as tRNA or rRNA. Of the two strands of the gene, only one serves as the template. The other, the coding strand, has the same sequence as the mRNA, with T in place of U.

Two differences between DNA and RNA to remember: RNA has ribose (DNA has deoxyribose) and uracil instead of thymine; also, RNA is usually single-stranded.

Practice★☆☆Not started
Which enzyme catalyses the transcription of DNA into RNA? State on which of the two strands of the gene it acts and in which direction it synthesises the RNA molecule.

Which enzyme catalyses the transcription of DNA into RNA? State on which of the two strands of the gene it acts and in which direction it synthesises the RNA molecule.

Solve
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State two structural differences between DNA and RNA, and explain which bases pair up during transcription when the template strand shows an adenine or a thymine.

State two structural differences between DNA and RNA, and explain which bases pair up during transcription when the template strand shows an adenine or a thymine.

Solve
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From the DNA template strand 3'-TACGGAACT-5', obtain the resulting mRNA sequence indicating its polarity, and state the maximum number of amino acids this fragment can…

From the DNA template strand 3'-TACGGAACT-5', obtain the resulting mRNA sequence indicating its polarity, and state the maximum number of amino acids this fragment can encode.

Solve

The genetic code

The mRNA has an alphabet of only four letters (A, U, G, C), and proteins use 20 amino acids. How do you translate a four-letter text into a twenty-letter one?

With 4 letters, pairs of bases would give only $4^2 = 16$ combinations, not enough for 20 amino acids; with triplets there are more than enough. That is why the codon has three nucleotides.

The AUG codon codes for methionine and is the start codon. Stop codons do not code for any amino acid: when the ribosome reaches one, translation ends and the protein is released.

Diagram of the genetic code: the AUG codon of the mRNA, made of the bases A, U, and G, codes for the amino acid methionine and marks the start; there are 64 codons for 20 amino acids, so the code is degenerate. A U G AUG codon (start) methionine 64 codons 20 amino acids → degenerate code

Here is the complete table of the genetic code (standard code). To read it, find the first base of the codon in the left column, the second in the top row, and the third inside the cell. The codons are written in mRNA, in the 5'→3' direction.

1st base ↓ / 2nd base → U C A G
U UUU, UUC: Phe · UUA, UUG: Leu UCU, UCC, UCA, UCG: Ser UAU, UAC: Tyr · UAA, UAG: stop UGU, UGC: Cys · UGA: stop · UGG: Trp
C CUU, CUC, CUA, CUG: Leu CCU, CCC, CCA, CCG: Pro CAU, CAC: His · CAA, CAG: Gln CGU, CGC, CGA, CGG: Arg
A AUU, AUC, AUA: Ile · AUG: Met (start) ACU, ACC, ACA, ACG: Thr AAU, AAC: Asn · AAA, AAG: Lys AGU, AGC: Ser · AGA, AGG: Arg
G GUU, GUC, GUA, GUG: Val GCU, GCC, GCA, GCG: Ala GAU, GAC: Asp · GAA, GAG: Glu GGU, GGC, GGA, GGG: Gly

Abbreviations: Phe phenylalanine, Leu leucine, Ser serine, Tyr tyrosine, Cys cysteine, Trp tryptophan, Pro proline, His histidine, Gln glutamine, Arg arginine, Ile isoleucine, Met methionine, Thr threonine, Asn asparagine, Lys lysine, Val valine, Ala alanine, Asp aspartic acid, Glu glutamic acid, Gly glycine.

Practice★☆☆Not started
What is a codon? State how many nucleotides make it up, how many distinct codons exist, and how many different amino acids they encode in total.

What is a codon? State how many nucleotides make it up, how many distinct codons exist, and how many different amino acids they encode in total.

Solve
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Look at the diagram of the flow of genetic information. State which molecules are labelled A, B and C, which processes occur at arrows 1 and 2, and what the area…

Look at the diagram of the flow of genetic information. State which molecules are labelled A, B and C, which processes occur at arrows 1 and 2, and what the area surrounded by the dashed line represents.

A 1 B 2 C
Solve
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Consider the following fragment of the coding sequence of an mRNA that is translated into a cytoplasmic protein: $5'\text{--- AUG - UCU - UCC - UCA - UCG --- } 3'$…

Consider the following fragment of the coding sequence of an mRNA that is translated into a cytoplasmic protein:

$5'\text{--- AUG - UCU - UCC - UCA - UCG --- } 3'$

(Note: the four codons following the AUG start codon all code for the amino acid serine).

  1. a) Based on this specific case, justify why the genetic code is degenerate and demonstrate that this property is not equivalent to saying that the code is "ambiguous".
  2. b) Suppose that two independent point mutations are introduced: Mutant 1 changes the second codon from UCU to UCC; Mutant 2 changes the third codon from UCC to UAC (which codes for tyrosine). Compare the impact of both mutations on the amino acid sequence of the protein and classify each mutation according to its functional effect.
  3. c) Reason what adaptive advantage is conferred by the fact that the degeneracy of the genetic code is almost always concentrated at the third base of each triplet (wobble hypothesis) rather than at the first or second, in the face of spontaneous point mutations.
Solve
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In gene therapy for Leber's hereditary optic neuropathy, researchers are investigating transferring a wild-type copy of a mitochondrial gene to the cell nucleus…

In gene therapy for Leber's hereditary optic neuropathy, researchers are investigating transferring a wild-type copy of a mitochondrial gene to the cell nucleus (allotopic expression) so that the protein is translated in the cytosol and imported into the mitochondrion. However, in the human mitochondrial genetic code, the triplet UGA codes for tryptophan, whereas in the standard nuclear code it acts as a termination codon.

  1. a) Predict what would happen if the mitochondrial gene is transferred to the nucleus without modifying its sequence and is transcribed and translated on cytoplasmic ribosomes. What impact would this have on the length and functionality of the resulting polypeptide?
  2. b) Design the site-directed mutagenesis strategy that the biotechnology team must apply to the coding sequence of the transgene before integrating it into the nucleus to ensure the synthesis of the native protein.
  3. c) Justify why the mitochondrial genome (with only $37$ genes and a very small number of tRNAs) could 'afford' drift and changes in codon assignments throughout evolution, whereas in the nuclear genome this type of alteration is lethal to the cell.
Solve

Translation: from mRNA to protein

Three types of RNA take part: mRNA carries the information from the gene; tRNA carries each amino acid and places it according to its anticodon; rRNA is part of the ribosome, together with proteins.

Animation of translation: a tRNA brings an amino acid from the right to the mRNA codon, the amino acid is joined to the chain, the tRNA leaves, the mRNA advances one codon, and the polypeptide grows. ribosome mRNA read codon by codon chain of amino acids = protein

The ribosome does not read blindly: it starts at AUG, and from there every three nucleotides form a codon. If it started one nucleotide earlier or later, all the codons would be grouped differently and a different protein would be made.

Practice★☆☆Not started
Define transcription and translation and state where in the eukaryotic cell each of these processes takes place.

Define transcription and translation and state where in the eukaryotic cell each of these processes takes place.

Solve
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What is the start codon of translation and which amino acid does it encode? Explain what function the stop codons fulfil and what happens when the ribosome reaches one…

What is the start codon of translation and which amino acid does it encode? Explain what function the stop codons fulfil and what happens when the ribosome reaches one of them.

Solve
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Briefly describe what the ribosome does during translation: how it reads the mRNA, how the amino acids arrive and what type of bond is formed between them.

Briefly describe what the ribosome does during translation: how it reads the mRNA, how the amino acids arrive and what type of bond is formed between them.

Solve
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Based on the following genetic code table: | Codon | Amino acid | | :---: | :---: | | AUG | Methionine (Met) | | CCU | Proline (Pro) | | GCU | Alanine (Ala) | | UAA |…

Based on the following genetic code table:

Codon Amino acid
AUG Methionine (Met)
CCU Proline (Pro)
GCU Alanine (Ala)
UAA Stop (Fin)
UAU Tyrosine (Tyr)
  1. a) Translate the following $\text{mRNA}$: $5'\text{-AUGGCUUAA-}3'$, and indicate the resulting amino acid sequence.
  2. b) Explain what role the first and the last codon of the fragment play.
Solve
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During translation, the mRNA is read in consecutive codons, with no separators between them. Explain what the reading frame is and reason what would happen to the…

During translation, the mRNA is read in consecutive codons, with no separators between them. Explain what the reading frame is and reason what would happen to the synthesised protein if the ribosome started reading one nucleotide before the correct position.

Solve

Following a tRNA through the ribosome

A charged tRNA brings an amino acid to the A site; the P site holds the tRNA attached to the growing peptide; the E site lets the discharged tRNA exit. The initiator tRNA is initially placed in P. The ribosome's peptidyl transferase activity catalyzes the peptide bond.

Ribosome reading the mRNA from 5′ to 3′, with a tRNA at each site: aminoacyl-tRNA entering at A, peptidyl-tRNA with the growing peptide at P, and discharged tRNA leaving through E. ribosome movement (reading 5′ → 3′) enters aminoacyl-tRNA tRNA leaves discharged growing peptide C 5′ 3′ mRNA N E P A

The tRNA has a cloverleaf shape, with an anticodon in one loop and the amino acid attached at its 3' end. Enzymes called aminoacyl-tRNA synthetases attach each amino acid to the tRNA that matches it; this is how the cell makes sure the amino acid is the correct one.

Practice★★☆Not started
Differentiate the functions of mRNA, tRNA and rRNA in protein synthesis, indicating what each type of RNA contributes to the process.

Differentiate the functions of mRNA, tRNA and rRNA in protein synthesis, indicating what each type of RNA contributes to the process.

Solve
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Describe the characteristic structure of a tRNA (clover-leaf shape, anticodon and 3' end) and explain how the cell manages to get each tRNA loaded with its correct amino…

Describe the characteristic structure of a tRNA (clover-leaf shape, anticodon and 3' end) and explain how the cell manages to get each tRNA loaded with its correct amino acid, mentioning the enzymes responsible.

Solve
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The following diagram represents a functional ribosome during the elongation phase of translation: a) Justify and deduce the polarity ($5'$ and $3'$ ends) of the mRNA…

The following diagram represents a functional ribosome during the elongation phase of translation:

mRNA AUG GCU UAA UAC ? stop codon
  1. a) Justify and deduce the polarity ($5'$ and $3'$ ends) of the mRNA strand and the direction in which the ribosome will move along it.
  2. b) Write the sequence of the anticodon of the tRNA marked with a question mark (?), mandatory specifying its $5'\to 3'$ polarity, and reason which amino acid it carries knowing that the GCU codon codes for alanine.
  3. c) In a mutant strain, a suppressor tRNA is produced that is capable of recognizing the UAA codon by inserting the amino acid tyrosine. Predict what will happen to translation and to the length of the resulting protein when the ribosome reaches the position marked with the stop codon compared to the wild-type cell.
Solve

Wobble: do we need 61 tRNAs?

There are 61 codons with meaning. If each one needed its own tRNA, cells would have to make 61 types. However, most eukaryotic cells produce only between 30 and 45. How do they manage?

Some wobble rules: a G in the anticodon can pair with C or U of the codon; a U in the anticodon, with A or G; and inosine (I, a modified base) with U, C, or A.

Practice★★★Not started
To translate the $61$ sense codons in the standard genetic code, most eukaryotic cells only need to synthesize between $30$ and $45$ different tRNA species, instead of…

To translate the $61$ sense codons in the standard genetic code, most eukaryotic cells only need to synthesize between $30$ and $45$ different tRNA species, instead of $61$.

  1. a) Explain the thermodynamic and structural basis of Crick's 'wobble hypothesis' and justify why this spatial flexibility is restricted to the third nucleotide of the codon ($3'$ end) and the first of the anticodon ($5'$ end).
  2. b) The amino acid valine is coded by four codons: $5'\text{-GUU-}3'$, $5'\text{-GUC-}3'$, $5'\text{-GUA-}3'$, and $5'\text{-GUG-}3'$. If a specific tRNA has inosine (I) at the $5'$ end of its anticodon (knowing that inosine can pair with U, C, and A), determine how many and which of these codons this single tRNA will be able to read, writing the sequence of said anticodon in the $5'\to 3'$ direction.
  3. c) Reason the adaptive advantage for the organism of having the degeneracy of the genetic code and wobble concentrated at the third position of the codon, compared to them occurring at the first or second base when point mutations occur.
Solve

mRNA processing in eukaryotes

If you measure the RNA just transcribed in the nucleus and compare it with the mRNA that reaches the ribosome, the latter is usually much shorter. Where did the missing pieces go?

Diagram of splicing in eukaryotes: the primary mRNA, with three exons and interspersed introns, loses the introns and leaves a mature mRNA made only of the joined exons. Exon 1 Intron 1 Exon 2 Intron 2 Exon 3 Primary mRNA: exons (color) + introns (gray) splicing Exon 1 Exon 2 Exon 3 Mature mRNA: only exons joined

How introns are "seen": hybridization

Since the mRNA is complementary to the template strand, the two can be hybridized in the laboratory: if they are mixed under suitable conditions, the bases pair (A with U, T with A, G with C, C with G) and form a DNA-RNA hybrid, a heteroduplex.

Each exon of the gene finds its partner in the mature mRNA and pairs with it. The introns, on the other hand, are no longer in the mature mRNA: they have nothing to pair with and remain as loops of single-stranded DNA sticking out of the hybrid. Under the electron microscope you see a stretch of double strand (DNA-RNA) interrupted by loops: there is at most one loop per intron, and each loop is made only of DNA (from the template strand), never of RNA. If the gene had no introns, the hybrid would be a continuous duplex, with no loops.

Practice★☆☆Not started
Define what a gene is from the point of view of gene expression and state which two types of functional products a gene can generate when it is expressed.

Define what a gene is from the point of view of gene expression and state which two types of functional products a gene can generate when it is expressed.

Solve
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Order the following stages of gene expression in a eukaryotic cell and justify the chosen order: binding of the mRNA to the ribosome, mRNA processing, translation in the…

Order the following stages of gene expression in a eukaryotic cell and justify the chosen order: binding of the mRNA to the ribosome, mRNA processing, translation in the cytosol, exit of the mRNA from the nucleus, transcription in the nucleus.

Solve
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A protein is made up of $300$ amino acids. a) Calculate how many nucleotides the mature mRNA that encodes it has, at a minimum, including the stop codon. b) Calculate…

A protein is made up of $300$ amino acids. a) Calculate how many nucleotides the mature mRNA that encodes it has, at a minimum, including the stop codon. b) Calculate how many base pairs the gene would occupy in an organism without introns. c) Reason why in eukaryotic organisms the gene is usually much longer than the corresponding mature mRNA.

Solve
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In the human genome, the fibronectin gene contains numerous exons and introns. In fibroblasts, it gives rise to an insoluble protein isoform that forms part of the…

In the human genome, the fibronectin gene contains numerous exons and introns. In fibroblasts, it gives rise to an insoluble protein isoform that forms part of the extracellular matrix, whereas in hepatocytes it originates a soluble isoform that circulates in the blood plasma.

  1. a) Justify the molecular mechanism by which a single genomic DNA sequence can give rise to these two proteins with such different functions and locations.
  2. b) A patient presents a point mutation consisting of a transition (G to A) at the splicing acceptor site of intron 4 of this gene. Predict two possible alterations in the structure of the resulting mature mRNA and their consequences for the synthesized protein.
  3. c) If we clone this intact human gene (with all its introns and exons) into a plasmid and introduce it into Escherichia coli, reason whether the bacterium will synthesize functional human fibronectin.
Solve
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A human gene of $24\,000$ base pairs (bp) consisting of $8$ exons and $7$ introns is studied. After being completely processed, its mature mRNA in muscle cells is $1200$…

A human gene of $24\,000$ base pairs (bp) consisting of $8$ exons and $7$ introns is studied. After being completely processed, its mature mRNA in muscle cells is $1200$ nucleotides long (including the UTR regions and the poly-A tail).

  1. a) If the template strand of genomic DNA is hybridized in the laboratory with said mature muscle mRNA and the resulting heteroduplex is observed under an electron microscope, predict what morphology it will present and how many single-stranded loops will be observed at most. Justify which nucleic acid each loop will be made of.
  2. b) A student claims that, having $1200$ nucleotides, the resulting protein will be exactly $400$ amino acids long. Refute this statement with reasoning, providing at least two arguments of a molecular nature.
  3. c) In nervous tissue, a mature mRNA originating from the same gene but with a size of $1500$ nucleotides is isolated. Reason what phenomenon has occurred and predict whether the neuronal protein will necessarily be longer than the muscular one, justifying your answer.
Solve

Gene expression in bacteria and in eukaryotes

Comparison of gene expression: in the bacterium, which has no nucleus, ribosomes translate the mRNA while RNA polymerase is still transcribing it; in the eukaryotic cell, the pre-mRNA is transcribed and processed by splicing in the nucleus, leaves through a nuclear pore, and is translated later in the cytoplasm. Bacterium: no nucleus DNA RNA polymerase movement ribosomes mRNA 5' polypeptide cytoplasm Coupled: ribosomes translate the mRNA while RNA polymerase is still transcribing it. Eukaryote: with nucleus nucleus pre-mRNA introns splicing mature mRNA nuclear envelope nuclear pore cytoplasm ribosomes 5' 3' polypeptides Separated: transcription and processing in the nucleus; translation happens later, in the cytoplasm.
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Streptomycin is a bactericidal antibiotic that binds to the $30\text{S}$ subunit of the prokaryotic ribosome ($70\text{S}$), causing mRNA misreading and inhibiting…

Streptomycin is a bactericidal antibiotic that binds to the $30\text{S}$ subunit of the prokaryotic ribosome ($70\text{S}$), causing mRNA misreading and inhibiting protein synthesis. Although it is considered selective against eukaryotic cytoplasmic ribosomes ($80\text{S}$), patients undergoing intensive treatments often experience nephrotoxicity and ototoxicity associated with cellular energy dysfunction.

  1. a) Based on the endosymbiotic theory, justify why this drug can damage human cells and cause an ATP deficit despite the described target selectivity.
  2. b) When analyzing a streptomycin-resistant bacterial strain, it is verified that it does not degrade the drug nor does it possess active efflux pumps, but it carries a mutation in the bacterial chromosome gene that encodes the $16\text{S}$ rRNA. Explain how this mutation confers resistance without completely impairing ribosome function.
  3. c) In a cellular experiment, cycloheximide (an $80\text{S}$ ribosome inhibitor) and chloramphenicol (a $70\text{S}$ ribosome inhibitor) are used. Predict what will happen to the assembly of the multienzyme complexes of the mitochondrial electron transport chain (whose subunits have a dual genetic origin) in the presence of each of these compounds separately.
Solve
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When observing gene expression in bacteria (Escherichia coli*) by electron microscopy, 'Christmas tree' structures can be distinguished where multiple ribosomes…

When observing gene expression in bacteria (Escherichia coli) by electron microscopy, 'Christmas tree' structures can be distinguished where multiple ribosomes translate mRNA while it is still being synthesized by RNA polymerase coupled to genomic DNA. In contrast, this is never observed in a human cell.

  1. a) Predict what immediate consequence the addition of rifampicin (an inhibitor that blocks RNA polymerase initiation but not ribosome activity) will have on bacterial protein synthesis, and compare this effect with what would occur in the short term in the cytoplasm of a eukaryotic cell.
  2. b) Reason why bacterial transcription-translation coupling is mechanically incompatible with the presence of introns and with the splicing mechanism typical of eukaryotes.
  3. c) The gene regulation mechanism by 'attenuation' in the bacterial tryptophan operon depends on the ribosome's rate of progress through a leader sequence determining the formation of termination hairpins in the nascent RNA. Justify in a reasoned manner why this regulatory system is unfeasible in eukaryotic cells.
Solve

Go back to the beginning: DNA does not leave the nucleus, but its information does. It is copied into an mRNA that passes through a nuclear pore and reaches the ribosomes, where it is translated into protein.

Summary

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