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Vibrations and waves · Optics

Optical systems: thin lenses and mirrors

A magnifying glass, a pair of glasses, a camera lens, a telescope and a car's rear-view mirror are all applications of the same idea: a curved surface (or a pair of them) that bends light rays in a controlled way to form an image. A single equation and one sign convention are enough to describe all of them.

Before you start, make sure you know: Light (4th ESO)

Thin lenses: converging and diverging

If you look at a printed page through a magnifying glass resting on the paper and slowly move it away, the letters first get bigger and stay the right way up, but at a certain distance the image blurs completely and then reappears upside down; by contrast, when you look through the peephole of a door, everything always looks upright and reduced, whatever the distance. Why do two curved pieces of glass produce such radically opposite effects?

Biconvex converging lens: three rays parallel to the optical axis are refracted by the lens and converge at the image focus F′. F′ converging lens optical axis parallel rays Tracing the three principal rays in a thin converging lens: an object placed beyond 2f forms a real, inverted image, smaller than the object, between F' and 2F'. object image F F'
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In the optics kit in the laboratory there are two lenses: one is thicker at the centre than at the edges, and the other is thicker at the edges than at the centre. a)…

In the optics kit in the laboratory there are two lenses: one is thicker at the centre than at the edges, and the other is thicker at the edges than at the centre.

  1. a) State which one is converging and which one is diverging.
  2. b) Describe what happens to a beam of rays parallel to the optical axis when passing through each of them: do they converge at a point or diverge as if coming from a point?
Solve
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An object is placed in front of a converging lens at a distance greater than twice its focal length. a) State the rules for drawing the three principal rays of a…

An object is placed in front of a converging lens at a distance greater than twice its focal length.

  1. a) State the rules for drawing the three principal rays of a converging lens (the ray parallel to the axis, the ray passing through the centre, and the ray passing through the object focus).
  2. b) Draw the ray diagram in your notebook and determine the characteristics of the image: is it real or virtual, upright or inverted, larger or smaller than the object?

You can do it on paper and send a photo with your answer.

Solve
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A watchmaker uses a magnifying glass to inspect the mechanism of a watch. a) What type of lens is a magnifying glass: converging or diverging? b) Where must the object…

A watchmaker uses a magnifying glass to inspect the mechanism of a watch.

  1. a) What type of lens is a magnifying glass: converging or diverging?
  2. b) Where must the object be placed relative to the focus of the lens for the magnifying glass to work?
  3. c) State the characteristics of the observed image (real or virtual, upright or inverted, larger or smaller).
Solve

The fundamental equation and lateral magnification

When you project the bulb of a lamp onto a piece of card using a lens with a focal length of $10\ \text{cm}$, you find that if you place the lamp at $30\ \text{cm}$ the image is in focus at $15\ \text{cm}$, but if you bring it closer, to $20\ \text{cm}$, the card has to be moved back to $20\ \text{cm}$. What mathematical rule determines exactly the distance and size of the image that will be formed?

Animation of a converging lens with focal length 60: the object moves away from and towards the lens by sliding; the real, inverted image gets closer and smaller, or moves away and grows, according to 1/f = 1/s + 1/s'. The distances s and s' update and everything returns to the initial state. object, s image, s' s s'
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A luminous object is placed $s = 30\ \text{cm}$ from a thin converging lens with focal length $f = 10\ \text{cm}$. Use the thin lens equation $1/f = 1/s + 1/s'$ with…

A luminous object is placed $s = 30\ \text{cm}$ from a thin converging lens with focal length $f = 10\ \text{cm}$. Use the thin lens equation $1/f = 1/s + 1/s'$ with this sign convention: $s$ is positive for a real object, $s'$ is positive if the image is real and negative if virtual, and $f$ is positive for converging lenses and negative for diverging lenses.

  1. a) Calculate the image distance $s'$.
  2. b) State whether the image is real or virtual and whether it can be projected onto a screen.
Solve
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A magnifying glass is a converging lens of focal length $f = 10\ \text{cm}$. A stamp placed $s = 6\ \text{cm}$ from the lens is observed. Observe the diagram: a)…

A magnifying glass is a converging lens of focal length $f = 10\ \text{cm}$. A stamp placed $s = 6\ \text{cm}$ from the lens is observed. Observe the diagram:

F F stamp s = 6 cm f = 10 cm s' = ?
  1. a) Calculate the image distance $s'$ and explain the meaning of its sign.
  2. b) Calculate the magnification and explain the meaning of its sign.
  3. c) State the characteristics of the image and why it cannot be formed on a screen.
Solve
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The wing mirror of a car is a convex mirror with focal length $f = -0,5\ \text{m}$. A car $1,5\ \text{m}$ high is travelling $s = 10\ \text{m}$ from the mirror. Observe…

The wing mirror of a car is a convex mirror with focal length $f = -0,5\ \text{m}$. A car $1,5\ \text{m}$ high is travelling $s = 10\ \text{m}$ from the mirror. Observe the diagram:

F f = −0,5 m h = 1,5 m car s = 10 m s' = ?, h' = ?
  1. a) Calculate the position of the image.
  2. b) Calculate the magnification and height of the image.
  3. c) In light of the result, explain the meaning of the warning "objects in mirror are closer than they appear".
Solve

Spherical mirrors

Concave spherical mirror with its optical axis, the vertex V, the focus F halfway along and the centre of curvature C, with two parallel rays that are reflected through the focus. V F C f f concave mirror incident rays optical axis
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An object $10\ \text{cm}$ high is placed $s = 60\ \text{cm}$ from a converging lens with focal length $f = 20\ \text{cm}$. Use $1/f = 1/s + 1/s'$ and the magnification…

An object $10\ \text{cm}$ high is placed $s = 60\ \text{cm}$ from a converging lens with focal length $f = 20\ \text{cm}$. Use $1/f = 1/s + 1/s'$ and the magnification $A = -s'/s$, with the usual sign convention (positive distances for real objects and real images). Observe the diagram:

F F 2F 2F h = 10 cm object s = 60 cm f = 20 cm s' = ? h' = ?
  1. a) Calculate the image distance $s'$.
  2. b) Calculate the magnification and the height of the image.
  3. c) Describe the image: real or virtual, upright or inverted, larger or smaller.
Solve
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A concave spherical laboratory mirror has a radius of curvature of $R = 40\ \text{cm}$. An object $4\ \text{cm}$ high is placed $s = 30\ \text{cm}$ from the mirror.…

A concave spherical laboratory mirror has a radius of curvature of $R = 40\ \text{cm}$. An object $4\ \text{cm}$ high is placed $s = 30\ \text{cm}$ from the mirror. Recall that $f = R/2$ and use the same equation $1/f = 1/s + 1/s'$ with the usual convention (positive distances for real objects and images). Observe the diagram:

C h = 4 cm object R = 40 cm s = 30 cm s' = ?, h' = ?
  1. a) Calculate the focal length of the mirror.
  2. b) Calculate the position of the image.
  3. c) Calculate the magnification and height of the image, and state whether it can be captured on a screen.
Solve
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It is desired to design a projector that forms a real image three times larger than the object on a screen located $4\ \text{m}$ from the object. Observe the diagram: a)…

It is desired to design a projector that forms a real image three times larger than the object on a screen located $4\ \text{m}$ from the object. Observe the diagram:

object lens screen s = ? s' = ? s + s' = 4 m
  1. a) Given that for a real image the object-screen distance is $s + s'$, set up the system of equations with the magnification condition $|A| = s'/s = 3$ and calculate $s$ and $s'$.
  2. b) Calculate the focal length of the required lens and its power in dioptres.
  3. c) Reason why a diverging lens would not be suitable for this project.
Solve

Lens power and applications

At the optician's you are never prescribed lenses by their focal length in centimetres, but with values such as "$+2{,}00\ \text{D}$" or "$-1{,}50\ \text{D}$", and if the specialist places two lenses together in the trial frame their effects simply add up. How can we measure the refractive capacity of a lens so that combining several is as straightforward as an ordinary addition?

Comparison of a biconvex converging lens of +2 D, with a focal length of 0,5 m for long-sightedness, and a biconcave diverging lens of −2,5 D, with a focal length of −0,4 m for short-sightedness. F F +2 D (converging, long-sightedness) f = +0,5 m −2,5 D (diverging, short-sightedness) f = −0,4 m
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Match each application with the type of mirror and briefly explain why: a car's wing mirror, a dentist's mirror used to view a magnified tooth, and a car headlight…

Match each application with the type of mirror and briefly explain why: a car's wing mirror, a dentist's mirror used to view a magnified tooth, and a car headlight mirror directing light from the bulb forward in an almost parallel beam.

  1. a) Wing mirror.
  2. b) Dentist's mirror.
  3. c) Headlight mirror.
Solve
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During an eye test, a hypermetropic (long-sighted) patient is prescribed lenses of $+2\ \text{D}$ and a myopic (short-sighted) patient is prescribed lenses of…

During an eye test, a hypermetropic (long-sighted) patient is prescribed lenses of $+2\ \text{D}$ and a myopic (short-sighted) patient is prescribed lenses of $-2,5\ \text{D}$. Recall that $P = 1/f$ with $f$ in metres.

  1. a) Calculate the focal length of each lens and state its type.
  2. b) Explain what focusing problem each patient has (where is the image of a distant object formed relative to the retina?) and why the sign of their lens corrects it.
Solve
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A refracting telescope belonging to an astronomy club has an objective lens of focal length $f_{\text{ob}} = 90\ \text{cm}$ and an eyepiece of…

A refracting telescope belonging to an astronomy club has an objective lens of focal length $f_{\text{ob}} = 90\ \text{cm}$ and an eyepiece of $f_{\text{oc}} = 3\ \text{cm}$. For a very distant object, the angular magnification of the telescope is $M = f_{\text{ob}}/f_{\text{oc}}$ and the length of the tube is approximately the sum of the two focal lengths. Observe the diagram:

L = ? distant star objective eyepiece common focus f objective = 90 cm f eyepiece = 3 cm
  1. a) Calculate the angular magnification of the telescope.
  2. b) Calculate the approximate length of the tube.
  3. c) Explain the role of each lens and why it is desirable for the objective to have a large diameter (think about the light it captures from a faint star).
Solve

Sign conventions and checking images

The convention in this section uses positive distances for real objects and images. Many exams use the Cartesian convention: origin at the lens and positive axis pointing to the right, with incident light travelling from left to right. A real object then has $sc<0$; an image on the right has $s'_c>0$.

To draw it, extend backwards the ray that arrives parallel and leaves diverging as if it came from the nearer focus; cross it with the ray through the optical centre. Always state the position, size, orientation and whether the image is real or virtual. An algebraic derivation and a ray diagram must predict the same image.

The diagram links the main ideas:

Ray tracing for a diverging lens: a real object placed at 20 cm produces a virtual, upright and smaller image between the lens and the object. Diverging lens F′ F Real object Virtual image

Summary

See all the exercises in this section