Back to homeMathematics · Secondary Year 5 · Change subject
Start for free
Secondary 5 · Mathematics
Trigonometry · Trigonometry

Trigonometric Ratios of an Angle

Before you start, make sure you know: Right triangles (Secondary Year 4 (second cycle, academic track))

Wilkin wants to know how tall an antenna tower near his school is, but he can't climb it. He measures its shadow on the ground and the angle at which the sun's rays hit the floor. How does he turn those two pieces of data into a height? Trigonometric ratios are the tool, and in this section we extend them to any angle, not just the acute angles of a right triangle. At the end we come back to the tower.

From the legs to the unit circle

In a right triangle with acute angle $\alpha$, the sine is the opposite leg divided by the hypotenuse, the cosine is the adjacent leg divided by the hypotenuse, and the tangent is the opposite leg divided by the adjacent leg. If we place the vertex of the angle at the origin and let the hypotenuse be the radius of a circle of radius $1$, the sine and the cosine become the coordinates of the point where the side of the angle meets the circle.

Unit circle with a point P in the first quadrant: its x-coordinate is the cosine and its y-coordinate is the sine of the angle alpha. α P (cos α, sin α) cos α sin α x y
Practice★☆☆Not started
Calculate the exact value of the sine, cosine and tangent of the smallest angle of a right-angled triangle, knowing that its shorter sides measure $5$ cm and $12$ cm.

Calculate the exact value of the sine, cosine and tangent of the smallest angle of a right-angled triangle, knowing that its shorter sides measure $5$ cm and $12$ cm.

Solve
Practice★★☆Not started
To optimize solar energy collection in winter, a rectangular panel $2$ meters long is raised by resting one of its shorter sides on flat ground, so that the opposite…

To optimize solar energy collection in winter, a rectangular panel $2$ meters long is raised by resting one of its shorter sides on flat ground, so that the opposite side is at a height of exactly $1.2$ meters. Determine the exact value of the cosine and tangent of the angle of inclination of the panel.

Solve

Degrees and radians

Angles are measured in degrees or in radians. One radian is the central angle that intercepts an arc whose length equals the radius. Since the whole circumference measures $2\pi r$, one full turn is $2\pi$ radians.

One radian: the arc of the circle has the same length as the radius and the central angle measures approximately 57.3 degrees. 1 rad r arc = r 1 rad ≈ 57.3°
Practice★☆☆Not started
Convert the angles of $135^\circ$ and $330^\circ$ to radians, and express the angles of $\frac{5\pi}{6}$ rad and $\frac{7\pi}{4}$ rad in sexagesimal degrees.

Convert the angles of $135^\circ$ and $330^\circ$ to radians, and express the angles of $\frac{5\pi}{6}$ rad and $\frac{7\pi}{4}$ rad in sexagesimal degrees.

Solve
Practice★★☆Not started
A grinder disc rotates at $7200$ revolutions per minute. Express this angular velocity in radians per second and calculate the exact angle (in radians) swept out by a…

A grinder disc rotates at $7200$ revolutions per minute. Express this angular velocity in radians per second and calculate the exact angle (in radians) swept out by a particle on its outer edge in $0.15$ seconds.

Solve

The special angles: $30^\circ$, $45^\circ$, and $60^\circ$

Three angles have exact ratios, with square roots instead of rounded decimals. They can be justified geometrically with two figures.

Proof with the square. A square of side $1$ has diagonal $\sqrt{1^2 + 1^2} = \sqrt{2}$. The diagonal makes a $45^\circ$ angle with the sides. Then $\sin45^\circ = \dfrac{1}{\sqrt2} = \dfrac{\sqrt2}{2}$, $\cos45^\circ = \dfrac{\sqrt2}{2}$, and $\tan45^\circ = 1$.

Proof with the equilateral triangle. An equilateral triangle of side $2$ is cut by its altitude into two right triangles with hypotenuse $2$, one leg $1$, and the other leg $\sqrt{2^2 - 1^2} = \sqrt3$. The acute angles are $30^\circ$ and $60^\circ$.

On the left, a square of side 1 with its diagonal of square root of 2 forming 45 degrees. On the right, an equilateral triangle of side 2 divided by its altitude of square root of 3 into two triangles of 30 and 60 degrees. 1 1 √2 45° 1 1 √3 2 60° 30°
Practice★☆☆Not started
Evaluate the following expression by replacing the trigonometric ratios with their exact values, without using a calculator:…

Evaluate the following expression by replacing the trigonometric ratios with their exact values, without using a calculator:

$\sin^2(30^\circ) + \cos^2(45^\circ) - \tan(60^\circ) \times \sin(60^\circ)$

Solve

The fundamental identity and the sign by quadrant

Since $P(\cos\alpha, \sin\alpha)$ is at distance $1$ from the origin, the Pythagorean theorem gives the most widely used relation in trigonometry. When we solve with a square root, the sign is decided by the quadrant where the angle lies, not by the root.

Unit circle divided into four quadrants with the signs of the sine, the cosine, and the tangent in each one. I · sin + cos + tan + II · sin + cos − tan − III · sin − cos − tan + IV · sin − cos + tan −
Practice★☆☆Not started
Knowing that $\cos \alpha = \frac{4}{5}$ and that $\alpha$ is an acute angle, find the exact value of $\sin \alpha$ and $\tan \alpha$ using fundamental trigonometric…

Knowing that $\cos \alpha = \frac{4}{5}$ and that $\alpha$ is an acute angle, find the exact value of $\sin \alpha$ and $\tan \alpha$ using fundamental trigonometric identities.

Solve
Practice★☆☆Not started
Determine which quadrant the angle $\beta$ lies in if both $\sin \beta < 0$ and $\tan \beta > 0$ hold simultaneously.

Determine which quadrant the angle $\beta$ lies in if both $\sin \beta < 0$ and $\tan \beta > 0$ hold simultaneously.

Solve
Practice★★☆Not started
Given that $\tan \gamma = -\frac{12}{5}$ and that $\gamma$ belongs to the second quadrant, calculate the exact value of $\sin \gamma$ and $\sec \gamma$.

Given that $\tan \gamma = -\frac{12}{5}$ and that $\gamma$ belongs to the second quadrant, calculate the exact value of $\sin \gamma$ and $\sec \gamma$.

Solve

Reciprocal ratios and identities

Besides sine, cosine, and tangent there are three more ratios, which are their reciprocals.

How to verify an identity

To prove an identity you work on one side only, usually the more complicated one, until you reach the other. The usual steps are to rewrite everything in terms of $\sin$ and $\cos$, factor out a common factor, add fractions with a common denominator, and use $\sin^2 + \cos^2 = 1$.

Practice★☆☆Not started
In a right-angled triangle, the tangent of one of its acute angles is $\frac{3}{4}$. Determine the exact value of the secant and cosecant of this angle.

In a right-angled triangle, the tangent of one of its acute angles is $\frac{3}{4}$. Determine the exact value of the secant and cosecant of this angle.

Solve
Practice★★☆Not started
Calculate the exact values of $\cot \alpha$ and $\csc \alpha$ given that $\sec \alpha = 3$ and that the sine of the angle is negative.

Calculate the exact values of $\cot \alpha$ and $\csc \alpha$ given that $\sec \alpha = 3$ and that the sine of the angle is negative.

Solve
Practice★★☆Not started
Simplify the following trigonometric expression as much as possible using fundamental identities, expressing the result in terms of a single trigonometric ratio:…

Simplify the following trigonometric expression as much as possible using fundamental identities, expressing the result in terms of a single trigonometric ratio:

$\frac{\sin^3 x + \sin x \times \cos^2 x}{\cos x}$

Solve
Practice★★★Not started
Prove the following trigonometric identity, showing the algebraic steps and fundamental relations used. Assume that $\alpha$ is an angle for which all ratios are…

Prove the following trigonometric identity, showing the algebraic steps and fundamental relations used. Assume that $\alpha$ is an angle for which all ratios are defined:

$\frac{1 - \sin \alpha}{\cos \alpha} + \frac{\cos \alpha}{1 - \sin \alpha} = 2\sec \alpha$

Solve

Large angles and reduction to the first quadrant

For an angle greater than $360^\circ$, you subtract full turns until it lies between $0^\circ$ and $360^\circ$, and then you locate its quadrant. To get its exact value, you relate it to an acute angle $\theta$ (the reference angle).

Angle of 150 degrees in the second quadrant. Its reference angle with the horizontal axis is 30 degrees, and its sine is equal to that of 30 degrees while its cosine is the opposite. reference 30° 150° from the x-axis P (−cos 30°, sin 30°) is the point where the side meets the circle
Practice★☆☆Not started
Find the equivalent angle in the first revolution (between $0^\circ$ and $360^\circ$) for the angle of $1950^\circ$ and determine the sign of its secant and cotangent.

Find the equivalent angle in the first revolution (between $0^\circ$ and $360^\circ$) for the angle of $1950^\circ$ and determine the sign of its secant and cotangent.

Solve
Practice★☆☆Not started
Calculate the numerical value of the following trigonometric expression corresponding to angles located on the semi-axes:…

Calculate the numerical value of the following trigonometric expression corresponding to angles located on the semi-axes:

$3\sin(90^\circ) - 2\cos(180^\circ) + 4\sin(270^\circ) - \cos(360^\circ)$

Solve
Practice★★☆Not started
Find the exact value of the following expression by first reducing all the angles to the first quadrant:…

Find the exact value of the following expression by first reducing all the angles to the first quadrant:

$\cos(120^\circ) \times \sin(225^\circ) - \tan(330^\circ) \times \cos(210^\circ)$

Solve
Practice★★★Not started
Simplify the following trigonometric expression as much as possible, assuming that $x$ is an angle in the first quadrant. Pay special attention to the signs when…

Simplify the following trigonometric expression as much as possible, assuming that $x$ is an angle in the first quadrant. Pay special attention to the signs when reducing to that quadrant:

$\frac{\sin(\pi - x) \times \cos\left(\frac{\pi}{2} + x\right) \times \tan(2\pi - x)}{\cos(\pi + x) \times \sin\left(\frac{3\pi}{2} - x\right)}$

Solve

Equations and relations between ratios

Sometimes the problem gives a relation between $\sin$ and $\cos$ and asks for the angle or the ratios. There are two paths: divide to get the tangent, or put everything in terms of a single ratio using the fundamental identity and solve an equation (often a quadratic).

From the value of the ratio to the angle

When you know the value of a ratio and it does not belong to a special angle, you get the angle with the inverse function on the calculator: $\sin^{-1}$ (arcsin), $\cos^{-1}$ (arccos), or $\tan^{-1}$ (arctan), with the calculator in DEG mode. If $\sin\theta = k$, the calculator returns the acute angle (or the one in quadrant I or IV); the other angle in the interval comes from the reference angle, as in the previous section.

Practice★★★Not started
Given the relation $5\sin \theta - 2\cos \theta = 0$, determine all possible exact values for $\sin \theta$, $\cos \theta$ and $\tan \theta$. Discuss with reasons which…

Given the relation $5\sin \theta - 2\cos \theta = 0$, determine all possible exact values for $\sin \theta$, $\cos \theta$ and $\tan \theta$. Discuss with reasons which quadrants the angle $\theta$ can lie in.

Solve
Practice★★★Not started
Find all angles $\alpha \in [0^\circ, 360^\circ)$ satisfying the following trigonometric equation: $2\cos^2 \alpha - 3\sin \alpha = 0$ (Hint: express the entire equation…

Find all angles $\alpha \in [0^\circ, 360^\circ)$ satisfying the following trigonometric equation:

$2\cos^2 \alpha - 3\sin \alpha = 0$

(Hint: express the entire equation in terms of a single trigonometric ratio using the fundamental identity).

Solve
Practice★★★Not started
A light ray passes from a liquid medium with refractive index $n_1 = 1.33$ to a crystal with index $n_2 = 1.52$. Snell's law states that…

A light ray passes from a liquid medium with refractive index $n_1 = 1.33$ to a crystal with index $n_2 = 1.52$. Snell's law states that $n_1 \sin \theta_1 = n_2 \sin \theta_2$, where $\theta_1$ and $\theta_2$ are the angles of incidence and refraction measured relative to the normal to the surface. If the ray is incident at an angle of $\theta_1 = \frac{\pi}{4}$ rad, determine the exact value of the cosine of the angle of refraction $\theta_2$.

Solve

Applications

Trigonometric ratios model any inclination: the height of a tower from its shadow, the displacement of a pendulum, the belt between two pulleys, or the area of a polygon.

Right triangle formed by a tower, its shadow on the ground, and the sun's rays with an angle of elevation of 40 degrees. 40° height h shadow = 30 m
Practice★★☆Not started
A building casts a shadow of $24$ meters when the angle of elevation of the sun above the horizon is $53^\circ$. Write the trigonometric expression to calculate the…

A building casts a shadow of $24$ meters when the angle of elevation of the sun above the horizon is $53^\circ$. Write the trigonometric expression to calculate the height of the building and determine its value. If the angle of elevation is halved, does the length of the shadow double? Justify your answer based on the non-linearity of the tangent ratio.

Solve
Practice★★☆Not started
A pendulum of length $80$ cm moves from its vertical equilibrium position to form an angle of $18^\circ$ with the vertical. Calculate the exact horizontal distance that…

A pendulum of length $80$ cm moves from its vertical equilibrium position to form an angle of $18^\circ$ with the vertical. Calculate the exact horizontal distance that the pendulum bob has moved and the height it has risen with respect to its lowest point. Express the results in terms of the trigonometric ratios of $18^\circ$.

18° x = ? h = ? 80 cm
Solve
Practice★★★Not started
Prove that the area of a regular polygon of $n$ sides inscribed in a circle of radius $R$ is given by the expression…

Prove that the area of a regular polygon of $n$ sides inscribed in a circle of radius $R$ is given by the expression $A = \frac{n \times R^2}{2} \sin\left(\frac{360^\circ}{n}\right)$. Then, apply the formula to calculate the exact area of a regular octagon inscribed in a circle of radius $10$ cm.

O 360°/n R R
Solve
Practice★★★Not started
Two circular pulleys of radii $R = 15$ cm and $r = 5$ cm are connected by a taut belt crossed between them. The distance between the centers of the pulleys is $40$ cm.…

Two circular pulleys of radii $R = 15$ cm and $r = 5$ cm are connected by a taut belt crossed between them. The distance between the centers of the pulleys is $40$ cm. If $\alpha$ is the angle formed by the straight section of the belt with the imaginary line joining the centers, calculate the exact value of $\sin \alpha$, $\cos \alpha$ and the total length of the straight section of the belt between the two points of tangency.

α R r d = 40 cm
Solve
Practice★★★Not started
Prove that if $\alpha$ and $\beta$ are two acute complementary angles (that is, $\alpha + \beta = \frac{\pi}{2}$ rad), then the following trigonometric relation always…

Prove that if $\alpha$ and $\beta$ are two acute complementary angles (that is, $\alpha + \beta = \frac{\pi}{2}$ rad), then the following trigonometric relation always holds:

$\frac{\tan \alpha + \tan \beta}{\sec \alpha \times \sec \beta} = 1$

Solve

Summary

See all the exercises in this section