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5th Year HL · Mathematics
Trigonometry · Trigonometry

Ratios of the Difference of Two Angles

The difference of two angles has its own formulae, very similar to those for the sum but with the signs swapped. With them we can calculate exact values such as $\sin(15^\circ)$, prove identities that appear year after year on Paper 2 of the Leaving Cert (such as $\cos(180^\circ-\alpha)=-\cos\alpha$) and solve problems involving two signals, two rays of light or two angles of observation. These formulae are in the Formulae and Tables booklet, but you need to know how to use them. Here is a question to hold on to: a surveyor at the Cliffs of Moher sees the base and the top of the O'Brien's Tower; what angle does the tower alone span?

The difference formulae: sine, cosine and tangent

They are obtained from the sum formulae by replacing $\beta$ with $-\beta$ and using the facts that $\sin(-\beta)=-\sin\beta$ and $\cos(-\beta)=\cos\beta$ (sine is an odd function, cosine is even). You will find these formulae in the Formulae and Tables booklet.

Unit circle showing the angles alpha and beta from the positive x-axis and the resulting difference angle alpha minus beta. β α α − β
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Simplify the following trigonometric expression as much as possible: $\cos(x) \cos(y) + \sin(x) \sin(y)$. Then, use the simplified result to evaluate the expression…

Simplify the following trigonometric expression as much as possible: $\cos(x) \cos(y) + \sin(x) \sin(y)$. Then, use the simplified result to evaluate the expression exactly when $x = 75^\circ$ and $y = 15^\circ$.

Solve
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Cian is solving an exercise where he has to calculate the exact value of $\cos(15^\circ)$ by applying the cosine difference formula with…

Cian is solving an exercise where he has to calculate the exact value of $\cos(15^\circ)$ by applying the cosine difference formula with $15^\circ = 60^\circ - 45^\circ$. On his exam, he writes the following working:

$$\cos(60^\circ - 45^\circ) = \cos(60^\circ)\cos(45^\circ) - \sin(60^\circ)\sin(45^\circ) = \frac{1}{2} \times \frac{\sqrt{2}}{2} - \frac{\sqrt{3}}{2} \times \frac{\sqrt{2}}{2} = \frac{\sqrt{2}-\sqrt{6}}{4}$$

When checking his result with a calculator, he is surprised to find that it gives a negative number (approximately $-0.26$), which he knows is impossible because $15^\circ$ lies in the first quadrant and its cosine must be positive.

  1. a) Identify precisely the mistake Cian made and explain, based on the parity of trigonometric functions ($\cos(-x) = \cos x$ and $\sin(-x) = -\sin x$), why a central positive sign appears in the cosine difference formula.
  2. b) Correct the calculation and find the exact, simplified value of $\cos(15^\circ)$.
Solve
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Prove analytically that $\tan(45^\circ - x) = \frac{1 - \tan x}{1 + \tan x}$. Use this result to find the exact value of $\tan(15^\circ)$ given that…

Prove analytically that $\tan(45^\circ - x) = \frac{1 - \tan x}{1 + \tan x}$. Use this result to find the exact value of $\tan(15^\circ)$ given that $\tan(30^\circ) = \frac{\sqrt{3}}{3}$.

Solve

Special cases: complementary and supplementary angles

When one of the two angles is $90^\circ$ or $180^\circ$, the difference formulae simplify a great deal and give very widely used identities.

Right-angled triangle showing the relationship between two complementary angles x and ninety minus x. x 90°−x sin(90°−x) = cos x
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Simplify the expression $\sin(90^\circ - x)$ by applying the formula for the sine of the difference of two angles and verify that it is equivalent to one of the basic…

Simplify the expression $\sin(90^\circ - x)$ by applying the formula for the sine of the difference of two angles and verify that it is equivalent to one of the basic trigonometric ratios of the angle $x$.

Solve
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Prove step by step that $\cos(180^\circ - \alpha) = -\cos \alpha$ using the formula for the cosine of the difference of two angles.

Prove step by step that $\cos(180^\circ - \alpha) = -\cos \alpha$ using the formula for the cosine of the difference of two angles.

Solve
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Simplify the following algebraic trigonometric expression and express it purely in terms of the tangents of the angles $a$ and $b$: $\frac{\sin(a - b)}{\cos a \cos b}$

Simplify the following algebraic trigonometric expression and express it purely in terms of the tangents of the angles $a$ and $b$:

$\frac{\sin(a - b)}{\cos a \cos b}$

Solve
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Given that two angles $\alpha$ and $\beta$ are complementary ($\alpha + \beta = 90^\circ$), prove step by step that the identity $\sin(\alpha - \beta) = \cos(2\beta)$…

Given that two angles $\alpha$ and $\beta$ are complementary ($\alpha + \beta = 90^\circ$), prove step by step that the identity $\sin(\alpha - \beta) = \cos(2\beta)$ holds.

Solve

Calculating exact values by combining special angles

Just as with the sum, an angle such as $15^\circ$ is written as the difference of two special angles ($45^\circ-30^\circ$, or alternatively $60^\circ-45^\circ$) so that its ratios can be calculated without a calculator.

Diagram breaking down the non-special angle of 15 degrees as the difference between the special angles of 45 and 30 degrees. 45° − 30° 15°non-special
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Calculate the exact value of $\cos(15^\circ)$ without using a calculator, applying the formula for the cosine of the difference of two angles and knowing that…

Calculate the exact value of $\cos(15^\circ)$ without using a calculator, applying the formula for the cosine of the difference of two angles and knowing that $15^\circ = 45^\circ - 30^\circ$.

Solve
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Find the exact value of $\sin(15^\circ)$ by expressing the angle as the difference $60^\circ - 45^\circ$ and applying the corresponding identity.

Find the exact value of $\sin(15^\circ)$ by expressing the angle as the difference $60^\circ - 45^\circ$ and applying the corresponding identity.

Solve
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Determine the exact value of $\tan(15^\circ)$ from the tangents of the special angles $45^\circ$ and $30^\circ$. Rationalise the result if necessary.

Determine the exact value of $\tan(15^\circ)$ from the tangents of the special angles $45^\circ$ and $30^\circ$. Rationalise the result if necessary.

Solve
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Calculate the exact value of $\tan(105^\circ)$ using the formula for the difference of two angles, considering that $105^\circ = 135^\circ - 30^\circ$.

Calculate the exact value of $\tan(105^\circ)$ using the formula for the difference of two angles, considering that $105^\circ = 135^\circ - 30^\circ$.

Solve
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Evaluate the following trigonometric expression exactly, without using a calculator, by identifying which expansion it corresponds to:…

Evaluate the following trigonometric expression exactly, without using a calculator, by identifying which expansion it corresponds to:

$\sin(75^\circ) \cos(15^\circ) - \cos(75^\circ) \sin(15^\circ)$

Solve

Solving equations and problems with known ratios

When the question gives the ratios of $\alpha$ and $\beta$ separately (rather than the angles), you first calculate the missing ratios and then substitute into the difference formula; if the unknown is an angle, you solve a trigonometric equation.

Navigation diagram showing the initial and corrected heading of a ship with its bearing angles and the difference angle of the turn. tan α = 3, tan β = ½(data) tan(α−β) =(tan α−tan β)/(1+tan α tan β)
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Given that $\sin \alpha = \frac{4}{5}$ and $\cos \beta = \frac{12}{13}$, and that both $\alpha$ and $\beta$ are angles in the first quadrant, calculate the exact value…

Given that $\sin \alpha = \frac{4}{5}$ and $\cos \beta = \frac{12}{13}$, and that both $\alpha$ and $\beta$ are angles in the first quadrant, calculate the exact value of $\sin(\alpha - \beta)$.

Solve
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In a maritime navigation simulation, a ship must adjust its current heading. The necessary correction angle is given by the expression $\alpha - \beta$. Given that…

In a maritime navigation simulation, a ship must adjust its current heading. The necessary correction angle is given by the expression $\alpha - \beta$. Given that $\alpha$ and $\beta$ are acute angles with $\tan \alpha = 3$ and $\tan \beta = \frac{1}{2}$, calculate the exact value of $\tan(\alpha - \beta)$ and deduce the size of the correction angle.

Solve
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Solve the following trigonometric equation, finding all possible solutions in the interval $0^\circ \leq x < 360^\circ$: $\sin(x - 30^\circ) = \frac{\sqrt{3}}{2}$

Solve the following trigonometric equation, finding all possible solutions in the interval $0^\circ \leq x < 360^\circ$:

$\sin(x - 30^\circ) = \frac{\sqrt{3}}{2}$

Solve
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Solve the following trigonometric equation, determining all possible solutions in the interval $[0, 2\pi)$ radians: $\cos(x - 45^\circ) + \cos(x + 45^\circ) = 1$

Solve the following trigonometric equation, determining all possible solutions in the interval $[0, 2\pi)$ radians:

$\cos(x - 45^\circ) + \cos(x + 45^\circ) = 1$

Solve

Applications: optics, surveying and signals

Two rays of light, two lines of sight from an observation point or two out-of-phase signals can all be described by a single difference angle, even though the context (physics, surveying, electricity) changes completely. This is how Higher Level Section B questions are often built.

A surveyor's lines of sight to the base and the top of a lighthouse, with angles of elevation alpha and beta, used to calculate the difference angle. α β top base
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A light ray passes through two different media with angles of refraction $\alpha$ and $\beta$. If, from the material properties, we know that $\cos \alpha = \frac{3}{5}$…

A light ray passes through two different media with angles of refraction $\alpha$ and $\beta$. If, from the material properties, we know that $\cos \alpha = \frac{3}{5}$ (where $\alpha$ is an angle in the fourth quadrant) and $\sin \beta = \frac{5}{13}$ (where $\beta$ is an angle in the second quadrant), determine the exact value of $\cos(\alpha - \beta)$.

Solve
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In a market study, the seasonal sales cycles of two products are modelled using trigonometric functions. The phase difference that determines direct competition is given…

In a market study, the seasonal sales cycles of two products are modelled using trigonometric functions. The phase difference that determines direct competition is given by the value of $\cos(x - y)$. If $\sin x = \frac{1}{3}$ and $\cos y = \frac{2}{5}$, with $x$ located in the first quadrant and $y$ in the fourth quadrant, find the exact value of $\cos(x - y)$.

Solve
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A surveyor observes a cliff of height $H$ and, located right on the edge above it, a lighthouse of height $h$. From their position at a horizontal distance $d$, the…

A surveyor observes a cliff of height $H$ and, located right on the edge above it, a lighthouse of height $h$. From their position at a horizontal distance $d$, the angle of elevation to the base of the lighthouse is $\beta$ and to the top of the lighthouse is $\alpha$. Express the tangent of the angle subtended by the lighthouse alone, that is $\tan(\alpha - \beta)$, purely in terms of the distances $H$, $h$ and $d$.

β α α - β H h d
Solve
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In an alternating current circuit, the potential difference between two nodes is given by the superposition of two out-of-phase signals:…

In an alternating current circuit, the potential difference between two nodes is given by the superposition of two out-of-phase signals: $V(t) = 10 \sin(\omega t) - 10 \sin(\omega t - \frac{\pi}{3})$. Use the trigonometric difference angle formulas to express the potential difference $V(t)$ in the simplified form $A \sin(\omega t + \phi)$, determining the values of $A$ and $\phi$.

Solve

Back to the beginning: O'Brien's Tower at the Cliffs of Moher spans the angle $\alpha-\beta$, found from $\tan(\alpha-\beta)$ as in the examples above. And to calculate the exact value of $\sin(15^\circ)$, we apply the difference formula: $\sin(45^\circ-30^\circ) = \sin(45^\circ)\cos(30^\circ) - \cos(45^\circ)\sin(30^\circ) = \frac{\sqrt{2}}{2}\cdot\frac{\sqrt{3}}{2} - \frac{\sqrt{2}}{2}\cdot\frac{1}{2} = \frac{\sqrt{6}-\sqrt{2}}{4}$.

Summary

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