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Secondary 5 · Mathematics
Trigonometry · Trigonometry

Law of Sines

Before you start, make sure you know: Right triangles (Secondary Year 4 (second cycle, academic track))

Two lookout towers on the coast of Samaná receive a distress signal from a boat. Neither tower is at the point where a right angle forms with the boat. How do they calculate how far away it is? Right triangles aren't enough: you need a tool that works in any triangle. The law of sines is the first one.

The law and the circumscribed circle

In any triangle $ABC$, each side is proportional to the sine of its opposite angle, and that constant ratio is the diameter of the circle that passes through the three vertices.

Triangle inscribed in a circumscribed circle, with vertices A, B, C on the circle and its opposite sides a, b, c labeled. A B C a b c

You use it when you know a side and its opposite angle, plus one more piece of data.

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In a triangle $ABC$, the angles $A = 45^\circ$ and $B = 60^\circ$ are known, as well as the length of side $a = 12$ cm. Calculate the length of side $b$ using the sine…

In a triangle $ABC$, the angles $A = 45^\circ$ and $B = 60^\circ$ are known, as well as the length of side $a = 12$ cm. Calculate the length of side $b$ using the sine rule.

Solve
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In any triangle, side $c$ measures $24$ cm and the opposite angle $C$ measures $30^\circ$. Calculate the radius $R$ of the circumcircle of this triangle.

In any triangle, side $c$ measures $24$ cm and the opposite angle $C$ measures $30^\circ$. Calculate the radius $R$ of the circumcircle of this triangle.

Solve
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In an isosceles triangle, the non-equal angle measures $40^\circ$ and the equal sides measure $15$ cm. Calculate the length of the remaining side by directly applying…

In an isosceles triangle, the non-equal angle measures $40^\circ$ and the equal sides measure $15$ cm. Calculate the length of the remaining side by directly applying the sine rule.

Solve

Finding an angle: the ambiguous case

When the unknown is an angle (side-side-angle), solving for the sine can give two solutions: an acute angle and its supplement, because $\sin(180^\circ-x)=\sin x$.

Ambiguous case: the opposite side, with its endpoint fixed at C, swings like a compass over the dashed arc and meets the base at B₁ and B₂, showing two possible triangles with the same angle A and the same given sides. A C B₁ B₂
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Given a triangle $ABC$ in which sides $a = 15$ cm and $b = 10$ cm and the obtuse angle $A = 120^\circ$ are known, determine the value of angle $B$.

Given a triangle $ABC$ in which sides $a = 15$ cm and $b = 10$ cm and the obtuse angle $A = 120^\circ$ are known, determine the value of angle $B$.

Solve
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Determine whether it is possible to construct a triangle $ABC$ with the following data: $a = 8$ cm, $b = 14$ cm, and $A = 45^\circ$. Justify your answer mathematically…

Determine whether it is possible to construct a triangle $ABC$ with the following data: $a = 8$ cm, $b = 14$ cm, and $A = 45^\circ$. Justify your answer mathematically using the sine rule.

Solve
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In triangle $ABC$, sides $a = 10$ cm, $b = 14$ cm, and angle $A = 30^\circ$ are known. Calculate the two possible values for angle $B$ and the corresponding lengths of…

In triangle $ABC$, sides $a = 10$ cm, $b = 14$ cm, and angle $A = 30^\circ$ are known. Calculate the two possible values for angle $B$ and the corresponding lengths of side $c$ for each case.

30° A C B₂ B₁ b = 14 a = 10 a = 10
Solve
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In the construction of a triangle $ABC$, side $a = 10$ cm and angle $A = 45^\circ$ are fixed. Side $b$ has a variable length $x$ cm. Determine, giving reasons, the…

In the construction of a triangle $ABC$, side $a = 10$ cm and angle $A = 45^\circ$ are fixed. Side $b$ has a variable length $x$ cm. Determine, giving reasons, the strict interval of real values of $x$ for which there exist exactly two distinct triangles satisfying these conditions simultaneously.

Solve

Triangulation: distances with two angles

In surveying and navigation, you measure the distance between two accessible points and the angles from them toward a faraway point. Then you apply the law of sines.

Triangulation: two stations A and B, 50 km apart, measure angles of 40° and 65° toward a signal S. 40° 65° A B S 50 km
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Two coastguard stations, $A$ and $B$, are separated by a distance of $50$ km along a straight coastline. A ship $S$ emits a distress signal. Station $A$ detects the…

Two coastguard stations, $A$ and $B$, are separated by a distance of $50$ km along a straight coastline. A ship $S$ emits a distress signal. Station $A$ detects the signal forming an angle of $40^\circ$ with the coastline, while station $B$ detects it with an angle of $65^\circ$. Calculate the straight-line distance from each station to the ship.

A B S 50 km 40° 65° d₁ d₂
Solve
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An ancient tower has tilted and now forms an angle of $85^\circ$ with the horizontal ground. A surveyor stands $40$ m from the base of the tower, directly in the…

An ancient tower has tilted and now forms an angle of $85^\circ$ with the horizontal ground. A surveyor stands $40$ m from the base of the tower, directly in the direction in which it is leaning. From that point, he measures the angle of elevation to the top of the tower, obtaining $50^\circ$. Calculate the total length of the tower from its base to the top.

Solve
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A cable car ascends in a straight line from a base station $A$ to the summit $C$ of a mountain. From a point $D$, situated $200$ m behind $A$ in the same horizontal…

A cable car ascends in a straight line from a base station $A$ to the summit $C$ of a mountain. From a point $D$, situated $200$ m behind $A$ in the same horizontal plane, the angle of elevation to $C$ is $22^\circ$. From station $A$, the angle of elevation to the summit is $35^\circ$. Calculate the length of the cable car wire $AC$ by solving triangle $ADC$.

D A C 200 m 22° 35° cable
Solve

Area and combined problems

With one side and two angles you can find the other sides and, with them, the area $\frac12 ab\sin C$. It also works for regular polygons, dividing them into isosceles triangles from the center.

Triangular lot with angles of 60° and 75° at the ends of a 120 m side. 60° 75° 120 m
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Calculate the perimeter of a regular heptagon (a 7-sided polygon) inscribed in a circle of radius $R = 10$ cm. Use the law of sines on the isosceles triangles formed…

Calculate the perimeter of a regular heptagon (a 7-sided polygon) inscribed in a circle of radius $R = 10$ cm. Use the law of sines on the isosceles triangles formed from the center of the polygon.

Solve
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A triangular plot of land has two angles measuring $60^\circ$ and $75^\circ$. The side between these two angles is bounded by a straight wall measuring $120$ m.…

A triangular plot of land has two angles measuring $60^\circ$ and $75^\circ$. The side between these two angles is bounded by a straight wall measuring $120$ m. Calculate the total area of the plot.

Solve
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The slope of a mountain has a constant inclination of $15^\circ$ relative to the horizontal plane. Two points $A$ and $B$ are on the slope, with $B$ situated $50$ m…

The slope of a mountain has a constant inclination of $15^\circ$ relative to the horizontal plane. Two points $A$ and $B$ are on the slope, with $B$ situated $50$ m further up than $A$ along the slope. A vertical telecommunications pole is installed at point $B$. From point $A$, the angle of elevation to the top of the pole is $42^\circ$ measured from the horizontal. Calculate the exact height of the pole.

15° 42° A B C 50 m h
Solve

Proof challenges

Many challenges ask you to prove a relationship between sides and angles. The strategy is almost always the same: with the law of sines you write each side as $a=2R\sin A$, $b=2R\sin B$, $c=2R\sin C$, and then you work only with sines.

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In a triangle $ABC$, the lengths of sides $a$, $b$, and $c$ are in arithmetic progression, satisfying the relation $2b = a + c$. Prove that the sines of the opposite…

In a triangle $ABC$, the lengths of sides $a$, $b$, and $c$ are in arithmetic progression, satisfying the relation $2b = a + c$. Prove that the sines of the opposite angles maintain an analogous relation: $\sin A + \sin C = 2 \sin B$.

Solve
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In a triangle $ABC$, angle $A$ is exactly twice angle $B$ ($A = 2B$). Prove, using the sine rule and double-angle trigonometric identities, that the lengths of the sides…

In a triangle $ABC$, angle $A$ is exactly twice angle $B$ ($A = 2B$). Prove, using the sine rule and double-angle trigonometric identities, that the lengths of the sides satisfy the relation $a = 2b \cos B$.

Solve
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Prove, starting from the sine rule, that in any triangle $ABC$ the following trigonometric identity relating its sides and angles holds:…

Prove, starting from the sine rule, that in any triangle $ABC$ the following trigonometric identity relating its sides and angles holds:

$a \sin(B - C) + b \sin(C - A) + c \sin(A - B) = 0$

Solve

Summary

Back to the beginning: with the distance between the two towers and the two angles of the signal, the law of sines gives the distance to the boat.

See all the exercises in this section