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The Concept of Weight

Before you start, make sure you know: Gravitational Phenomena (Secondary Year 2)

An astronaut with a mass of 70 kg weighs about $686\ \text{N}$ on Earth, but on the Moon, with exactly the same mass, a spring scale would read only about $112\ \text{N}$. Nothing about the astronaut's body has changed: what changes is the celestial body pulling on them, and that is precisely what weight measures.

Weight: A Special Case of Gravitation

When you drop an apple and a stone, Earth pulls on both of them toward the ground with a force proportional to their mass, and both fall with the same acceleration, $9.8\ \text{m/s}^2$. How does this everyday force connect to Newton's law of gravitation, which keeps the planets in orbit?

Object of mass m on the surface of a planet of mass M and radius R: the weight P is a vertical force directed toward the center of the planet R m P planet (M, R) P = m·g, toward the center of the planet g = G·M/R²

Another way to read $g$: since $9.8\ \text{m/s}^2 = 9.8\ \text{N/kg}$, it means that each kilogram of mass weighs $9.8\ \text{N}$ on Earth. If you need a quick estimate, you can use $g \approx 10\ \text{m/s}^2$ and then refine with $9.8$.

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A rucksack full of books has a mass of $6\ \text{kg}$, as shown in the figure. Calculate its weight on Earth using $P = m\times g$, taking $g = 9.8\ \text{m/s}^2$.

A rucksack full of books has a mass of $6\ \text{kg}$, as shown in the figure.

m = 6 kg P = ? g = 9.8 m/s²

Calculate its weight on Earth using $P = m\times g$, taking $g = 9.8\ \text{m/s}^2$.

Solve
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A bag of cement weighs $196\ \text{N}$ on Earth ($g = 9.8\ \text{m/s}^2$). Rearrange for mass in the expression $P = m\times g$ and calculate it.

A bag of cement weighs $196\ \text{N}$ on Earth ($g = 9.8\ \text{m/s}^2$). Rearrange for mass in the expression $P = m\times g$ and calculate it.

Solve
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A car with a mass of $1200\ \text{kg}$ carries four passengers of $70\ \text{kg}$ each. Take $g \approx 10\ \text{m/s}^2$. a) What is the total mass of the combination?…

A car with a mass of $1200\ \text{kg}$ carries four passengers of $70\ \text{kg}$ each. Take $g \approx 10\ \text{m/s}^2$.

  1. a) What is the total mass of the combination?
  2. b) What total weight is supported between the four tyres?
  3. c) How many newtons of weight does each passenger add?
Solve

Constant Mass, Variable Weight

An astronaut in orbit floats, but if they push a $500\ \text{kg}$ module, they need almost the same force to set it in motion as on Earth. Which quantity changes with location and which stays constant?

A 6 kg object has constant mass but weighs 58.8 N on Earth and 9.6 N on the Moon, shown with arrows of different lengths Earth m = 6 kg P = 58.8 N Moon m = 6 kg P = 9.6 N

The instruments confirm this: a balance scale compares masses (the celestial body attracts both pans equally), so it reads the same anywhere. A spring scale measures the force that stretches a spring, that is, the weight, and it changes with $g$. A bathroom scale is really a force meter that converts to kilograms by assuming $g = 9.8\ \text{m/s}^2$: on the Moon it would give a wrong "mass."

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An astronaut with all their equipment has a mass of $90\ \text{kg}$ and is on the Moon, where $g = 1.6\ \text{m/s}^2$. Calculate their weight there. Has their mass…

An astronaut with all their equipment has a mass of $90\ \text{kg}$ and is on the Moon, where $g = 1.6\ \text{m/s}^2$. Calculate their weight there. Has their mass changed compared to what it was on Earth? Justify your answer.

Solve
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State whether each of these statements refers to mass or weight, and correct any that are incorrectly phrased: a) "This watermelon weighs $4\ \text{kg}$." b) "My mass is…

State whether each of these statements refers to mass or weight, and correct any that are incorrectly phrased:

  1. a) "This watermelon weighs $4\ \text{kg}$."
  2. b) "My mass is $540\ \text{N}$."
  3. c) "With a force meter we measure mass in newtons."
Solve
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The rover of a mission to Mars has a mass of $200\ \text{kg}$, as shown in the figure. a) Calculate its weight on Earth ($g = 9.8\ \text{m/s}^2$). b) Calculate its…

The rover of a mission to Mars has a mass of $200\ \text{kg}$, as shown in the figure.

Earth g = 9.8 m/s² Mars g = 3.7 m/s² m = 200 kg m = 200 kg P = ? P = ?
  1. a) Calculate its weight on Earth ($g = 9.8\ \text{m/s}^2$).
  2. b) Calculate its weight on Mars ($g = 3.7\ \text{m/s}^2$).
  3. c) By how many newtons does the rover become "lighter" when travelling to Mars? Has its mass changed? Justify your answer.
Solve

Weight on Other Celestial Bodies: First g, Then P

To calculate weight on another celestial body there are two steps: first obtain that body's gravity $g$ with $g = G M/R^2$, and then apply $P = m\,g$. Explore how the gravitational field changes depending on the mass of the source:

Gravity also decreases as you move away from the surface, because the distance to the center goes from $R$ to $R + h$: $g(h) = \dfrac{G M}{(R + h)^2}$. At an altitude of $400\ \text{km}$ (the International Space Station), $g$ drops only to about $8.7\ \text{m/s}^2$, barely 11%. The astronauts float there not because there is no gravity, but because the station and they are in free fall around Earth: they fall together, so nothing pushes against the floor. And on Earth itself, $g$ varies slightly: $9.83\ \text{m/s}^2$ at the poles and $9.78\ \text{m/s}^2$ at the equator.

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A space probe of $15\ \text{kg}$ arrives at Jupiter, where $g = 24.8\ \text{m/s}^2$. Calculate its weight there and compare it with its weight on Earth (…

A space probe of $15\ \text{kg}$ arrives at Jupiter, where $g = 24.8\ \text{m/s}^2$. Calculate its weight there and compare it with its weight on Earth ($g = 9.8\ \text{m/s}^2$): how many extra newtons does it weigh?

Solve
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Gravity at a height $h$ above the Earth's surface is calculated using $g(h) = \frac{G\times M}{(R + h)^2}$. Use $M = 5.97\times10^{24}\ \text{kg}$,…

Gravity at a height $h$ above the Earth's surface is calculated using $g(h) = \frac{G\times M}{(R + h)^2}$. Use $M = 5.97\times10^{24}\ \text{kg}$, $R = 6.37\times10^{6}\ \text{m}$, $G = 6.67\times10^{-11}\ \text{N}\times\text{m}^2/\text{kg}^2$ and $h = 4\times10^{5}\ \text{m}$, the height at which the International Space Station orbits.

  1. a) Calculate the value of $g$ at that height.
  2. b) Compare it with $9.8\ \text{m/s}^2$ at the surface: has it decreased much?
Solve
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The BepiColombo probe is travelling towards Mercury. a) Calculate the surface gravity of Mercury using $g = \frac{G\times M}{R^2}$, with…

The BepiColombo probe is travelling towards Mercury.

  1. a) Calculate the surface gravity of Mercury using $g = \frac{G\times M}{R^2}$, with $M = 3.30\times10^{23}\ \text{kg}$, $R = 2.44\times10^{6}\ \text{m}$ and $G = 6.67\times10^{-11}\ \text{N}\times\text{m}^2/\text{kg}^2$.
  2. b) How much will the probe weigh on Mercury if its mass is $300\ \text{kg}$?
  3. c) Compare that weight with its weight on Earth: where does it weigh more and what is the difference in newtons?
Solve

Comparing Weight Without Recalculating Everything

Weight of the same object on Earth, Mars, and the Moon: vertical arrows, large on Earth, medium on Mars, and small on the Moon m P Earth: P large m P Moon: P small m P Mars: P medium

This also works for other comparisons: a vertical jump with initial speed $v_0$ reaches $h = \dfrac{v_0^2}{2g}$, so the height is inversely proportional to $g$. And if you are told that on some world you weigh $2.5$ times more than on Earth, its gravity is $2.5$ times Earth's.

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A newly discovered planet has twice the mass of the Earth and twice the radius. a) By comparing with the expression $g = \frac{G\times M}{R^2}$ for Earth, deduce the…

A newly discovered planet has twice the mass of the Earth and twice the radius.

  1. a) By comparing with the expression $g = \frac{G\times M}{R^2}$ for Earth, deduce the value of $g$ on the surface of that planet (take Earth's surface gravity as $9.8\ \text{m/s}^2$).
  2. b) How much would an automated probe of $80\ \text{kg}$ weigh there?
Solve
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The height reached in a vertical jump with initial velocity $v_0$ is $h = \frac{v_0^2}{2\times g}$. An athlete pushes off with $v_0 = 3\ \text{m/s}$, as shown in the…

The height reached in a vertical jump with initial velocity $v_0$ is $h = \frac{v_0^2}{2\times g}$. An athlete pushes off with $v_0 = 3\ \text{m/s}$, as shown in the figure.

Earth Moon v₀ = 3 m/s v₀ = 3 m/s h = ? h = ?
  1. a) What height does it reach on Earth ($g = 9.8\ \text{m/s}^2$)?
  2. b) What height would it reach on the Moon ($g = 1.6\ \text{m/s}^2$)?
  3. c) How many times higher does the athlete jump on the Moon? Relate that factor to the ratio of the two gravities.
Solve
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An astronaut of $60\ \text{kg}$ travels through the Solar System and notices that on one of the worlds they visit they weigh about $2.5$ times more than on Earth. a) How…

An astronaut of $60\ \text{kg}$ travels through the Solar System and notices that on one of the worlds they visit they weigh about $2.5$ times more than on Earth.

  1. a) How much do they weigh on Earth ($g = 9.8\ \text{m/s}^2$)?
  2. b) What is the approximate value of $g$ on that world?
  3. c) From this list, deduce which world it is: Moon $1.6\ \text{m/s}^2$, Mars $3.7\ \text{m/s}^2$, Venus $8.9\ \text{m/s}^2$ and Jupiter $24.8\ \text{m/s}^2$.
  4. d) Calculate their exact weight on that world.
Solve

Back to the beginning: the 70 kg astronaut weighs $70 \times 9.8 = 686\ \text{N}$ on Earth and $70 \times 1.6 = 112\ \text{N}$ on the Moon. Their mass did not change; what changed was the $g$ of the celestial body attracting them.

Summary

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