Average rate of change of a function
A bus from Dublin to Galway covers about 210 km in 3 hours: its average speed is 70 km/h, but that says nothing about how the journey went at each moment. The same happens with any function: the average rate of change measures how much it changes, on average, between two points. In this topic you will formalise it and get it ready for the next step: shrinking the interval down to a single point, which leads to differentiation from first principles. Going back to the bus: its average speed is just the ARC of its distance function over the journey.
Average rate of change: definition and calculation
Calculate the average rate of change of the function $f(x) = 3x - 5$ on the interval $[1, 4]$. Does this value match the gradient of the line representing the function?
Calculate the average rate of change of the function $f(x) = 3x - 5$ on the interval $[1, 4]$. Does this value match the gradient of the line representing the function?
Find the average rate of change of the quadratic function $g(x) = x^2 - 4x + 1$ on the intervals $[0, 2]$ and $[2, 4]$.
Find the average rate of change of the quadratic function $g(x) = x^2 - 4x + 1$ on the intervals $[0, 2]$ and $[2, 4]$.
Determine the value of the parameter $k$ so that the average rate of change of the function $f(x) = kx^2 - 3x + 2$ on the interval $[1, 3]$ is equal to $5$.
Determine the value of the parameter $k$ so that the average rate of change of the function $f(x) = kx^2 - 3x + 2$ on the interval $[1, 3]$ is equal to $5$.
Geometric interpretation: the secant line
This works the same way for any type of function: polynomial, rational or with radicals. Only the expression you substitute changes.
Calculate the average rate of change of the rational function $f(x) = \frac{2x + 1}{x - 1}$ on the interval $[2, 5]$.
Calculate the average rate of change of the rational function $f(x) = \frac{2x + 1}{x - 1}$ on the interval $[2, 5]$.
Look at the graph of the function $f(x)$ shown in the figure. Calculate the average rate of change on the interval $[-2, 2]$. What geometrical interpretation does this…
Look at the graph of the function $f(x)$ shown in the figure. Calculate the average rate of change on the interval $[-2, 2]$. What geometrical interpretation does this value have with respect to the secant line drawn?
Given the function $f(x) = -x^2 + 6x - 5$, find the equation of the secant line passing through the points on the graph with x-coordinates $x = 1$ and $x = 4$. How is…
Given the function $f(x) = -x^2 + 6x - 5$, find the equation of the secant line passing through the points on the graph with x-coordinates $x = 1$ and $x = 4$. How is the gradient of this line related to the average rate of change on that interval?
The ARC on a general interval $[a, a+h]$
To study what happens right at a point $x=a$ it is convenient to write the other endpoint as $a+h$, where $h$ is the step size. That way the ARC becomes a function of $h$, and we can see what happens as we shrink it.
As $h$ gets closer and closer to $0$, the second endpoint $a+h$ slides towards $a$. Simplify the expression first, then ask which value it approaches. For $f(x)=x^2$: $\text{ARC}[1,1+h]=\dfrac{(1+h)^2-1}{h}=\dfrac{2h+h^2}{h}=2+h$. For $h=0.1$, $0.01$, $0.001$ this gives $2.1$, $2.01$, $2.001$, so the ARC approaches $2$ as $h$ tends to $0$. We write this informally as $2+h\to 2$. You cannot just put $h=0$ in the original fraction, because that gives $\frac{0}{0}$: you must simplify first.
Calculate the average rate of change of the function $f(x) = \frac{1}{x}$ on the general interval $[a, a+h]$, simplifying the resulting expression as much as possible.
Calculate the average rate of change of the function $f(x) = \frac{1}{x}$ on the general interval $[a, a+h]$, simplifying the resulting expression as much as possible.
We want to study the average rate of change of the quadratic function $f(x) = 2x^2 - 3x + 1$ on three intervals starting at the same point $a = 1$: $[1, 2]$, $[1; 1.5]$,…
We want to study the average rate of change of the quadratic function $f(x) = 2x^2 - 3x + 1$ on three intervals starting at the same point $a = 1$: $[1, 2]$, $[1; 1.5]$, and $[1; 1.1]$. Two classmates propose different strategies:
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Clara's method: calculate $f(b)$ and $f(1)$ separately for each endpoint and apply the formula $\text{ARC} = \frac{f(b) - f(1)}{b - 1}$ three times independently.
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Daniel's method: express the upper endpoint as $1+h$, deduce a simplified general algebraic formula for $\text{ARC}[1, 1+h] = \frac{f(1+h) - f(1)}{h}$ in terms of the increment $h$, and then specialise by substituting $h = 1$, $h = 0.5$, and $h = 0.1$.
- a) Apply Daniel's method: expand and simplify as much as possible the algebraic expression for $\text{ARC}[1, 1+h]$, and find the three required values.
- b) Apply Clara's method only for the interval $[1; 1.1]$ and verify that both methods lead to the exact same result.
- c) Argue which of the two methods is more advantageous when many intervals sharing the origin $a = 1$ must be evaluated, and explain how the expression obtained by Daniel allows you to deduce the trend of the rate as the increment $h$ approaches zero.
Calculate the average rate of change of the function $f(x) = \sqrt{x+2}$ on the interval $[2, 2+h]$. Then, determine which value this rate of change approaches as $h$…
Calculate the average rate of change of the function $f(x) = \sqrt{x+2}$ on the interval $[2, 2+h]$. Then, determine which value this rate of change approaches as $h$ tends to $0$.
The ARC as average velocity and other quantities
When $f$ measures position as a function of time, the ARC is the average velocity. The same idea works for any other quantity: temperature, the volume of a tank, a company's profit.
The distance in metres travelled by a cyclist as a function of time in seconds is given by the expression $d(t) = 2t^2 + 5t$. What was their average speed between the…
The distance in metres travelled by a cyclist as a function of time in seconds is given by the expression $d(t) = 2t^2 + 5t$. What was their average speed between the times $t = 2$ and $t = 5$?
The monthly profits of a company, in thousands of euros, are given by the function $B(x) = -2x^2 + 24x - 10$, where $x$ is the amount spent on advertising in thousands…
The monthly profits of a company, in thousands of euros, are given by the function $B(x) = -2x^2 + 24x - 10$, where $x$ is the amount spent on advertising in thousands of euros. Calculate the average rate of change of profit if the advertising investment increases from $3$ to $6$ thousand euros, and interpret the result.
A distress flare is launched vertically upwards from the top of a cliff. Its height in metres above sea level after $t$ seconds is given by $h(t) = 80 + 30t - 5t^2$.…
A distress flare is launched vertically upwards from the top of a cliff. Its height in metres above sea level after $t$ seconds is given by $h(t) = 80 + 30t - 5t^2$. Determine the average velocity of the flare on the intervals $[1, 3]$ and $[3, 5]$. What does the sign of the results obtained indicate?
Comparing rates of change and special cases
Not all functions grow in the same way. Comparing the ARC of two functions on the same interval tells us which one changes faster on average over that stretch, although the comparison may be reversed on another interval.
Compare the average rate of change of the functions $f(x) = 2^x$ and $g(x) = x^3$ on the interval $[2, 4]$. Which of the two functions experiences greater average growth…
Compare the average rate of change of the functions $f(x) = 2^x$ and $g(x) = x^3$ on the interval $[2, 4]$. Which of the two functions experiences greater average growth on that interval?
Consider the exponential function $f(x) = 2^x$. a) Before carrying out any numerical calculations, observe the general behaviour of an exponential function and estimate,…
Consider the exponential function $f(x) = 2^x$.
- a) Before carrying out any numerical calculations, observe the general behaviour of an exponential function and estimate, with reasoning, which of the two rates will be greater: $\text{ARC}[0, 2]$ or $\text{ARC}[2, 4]$. Do you expect both to be positive?
- b) Calculate $\text{ARC}[0, 2]$ and $\text{ARC}[2, 4]$ exactly. Check whether the numerical result confirms your previous estimation.
- c) Can there be any non-constant polynomial function for which $\text{ARC}[0, 2] = \text{ARC}[2, 4]$ holds? Justify what type of function would satisfy this equality and why this does not happen for $f(x) = 2^x$.
Prove analytically that the average rate of change of any linear function $f(x) = mx + n$ on an arbitrary interval $[a, b]$ is always constant and equal to $m$.
Prove analytically that the average rate of change of any linear function $f(x) = mx + n$ on an arbitrary interval $[a, b]$ is always constant and equal to $m$.
On a summer day in Cork, weather records indicate that the temperature $T$ (in degrees Celsius) between $10:00$ ($t = 0$) and $16:00$ ($t = 6$) fits a piecewise linear…
On a summer day in Cork, weather records indicate that the temperature $T$ (in degrees Celsius) between $10:00$ ($t = 0$) and $16:00$ ($t = 6$) fits a piecewise linear model:
$$T(t) = \begin{cases} 28 + 2.5t & \text{if } 0 \le t \le 4 \\ 38 + 0.5(t - 4) & \text{if } 4 < t \le 6 \end{cases}$$- a) Calculate the average rate of change of the temperature on the interval $[0, 4]$ and on the interval $[4, 6]$. Do not forget to state the units of measurement for the results.
- b) Without performing any additional numerical calculations, deduce the value of $\text{ARC}[1, 3]$. Justify your answer using the properties of the average rate of change in affine functions.
- c) Calculate $\text{ARC}[0, 6]$ over the entire period and interpret its physical meaning.
Given the piecewise function: $f(x) = \begin{cases} x^2 - 2x & \text{if } x \le 2 \\ \frac{4}{x} - 2 & \text{if } x > 2 \end{cases}$ Calculate the average rate of change…
Given the piecewise function:
$f(x) = \begin{cases} x^2 - 2x & \text{if } x \le 2 \\ \frac{4}{x} - 2 & \text{if } x > 2 \end{cases}$
Calculate the average rate of change on the interval $[0, 4]$. Check whether the function is continuous at $x=2$ and explain whether this affects the calculation of the average rate of change.
Summary
Back to the Dublin to Galway bus: the ARC of distance over time gives 70 km/h.