Indeterminate forms
You already know the individual tools: factorising, the conjugate, infinitesimals, the number $e$. This section organises them into a closed list of indeterminate forms and trains the cases where two techniques are combined: roots of different index, parameters that must give a specific result, and exponents that hide a $1^\infty$ with variables.
The complete list of indeterminate forms
When you substitute $x=a$ (or $x\to\infty$) into a limit, there is only a closed set of results that do not let you conclude anything without first transforming the expression.
Observe the following graph of the function $f(x)$ and determine, intuitively, the value of the indicated limits. If any limit does not exist or is infinite, state so…
Observe the following graph of the function $f(x)$ and determine, intuitively, the value of the indicated limits. If any limit does not exist or is infinite, state so clearly.
- a) $\lim_{x \to -2} f(x)$
- b) $\lim_{x \to 0} f(x)$
- c) $\lim_{x \to 3} f(x)$
- d) $\lim_{x \to +\infty} f(x)$
$\dfrac{\infty}{\infty}$: comparing degrees and the hierarchy
When the numerator and denominator both tend to infinity, the result depends on which one "wins": compare degrees for polynomials, or use the hierarchy of infinities if exponentials, logarithms or factorials are mixed in.
Resolve the indeterminate form $\left[\frac{\infty}{\infty}\right]$ in the following limits of rational functions by comparing the degrees of the numerator and…
Resolve the indeterminate form $\left[\frac{\infty}{\infty}\right]$ in the following limits of rational functions by comparing the degrees of the numerator and denominator:
- a) $\lim_{x \to +\infty} \frac{5x^2 - 3x + 2}{2x^2 + 1}$
- b) $\lim_{x \to +\infty} \frac{x + 5}{x^2 - 3}$
- c) $\lim_{x \to +\infty} \frac{x^3 - 1}{x^2 + 10x}$
Determine the value of the limit at infinity by analysing the degree of the dominant terms in the numerator and the denominator. Take special care with the powers inside…
Determine the value of the limit at infinity by analysing the degree of the dominant terms in the numerator and the denominator. Take special care with the powers inside the roots:
$$\lim_{x \to +\infty} \frac{\sqrt{9x^2 + 2x - 1} + 2x}{\sqrt[3]{x^3 + 5x^2}}$$Use comparison of orders of infinity to solve the following limits without performing lengthy calculations. Justify your answer by indicating which function "dominates"…
Use comparison of orders of infinity to solve the following limits without performing lengthy calculations. Justify your answer by indicating which function "dominates" the other:
- a) $\lim_{x \to +\infty} \frac{e^x + x^5}{100x^6 - \ln(x)}$
- b) $\lim_{x \to +\infty} \frac{\sqrt{x^7 + 1}}{x^3 \cdot \ln(x)}$
$\infty-\infty$ with roots of different index: the double conjugate
If the subtraction that gives $\infty-\infty$ mixes a square root and a cube root (or any pair of different indices), a single conjugate is not enough: you have to apply the technique twice, once for each type of root.
Solve the following limit using the double conjugate technique to resolve the $\frac{0}{0}$ indeterminate form: $$\lim_{x \to 0} \frac{\sqrt{1+x} -…
Solve the following limit using the double conjugate technique to resolve the $\frac{0}{0}$ indeterminate form:
$$\lim_{x \to 0} \frac{\sqrt{1+x} - \sqrt{1-x}}{\sqrt{4+x} - 2}$$Calculate the value of the following expression which presents an indeterminate form of the type $\infty - \infty$ with roots of different orders: $$\lim_{x \to +\infty}…
Calculate the value of the following expression which presents an indeterminate form of the type $\infty - \infty$ with roots of different orders:
$$\lim_{x \to +\infty} \left[ \sqrt{x^2 + 4x} - \sqrt[3]{x^3 - 6x^2} \right]$$Resolve the following indeterminate form $\infty - \infty$. To do so, perform the preliminary algebraic operation and simplify the resulting expression: $$\lim_{x \to 1}…
Resolve the following indeterminate form $\infty - \infty$. To do so, perform the preliminary algebraic operation and simplify the resulting expression:
$$\lim_{x \to 1} \left( \frac{6}{x^2 - 1} - \frac{3}{x - 1} \right)$$$1^\infty$ with parameters
When the base and the exponent of a $1^\infty$ depend on a parameter, you first identify the indeterminate form as usual, and then use the formula for the number $e$, keeping the parameter inside the calculation of $L$.
In the development of a new social network, the number of active users (in millions) follows the function $U(t) = \left(\frac{2t+3}{2t-1}\right)^{t+1}$, where $t$ is the…
In the development of a new social network, the number of active users (in millions) follows the function $U(t) = \left(\frac{2t+3}{2t-1}\right)^{t+1}$, where $t$ is the time in months since its launch (with $t>\frac{1}{2}$). Calculate the value the number of users approaches as time grows indefinitely ($t \to +\infty$).
Calculate the value of the following exponential limit which leads to an indeterminate form of the type $1^\infty$. Express the result in terms of the number $e$:…
Calculate the value of the following exponential limit which leads to an indeterminate form of the type $1^\infty$. Express the result in terms of the number $e$:
$$\lim_{x \to 0} (1 + \sin(x))^{\frac{2}{x}}$$Calculate the value of the following limit leading to an indeterminate form of the type $[1^\infty]$ using the shortcut formula for the number $e$: $$\lim_{x \to…
Calculate the value of the following limit leading to an indeterminate form of the type $[1^\infty]$ using the shortcut formula for the number $e$:
$$\lim_{x \to +\infty} \left( 1 + \frac{1}{x} \right)^{3x}$$Parameters so that a limit is finite and non-zero
The most complete exercise in this list: finding $a$ and $b$ so that an indeterminate limit gives a result that is both finite and non-zero. Normally you need to impose two conditions.
Determine the values of the real parameters $a$ and $b$ so that the following equality holds: $$\lim_{x \to 2} \frac{\sqrt{x^2 + ax + b} - 2}{x^2 - 5x + 6} =…
Determine the values of the real parameters $a$ and $b$ so that the following equality holds:
$$\lim_{x \to 2} \frac{\sqrt{x^2 + ax + b} - 2}{x^2 - 5x + 6} = -\frac{1}{2}$$That is, the limit must be a finite real number and equal $-\dfrac{1}{2}$. Once you have found $a$ and $b$, check that the limit really equals $-\dfrac{1}{2}$.
Find the values of the real parameters $a$ and $b$ so that the following limit is finite and equals $4$: $$\lim_{x \to +\infty} \sqrt{x^2 + ax + 1} - \sqrt{x^2 + bx}$$
Find the values of the real parameters $a$ and $b$ so that the following limit is finite and equals $4$:
$$\lim_{x \to +\infty} \sqrt{x^2 + ax + 1} - \sqrt{x^2 + bx}$$