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5th Year HL · Mathematics
Equations · Systems of equations

Non-linear systems

Picture a hurler's free taken from the 45 on a pitch in Croke Park: the ball's path is a curve and the line to the goalposts is straight. Where do they meet? That is a non-linear system. You already know a line with a parabola from Junior Cycle, and in the Leaving Cert Higher Level a line and a circle are central. Exponentials, logarithms and surds can be added, but the strategy is still the same: rearrange the simplest equation and substitute. At the end we come back to the line and the circle.

What a non-linear system is

Visual comparison between a linear equation that is easy to rearrange and a non-linear equation with a product of unknowns. x − y = 4(linear, easy to rearrange) x · y = 12(non-linear)
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Solve the following non-linear system, which represents the intersection between a parabola and a line: $y = x^2 - 4x + 3$ $y = x - 1$

Solve the following non-linear system, which represents the intersection between a parabola and a line:

$y = x^2 - 4x + 3$

$y = x - 1$

Solve
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Find the solutions to the following system formed by the equation of a circle and a line: $x^2 + y^2 = 25$ $x + y = 7$

Find the solutions to the following system formed by the equation of a circle and a line:

$x^2 + y^2 = 25$

$x + y = 7$

Solve
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Find the values of $x$ and $y$ that satisfy the following system: $xy = 12$ $x - y = 4$

Find the values of $x$ and $y$ that satisfy the following system:

$xy = 12$

$x - y = 4$

Solve
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Solve the following system containing algebraic fractions: $\frac{1}{x} + \frac{1}{y} = \frac{5}{6}$ $xy = 6$

Solve the following system containing algebraic fractions:

$\frac{1}{x} + \frac{1}{y} = \frac{5}{6}$

$xy = 6$

Solve

Exponentials and logarithms: change of variable

Diagram showing how equating the exponents of powers with the same base turns an exponential equation into a linear one. 2x+y = 25 2x−y = 21 same base → equate exponents x + y = 5 x − y = 1 linear system
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Solve the following system of exponential equations by expressing both powers with the same base: $2^{x+y} = 32$ $2^{x-y} = 2$

Solve the following system of exponential equations by expressing both powers with the same base:

$2^{x+y} = 32$

$2^{x-y} = 2$

Solve
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Determine the solution to the logarithmic system by applying the laws of logarithms: $\log x + \log y = 1$ $x - y = 3$

Determine the solution to the logarithmic system by applying the laws of logarithms:

$\log x + \log y = 1$

$x - y = 3$

Solve
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To solve the following system of exponential equations: $$\begin{cases} 2^x + 3^y = 11 \\ 2^{x+1} - 3^{y+1} = 7 \end{cases}$$ two students propose different strategies:…

To solve the following system of exponential equations:

$$\begin{cases} 2^x + 3^y = 11 \\ 2^{x+1} - 3^{y+1} = 7 \end{cases}$$

two students propose different strategies:

  • Aoife proposes isolating $y$ by applying logarithms in the first equation, writing $y = \log_3(11 - 2^x)$, and then substituting this expression into the second equation.

  • Cian proposes applying the properties of powers first to the second equation ($2^{x+1} = 2 \times 2^x$ and $3^{y+1} = 3 \times 3^y$) and carrying out the change of variables $u = 2^x$ and $v = 3^y$.

Compare both methods and justify which one is more suitable and why. Next, solve the system using the optimal path and explain which mathematical property allows you to finally isolate the exact values of $x$ and $y$ from $u$ and $v$.

Solve
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Solve the following system of exponential equations by applying a suitable change of variable: $3^x + 2^y = 11$ $3^{x+1} - 2^{y-1} = 26$

Solve the following system of exponential equations by applying a suitable change of variable:

$3^x + 2^y = 11$

$3^{x+1} - 2^{y-1} = 26$

Solve
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Solve the logarithmic and quadratic system, checking the validity of the solution obtained: $\log(x) - \log(y) = 1$ $x^2 - y^2 = 99$

Solve the logarithmic and quadratic system, checking the validity of the solution obtained:

$\log(x) - \log(y) = 1$

$x^2 - y^2 = 99$

Solve
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Solve the following mixed system combining exponential and logarithmic equations: $2^x \times 2^y = 64$ $\log_2 x + \log_2 y = 3$

Solve the following mixed system combining exponential and logarithmic equations:

$2^x \times 2^y = 64$

$\log_2 x + \log_2 y = 3$

Solve
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Solve the following logarithmic system by applying change-of-base properties and substitution: $\log_y x + \log_x y = \frac{5}{2}$ $xy = 27$

Solve the following logarithmic system by applying change-of-base properties and substitution:

$\log_y x + \log_x y = \frac{5}{2}$

$xy = 27$

Solve

Systems with surds

Diagram of the process of solving an equation with a radical, showing how squaring introduces a false solution that is discarded on checking. √x = 6 − x x² − 13x + 36 = 0 x = 4 ó x = 9 x = 4 ✓satisfies √x = 6−x x = 9 ✗does not satisfy
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Solve the following radical system. Make sure to check whether the solution obtained is valid in the original equation: $\sqrt{x} + y = 5$ $x - y = 1$

Solve the following radical system. Make sure to check whether the solution obtained is valid in the original equation:

$\sqrt{x} + y = 5$

$x - y = 1$

Solve
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Cian has solved the following non-linear system with radicals on the blackboard: $$\begin{cases} y - x = 2 \\ \sqrt{x + 4} = y \end{cases}$$ His steps were as follows:…

Cian has solved the following non-linear system with radicals on the blackboard:

$$\begin{cases} y - x = 2 \\ \sqrt{x + 4} = y \end{cases}$$

His steps were as follows:

  1. Isolates $y$ in the first equation: $y = x + 2$.

  2. Substitutes into the second equation: $\sqrt{x + 4} = x + 2$.

  3. Squares both sides: $x + 4 = (x + 2)^2 \implies x + 4 = x^2 + 4x + 4$.

  4. Collects like terms and factors: $x^2 + 3x = 0 \implies x(x + 3) = 0$, obtaining $x_1 = 0$ and $x_2 = -3$.

  5. Calculates the associated ordinates: $y_1 = 0 + 2 = 2$ and $y_2 = -3 + 2 = -1$.

Cian claims that the system has two solutions: $(0, 2)$ and $(-3, -1)$. Find the conceptual error made by Cian, explain why the squaring operation can introduce extraneous solutions, and provide the correct solution set, justifying your answer.

Solve
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Find the solution to the following radical system: $\sqrt{x+y} + \sqrt{x-y} = 4$ $x - y = 4$

Find the solution to the following radical system:

$\sqrt{x+y} + \sqrt{x-y} = 4$

$x - y = 4$

Solve
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Solve the following radical system, making sure to check which solutions are valid by analysing the domain of the roots: $\sqrt{x^2 - y^2} = \sqrt{33}$ $x + y = 11$

Solve the following radical system, making sure to check which solutions are valid by analysing the domain of the roots:

$\sqrt{x^2 - y^2} = \sqrt{33}$

$x + y = 11$

Solve

Symmetric and higher-degree systems

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The sum of two positive numbers is $10$ and the sum of their squares is $58$. Set up a non-linear system of equations and solve it to find these numbers.

The sum of two positive numbers is $10$ and the sum of their squares is $58$. Set up a non-linear system of equations and solve it to find these numbers.

Solve
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Solve the following system formed by a rational equation and a quadratic equation: $\frac{x+y}{x-y} = 5$ $x^2 + y^2 = 13$

Solve the following system formed by a rational equation and a quadratic equation:

$\frac{x+y}{x-y} = 5$

$x^2 + y^2 = 13$

Solve
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The circular orbit of a satellite in a reference frame follows the equation $x^2 + y^2 = 25$, while the path of a comet describes the hyperbola $xy = 12$. Solve the…

The circular orbit of a satellite in a reference frame follows the equation $x^2 + y^2 = 25$, while the path of a comet describes the hyperbola $xy = 12$. Solve the system to find the exact coordinates of the intersection points of both paths.

X Y x² + y² = 25 xy = 12
Solve
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Solve the higher-degree system of equations. (Hint: use algebraic identities and factorisation to simplify the first equation): $x^3 + y^3 = 35$ $x + y = 5$

Solve the higher-degree system of equations. (Hint: use algebraic identities and factorisation to simplify the first equation):

$x^3 + y^3 = 35$

$x + y = 5$

Solve
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Consider the following symmetric non-linear system depending on a non-zero real parameter $k$ ($k \ne 0$): $$\begin{cases} x + y = k \\ x^3 + y^3 = k \end{cases}$$ a)…

Consider the following symmetric non-linear system depending on a non-zero real parameter $k$ ($k \ne 0$):

$$\begin{cases} x + y = k \\ x^3 + y^3 = k \end{cases}$$
  1. a) Instead of substituting $y = k - x$ directly into the second equation (which would require expanding $(k - x)^3$), justify why it is advantageous to treat it as a symmetric system and use the algebraic identity $x^3 + y^3 = (x + y)^3 - 3xy(x + y)$ to obtain the product $P = x \times y$ in terms of $k$.
  2. b) Set up the quadratic equation $t^2 - S \times t + P = 0$ whose solutions provide the values of the unknowns $x$ and $y$.
  3. c) Discuss with justification for which values of the parameter $k$ the system has two distinct real solutions, a unique double solution, or no real solutions. Furthermore, explain why if the pair $(x_0, y_0)$ is a solution with $x_0 \ne y_0$, the pair $(y_0, x_0)$ is necessarily also a solution, interpreting this property as a geometric symmetry with respect to the line $y = x$.
Solve

Word problems

Many real situations give a sum or product and a second condition. Name the unknowns, write two equations, then substitute.

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A rectangular plot has a perimeter of $40$ m and an area of $96$ m$^2$. Set up a non-linear system of equations to calculate the dimensions of the plot and solve it.

A rectangular plot has a perimeter of $40$ m and an area of $96$ m$^2$. Set up a non-linear system of equations to calculate the dimensions of the plot and solve it.

x y A = 96 m² P = 40 m Length
Solve
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A cyclist completes a $60$ km journey at a constant speed. If they had travelled $2$ km/h faster, it would have taken them $1$ hour less to complete the journey. Set up…

A cyclist completes a $60$ km journey at a constant speed. If they had travelled $2$ km/h faster, it would have taken them $1$ hour less to complete the journey. Set up and solve a non-linear system to find the average speed $v$ and the time $t$ taken.

Solve
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A group of friends decides to buy a birthday present costing $120$ €, splitting the cost equally. At the last minute, two more friends join the group, which reduces each…

A group of friends decides to buy a birthday present costing $120$ €, splitting the cost equally. At the last minute, two more friends join the group, which reduces each person's share by $3$ €. Set up and solve a system to find how many friends there were initially and how much each person paid.

Solve
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In a right-angled triangle, the hypotenuse measures $13$ cm and the total perimeter is $30$ cm. Set up a system of equations to determine the lengths of the two legs.

In a right-angled triangle, the hypotenuse measures $13$ cm and the total perimeter is $30$ cm. Set up a system of equations to determine the lengths of the two legs.

x y 13 cm P = 30 cm
Solve
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A farming cooperative in County Wexford is going to prepare a rectangular basin for drip irrigation protected by a perimeter fence of $36\text{ m}$. Due to hydraulic…

A farming cooperative in County Wexford is going to prepare a rectangular basin for drip irrigation protected by a perimeter fence of $36\text{ m}$. Due to hydraulic requirements of the pumping system, the installation company specifies that the difference between the base area and the square of the shorter side must be exactly equal to $36\text{ m}^2$.

  1. a) Model the situation using a non-linear system of equations, denoting by $x$ the length of the longer side and by $y$ that of the shorter side (with $x \ge y > 0$).
  2. b) Solve the system algebraically by substitution.
  3. c) Interpret the solutions obtained within the real-world context: how many different dimensional configurations are technically possible to build the basin while meeting all requirements? Justify the dimensions of each permissible option.
Solve
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A sheet-metal cylindrical tank has an interior volume of $54\pi$ m³ and a curved surface area (excluding the bases) of $36\pi$ m². Set up a system to find the base…

A sheet-metal cylindrical tank has an interior volume of $54\pi$ m³ and a curved surface area (excluding the bases) of $36\pi$ m². Set up a system to find the base radius $r$ and the height $h$ of the cylinder, and solve it.

r h V = 54π Aₗ = 36π
Solve
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A principal $C$ is invested at an annual compound interest rate $r$ (expressed as a decimal). At the end of the first year, the accumulated amount is $11000$ €. At the…

A principal $C$ is invested at an annual compound interest rate $r$ (expressed as a decimal). At the end of the first year, the accumulated amount is $11000$ €. At the end of the second year, the amount rises to $12100$ €. Set up a non-linear system to calculate the initial principal $C$ and the interest rate $r$, and solve it.

Solve

Line and circle: tangency

A line can cut a curve at two points, at one point (if it is tangent) or at none. When the system has a parameter, discussing how many real solutions it has is equivalent to studying the discriminant of the resulting quadratic equation.

Three positions of a line relative to a circle according to the number of solutions: secant with two points of intersection, tangent with a single point of contact, and exterior with no points of intersection. two intersections2 solutions tangent: one intersection1 solution no intersection0 solutions

Back to the start: a free from the 45 is a line meeting a curve, and the discriminant tells you whether the ball's path meets the line at two points, one or none.

Perpendicular bisectors and the circumcentre

The perpendicular bisector of a segment $AB$ is the line through the midpoint of $AB$ with slope perpendicular to $AB$ (slopes multiply to $-1$). Every point on it is equidistant from $A$ and $B$. In a triangle, the perpendicular bisectors of two sides meet at the circumcentre, the centre of the circle through all three vertices. To find it, write two perpendicular bisectors and solve them as a linear system.

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The boundary coverage of a rural telecommunications station is described by the circle with equation $x^2 + y^2 = 25$ (where $x$ and $y$ are measured in kilometres…

The boundary coverage of a rural telecommunications station is described by the circle with equation $x^2 + y^2 = 25$ (where $x$ and $y$ are measured in kilometres relative to the antenna located at the origin). A straight forest track follows the path $y = 2x - 5$.

  1. a) Before calculating the solutions algebraically, make a reasoned geometric estimate: if an off-road vehicle travels along the track and crosses the vertical axis at $x = 0$, is that point inside, on, or outside the coverage boundary? Estimate in which quadrants of the Cartesian plane the vehicle's entry and exit into the covered area will occur.
  2. b) Set up and solve the system formed by both equations to determine the exact coordinates of the intersection points between the track and the coverage boundary.
  3. c) Check whether the calculated points match your previous estimate and find the exact distance travelled by the off-road vehicle within the antenna's coverage radius.
Solve
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Discuss for which values of the parameter $k$ the following system has exactly one solution (geometrically, this corresponds to the tangency condition between the circle…

Discuss for which values of the parameter $k$ the following system has exactly one solution (geometrically, this corresponds to the tangency condition between the circle and the line):

$x^2 + y^2 = 10$

$x + y = k$

Solve
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A team of engineers is designing the slip road merging a parabolic frontage road with equation $y = a \times x^2 + c$ into a straight road with equation $y = 4x - 5$. To…

A team of engineers is designing the slip road merging a parabolic frontage road with equation $y = a \times x^2 + c$ into a straight road with equation $y = 4x - 5$. To ensure maximum safety during the merging manoeuvre, both roadways must join smoothly (that is, they must be tangent) exactly at the point with abscissa $x = 3$.

  1. a) Formulate the inverse problem: determine the values of the real parameters $a$ and $c$ that define the parabola, knowing that the non-linear system formed by the line and the parabola must have the point with abscissa $x = 3$ as its unique solution. (Hint: analyse the required coefficients of the resolving quadratic equation for it to admit a double root at that value).
  2. b) Using the discriminant $\Delta$ of the intersection equation, formally justify why the tangency condition requires $\Delta = 0$ and explain what it would geometrically represent for the layout of the roads if said discriminant were strictly positive or strictly negative.
Solve

Summary

See all the exercises in this section