Nature of Light: Electromagnetic Waves and the Spectrum
When you watch the sunrise over Popocatépetl, the light from the Sun has crossed about 150 million kilometers of empty space. How can something travel with no air, no wire, and nothing to hold it up? For centuries, Newton argued that light was made of tiny particles and Huygens argued that it was a wave. In this section you will see how the debate was settled.
Two historical models of light
At the end of the 17th century there were two rival explanations of what light is.
Both models explained reflection well, so that phenomenon could not be used to decide between them. What does decide it is interference: in 1801 Young passed light through two very close slits and got alternating bright and dark fringes on the screen. A stream of particles would not produce that pattern; only waves, which add up (bright fringe) or cancel (dark fringe) when they overlap, do. With this the wave model gained strength, and Maxwell later gave it its definitive form.
Throughout history, two models concerning the nature of light have competed: the corpuscular model, defended by Newton at the end of the 17th century, and the wave…
Throughout history, two models concerning the nature of light have competed: the corpuscular model, defended by Newton at the end of the 17th century, and the wave model, proposed by his contemporary Huygens.
Match each statement with the model it belongs to:
- a) Light is made up of small particles that travel in straight lines.
- b) Light propagates as a wave disturbance, in a similar way to waves on the surface of water.
- c) Reflection is explained as particles bouncing off a polished surface.
- d) Light should exhibit characteristic wave phenomena, such as diffraction and interference.
The debate on the nature of light lasted for more than two centuries and marked the history of physics. The figure schematically shows Young's double-slit experiment…
The debate on the nature of light lasted for more than two centuries and marked the history of physics. The figure schematically shows Young's double-slit experiment described in section b).
- a) Summarise what Newton's corpuscular model and Huygens' wave model consisted of, and state an optical phenomenon that both models were able to explain.
- b) In 1801, Young presented his double-slit experiment: when light passed through two close slits, a pattern of alternating bright and dark fringes appeared on the screen. Explain which wave phenomenon this pattern reveals and why it proved decisive against the corpuscular model.
- c) What did Maxwell prove in 1865 about the type of wave that light is, and what did he predict about its speed in a vacuum?
- d) At the beginning of the 20th century, the photoelectric effect, interpreted by Einstein in 1905, could only be explained by assuming that light exchanges energy in discrete packets, photons. State in your own words the wave-particle duality with which modern physics describes light.
Light as an electromagnetic wave
If you make electric charges oscillate in an antenna, another antenna kilometers away detects a current with no wire between them. How does that disturbance travel through space?
According to Maxwell's theory, light is an electromagnetic wave. The figure represents an instant of that wave propagating through a vacuum. a) State which two fields…
According to Maxwell's theory, light is an electromagnetic wave. The figure represents an instant of that wave propagating through a vacuum.
- a) State which two fields oscillate, perpendicular to each other and to the direction of propagation, in an electromagnetic wave.
- b) Explain the fundamental difference between the propagation of light and that of sound: which of the two requires a material medium and which can travel through a vacuum? Give an astronomical example that demonstrates this.
Maxwell predicted in 1865 that light is an electromagnetic wave and that its speed in a vacuum depends only on two constants of electromagnetism:…
Maxwell predicted in 1865 that light is an electromagnetic wave and that its speed in a vacuum depends only on two constants of electromagnetism: $c = \frac{1}{\sqrt{\varepsilon_0 \times \mu_0}}$. Given: $\varepsilon_0 = 8.85\times10^{-12}\ \text{C}^2/\text{N}\times\text{m}^2$ and $\mu_0 = 4\pi\times10^{-7}\ \text{N/A}^2$.
- a) Calculate the value of $c$ obtained from these data.
- b) Compare it with the accepted value, $c = 3\times10^{8}\ \text{m/s}$, and explain why this agreement was decisive proof that light is an electromagnetic wave.
Speed of light, times, and distances
A satellite call or a GPS signal takes a minimum amount of time to arrive. Since light has a finite speed, the distance traveled is $d = c\,t$.
Measuring such a short time: Fizeau's toothed wheel
In 1849, Fizeau measured $c$ on Earth without fast clocks. He used a rotating toothed wheel: light passes through a gap between two teeth, travels to a distant mirror, and comes back. If on return it meets a tooth instead of a gap, the beam is blocked.
The wheel works as a clock. A wheel with $N$ teeth and $N$ gaps has $N$ "divisions" (one tooth plus one gap), so each division takes up $1/N$ of a turn. If the wheel makes $f_g$ turns per second, a fraction of a turn $\varphi$ takes $t = \varphi/f_g$. When the beam is blocked for the first time, the round-trip time of the light is exactly the time the wheel takes to turn half a division, that is, $\varphi = \dfrac{1}{2N}$ of a turn.
The astronauts of the Apollo missions left retroreflectors on the Moon. A laser pulse is sent from an observatory on Earth, reflects off them and returns. The Earth-Moon…
The astronauts of the Apollo missions left retroreflectors on the Moon. A laser pulse is sent from an observatory on Earth, reflects off them and returns. The Earth-Moon distance is $d = 3.84\times10^{8}\ \text{m}$ and light travels at $c = 3\times10^{8}\ \text{m/s}$. Observe the diagram:
- a) Calculate the time taken for the pulse to reach the Moon.
- b) Calculate the total round-trip time measured by the observatory.
A geostationary telecommunications satellite orbits at $36000\ \text{km}$ above the equator. A transcontinental video call sends the signal up to the satellite, which…
A geostationary telecommunications satellite orbits at $36000\ \text{km}$ above the equator. A transcontinental video call sends the signal up to the satellite, which forwards it to the receiving station on the surface (given: $c = 3\times10^{8}\ \text{m/s}$). Observe the diagram:
- a) Express the altitude of the satellite in meters, in scientific notation.
- b) Calculate the minimum time taken for the signal to travel up to the satellite and down to the receiving station.
- c) Explain what effect this delay produces in a live conversation and why it is barely noticeable when the signal travels through a submarine cable.
In 1849 Fizeau measured the speed of light on Earth's surface for the first time using a toothed wheel. A beam of light passed through the gap between two teeth,…
In 1849 Fizeau measured the speed of light on Earth's surface for the first time using a toothed wheel. A beam of light passed through the gap between two teeth, travelled $d = 8.63\ \text{km}$ to a mirror and returned; if on its return it encountered a tooth instead of a gap, the beam disappeared from the observer's view. The wheel had $720$ teeth and $720$ equal gaps (given: $c = 3\times10^{8}\ \text{m/s}$). Observe the setup:
- a) Calculate the time taken for light to travel to the mirror and back.
- b) The first eclipse occurs when, during that time, the wheel rotates half a division, that is, $1/1440$ of a turn. Calculate how many revolutions per second the wheel must turn to produce it, and express it also in revolutions per minute.
- c) Comment on what makes this method ingenious: what quantity is measured directly using the wheel, and how is timing a millionth-of-a-second interval avoided?
The GPS system positions a receiver by measuring the time taken for the electromagnetic signal to arrive from each satellite, which orbits at an altitude of…
The GPS system positions a receiver by measuring the time taken for the electromagnetic signal to arrive from each satellite, which orbits at an altitude of $20200\ \text{km}$ (given: $c = 3\times10^{8}\ \text{m/s}$).
- a) Calculate the time taken for the signal to travel from the satellite to the receiver.
- b) If the receiver's clock accumulates an error of $30\ \text{ns}$, calculate the distance error that this time discrepancy introduces by applying $\Delta x = c \times \Delta t$.
- c) In light of the result, justify why GPS satellites carry atomic clocks with nanosecond precision and describe what would happen to positioning accuracy if ordinary quartz clocks were used.
The electromagnetic spectrum
In 1800, William Herschel placed thermometers along the rainbow from a prism and saw that the mercury rose the most just beyond the red, where no light was visible at all. What invisible radiation lies outside the colors?
Within the visible range, red has the lowest frequency (longest $\lambda$) and violet has the highest (shortest $\lambda$).
A radio station broadcasts in FM at a frequency of $f = 98.5\ \text{MHz}$. Radio waves are electromagnetic waves that travel through a vacuum at…
A radio station broadcasts in FM at a frequency of $f = 98.5\ \text{MHz}$. Radio waves are electromagnetic waves that travel through a vacuum at $c = 3\times10^{8}\ \text{m/s}$.
- a) Express the frequency in hertz, in standard form.
- b) Calculate the wavelength of the signal by applying $c = \lambda \times f$.
A violet laser pointer emits light with a wavelength of $\lambda = 400\ \text{nm}$ (given: $c = 3\times10^{8}\ \text{m/s}$). a) Express the wavelength in meters, in…
A violet laser pointer emits light with a wavelength of $\lambda = 400\ \text{nm}$ (given: $c = 3\times10^{8}\ \text{m/s}$).
- a) Express the wavelength in meters, in scientific notation.
- b) Calculate the frequency of this light.
Arrange the following bands of the electromagnetic spectrum in order from shortest to longest wavelength: microwaves, X-rays, visible light, radio waves, ultraviolet…
Arrange the following bands of the electromagnetic spectrum in order from shortest to longest wavelength: microwaves, X-rays, visible light, radio waves, ultraviolet radiation, infrared radiation.
Then state which of them has the highest frequency and which the lowest, and what general relationship exists between wavelength and frequency.
Visible light ranges in color from red ($\lambda \approx 700\ \text{nm}$) to violet ($\lambda \approx 400\ \text{nm}$) (given: $c = 3\times10^{8}\ \text{m/s}$). a)…
Visible light ranges in color from red ($\lambda \approx 700\ \text{nm}$) to violet ($\lambda \approx 400\ \text{nm}$) (given: $c = 3\times10^{8}\ \text{m/s}$).
- a) Calculate the frequency of red light and that of violet light.
- b) How many times higher is the frequency of violet than that of red? Express the result to two significant figures.
Bands of the spectrum and their uses
Your cell phone, the microwave oven, the TV remote, and an X-ray all use electromagnetic waves. What changes is the $\lambda$, and their behavior and uses depend on it.
| Band | Approximate $\lambda$ | Example |
|---|---|---|
| Radio waves | m to km | FM radio, TV |
| Microwaves | mm to cm | oven, WiFi, radar |
| Infrared | $10^{-6}$ to $10^{-3}$ m | remote control, heat |
| Visible | 380 to 750 nm | light, colors |
| Ultraviolet | 10 to 380 nm | black light, germicidal lamp |
| X-rays | 0.01 to 10 nm | X-ray images |
| Gamma rays | less than 0.01 nm | radiotherapy |
A useful idea: a wave gets around obstacles (diffraction) better the longer its $\lambda$ is compared with the obstacle or the opening. That is why $2.4\ \text{GHz}$ WiFi ($\lambda\approx12.5\ \text{cm}$) passes through the house better than $5\ \text{GHz}$ WiFi ($\lambda=6\ \text{cm}$). And if the opening is much smaller than $\lambda$, the wave doesn't get through: the mesh on the microwave oven door (holes of $2\ \text{mm}$) blocks microwaves of $12\ \text{cm}$ but lets visible light through ($\lambda\sim500\ \text{nm}$, much smaller than $2\ \text{mm}$).
Radio telescopes study the universe through the $21\ \text{cm}$ line emitted by neutral hydrogen in the interstellar medium (given: $c = 3\times10^{8}\ \text{m/s}$). a)…
Radio telescopes study the universe through the $21\ \text{cm}$ line emitted by neutral hydrogen in the interstellar medium (given: $c = 3\times10^{8}\ \text{m/s}$).
- a) Express $21\ \text{cm}$ in meters and calculate the frequency of this radiation, in hertz and gigahertz.
- b) State which band of the electromagnetic spectrum it belongs to and give a reasoned advantage of observing the cosmos in that band compared to visible light.
A home router broadcasts Wi-Fi in two bands: $2.4\ \text{GHz}$ and $5\ \text{GHz}$ (given: $c = 3\times10^{8}\ \text{m/s}$). The figure shows what happens to a wave when…
A home router broadcasts Wi-Fi in two bands: $2.4\ \text{GHz}$ and $5\ \text{GHz}$ (given: $c = 3\times10^{8}\ \text{m/s}$). The figure shows what happens to a wave when it reaches an obstacle with an aperture.
- a) Calculate the wavelength of each band and express it in centimeters.
- b) In practice, the $2.4\ \text{GHz}$ band penetrates walls and furniture better. Using the calculated wavelengths and the phenomenon of diffraction, explain why the longer-wavelength signal gets around obstacles better.
The LED of a remote control emits infrared radiation of $\lambda = 940\ \text{nm}$ (given: $c = 3\times10^{8}\ \text{m/s}$; the human eye detects radiation between…
The LED of a remote control emits infrared radiation of $\lambda = 940\ \text{nm}$ (given: $c = 3\times10^{8}\ \text{m/s}$; the human eye detects radiation between $380\ \text{nm}$ and $750\ \text{nm}$). The figure places the LED emission in the spectrum.
- a) Calculate its frequency.
- b) By comparing wavelengths with the visible range, explain why we do not see the flash from the LED even though a cell phone camera records it on screen.
The visible spectrum extends, approximately, from $\lambda = 380\ \text{nm}$ (violet) to $\lambda = 750\ \text{nm}$ (red) (given: $c = 3\times10^{8}\ \text{m/s}$). a)…
The visible spectrum extends, approximately, from $\lambda = 380\ \text{nm}$ (violet) to $\lambda = 750\ \text{nm}$ (red) (given: $c = 3\times10^{8}\ \text{m/s}$).
- a) Calculate the frequency range of the visible spectrum, in scientific notation.
- b) State which color corresponds to the highest frequency end and which to the lowest, and write down the general relationship between wavelength and frequency for any electromagnetic wave in a vacuum.
A microwave oven heats food using electromagnetic waves of $f = 2.45\ \text{GHz}$ (given: $c = 3\times10^{8}\ \text{m/s}$). Observe the diagram of the door: a) Calculate…
A microwave oven heats food using electromagnetic waves of $f = 2.45\ \text{GHz}$ (given: $c = 3\times10^{8}\ \text{m/s}$). Observe the diagram of the door:
- a) Calculate its wavelength and express it in centimeters.
- b) The oven door has a metal mesh with holes of about $2\ \text{mm}$: we can see inside, but the microwaves do not escape. Justify this by comparing the size of the holes with the wavelength of microwaves and with that of visible light ($\lambda \approx 500\ \text{nm}$).
Wave-particle duality: the photon
The wave model explains interference and diffraction, as in Young's experiment. But in 1905 Einstein explained the photoelectric effect by admitting that light exchanges energy in packets.
A hospital germicidal lamp emits ultraviolet radiation of $\lambda = 254\ \text{nm}$ (UVC band), whereas a "black light" lamp emits $\lambda = 365\ \text{nm}$ (UVA band)…
A hospital germicidal lamp emits ultraviolet radiation of $\lambda = 254\ \text{nm}$ (UVC band), whereas a "black light" lamp emits $\lambda = 365\ \text{nm}$ (UVA band) (given: $c = 3\times10^{8}\ \text{m/s}$).
- a) Calculate the frequency of each type of radiation.
- b) UVC destroys the genetic material of bacteria and viruses, whereas UVA is much less aggressive. Relate this behavior to the calculated frequencies and to the position of each band within the electromagnetic spectrum.
Quantum physics closed the historical debate: light exchanges energy in packets called photons, each with energy $E = h \times f$ (given:…
Quantum physics closed the historical debate: light exchanges energy in packets called photons, each with energy $E = h \times f$ (given: $h = 6.63\times10^{-34}\ \text{J}\times\text{s}$).
- a) Calculate the energy of a photon from a radio station broadcasting at $f = 100\ \text{MHz}$.
- b) Calculate the energy of an X-ray photon of $f = 3\times10^{18}\ \text{Hz}$.
- c) Calculate how many times more energetic the X-ray photon is than the radio photon and use that factor to justify two facts: we live surrounded by radio waves without suffering any ionisation damage, whereas X-rays are carried out with controlled doses and lead protection.
E and B fields, and distances in light-years
In an electromagnetic wave in a vacuum the fields are linked by $E = c\,B$, and the direction of propagation is that of $\vec E\times\vec B$. A light-year is the distance light travels in one year: $c\times3.16\times10^{7}\ \text{s} \approx 9.5\times10^{15}\ \text{m}$.
In the vicinity of a transmitting antenna, the electromagnetic wave has a maximum electric field of $E_{max} = 300\ \text{V/m}$ and a frequency of $f = 90\ \text{MHz}$…
In the vicinity of a transmitting antenna, the electromagnetic wave has a maximum electric field of $E_{max} = 300\ \text{V/m}$ and a frequency of $f = 90\ \text{MHz}$ (given: $c = 3\times10^{8}\ \text{m/s}$; in an electromagnetic wave $E = c \times B$).
- a) Calculate the maximum value of the magnetic field, $B_{max}$.
- b) Calculate the wavelength of the signal.
- c) Sketch the wave at a given instant in your notebook: mark the direction of propagation and the orientations of $\vv{E}$ and $\vv{B}$, knowing that they are perpendicular to each other and to the direction of propagation, and that the latter is in the direction of the vector product $\vv{E} \wedge \vv{B}$.
Andromeda, the large galaxy closest to the Milky Way, is $2.5$ million light years away (given: $c = 3\times10^{8}\ \text{m/s}$; one year…
Andromeda, the large galaxy closest to the Milky Way, is $2.5$ million light years away (given: $c = 3\times10^{8}\ \text{m/s}$; one year $\approx 3.16\times10^{7}\ \text{s}$).
- a) Calculate how many meters there are in one light year.
- b) Express the distance to Andromeda in meters and in kilometers, in scientific notation.
- c) The light from Andromeda captured today by telescopes left the galaxy long before modern human beings existed. Explain why observing distant objects is equivalent to "looking back in time" and why astronomers prefer to express these distances in light years.
Thermal radiation and Wien's law
When you heat a steel bar it goes from dark to dull red, orange, and white. What relationship is there between temperature and color?
A weather radar emits microwave pulses of $f = 2.8\ \text{GHz}$ that are reflected by raindrops. The echo from a storm returns $0.50\ \text{ms}$ after the pulse is…
A weather radar emits microwave pulses of $f = 2.8\ \text{GHz}$ that are reflected by raindrops. The echo from a storm returns $0.50\ \text{ms}$ after the pulse is emitted (given: $c = 3\times10^{8}\ \text{m/s}$). Observe the diagram:
- a) Calculate the distance to the storm, taking into account that the pulse travels twice that distance.
- b) Calculate the wavelength of the radar.
- c) Raindrops are a few millimeters in size. Explain why microwaves rather than visible light are used to detect precipitation tens of kilometers away, considering how each type of radiation interacts with clouds.
The color of a star reveals its surface temperature: the spectrum of a hot body reaches its emission maximum at a wavelength given by Wien's law,…
The color of a star reveals its surface temperature: the spectrum of a hot body reaches its emission maximum at a wavelength given by Wien's law, $\lambda_{max} \times T = 2.9\times10^{-3}\ \text{m}\times\text{K}$, with the temperature $T$ in kelvin. The graph shows the emission curve of the Sun.
- a) The Sun has a surface temperature of $5800\ \text{K}$. Calculate the wavelength at which it emits with maximum intensity, express it in nanometers and state which band of the spectrum it belongs to.
- b) Betelgeuse, the red supergiant in Orion, has a surface temperature of about $3300\ \text{K}$. Repeat the calculation and explain why it appears reddish to us.
- c) Applying the law, predict the dominant color of a star of $10000\ \text{K}$ and justify your answer based on the position of its emission maximum in the spectrum.
Back to the beginning: Newton or Huygens? Both were partly right. Light propagates as Maxwell's electromagnetic wave, which also crosses the vacuum from the Sun, but it exchanges energy in photons.