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Secondary 6 · Physics
Interaction · Kinematics

Free Fall

Before you start, make sure you know: Uniformly accelerated rectilinear motion (Secondary Year 3 (first cycle))

A ripe mango lets go of the tree and hits the ground in an instant, while a leaf floats down slowly. On the Moon, where there is no air, an astronaut dropped a hammer and a feather at the same time and they landed together. Does the heavier object fall faster? At the end of this page you will answer with numbers.

Gravity as a Constant Acceleration

Free fall is the motion of an object under the influence of gravity alone, vertically and with no air friction. It is a vertical UAM (uniformly accelerated motion) with acceleration $a = g$.

A sphere falls from rest; the marks at equal 1 s intervals get farther and farther apart, with distances in the ratio 1, 3, 5, 7, because the speed increases g ≈ 9.8 m/s² 0 s 1 s: 4.9 m 2 s: 19.6 m 3 s: 44.1 m 4 s: 78.4 m ground

Notice that between successive marks the sphere travels 4.9 m, 14.7 m, 24.5 m, 34.3 m, that is, in the ratio 1 : 3 : 5 : 7.

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On the Moon, where there is no air, an astronaut dropped a hammer and a feather at the same time and both reached the ground at the same time. The scene is shown in the…

On the Moon, where there is no air, an astronaut dropped a hammer and a feather at the same time and both reached the ground at the same time. The scene is shown in the figure.

hammer feather
  1. a) What does this fact show about falling objects when there is no air resistance?
  2. b) What is the acceleration called with which objects fall on Earth, and what is its approximate value?
Solve
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In free fall, the speed of an object increases by $9.8\ \text{m/s}$ every second. An object is dropped from rest. a) Calculate its speed at $1\ \text{s}$, $2\ \text{s}$…

In free fall, the speed of an object increases by $9.8\ \text{m/s}$ every second. An object is dropped from rest.

  1. a) Calculate its speed at $1\ \text{s}$, $2\ \text{s}$ and $3\ \text{s}$.
  2. b) What acceleration does the object have during the fall, and which letter is used to represent it?
Solve

Speed and Distance in Free Fall

When a ball is released from rest, it is measured to fall about $5\ \text{m}$ in $1\ \text{s}$, about $20\ \text{m}$ in $2\ \text{s}$, and about $45\ \text{m}$ in $3\ \text{s}$. The distance does not grow steadily: it shoots up. What is the relationship between time and distance?

In the $v(t)$ graph you see a line with slope $g$. The position graph curves more and more, because the speed never stops increasing.

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A stone is dropped from rest. With $g = 9.8\ \text{m/s}^2$, calculate its velocity after $2\ \text{s}$ of falling using $v = v_0 + g \times t$.

A stone is dropped from rest. With $g = 9.8\ \text{m/s}^2$, calculate its velocity after $2\ \text{s}$ of falling using $v = v_0 + g \times t$.

Solve
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An object is dropped from rest. With $g = 9.8\ \text{m/s}^2$, calculate the distance it has fallen after $3\ \text{s}$ using $h = \frac{1}{2} g \times t^2$.

An object is dropped from rest. With $g = 9.8\ \text{m/s}^2$, calculate the distance it has fallen after $3\ \text{s}$ using $h = \frac{1}{2} g \times t^2$.

Solve
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A coin falls from a height of $1.25\ \text{m}$. Take $g \approx 10\ \text{m/s}^2$. a) How long does it take to reach the ground? b) With what speed does it arrive?

A coin falls from a height of $1.25\ \text{m}$. Take $g \approx 10\ \text{m/s}^2$.

  1. a) How long does it take to reach the ground?
  2. b) With what speed does it arrive?
Solve

Problems with Height, Time, and Landing Speed

Almost all problems about falling from rest ask for one of two things: the time it takes or the speed it lands with. With the height $h$ you first calculate the time and then the speed.

To convert from m/s to km/h, multiply by $3.6$. For example, $20\ \text{m/s} = 72\ \text{km/h}$.

Another way to use the equation: the distance fallen during a specific second is the difference between what has fallen by the end of that second and what has fallen by its beginning. The last second of a $5\ \text{s}$ fall is $h(5) - h(4)$.

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A ball is dropped from a bridge $20\ \text{m}$ high, as shown in the figure. Take $g \approx 10\ \text{m/s}^2$. a) How long does it take to reach the water? b) With what…

A ball is dropped from a bridge $20\ \text{m}$ high, as shown in the figure. Take $g \approx 10\ \text{m/s}^2$.

20 m t = ? v = ?
  1. a) How long does it take to reach the water?
  2. b) With what speed does it arrive?
Solve
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A stone is dropped from the top of a tower $45\ \text{m}$ high. Take $g \approx 10\ \text{m/s}^2$. a) Calculate the time of fall. b) Calculate the speed with which it…

A stone is dropped from the top of a tower $45\ \text{m}$ high. Take $g \approx 10\ \text{m/s}^2$.

  1. a) Calculate the time of fall.
  2. b) Calculate the speed with which it hits the ground.
Solve
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An object is dropped from a bridge $80\ \text{m}$ high. Take $g \approx 10\ \text{m/s}^2$. a) Calculate the time of fall. b) Calculate the velocity upon reaching the…

An object is dropped from a bridge $80\ \text{m}$ high. Take $g \approx 10\ \text{m/s}^2$.

  1. a) Calculate the time of fall.
  2. b) Calculate the velocity upon reaching the water, in $\text{m/s}$.
  3. c) Express this velocity in $\text{km/h}$ and comment on why jumping from a bridge is dangerous even into water.
Solve

Downward Throw

If instead of dropping the object you throw it downward with an initial velocity $v_0$, it no longer starts from rest. Taking the downward direction as positive:

If you are given the height and asked for the time, you get a quadratic equation. It is solved with the quadratic formula, and the negative solution is discarded.

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A ball is thrown vertically downwards with an initial velocity of $5\ \text{m/s}$. Take $g \approx 10\ \text{m/s}^2$. a) What is its velocity after $2\ \text{s}$? b)…

A ball is thrown vertically downwards with an initial velocity of $5\ \text{m/s}$. Take $g \approx 10\ \text{m/s}^2$.

  1. a) What is its velocity after $2\ \text{s}$?
  2. b) What distance has it covered in those $2\ \text{s}$?
Solve
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An object is thrown vertically downwards from a window at $8\ \text{m/s}$ and falls from a height of $36\ \text{m}$. Take $g \approx 10\ \text{m/s}^2$. a) Set up the…

An object is thrown vertically downwards from a window at $8\ \text{m/s}$ and falls from a height of $36\ \text{m}$. Take $g \approx 10\ \text{m/s}^2$.

  1. a) Set up the equation $36 = 8 \times t + 5 \times t^2$ and solve it to find the time of fall.
  2. b) With what velocity does it hit the ground?
Solve

The Vertical Upward Throw

If you throw an object upward, gravity slows it down. Taking the upward direction as positive, $a = -g$. The velocity decreases until it is zero at the highest point, and then the object falls.

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A ball is thrown vertically upwards at $15\ \text{m/s}$. Take $g \approx 10\ \text{m/s}^2$. a) How long does it take to reach its maximum height? Hint: at the highest…

A ball is thrown vertically upwards at $15\ \text{m/s}$. Take $g \approx 10\ \text{m/s}^2$.

  1. a) How long does it take to reach its maximum height? Hint: at the highest point, the velocity is zero.
  2. b) What maximum height does it reach above the release point?
Solve
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A stone is thrown vertically upwards from a bridge at $10\ \text{m/s}$. Take $g \approx 10\ \text{m/s}^2$. a) What maximum height does it reach above the level of the…

A stone is thrown vertically upwards from a bridge at $10\ \text{m/s}$. Take $g \approx 10\ \text{m/s}^2$.

  1. a) What maximum height does it reach above the level of the bridge?
  2. b) How long does it take to pass the level of the bridge again?
Solve

Symmetry of Rising and Falling

Toss a coin upward and time it: it takes almost the same time to go up as to come down. The descent looks like the ascent played backward.

Velocity-time graph of a vertical throw: a descending line that goes from v₀ to −v₀ and crosses the axis at the highest point v t v₀ −v₀ t₁ 2t₁ goes up (v > 0) goes down (v < 0) t up = t down

If you are asked when it passes through an intermediate height, set up $y = v_0 t - 5t^2$ with that height and solve: you get two times, one going up and one going down. The velocities at those two instants have the same magnitude and opposite signs.

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You throw a ball vertically upwards at $20\ \text{m/s}$ from the ground, as shown in the figure. Take $g \approx 10\ \text{m/s}^2$. a) What maximum height does it reach?…

You throw a ball vertically upwards at $20\ \text{m/s}$ from the ground, as shown in the figure. Take $g \approx 10\ \text{m/s}^2$.

v₀ = 20 m/s h = ?
  1. a) What maximum height does it reach?
  2. b) How much time passes until it returns to your hands?
  3. c) With what velocity does it return? Compare it with the launch velocity and comment on the result.
Solve
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A ball is thrown vertically upwards at $25\ \text{m/s}$ from the ground, as shown in the figure. Take $g \approx 10\ \text{m/s}^2$. a) Calculate the maximum height and…

A ball is thrown vertically upwards at $25\ \text{m/s}$ from the ground, as shown in the figure. Take $g \approx 10\ \text{m/s}^2$.

v₀ = 25 m/s h = 20 m t₁ = ? t₂ = ? h max = ?
  1. a) Calculate the maximum height and the time at which it reaches it.
  2. b) Set up the equation to find at what times it passes through the height of $20\ \text{m}$ and solve it: you will get two solutions.
  3. c) Calculate the velocity of the ball for each of these two solutions.
  4. d) Explain the physical meaning of the two solutions and the relationship between the two velocities.
Solve

Two Objects on the Same Vertical

Two objects on the same vertical: one falls from the top and the other rises from the ground; the question is when and at what height they meet When and at what height do they meet? y (height) 0 ground (origin) falls starts from rest rises has v₀ upward
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From the edge of a roof $40\ \text{m}$ above the ground, a ball is thrown vertically upwards at $10\ \text{m/s}$, as shown in the figure. Take…

From the edge of a roof $40\ \text{m}$ above the ground, a ball is thrown vertically upwards at $10\ \text{m/s}$, as shown in the figure. Take $g \approx 10\ \text{m/s}^2$.

v₀ = 10 m/s h = ? 40 m
  1. a) What maximum height does it reach above the roof? And above the ground?
  2. b) How long does it take to go up?
  3. c) Set up the position equation taking the ground as the origin and calculate the total time of flight until the ball reaches the ground.
  4. d) With what velocity does it hit the ground?
Solve
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From the top of a tower $80\ \text{m}$ high, a stone is dropped, and at the same instant, another stone is thrown vertically upwards from the ground at $40\ \text{m/s}$,…

From the top of a tower $80\ \text{m}$ high, a stone is dropped, and at the same instant, another stone is thrown vertically upwards from the ground at $40\ \text{m/s}$, as shown in the figure. Take $g \approx 10\ \text{m/s}^2$.

stone 1 stone 2 v₀ = 40 m/s h = ? 80 m
  1. a) Write the height equations for each stone, $h_1$ and $h_2$, measured from the ground.
  2. b) Calculate the instant at which they cross paths.
  3. c) At what height do they cross paths?
  4. d) Calculate the velocity of each stone at that instant and state whether each one is moving up or down.
Solve
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A hot air balloon ascends at a constant velocity of $5\ \text{m/s}$. When it is $30\ \text{m}$ above the ground, a ballast bag comes loose. Take…

A hot air balloon ascends at a constant velocity of $5\ \text{m/s}$. When it is $30\ \text{m}$ above the ground, a ballast bag comes loose. Take $g \approx 10\ \text{m/s}^2$.

  1. a) Explain why the bag, upon coming loose, continues to move upwards for a moment instead of falling immediately.
  2. b) Taking the ground as the origin and upwards as positive, set up the position equation of the bag and calculate the time it takes to reach the ground.
  3. c) With what velocity does it hit the ground?
Solve

Applications: Reaction Time and Comparisons

With $h = \frac{1}{2} g t^2$ you can measure real things. For reaction time, one person drops a ruler and another catches it; with the distance it fell, $t = \sqrt{2h/g}$. Remember to convert centimeters to meters.

The less the ruler falls, the faster the reflexes.

If two objects are dropped one second apart from the same height, the second one is always slower than the first, so the separation between them grows while they fall: $d = \frac{1}{2} g\,[\,t^2 - (t-1)^2\,] = \frac{1}{2} g\,(2t - 1)$ increases with $t$.

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A humanitarian aid package is dropped from a hovering helicopter at a height of $125\ \text{m}$, as shown in the figure. Take $g \approx 10\ \text{m/s}^2$. a) How long…

A humanitarian aid package is dropped from a hovering helicopter at a height of $125\ \text{m}$, as shown in the figure. Take $g \approx 10\ \text{m/s}^2$.

125 m t = ? v = ?
  1. a) How long does it take to reach the ground?
  2. b) With what velocity does it arrive?
  3. c) Calculate how far it falls in the final second by comparing the distances fallen after $4\ \text{s}$ and after $5\ \text{s}$.
Solve
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To measure reaction time, one person holds a vertical ruler by its top end and drops it without warning; another person catches it after it has fallen $20\ \text{cm}$,…

To measure reaction time, one person holds a vertical ruler by its top end and drops it without warning; another person catches it after it has fallen $20\ \text{cm}$, as shown in the figure. Take $g \approx 10\ \text{m/s}^2$.

holds catches 20 cm t = ?
  1. a) Express the distance in meters and calculate the time the ruler has been falling.
  2. b) If a person's typical reaction time is $0.25\ \text{s}$, what does the result say about the reflexes of the person who caught it?
Solve
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Some keys drop from a balcony at a height of $5\ \text{m}$. Take $g \approx 10\ \text{m/s}^2$. a) How long do they take to reach the ground and with what velocity do…

Some keys drop from a balcony at a height of $5\ \text{m}$. Take $g \approx 10\ \text{m/s}^2$.

  1. a) How long do they take to reach the ground and with what velocity do they arrive?
  2. b) From what height would they have to fall for the time of fall to double? Is it also double the height? Comment on the result.
Solve

Limits of the Model and Use of g

The free-fall model assumes that only gravity acts. With air, a light object with a large surface area (a leaf, a feather, a coin falling from a great height) experiences air friction that slows it down, and the acceleration stops being constant. In that case the real landing speed is less than the calculated one. The model is very good for dense objects falling moderate heights.

Using $g \approx 10\ \text{m/s}^2$ instead of $9.8\ \text{m/s}^2$ simplifies the calculations, but gives a slightly shorter fall time and a slightly higher landing speed. For estimates it is acceptable; for precise measurements use $9.8$.

A speed limit can be used to set a maximum height: if an egg breaks at more than $v_{\text{limit}}$, the safe height is $h = \dfrac{v_{\text{limit}}^2}{2g}$.

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There is an urban legend that a coin dropped from a skyscraper $180\ \text{m}$ high can be fatal. Take $g \approx 10\ \text{m/s}^2$ and first assume there is no air…

There is an urban legend that a coin dropped from a skyscraper $180\ \text{m}$ high can be fatal. Take $g \approx 10\ \text{m/s}^2$ and first assume there is no air resistance.

  1. a) Calculate the time of fall.
  2. b) Calculate the velocity with which it would hit the ground and express it in $\text{km/h}$.
  3. c) In reality, air resistance slows down such a light object significantly. Reason whether the actual speed will be greater or smaller than the calculated one and which part of the free fall model no longer holds.
Solve
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A diver drops from a diving board at a height of $19.6\ \text{m}$. a) With $g = 9.8\ \text{m/s}^2$, calculate the time of fall and the speed of entry into the water. b)…

A diver drops from a diving board at a height of $19.6\ \text{m}$.

  1. a) With $g = 9.8\ \text{m/s}^2$, calculate the time of fall and the speed of entry into the water.
  2. b) Repeat the calculation using the approximation $g \approx 10\ \text{m/s}^2$, rounding to two decimal places.
  3. c) Compare the results and comment on whether the approximation $g \approx 10\ \text{m/s}^2$ overestimates or underestimates the time of fall, and in what type of problems it might be acceptable.
Solve
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In a school "egg drop" competition, the egg breaks if it hits the ground at more than $8\ \text{m/s}$. Take $g \approx 10\ \text{m/s}^2$ and ignore air resistance. a)…

In a school "egg drop" competition, the egg breaks if it hits the ground at more than $8\ \text{m/s}$. Take $g \approx 10\ \text{m/s}^2$ and ignore air resistance.

  1. a) Calculate the time of fall corresponding to this speed limit and the maximum height from which the unprotected egg can be dropped.
  2. b) If it is dropped from a window at $20\ \text{m}$, with what speed does it arrive? Does it survive?
  3. c) Propose two design improvements so that the egg survives a drop from $20\ \text{m}$ and justify them by relating them to the time of fall or the impact speed.
Solve

Summary

Back to the beginning: without air, the mango and the leaf would fall together, because all objects accelerate with the same $g$. Only the air makes the difference.

See all the exercises in this section