Linear Momentum and Impulse
A loaded truck traveling slowly along the Mexico City–Puebla highway is much harder to stop than a fast motorcycle. Seat belts and airbags don't reduce the impact "by magic": they lengthen the time over which the force acts. And two skaters who push off each other fly apart in opposite directions without anyone pushing them from outside. All of this is explained by a quantity that combines mass and velocity: linear momentum.
Linear momentum: p = m · v
Stopping a soccer ball moving at $20\ \text{km/h}$ with your hands is easy, but trying to stop a bowling ball at that same speed would hurt your fingers. What quantity measures how hard it is to change a body's motion by combining its mass and its speed?
It says "relative to a frame of reference" because velocity depends on who measures it: a truck passenger is at rest relative to the truck, but moving relative to the sidewalk.
A tennis ball of $0.06\ \text{kg}$ leaves the serve at $50\ \text{m/s}$. a) Write the definition of linear momentum, $\vec{p} = m \cdot \vec{v}$, and state its SI unit.…
A tennis ball of $0.06\ \text{kg}$ leaves the serve at $50\ \text{m/s}$.
- a) Write the definition of linear momentum, $\vec{p} = m \cdot \vec{v}$, and state its SI unit.
- b) Calculate the magnitude of the linear momentum of the ball.
A lorry of $3000\ \text{kg}$ travels at $10\ \text{m/s}$ and a motorcycle with its rider, weighing $200\ \text{kg}$ in total, travels at $20\ \text{m/s}$. The diagram…
A lorry of $3000\ \text{kg}$ travels at $10\ \text{m/s}$ and a motorcycle with its rider, weighing $200\ \text{kg}$ in total, travels at $20\ \text{m/s}$. The diagram compares both vehicles.
- a) Calculate the linear momentum of each vehicle.
- b) How many times greater is the linear momentum of the lorry than that of the motorcycle?
- c) Explain why the lorry, although travelling more slowly, is much harder to stop.
A runner with a mass of $60\ \text{kg}$ moves in a straight line towards the east at $3\ \text{m/s}$. a) Calculate the magnitude of her linear momentum. b) State the…
A runner with a mass of $60\ \text{kg}$ moves in a straight line towards the east at $3\ \text{m/s}$.
- a) Calculate the magnitude of her linear momentum.
- b) State the direction and sense of the vector $\vec{p}$.
- c) What must happen for her linear momentum to change? Relate this to the net force acting on the runner.
Impulse and the impulse theorem
According to Newton's second law, if the net force on a body is not zero, its state of motion changes. Impulse measures how much it changes, taking into account how long the force acts.
Since $1\ \text{N} = 1\ \text{kg}\,\text{m/s}^2$, it follows that $1\ \text{N}\,\text{s} = 1\ \text{kg}\,\text{m/s}$: impulse and momentum are measured in the same unit, and that makes sense, because one is the change in the other.
For the same $\Delta p$, the greater $\Delta t$ is, the smaller the average force. That's why airbags work.
When pushing a supermarket trolley, an average force of $20\ \text{N}$ is exerted for $3\ \text{s}$. a) Write the definition of mechanical impulse,…
When pushing a supermarket trolley, an average force of $20\ \text{N}$ is exerted for $3\ \text{s}$.
- a) Write the definition of mechanical impulse, $\vec{I} = \vec{F} \cdot \Delta t$, and state its unit.
- b) Calculate the impulse received by the trolley.
A soccer ball of $0.4\ \text{kg}$, initially at rest on the ground, flies off at $15\ \text{m/s}$ during the kickoff of the game. a) Calculate the linear momentum of the…
A soccer ball of $0.4\ \text{kg}$, initially at rest on the ground, flies off at $15\ \text{m/s}$ during the kickoff of the game.
- a) Calculate the linear momentum of the soccer ball before and after the kick.
- b) Calculate the change in linear momentum of the soccer ball, $\Delta \vec{p}$.
Impulse is measured in $\text{N} \times \text{s}$ and linear momentum in $\text{kg} \times \text{m/s}$. a) Using the definition of a newton deduced from…
Impulse is measured in $\text{N} \times \text{s}$ and linear momentum in $\text{kg} \times \text{m/s}$.
- a) Using the definition of a newton deduced from $\vec{F} = m \cdot \vec{a}$, show that $1\ \text{N} \times \text{s} = 1\ \text{kg} \times \text{m/s}$.
- b) Explain why it makes physical sense for impulse and the change in linear momentum to be measured in the same unit.
A cyclist and their bicycle have a total mass of $80\ \text{kg}$ and travel at $54\ \text{km/h}$. a) Express the velocity in $\text{m/s}$. b) Calculate the linear…
A cyclist and their bicycle have a total mass of $80\ \text{kg}$ and travel at $54\ \text{km/h}$.
- a) Express the velocity in $\text{m/s}$.
- b) Calculate the linear momentum of the system.
- c) What impulse must be applied, as a minimum, to stop them? State its magnitude and sense.
In a volleyball match, a ball of $0.25\ \text{kg}$ reaches a player's hands at $10\ \text{m/s}$ and is returned in the opposite direction at $20\ \text{m/s}$. The…
In a volleyball match, a ball of $0.25\ \text{kg}$ reaches a player's hands at $10\ \text{m/s}$ and is returned in the opposite direction at $20\ \text{m/s}$. The contact with her hands lasts $0.05\ \text{s}$. The diagram shows the ball before and after contact.
- a) Taking the direction in which the ball leaves as positive, calculate the change in its linear momentum (be careful with the signs of the velocities).
- b) Apply the impulse-momentum theorem, $\vec{F} \cdot \Delta t = \Delta \vec{p}$, and calculate the average force that the player exerts on the ball.
A laboratory trolley of $2\ \text{kg}$, at rest on a track, receives an impulse of $10\ \text{N} \times \text{s}$ from a sharp blow. a) Applying…
A laboratory trolley of $2\ \text{kg}$, at rest on a track, receives an impulse of $10\ \text{N} \times \text{s}$ from a sharp blow.
- a) Applying $\vec{I} = \Delta \vec{p}$, calculate the velocity acquired by the trolley.
- b) What impulse would be needed to impart to it so that, starting from rest, it reached double the velocity? Reason the proportionality between impulse and final velocity.
A squash ball of $0.5\ \text{kg}$ hits a wall perpendicularly at $8\ \text{m/s}$ and bounces back at $6\ \text{m/s}$ in the opposite direction. The contact with the wall…
A squash ball of $0.5\ \text{kg}$ hits a wall perpendicularly at $8\ \text{m/s}$ and bounces back at $6\ \text{m/s}$ in the opposite direction. The contact with the wall lasts $0.1\ \text{s}$.
- a) Calculate the change in the linear momentum of the ball (be careful with the signs of the velocities).
- b) Calculate the average force that the wall exerts on the ball.
- c) By Newton's third law (action and reaction), what force does the ball exert on the wall during contact? State its magnitude and sense.
In a crash test, a car of $1200\ \text{kg}$ travelling at $72\ \text{km/h}$ impacts a wall and comes to a stop in $0.1\ \text{s}$ (take $g = 10\ \text{m/s}^2$). a)…
In a crash test, a car of $1200\ \text{kg}$ travelling at $72\ \text{km/h}$ impacts a wall and comes to a stop in $0.1\ \text{s}$ (take $g = 10\ \text{m/s}^2$).
- a) Express the velocity in $\text{m/s}$.
- b) Calculate the change in the linear momentum of the car during the collision.
- c) Calculate the average force that the wall exerts on the car.
- d) Calculate the weight of the car and express the force of the collision as a "number of times the weight": explain why collisions at that speed are so destructive.
A driver of $70\ \text{kg}$ is travelling at $54\ \text{km/h}$ and suffers a head-on collision that stops the car almost instantly. a) Express the velocity in…
A driver of $70\ \text{kg}$ is travelling at $54\ \text{km/h}$ and suffers a head-on collision that stops the car almost instantly.
- a) Express the velocity in $\text{m/s}$ and calculate the change in the driver's linear momentum.
- b) The airbag takes $0.15\ \text{s}$ to stop the driver: calculate the average force it exerts on them.
- c) Without an airbag, the driver's head, having a mass of about $5\ \text{kg}$, would hit the steering wheel and stop in barely $0.01\ \text{s}$: calculate the change in the linear momentum of the head and the average force it would withstand, and compare it with the force on the head if the airbag stopped it in $0.15\ \text{s}$.
- d) In view of the results, explain the two functions of the airbag: what it achieves by increasing the braking time (relate it to $\vec{F} \cdot \Delta t = \Delta \vec{p}$) and how it distributes the force over the body.
Conservation of linear momentum
If you are standing on skates on an ice rink and throw a heavy ball forward, you are pushed backward. Why does pushing a mass forward make you recoil without anyone pushing you from outside?
It is the same idea as the third law: each body exerts a force on the other, and whatever momentum one gains, the other loses.
Two ice skaters, initially at rest and facing each other, push each other with their hands and move away in opposite directions. The diagram shows the situation before…
Two ice skaters, initially at rest and facing each other, push each other with their hands and move away in opposite directions. The diagram shows the situation before and after the push.
- a) What is the total linear momentum of the system formed by the two skaters before pushing each other?
- b) Given that the external forces acting on the system are negligible during the push, what is the total linear momentum afterwards? State the principle on which you base your answer.
- c) If one skater has twice the mass of the other, which of the two moves off with a higher speed? Reason your answer.
In a game of billiards, the cue ball hits another ball that was at rest. a) During the collision, very intense forces act between the balls, while external forces…
In a game of billiards, the cue ball hits another ball that was at rest.
- a) During the collision, very intense forces act between the balls, while external forces (weight, normal force, and friction with the cloth) are comparatively negligible: what quantity is conserved for the system formed by the two balls?
- b) Is the velocity of each ball necessarily conserved? Explain the difference between conserving the linear momentum of the system and conserving the velocity of each body.
A skater of $60\ \text{kg}$, at rest on the ice, throws a backpack of $3\ \text{kg}$ horizontally at $10\ \text{m/s}$. a) What is the total linear momentum of the…
A skater of $60\ \text{kg}$, at rest on the ice, throws a backpack of $3\ \text{kg}$ horizontally at $10\ \text{m/s}$.
- a) What is the total linear momentum of the skater-backpack system before the throw?
- b) Applying the conservation of linear momentum, calculate the recoil velocity of the skater.
- c) Relate this phenomenon to rocket propulsion.
Collisions: elastic and inelastic
Two marbles collide and bounce off each other; two balls of clay that collide at the same speed get squashed and move together very slowly. What is it that changes between one case and the other?
In every collision there is a transfer of energy: the kinetic energy that is "missing" in an inelastic collision doesn't disappear; it is converted into deformation, heat and sound (less useful forms). If the total kinetic energy doesn't change, the collision is elastic.
In a fairground dodgem ride, a bumper car of $2\ \text{kg}$ moving at $3\ \text{m/s}$ hits from behind another car of $4\ \text{kg}$ that is stationary, and they remain…
In a fairground dodgem ride, a bumper car of $2\ \text{kg}$ moving at $3\ \text{m/s}$ hits from behind another car of $4\ \text{kg}$ that is stationary, and they remain locked together after the collision. The diagram shows the situation before and after the collision.
- a) Calculate the total linear momentum of the system before the collision.
- b) Applying the conservation of linear momentum, calculate the velocity with which the two locked cars move.
- c) Check that the total linear momentum after the collision matches the initial momentum.
Two bumper cars collide head-on: one of $3\ \text{kg}$ moving at $4\ \text{m/s}$ and another of $1\ \text{kg}$ coming in the opposite direction, also at $4\ \text{m/s}$.…
Two bumper cars collide head-on: one of $3\ \text{kg}$ moving at $4\ \text{m/s}$ and another of $1\ \text{kg}$ coming in the opposite direction, also at $4\ \text{m/s}$. After the collision, they remain locked together.
- a) Taking the direction of the more massive car as positive, calculate the total linear momentum before the collision (be careful with the signs).
- b) Calculate the velocity of the combined system after the collision and state in which direction they move.
- c) Explain what would have happened if the total linear momentum before the collision had been zero.
A tanker wagon of $20000\ \text{kg}$ moving at $4\ \text{m/s}$ along a straight track collides with two coupled wagons, of $10000\ \text{kg}$ each, that are stationary,…
A tanker wagon of $20000\ \text{kg}$ moving at $4\ \text{m/s}$ along a straight track collides with two coupled wagons, of $10000\ \text{kg}$ each, that are stationary, and the whole assembly becomes coupled together after the manoeuvre.
- a) Calculate the linear momentum of the system before the collision.
- b) Calculate the velocity of the three wagons combined after coupling.
- c) Justify, by stating the corresponding principle and the conditions satisfied, why the conservation of linear momentum can be applied even though the collision deforms the couplings.
A steel ball of $2\ \text{kg}$ rolling at $6\ \text{m/s}$ collides head-on with another ball of $1\ \text{kg}$ that is at rest. After the collision, the ball of…
A steel ball of $2\ \text{kg}$ rolling at $6\ \text{m/s}$ collides head-on with another ball of $1\ \text{kg}$ that is at rest. After the collision, the ball of $2\ \text{kg}$ continues in the same direction at $2\ \text{m/s}$.
- a) Applying the conservation of linear momentum, calculate the velocity of the ball of $1\ \text{kg}$ after the collision.
- b) The kinetic energy of a body is $E_c = \frac{1}{2} \times m \times v^2$: calculate the total kinetic energy of the system before and after the collision.
- c) In view of the previous section, classify the collision (elastic or inelastic) and explain the criterion you used.
After the collision: friction stops the combined object
A collision lasts a fraction of a second, and in that instant momentum is conserved. But what happens afterward matters too: if the resulting combined object slides on a table or the floor, friction gradually slows it until it stops. A typical case is a bullet embedding itself in a wooden block. How are the two momentum situations, the collision and the slowing down, connected?
It is solved in two stages, each with its own tool:
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During the collision (very brief): the internal forces are enormous and friction is negligible. Conservation of momentum is applied to find the velocity $v$ right after impact.
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After the collision: there is no longer any bullet-block interaction; friction acts and Newton's second law is applied.
In a ballistics laboratory, a bullet of $0.02\ \text{kg}$ is fired horizontally at $400\ \text{m/s}$ into a wooden block of $1.98\ \text{kg}$ at rest on a horizontal…
In a ballistics laboratory, a bullet of $0.02\ \text{kg}$ is fired horizontally at $400\ \text{m/s}$ into a wooden block of $1.98\ \text{kg}$ at rest on a horizontal surface. The bullet becomes embedded in the block and the combined system slides until coming to rest. The coefficient of friction between the block and the surface is $\mu = 0.4$ (take $g = 10\ \text{m/s}^2$). The diagram shows the instant before impact and the system sliding afterwards.
- a) Apply the conservation of linear momentum to the collision and calculate the velocity of the bullet-block system immediately after impact.
- b) Calculate the deceleration of the system (remember that $F_r = \mu \times N$).
- c) Calculate the distance travelled by the system before coming to rest (use $v^2 = 2 \times a \times x$).
Explosions and recoil
An explosion or a launch is, for linear momentum, the reverse of an inelastic collision: a body (or a system at rest) separates into several fragments. Think of the fireworks in Tultepec: the rocket bursts and the fragments fly off in all directions, but the total momentum of the whole is the same as it was before.
An astronaut of $80\ \text{kg}$ (including spacesuit) is at rest next to her spacecraft, floating in space, and throws a tool of $2\ \text{kg}$ away from herself at…
An astronaut of $80\ \text{kg}$ (including spacesuit) is at rest next to her spacecraft, floating in space, and throws a tool of $2\ \text{kg}$ away from herself at $8\ \text{m/s}$.
- a) What is the total linear momentum of the system before the throw?
- b) Calculate the recoil velocity of the astronaut.
- c) How can she use this same principle to return to the spacecraft if she is drifting? Propose a manoeuvre and justify it.
A firework rocket of $5\ \text{kg}$ is moving horizontally at $8\ \text{m/s}$ when it explodes into two fragments. A fragment of $3\ \text{kg}$ continues in the same…
A firework rocket of $5\ \text{kg}$ is moving horizontally at $8\ \text{m/s}$ when it explodes into two fragments. A fragment of $3\ \text{kg}$ continues in the same direction at $12\ \text{m/s}$. The diagram shows the rocket before exploding and the two fragments after.
- a) Calculate the linear momentum of the rocket before the explosion.
- b) Applying the conservation of linear momentum, calculate the velocity of the other fragment, of $2\ \text{kg}$.
- c) Now suppose that the $3\ \text{kg}$ fragment were to move off at $20\ \text{m/s}$: calculate again the velocity of the $2\ \text{kg}$ fragment and interpret the sign of the result.
A worker of $60\ \text{kg}$ cleaning plastics from a lagoon is standing in a boat of $120\ \text{kg}$, both at rest on the water. Suddenly, he jumps horizontally towards…
A worker of $60\ \text{kg}$ cleaning plastics from a lagoon is standing in a boat of $120\ \text{kg}$, both at rest on the water. Suddenly, he jumps horizontally towards the jetty with a speed of $3\ \text{m/s}$.
- a) Applying the conservation of linear momentum, calculate the recoil velocity of the boat.
- b) What is the total linear momentum of the worker-boat system before and after the jump?
- c) Explain why the conservation of linear momentum is no longer useful for predicting the movement if the worker pushes off the jetty to jump: is the worker-boat system still an isolated system?
Two laboratory trolleys, of $1\ \text{kg}$ and $3\ \text{kg}$, are at rest and in contact, with a compressed spring between them. Upon releasing the spring, the trolley…
Two laboratory trolleys, of $1\ \text{kg}$ and $3\ \text{kg}$, are at rest and in contact, with a compressed spring between them. Upon releasing the spring, the trolley of $1\ \text{kg}$ moves off at $6\ \text{m/s}$. The diagram shows the trolleys before and after releasing the spring.
- a) Applying the conservation of linear momentum, calculate the velocity with which the trolley of $3\ \text{kg}$ moves off.
- b) Check that the total linear momentum of the system after the "explosion" is still zero.
- c) If the spring is compressed further and the trolley of $3\ \text{kg}$ moves off at $3\ \text{m/s}$, at what velocity does the trolley of $1\ \text{kg}$ move off?
- d) Based on the results, explain why, in an explosion, the lighter fragment always moves off faster than the heavier one.
Go back to the beginning: the truck is hard to stop because of its enormous momentum $mv$; the airbag lengthens $\Delta t$ so that the same $\Delta p$ requires less force; and the skaters separate because their total momentum, which was zero, is split into two equal and opposite parts.