Work

The work done by a constant force on a moving body is $W = \vec{F} \cdot \vec{d} = F \cdot d \cdot \cos \alpha$, where $\alpha$ is the angle between the force and the displacement. Without performing calculations, state whether the work is positive, negative, or zero in each case, justifying your answer using the value of $\alpha$:

1. a) The pulling force of a tractor towing a trailer along a horizontal path.
2. b) The friction force opposing the motion of the trailer.
3. c) The normal force exerted by the ground on the trailer.
4. d) The force with which a worker holds a box at rest on their shoulder.

A warehouse worker pushes a pallet with a constant horizontal force of $250\ \text{N}$, moving it $12\ \text{m}$ along the floor in a straight line.

1. a) What angle does the force make with the displacement?
2. b) Calculate the work done by the worker.

A person walks their dog, pulling on the lead with a constant force of $80\ \text{N}$ at an angle of $60^\circ$ to the horizontal over a straight section of $25\ \text{m}$ ($\cos 60^\circ = 0.5$), as shown in the figure.

Calculate the work done.

You place a toolbox of $10\ \text{kg}$ onto a shelf located $2.5\ \text{m}$ above the floor (take $g = 9.8\ \text{m/s}^2$).

1. a) Calculate the weight of the box.
2. b) Calculate the work done by the weight while raising it. Remember that weight points downwards and displacement upwards.
3. c) What is the minimum work that you do against gravity?

A traveller pushes their luggage trolley through an airport terminal in a straight line on a horizontal floor.

1. a) Reason, using the expression $W = F \times d \times \cos \alpha$, why the work done by the normal force and the work done by the weight are zero during the journey.
2. b) If the traveller exerts a horizontal force of $18\ \text{N}$ over $100\ \text{m}$, what work do they do?

When dragging a sofa $8\ \text{m}$ across a living room floor, the kinetic friction force is $35\ \text{N}$.

1. a) What angle does the friction force make with the displacement?
2. b) Calculate the work done by friction and interpret its sign.

In a treasure hunt, a student drags a box of books $15\ \text{m}$ across the horizontal floor of the gymnasium by pushing with a horizontal force of $120\ \text{N}$, while kinetic friction opposes the motion with $40\ \text{N}$, as shown in the figure.

1. a) Calculate the work done by the student.
2. b) Calculate the work done by friction (remember it is negative: $\alpha = 180^\circ$).
3. c) Calculate the work done by weight and by the normal force, justifying their values.
4. d) Find the net work done on the box.

A musher pulls their team's sled using a rope at an angle of $37^\circ$ to the horizontal, exerting a constant force of $100\ \text{N}$ over $50\ \text{m}$ ($\sen 37^\circ \approx 0.6$; $\cos 37^\circ \approx 0.8$). Friction with the snow opposes with $30\ \text{N}$.

1. a) Calculate the work done by the musher.
2. b) Calculate the work done by friction.
3. c) Find the net work done on the sled.

In the laboratory, a trolley on an air track moves $\vec{d} = (5, 0)\ \text{m}$ while acted upon by a constant force $\vec{F} = (6, 8)\ \text{N}$, as shown in the figure.

1. a) Calculate the work using the dot product $W = \vec{F} \cdot \vec{d} = F_x \cdot d_x + F_y \cdot d_y$.
2. b) Explain why the vertical component of the force does not contribute to the work.

A constant force $\vec{F} = (15, -8)\ \text{N}$ acts on a machine component while the component moves through a displacement of $\vec{d} = (4, 2)\ \text{m}$, as shown in the figure.

1. a) Calculate the work using the dot product $W = \vec{F} \cdot \vec{d} = F_x \cdot d_x + F_y \cdot d_y$.
2. b) Check that the component $F_y$ does negative work and interpret what that sign means physically.

On a laboratory air table, a puck of $4\ \text{kg}$, initially at rest at point $A(1, 2)$, moves to point $B(9, 5)$ while a constant force $\vec{F} = (6, 8)\ \text{N}$ acts on it (the coordinates are in meters), as shown in the figure.

1. a) Determine the displacement vector $\vec{d} = \vec{AB}$.
2. b) Calculate the work done by the force using the scalar product $W = \vec{F} \cdot \vec{d}$.
3. c) Since friction is negligible, this work is the net work: apply the work-energy theorem and calculate the speed of the puck when it reaches $B$.

To load a fridge of $60\ \text{kg}$ into a van, it is pushed up a ramp of $3\ \text{m}$ at an angle of $20^\circ$ to the horizontal ($\sen 20^\circ \approx 0.34$; take $g = 10\ \text{m/s}^2$), as shown in the figure.

1. a) Calculate the component of the weight parallel to the ramp.
2. b) Calculate the work done by the weight during the ascent.
3. c) What minimum work must the person pushing do against that component of weight?

A box of $25\ \text{kg}$ starts from rest on the horizontal floor of a warehouse, where the coefficient of kinetic friction is $\mu = 0.2$. It is pushed with a constant horizontal force of $100\ \text{N}$ over $12\ \text{m}$ (take $g = 10\ \text{m/s}^2$), as shown in the figure.

1. a) Calculate the kinetic friction force, $F_{roz} = \mu \times N$, taking into account that on a horizontal floor the normal force is $N = m \times g$.
2. b) Calculate the work done by each of the forces (push, friction, weight, and normal force) and the net work.
3. c) Apply the work-energy theorem to find the speed of the box at the end of the $12\ \text{m}$.

A block of $10\ \text{kg}$ is pulled up a frictionless inclined plane of $30^\circ$ using a force $\vec{F}$ parallel to the plane, so that the block ascends at a constant speed along $5\ \text{m}$ ($\sen 30^\circ = 0.5$; take $g = 10\ \text{m/s}^2$), as shown in the figure.

1. a) Calculate the value of $F$ for the speed to be constant.
2. b) Calculate the work done by each force: the applied force, the weight, and the normal force.
3. c) Find the net work and explain, using the work-energy theorem, why that result was to be expected.

A worker pulls a $25\ \text{kg}$ box up a $20\ \text{m}$ ramp inclined at $37^\circ$ to the horizontal, pulling with a rope parallel to the ramp and at constant speed ($\sen 37^\circ \approx 0.6$; $\cos 37^\circ \approx 0.8$; coefficient of friction $\mu = 0.25$; take $g = 10\ \text{m/s}^2$), as shown in the figure.

1. a) Calculate the normal force exerted by the ramp and the friction force.
2. b) Calculate the force with which the worker pulls.
3. c) Calculate the work done by each force (pull, weight, friction, and normal force) and check that the net work is zero. Why did it have to be zero?

The work-energy theorem states that the net work done on a body is equal to the change in its kinetic energy: $W_{neto} = \Delta E_c = \frac{1}{2} \times m \times v^2 - \frac{1}{2} \times m \times v_0^2$. A demonstration ball of $2\ \text{kg}$ increases its speed from $3\ \text{m/s}$ to $5\ \text{m/s}$ on an air track.

1. a) Calculate its initial kinetic energy and its final kinetic energy.
2. b) What is the net work done on the ball?

A passenger car of $1200\ \text{kg}$ accelerates from rest to $108\ \text{km/h}$ when joining a dual carriageway.

1. a) Express the final velocity in $\text{m/s}$.
2. b) Calculate the change in kinetic energy of the car.
3. c) What net work has been done by the forces acting on the car? Express it in $\text{kJ}$.

A car of $1000\ \text{kg}$ travelling at $20\ \text{m/s}$ brakes to a halt over a distance of $50\ \text{m}$ along a horizontal section.

1. a) Calculate the change in kinetic energy during braking.
2. b) Applying the work-energy theorem, find the work done by the net braking force.
3. c) What is the average value of this net braking force? State its sense.

A construction crane lowers a beam of $500\ \text{kg}$ from a height of $8\ \text{m}$ to the ground at constant speed (take $g = 9.8\ \text{m/s}^2$).

1. a) Calculate the work done by the weight during the descent.
2. b) Calculate the work done by the tension in the cable.
3. c) What is the net work? Relate this to the fact that the speed is constant, using the work-energy theorem.

A passenger car of $1000\ \text{kg}$ travels at $20\ \text{m/s}$ along a horizontal road and locks its wheels during emergency braking. The coefficient of friction between the tyres and the asphalt is $\mu = 0.5$ (take $g = 10\ \text{m/s}^2$).

1. a) Calculate the friction force during braking.
2. b) Apply the work-energy theorem to calculate the distance it travels until coming to a stop.
3. c) Reason, from the expression obtained, what happens to the braking distance if the initial speed is doubled: does it also double?

On an ice rink, a puck of mass $m$ is launched with an initial speed of $v_0 = 10\ \text{m/s}$, and slides in a straight line until coming to a stop due to friction ($\mu = 0.25$; take $g = 10\ \text{m/s}^2$).

1. a) Write the expression for the work done by friction and, applying the work-energy theorem, obtain the stopping distance $d$ as a function of $v_0$, $\mu$, and $g$.
2. b) Calculate this distance numerically.
3. c) Reason, from the expression obtained, whether the stopping distance depends on the mass of the puck. What practical implication does this result have for road safety?

A firefighter of $80\ \text{kg}$ with their equipment climbs a fire escape from the ground to a terrace located $18\ \text{m}$ higher up (take $g = 10\ \text{m/s}^2$).

1. a) Calculate the work done by the weight during the ascent.
2. b) Calculate the work done by the firefighter against gravity.
3. c) If instead of the fire escape they had climbed a longer ramp to the same terrace, how would that work change? Justify your answer.

A cable car cabin with its passengers has a total mass of $800\ \text{kg}$. On the outbound journey, it ascends from the base station, at an altitude of $1200\ \text{m}$, to the top station, at $1750\ \text{m}$. It then partially descends to an intermediate station located at $1550\ \text{m}$ (take $g = 10\ \text{m/s}^2$), as shown in the figure.

1. a) Calculate the work done by weight during the ascent.
2. b) Calculate the work done by weight during the partial descent.
3. c) Calculate the total work done by weight over the entire journey and verify that it depends only on the net difference in altitude between the starting and ending points. What property of the gravitational force does this result highlight?

An elevator cabin with its passengers has a mass of $600\ \text{kg}$. It starts from rest and ascends $12\ \text{m}$ with a constant acceleration of $1.2\ \text{m/s}^2$ (take $g = 10\ \text{m/s}^2$).

1. a) Calculate the force exerted by the cable applying Newton's second law: $T - m \times g = m \times a$.
2. b) Calculate the work done by the cable and the work done by weight during these $12\ \text{m}$.
3. c) Find the net work and, using the work-energy theorem, the speed of the cabin after $12\ \text{m}$. Check the result using kinematics: $v^2 = 2 \times a \times h$.