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Relativistic, quantum, nuclear, and particle physics · Relativity

Length contraction, time dilation and relativistic energy

Every second, muons created by cosmic rays several kilometres up in the atmosphere reach the Earth. On their own clock they live for barely $2,2\ \mu\text{s}$: at the speed they travel, they should cover only a few hundred metres before decaying, a long way short of the ground. And yet detectors on the surface register them by the million. The explanation is not that muons live longer: it is that time itself passes differently for someone watching them rush by.

Before you start, make sure you know: Kinetic energy and potential energy (1st Bachillerato)
Before you start, make sure you know: Power, energy consumption and efficiency (1st Bachillerato)

The Lorentz factor

When the lifetime of unstable particles is measured in accelerators at different speeds ($0{,}1\cdot c \to 1\ \mu\text{s}$; $0{,}8\cdot c \to 1{,}7\ \mu\text{s}$; $0{,}99\cdot c \to 7{,}1\ \mu\text{s}$), the time observed in the laboratory shoots up compared with the time at rest: what mathematical factor determines the speed above which classical physics stops being valid?

Graph of the Lorentz factor γ against speed v/c, showing how it stays close to 1 at low speeds and diverges towards infinity as it approaches the speed of light. v/c γ v = c 0,1c → 1,005 0,5c → 1,15 0,9c → 2,29

This table of values gives a feel for how quickly $\gamma$ grows close to $c$: at $0,1c$ it is barely $1,005$ (effects of roughly half a per cent), but at $0,99c$ it is already $7,09$, and it keeps growing ever faster.

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Length contraction is given by $L = \frac{L_0}{\gamma}$. A spacecraft measures $L_0 = 100\ \text{m}$ at rest and travels at $\gamma = 2$. What length does an observer on…

Length contraction is given by $L = \frac{L_0}{\gamma}$. A spacecraft measures $L_0 = 100\ \text{m}$ at rest and travels at $\gamma = 2$. What length does an observer on Earth measure?

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The Lorentz factor is $\gamma = \frac{1}{\sqrt{1 - \frac{v^2}{c^2}}}$, from which $v = c \cdot \sqrt{1 - \frac{1}{\gamma^2}}$. a) Calculate the speed of a spacecraft…

The Lorentz factor is $\gamma = \frac{1}{\sqrt{1 - \frac{v^2}{c^2}}}$, from which $v = c \cdot \sqrt{1 - \frac{1}{\gamma^2}}$.

  1. a) Calculate the speed of a spacecraft travelling with $\gamma = 2$, expressed as a fraction of $c$.
  2. b) Express that speed in $\text{m/s}$ (given: $c = 3 \cdot 10^{8}\ \text{m/s}$).
Solve

Time dilation

Light clock: at rest the light goes straight up and down; seen moving it travels a longer zigzag, so each tick lasts longer. at rest: tick = Δt₀ (proper time) v moving: the light travels a longer path → the tick lasts Δt = γ·Δt₀ > Δt₀
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A phenomenon lasts $\Delta t_0 = 10\ \text{s}$ as measured in its proper reference frame. For an observer seeing it pass at high speed, the Lorentz factor is…

A phenomenon lasts $\Delta t_0 = 10\ \text{s}$ as measured in its proper reference frame. For an observer seeing it pass at high speed, the Lorentz factor is $\gamma = 2$. Given that time dilation is $\Delta t = \gamma \cdot \Delta t_0$, how long does the phenomenon last for that observer?

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An astronaut travels in a spacecraft at $\gamma = 1,25$. From Earth, the trip is measured to last $8$ years. a) Using $\Delta t = \gamma \cdot \Delta t_0$, by how many…

An astronaut travels in a spacecraft at $\gamma = 1,25$. From Earth, the trip is measured to last $8$ years.

  1. a) Using $\Delta t = \gamma \cdot \Delta t_0$, by how many years does the astronaut age?
  2. b) If he left at $30$ years of age, how old is he upon return, and how old is his twin brother, who stayed on Earth?
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A muon is created at an altitude of $15\ \text{km}$, travels at $v = 0,9995c$ with $\gamma = 31,6$, and its proper mean lifetime is $2,2\ \mu\text{s}$ (given:…

A muon is created at an altitude of $15\ \text{km}$, travels at $v = 0,9995c$ with $\gamma = 31,6$, and its proper mean lifetime is $2,2\ \mu\text{s}$ (given: $c = 3 \cdot 10^{8}\ \text{m/s}$). The diagram compares both viewpoints.

according to Earth muon v = 0,9995c 15 km Δt = ? d = ? according to the muon muon at rest proper lifetime: 2,2 μs ground moves up L = ?
  1. a) Calculate its mean lifetime seen from Earth ($\Delta t = \gamma \cdot \Delta t_0$).
  2. b) Calculate the average distance it travels according to Earth and conclude whether it can reach the surface.
  3. c) From the muon's point of view, its lifetime is $2,2\ \mu\text{s}$ but the atmosphere contracts: calculate the thickness of the atmosphere it passes through ($L = \frac{L_0}{\gamma}$) and the distance it travels in its proper lifetime, and check that you reach the same conclusion as in b).
  4. d) Explain why both observers agree on the final result (the muon reaches the ground) even though they explain it differently.
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Length contraction and the twin paradox

Comparison of the length of a spacecraft at rest (L₀) and of the same spacecraft moving at relativistic speed, shorter in the direction of travel (L = L₀/γ), with the same height. at rest: L₀ in motion: L = L₀/γ v the same spacecraft, seen at rest and in motion
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Length contraction only affects the dimension parallel to motion. A spacecraft with a proper length of $50\ \text{m}$ and a proper height of $20\ \text{m}$ travels…

Length contraction only affects the dimension parallel to motion. A spacecraft with a proper length of $50\ \text{m}$ and a proper height of $20\ \text{m}$ travels horizontally at $\gamma = 1,25$. The diagram shows its proper dimensions.

v proper length: 50 m proper height: 20 m from Earth: L = ? h = ?
  1. a) What length is measured from Earth ($L = \frac{L_0}{\gamma}$)?
  2. b) What height is measured from Earth? Justify your answer.
Solve
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A spacecraft of proper length $L_0 = 120\ \text{m}$ travels at $\gamma = 1,5$. a) What length does an observer on Earth measure ($L = \frac{L_0}{\gamma}$)? b) If the…

A spacecraft of proper length $L_0 = 120\ \text{m}$ travels at $\gamma = 1,5$.

  1. a) What length does an observer on Earth measure ($L = \frac{L_0}{\gamma}$)?
  2. b) If the trip lasts $10$ years for Earth, how long does it last for the crew ($\Delta t = \gamma \cdot \Delta t_0$)?
  3. c) Reason which of the two observers measures the proper time of the journey and why.
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Proxima Centauri, the closest star to the Sun, is $4,2$ light years away as measured from Earth. A spacecraft travels there at $\gamma = 2$, which corresponds to…

Proxima Centauri, the closest star to the Sun, is $4,2$ light years away as measured from Earth. A spacecraft travels there at $\gamma = 2$, which corresponds to $v = 0,866c$ (obtained from $v = c \cdot \sqrt{1 - \frac{1}{\gamma^2}}$). Remember that a light year is the distance light travels in one year. The diagram summarizes the journey.

Earth Proxima Centauri v = 0,866c (γ = 2) 4,2 light years (measured from Earth) L for the crew = ?
  1. a) How long does the journey last for observers on Earth?
  2. b) How long does it last for the crew ($\Delta t = \gamma \cdot \Delta t_0$)?
  3. c) What Earth–star distance does the crew measure ($L = \frac{L_0}{\gamma}$)?
  4. d) Check the consistency of the results: the crew must travel the contracted distance from part c) at speed $0,866c$ in the time from part b). Verify this numerically.
Solve

Mass-energy equivalence: $E = m\cdot c^2$

When the mass of the fragments after a nuclear fission reaction is measured with extreme precision, the final mass is $0{,}1\,\%$ less than the initial mass, while an immense amount of thermal energy is released: where has the missing mass gone?

In fission the mass of the fragments is slightly less than the initial mass: the missing mass is released as energy, E = Δm·c². m initial mass fragments: 0.999·m energy the missing mass, Δm, comes out as energy: E = Δm·c² c² is huge: 1 g of mass is equivalent to 9·10¹³ J
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The energy associated with a rest mass is $E = m \cdot c^2$, with $c = 3 \cdot 10^{8}\ \text{m/s}$. Calculate the energy corresponding to $1\ \text{kg}$ of mass and…

The energy associated with a rest mass is $E = m \cdot c^2$, with $c = 3 \cdot 10^{8}\ \text{m/s}$. Calculate the energy corresponding to $1\ \text{kg}$ of mass and express it in standard form.

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The Sun radiates a power of $3,9 \cdot 10^{26}\ \text{W}$ by converting part of its mass into energy. a) Calculate the energy it emits each second. b) Using…

The Sun radiates a power of $3,9 \cdot 10^{26}\ \text{W}$ by converting part of its mass into energy.

  1. a) Calculate the energy it emits each second.
  2. b) Using $E = m \cdot c^2$ with $c = 3 \cdot 10^{8}\ \text{m/s}$, calculate the mass that the Sun converts into energy each second.
  3. c) Express the result in tonnes ($1\ \text{t} = 10^{3}\ \text{kg}$).
Solve
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In a positron emission tomography (PET) scan, a positron emitted by a radioactive tracer annihilates with an electron in the tissue, and all its mass is converted into…

In a positron emission tomography (PET) scan, a positron emitted by a radioactive tracer annihilates with an electron in the tissue, and all its mass is converted into energy, emitted as two gamma photons. The mass of each particle is $9,11 \cdot 10^{-31}\ \text{kg}$ (given: $c = 3 \cdot 10^{8}\ \text{m/s}$). The diagram represents the process.

electron positron annihilation γ γ E of each photon = ?
  1. a) Calculate the total mass annihilated in the event.
  2. b) Calculate the energy released ($E = m \cdot c^2$).
  3. c) What energy does each photon carry if the two share the energy equally?
  4. d) Explain why matter-antimatter annihilation is the most efficient possible process for converting mass into energy, and compare it with solar fusion, which converts less than $1\ \%$ of the mass.
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The Sun has a mass of $2 \cdot 10^{30}\ \text{kg}$ and radiates a power of $3,9 \cdot 10^{26}\ \text{W}$ by converting mass into energy ($E = m \cdot c^2$;…

The Sun has a mass of $2 \cdot 10^{30}\ \text{kg}$ and radiates a power of $3,9 \cdot 10^{26}\ \text{W}$ by converting mass into energy ($E = m \cdot c^2$; $c = 3 \cdot 10^{8}\ \text{m/s}$).

  1. a) Calculate the mass the Sun loses each second.
  2. b) Calculate the mass lost in $10^{10}$ years ($3,2 \cdot 10^{17}\ \text{s}$), which is of the order of its total lifetime.
  3. c) What fraction of the solar mass does this represent? Express it as a percentage.
  4. d) Conclude whether radiation significantly changes the Sun's mass over its lifetime and comment on why its gravity is barely affected.
Solve

Back to the beginning: at $v = 0{,}998\cdot c$ (where $\gamma \approx 15{,}8$), the lifetime measured from Earth is dilated to $\Delta t = \gamma\cdot\Delta t_0 \approx 15{,}8 \cdot 2{,}2\ \mu\text{s} \approx 35\ \mu\text{s}$, enough time to cover $d = v\cdot\Delta t \approx 10{,}4\ \text{km}$, so that muons created at a height of $10\ \text{km}$ reach the detectors at the surface.

Summary

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