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Optical Systems: Thin Lenses and Mirrors

Before you start, make sure you know: Light (Secondary Year 2)

The peephole in a door always shows you everything upright and small. A magnifying glass, on the other hand, enlarges the letters, but if you move it away from the paper the image blurs and then reappears upside down. Why do two curved pieces of glass behave so differently? With a single equation and a sign convention you can describe magnifying glasses, lenses, cameras, telescopes, and rearview mirrors.

Thin lenses: converging and diverging

Converging lens: three rays parallel to the optical axis are refracted and converge at the image focus F'. F′ converging lens optical axis Ray tracing in a converging lens: an object beyond 2f forms a real, inverted, smaller image between F' and 2F'. object image F F′

A magnifying glass is a converging lens with the object between the lens and the focus ($svirtual, upright, enlarged image. A real image can be projected onto a screen; a virtual one cannot.

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In the optics kit in the laboratory there are two lenses: one is thicker at the center than at the edges, and the other is thicker at the edges than at the center. a)…

In the optics kit in the laboratory there are two lenses: one is thicker at the center than at the edges, and the other is thicker at the edges than at the center.

  1. a) State which one is converging and which one is diverging.
  2. b) Describe what happens to a beam of rays parallel to the optical axis when passing through each of them: do they converge at a point or diverge as if coming from a point?
Solve
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An object is placed in front of a converging lens at a distance greater than twice its focal length. a) State the rules for drawing the three principal rays of a…

An object is placed in front of a converging lens at a distance greater than twice its focal length.

  1. a) State the rules for drawing the three principal rays of a converging lens (the ray parallel to the axis, the ray passing through the center, and the ray passing through the object focus).
  2. b) Draw the ray diagram in your notebook and determine the characteristics of the image: is it real or virtual, upright or inverted, larger or smaller than the object?
Solve
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A watchmaker uses a magnifying glass to inspect the mechanism of a watch. a) What type of lens is a magnifying glass: converging or diverging? b) Where must the object…

A watchmaker uses a magnifying glass to inspect the mechanism of a watch.

  1. a) What type of lens is a magnifying glass: converging or diverging?
  2. b) Where must the object be placed relative to the focus of the lens for the magnifying glass to work?
  3. c) State the characteristics of the observed image (real or virtual, upright or inverted, larger or smaller).
Solve

The lens equation and lateral magnification

With a lens of $10\ \text{cm}$ focal length you project a light bulb onto a piece of cardstock. If the bulb is $30\ \text{cm}$ away, the image is in focus at $15\ \text{cm}$; if you bring it closer, to $20\ \text{cm}$, you have to move the cardstock back to $20\ \text{cm}$. What rule fixes the position and size of the image?

If the object is inside the focus ($s0$ (this is the magnifying glass).

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A luminous object is placed $s = 30\ \text{cm}$ from a thin converging lens with focal length $f = 10\ \text{cm}$. Use the thin lens equation $1/f = 1/s + 1/s'$ with…

A luminous object is placed $s = 30\ \text{cm}$ from a thin converging lens with focal length $f = 10\ \text{cm}$. Use the thin lens equation $1/f = 1/s + 1/s'$ with this sign convention: $s$ is positive for a real object, $s'$ is positive if the image is real and negative if virtual, and $f$ is positive for converging lenses and negative for diverging lenses.

  1. a) Calculate the image distance $s'$.
  2. b) State whether the image is real or virtual and whether it can be projected onto a screen.
Solve
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An object $10\ \text{cm}$ high is placed $s = 60\ \text{cm}$ from a converging lens with focal length $f = 20\ \text{cm}$. Use $1/f = 1/s + 1/s'$ and the magnification…

An object $10\ \text{cm}$ high is placed $s = 60\ \text{cm}$ from a converging lens with focal length $f = 20\ \text{cm}$. Use $1/f = 1/s + 1/s'$ and the magnification $A = -s'/s$, with the usual sign convention (positive distances for real objects and real images). Observe the diagram:

F F 2F 2F h = 10 cm object s = 60 cm f = 20 cm s' = ? h' = ?
  1. a) Calculate the image distance $s'$.
  2. b) Calculate the magnification and the height of the image.
  3. c) Describe the image: real or virtual, upright or inverted, larger or smaller.
Solve
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A magnifying glass is a converging lens of focal length $f = 10\ \text{cm}$. A stamp placed $s = 6\ \text{cm}$ from the lens is observed. Observe the diagram: a)…

A magnifying glass is a converging lens of focal length $f = 10\ \text{cm}$. A stamp placed $s = 6\ \text{cm}$ from the lens is observed. Observe the diagram:

F F stamp s = 6 cm f = 10 cm s' = ?
  1. a) Calculate the image distance $s'$ and explain the meaning of its sign.
  2. b) Calculate the magnification and explain the meaning of its sign.
  3. c) State the characteristics of the image and why it cannot be formed on a screen.
Solve

Diverging lenses and limiting cases

In a diverging lens, the ray parallel to the axis exits spreading out; its backward extension passes through the focus on the object's side. The ray through the center is not deflected. The (extended) rays cross between the lens and the object.

Diverging lens: a real object produces a virtual, upright, smaller image between the lens and the object. diverging lens real object virtual image F
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Glasses for correcting myopia (short-sightedness) use diverging lenses. a) Draw the ray diagram of a diverging lens with an object in front of it in your notebook. b)…

Glasses for correcting myopia (short-sightedness) use diverging lenses.

  1. a) Draw the ray diagram of a diverging lens with an object in front of it in your notebook.
  2. b) From the drawing, justify why a diverging lens always produces virtual, upright images that are smaller than the object.

You can do it on paper and send a photo with your answer.

Solve
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An object $5\ \text{cm}$ high is $s = 30\ \text{cm}$ from a diverging lens of focal length $f = -20\ \text{cm}$. Observe the diagram: a) Calculate the image distance…

An object $5\ \text{cm}$ high is $s = 30\ \text{cm}$ from a diverging lens of focal length $f = -20\ \text{cm}$. Observe the diagram:

F h = 5 cm object f = −20 cm s = 30 cm s' = ? h' = ?
  1. a) Calculate the image distance $s'$.
  2. b) Calculate the magnification and the height of the image.
  3. c) Confirm with the results that the image is virtual, upright, and smaller, as expected for a diverging lens.
Solve
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A camera lens can be approximated as a converging lens of focal length $f = 12\ \text{cm}$. Objects located at $s = 36\ \text{cm}$, $s = 24\ \text{cm}$, and…

A camera lens can be approximated as a converging lens of focal length $f = 12\ \text{cm}$. Objects located at $s = 36\ \text{cm}$, $s = 24\ \text{cm}$, and $s = 18\ \text{cm}$ from the lens are photographed.

  1. a) Calculate the image distance $s'$ and the magnification in all three cases.
  2. b) Describe and justify the trend: as the object is moved closer to the focus, what happens to the position and size of the image?
  3. c) Analyse the limiting cases: what happens if the object is exactly at $s = f$? What if it is closer than the focal length?
Solve

Plane mirrors

When you look at yourself in the bathroom mirror, your image seems to be behind the glass. There is no real light there: the reflected rays only appear to come from that point.

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A person is standing $2\ \text{m}$ from a flat wall mirror. Observe the diagram: a) At what distance behind the mirror is their image formed? b) State the…

A person is standing $2\ \text{m}$ from a flat wall mirror. Observe the diagram:

mirror 2 m ? image
  1. a) At what distance behind the mirror is their image formed?
  2. b) State the characteristics of the image: is it real or virtual, upright or inverted, and what size is it compared to the person?
  3. c) At what distance does the person see their own image?
Solve
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A person $1.80\ \text{m}$ tall, with their eyes $1.70\ \text{m}$ above the ground, wants to buy the smallest vertical flat mirror that allows them to see themselves full…

A person $1.80\ \text{m}$ tall, with their eyes $1.70\ \text{m}$ above the ground, wants to buy the smallest vertical flat mirror that allows them to see themselves full length.

  1. a) Draw the rays traveling from the feet and the top of the head to the eyes reflecting off the mirror in your notebook, and, applying the law of reflection and similar triangles, deduce that the minimum height of the mirror is half the height of the person.
  2. b) Calculate this minimum height and the heights above the ground at which the bottom and top edges of the mirror should be placed.
Solve

Spherical mirrors

Concave mirror: the vertex V, the focus F halfway, and the center of curvature C; two parallel rays are reflected passing through F. V F C concave mirror incident rays
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Match each application with the type of mirror and briefly explain why: a car's wing mirror, a dentist's mirror used to view a magnified tooth, and a car headlight…

Match each application with the type of mirror and briefly explain why: a car's wing mirror, a dentist's mirror used to view a magnified tooth, and a car headlight mirror directing light from the bulb forward in an almost parallel beam.

  1. a) Wing mirror.
  2. b) Dentist's mirror.
  3. c) Headlight mirror.
Solve
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A concave spherical laboratory mirror has a radius of curvature of $R = 40\ \text{cm}$. An object $4\ \text{cm}$ high is placed $s = 30\ \text{cm}$ from the mirror.…

A concave spherical laboratory mirror has a radius of curvature of $R = 40\ \text{cm}$. An object $4\ \text{cm}$ high is placed $s = 30\ \text{cm}$ from the mirror. Recall that $f = R/2$ and use the same equation $1/f = 1/s + 1/s'$ with the usual convention (positive distances for real objects and images). Observe the diagram:

C h = 4 cm object R = 40 cm s = 30 cm s' = ?, h' = ?
  1. a) Calculate the focal length of the mirror.
  2. b) Calculate the position of the image.
  3. c) Calculate the magnification and height of the image, and state whether it can be captured on a screen.
Solve
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The wing mirror of a car is a convex mirror with focal length $f = -0.5\ \text{m}$. A car $1.5\ \text{m}$ high is travelling $s = 10\ \text{m}$ from the mirror. Observe…

The wing mirror of a car is a convex mirror with focal length $f = -0.5\ \text{m}$. A car $1.5\ \text{m}$ high is travelling $s = 10\ \text{m}$ from the mirror. Observe the diagram:

F f = −0.5 m h = 1.5 m car s = 10 m s' = ?, h' = ?
  1. a) Calculate the position of the image.
  2. b) Calculate the magnification and height of the image.
  3. c) In light of the result, explain the meaning of the warning "objects in mirror are closer than they appear".
Solve

Mirrors: field of view and light concentration

Two extreme cases help in understanding mirrors.

Object at infinity (the Sun): $s\to\infty$ makes $1/s\to 0$, so $s'=f$. Parallel rays are concentrated at the focus; the receiver of a solar oven is placed there. Conversely, a point source at the focus of a concave mirror produces a parallel beam (car headlight, flashlight).

Convex rearview mirror. Since $f<0$ and $s>0$, always $s'<0$ and $|A|<1$. A car looks smaller than in a plane mirror, so a much wider area fits in the same mirror. The cost: small things are interpreted as far away, and how close they are gets underestimated.

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A solar furnace like the one in Odeillo (France) concentrates sunlight using a concave spherical mirror of radius $R = 1.2\ \text{m}$. Observe the diagram: a) Calculate…

A solar furnace like the one in Odeillo (France) concentrates sunlight using a concave spherical mirror of radius $R = 1.2\ \text{m}$. Observe the diagram:

sunlight C R = 1.2 m ? receiver
  1. a) Calculate its focal length.
  2. b) Sunlight arrives in practically parallel rays (object at infinity): using $1/f = 1/s + 1/s'$ with $s \rightarrow \infty$, reason where the receiver should be placed to concentrate the energy.
  3. c) If an object is placed $s = 0.9\ \text{m}$ from the same mirror, calculate the position of the image and the magnification, and state its characteristics.
  4. d) Explain where a point light source should be located for the mirror to produce an emergent parallel beam, as in a searchlight, and justify it using the equation.
Solve
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A convex side mirror has $f = -0.4\ \text{m}$. A car $1.8\ \text{m}$ wide is $s = 8\ \text{m}$ away. a) Calculate the position of the image, the magnification, and the…

A convex side mirror has $f = -0.4\ \text{m}$. A car $1.8\ \text{m}$ wide is $s = 8\ \text{m}$ away.

  1. a) Calculate the position of the image, the magnification, and the apparent width of the car in the mirror.
  2. b) Compare with a flat mirror of the same size, in which the image would have the actual size of the object: using your results, explain why the convex mirror allows a much larger field of view to be covered in a small mirror.
  3. c) Comment on the drawback of this design for estimating distances and why regulations require the inclusion of the corresponding warning.
Solve

Lens power and lenses in contact

At the optometrist's office they give you values like "$+2.00$" or "$-1.50$," not focal distances in centimeters. And if two lenses are put together, their effects simply add.

Comparison of a converging lens of plus 2 diopters, for farsightedness, and a diverging lens of minus 2.5 diopters, for nearsightedness. F +2 D: converging f = 0.5 m −2.5 D: diverging f = −0.4 m
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The power of a lens is defined as $P = 1/f$, with $f$ in meters, and is measured in diopters ($\text{D}$). a) Calculate the power of a converging lens of focal length…

The power of a lens is defined as $P = 1/f$, with $f$ in meters, and is measured in diopters ($\text{D}$).

  1. a) Calculate the power of a converging lens of focal length $f = 0.5\ \text{m}$.
  2. b) Calculate the focal length of a lens of $-4\ \text{D}$ and state whether it is converging or diverging.
Solve
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During an eye exam, a hypermetropic (farsighted) patient is prescribed lenses of $+2\ \text{D}$ and a myopic (nearsighted) patient is prescribed lenses of…

During an eye exam, a hypermetropic (farsighted) patient is prescribed lenses of $+2\ \text{D}$ and a myopic (nearsighted) patient is prescribed lenses of $-2.5\ \text{D}$. Recall that $P = 1/f$ with $f$ in meters.

  1. a) Calculate the focal length of each lens and state its type.
  2. b) Explain what focusing problem each patient has (where is the image of a distant object formed relative to the retina?) and why the sign of their lens corrects it.
Solve
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In the design of an optical instrument, two thin lenses are glued together in contact: one of $+3\ \text{D}$ and another of $-1\ \text{D}$. For thin lenses in contact,…

In the design of an optical instrument, two thin lenses are glued together in contact: one of $+3\ \text{D}$ and another of $-1\ \text{D}$. For thin lenses in contact, their powers add: $P = P_1 + P_2$.

  1. a) Calculate the power and focal length of the combination and state whether it behaves as a converging or diverging lens.
  2. b) The combination is used as a magnifying glass with an object at $s = 0.3\ \text{m}$: calculate the image position and magnification, and state the characteristics of the image.
  3. c) In light of the signs, explain why the overall combination is dominated by one of the two lenses.
Solve

Projector, telescope, and microscope

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A slide projector uses a converging lens of focal length $f = 15\ \text{cm}$. The slide is placed $s = 20\ \text{cm}$ from the lens. a) Calculate the distance at which…

A slide projector uses a converging lens of focal length $f = 15\ \text{cm}$. The slide is placed $s = 20\ \text{cm}$ from the lens.

  1. a) Calculate the distance at which the screen must be placed for the image to be in focus.
  2. b) Calculate the magnification.
  3. c) Explain why the slide must be placed upside down in the slide holder.
Solve
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It is desired to design a projector that forms a real image three times larger than the object on a screen located $4\ \text{m}$ from the object. Observe the diagram: a)…

It is desired to design a projector that forms a real image three times larger than the object on a screen located $4\ \text{m}$ from the object. Observe the diagram:

object lens screen s = ? s' = ? s + s' = 4 m
  1. a) Given that for a real image the object-screen distance is $s + s'$, set up the system of equations with the magnification condition $|A| = s'/s = 3$ and calculate $s$ and $s'$.
  2. b) Calculate the focal length of the required lens and its power in dioptres.
  3. c) Reason why a diverging lens would not be suitable for this project.
Solve
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A refracting telescope belonging to an astronomy club has an objective lens of focal length $f_{\text{ob}} = 90\ \text{cm}$ and an eyepiece of…

A refracting telescope belonging to an astronomy club has an objective lens of focal length $f_{\text{ob}} = 90\ \text{cm}$ and an eyepiece of $f_{\text{oc}} = 3\ \text{cm}$. For a very distant object, the angular magnification of the telescope is $M = f_{\text{ob}}/f_{\text{oc}}$ and the length of the tube is approximately the sum of the two focal lengths. Observe the diagram:

L = ? distant star objective eyepiece common focus f objective = 90 cm f eyepiece = 3 cm
  1. a) Calculate the angular magnification of the telescope.
  2. b) Calculate the approximate length of the tube.
  3. c) Explain the role of each lens and why it is desirable for the objective to have a large diameter (think about the light it captures from a faint star).
Solve

The eye as an optical system

The eye is a lens (the crystalline lens) that always forms the image on the retina, at a fixed distance (about $2.4\ \text{cm}$). Since $s'$ does not change, to focus on objects at different distances the eye changes $f$: this is called accommodation, and it is done by the ciliary muscles as they bulge or flatten the lens.

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An optical laboratory microscope has an objective lens with $40$ magnification and an eyepiece with $10$ magnification, so that the total magnification is the product of…

An optical laboratory microscope has an objective lens with $40$ magnification and an eyepiece with $10$ magnification, so that the total magnification is the product of both.

  1. a) Calculate the total magnification of the microscope.
  2. b) Explain the role of each lens: what type of image does the objective form of the specimen, and how does the eyepiece act on that intermediate image?
  3. c) A cell measures $20\ \mu\text{m}$: calculate the apparent size with which it is observed through the microscope, expressed in $\text{mm}$.
Solve
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The human eye can be modelled as a lens (the crystalline lens) whose image is always formed on the retina, located $2.4\ \text{cm}$ from the lens. The lens changes its…

The human eye can be modelled as a lens (the crystalline lens) whose image is always formed on the retina, located $2.4\ \text{cm}$ from the lens. The lens changes its focal length thanks to the ciliary muscles (accommodation). Observe the diagram:

lens retina distant object f = ? 2.4 cm
  1. a) Calculate the focal length of the lens when observing a very distant object ($s \rightarrow \infty$).
  2. b) Calculate the focal length required to read a book $25\ \text{cm}$ from the eye.
  3. c) Using both results, explain what accommodation consists of and why with age (presbyopia) it becomes difficult to focus on close objects.
Solve

Summary

Back to the beginning: the magnifying glass gives an upright, enlarged image only with the object inside the focus; moving it away switches to a real inverted image. The peephole uses a diverging lens, which always gives a virtual, upright, smaller image.

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