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Polarization and Atomic Spectra · Polarization and Emission Spectra

Emission Spectra of Atoms

A neon sign glows red-orange, a sodium streetlight glows yellow, and a light bulb glows white. If you spread each of these lights into a rainbow with a prism, you get three very different pictures. Why does a gas glow in only a few exact colors, and how can astronomers use that to find out what a distant nebula is made of? By the end of this page you will be able to answer both questions.

Continuous vs. emission spectra

A spectrum is light spread out by wavelength, usually with a prism or a diffraction grating. A hand-held spectroscope does this and lets you see the result.

The hot filament of an incandescent bulb gives a continuous spectrum: every color from red to violet, blending smoothly with no gaps.

A thin gas excited by electricity (a neon sign, a sodium lamp) gives an emission spectrum: a few thin bright lines of specific colors on a dark background.

A continuous spectrum with all colors, and an emission spectrum with only a few thin bright lines on a dark background. Incandescent bulb: continuous spectrum Hydrogen gas: emission spectrum 400 nm 700 nm

Gas atoms are far apart, so each atom acts on its own. The light it gives off is not a smooth blend: only certain wavelengths appear. Why? The next section explains.

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Describe what an emission spectrum of a gas looks like and how it differs from the continuous spectrum of a glowing light bulb filament. Why do different elements…

Describe what an emission spectrum of a gas looks like and how it differs from the continuous spectrum of a glowing light bulb filament. Why do different elements produce different line patterns?

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Energy levels and photons

Electrons in an atom cannot have just any energy. Only certain energy levels are allowed, like the steps of a staircase: you can stand on a step, but not between steps.

When an atom is excited (by heat or electric current), an electron jumps to a higher level. It soon falls back to a lower level and the atom gives off the energy difference as a single photon:

$$E_{photon} = E_i - E_f = hf = \frac{hc}{\lambda}$$

Here $E_i$ is the starting (higher) level and $E_f$ the final (lower) level. Because only certain gaps exist, only certain photon energies appear, and each energy means one color: one spectral line.

Each element has its own set of levels, so each has its own pattern of lines. That is why the pattern works as a fingerprint.

Energy level diagram: an electron drops from a higher level to a lower level and emits a photon. Level 3: −1.51 eV Level 2: −3.40 eV Level 1: −13.6 eV photon

Notice that the energies are negative. Zero is the energy of a free electron, so a bound electron has less than zero. The photon energy is still the positive gap between two levels.

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An atom has energy levels $E_1 = 0$, $E_2 = 2.0$ eV and $E_3 = 3.0$ eV. List every photon energy this atom can emit when it relaxes from level 3 to lower levels,…

An atom has energy levels $E_1 = 0$, $E_2 = 2.0$ eV and $E_3 = 3.0$ eV. List every photon energy this atom can emit when it relaxes from level 3 to lower levels, including two-step paths. How many distinct spectral lines appear? Which line has the longest wavelength?

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Photon energy, frequency and wavelength

Light with frequency $f$ comes in photons of energy $E = hf$, where $h = 6.63 \times 10^{-34}\ \text{J·s}$. Since $c = f\lambda$, we can also write $E = hc/\lambda$.

Higher frequency means shorter wavelength and more energy per photon. Along the electromagnetic spectrum, from lowest to highest photon energy: radio waves, microwaves, infrared, visible (red to violet), ultraviolet, X-rays, gamma rays.

Atomic physicists measure energies in electron-volts: $1\ \text{eV} = 1.60 \times 10^{-19}\ \text{J}$. A handy shortcut is

$$hc = 1240\ \text{eV·nm}, \qquad \lambda\ (\text{nm}) = \frac{1240}{E\ (\text{eV})}$$
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A photon of green light has a frequency of $5.7 \times 10^{14}$ Hz. Find its energy in joules.

A photon of green light has a frequency of $5.7 \times 10^{14}$ Hz. Find its energy in joules.

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Rank these types of electromagnetic radiation from lowest to highest photon energy: visible light, X-rays, radio waves, infrared, ultraviolet. Explain the rule you used.

Rank these types of electromagnetic radiation from lowest to highest photon energy: visible light, X-rays, radio waves, infrared, ultraviolet. Explain the rule you used.

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A hydrogen atom drops from an energy level of $-1.51$ eV to one of $-3.40$ eV. (a) Find the energy of the emitted photon in eV. (b) Convert it to joules, using…

A hydrogen atom drops from an energy level of $-1.51$ eV to one of $-3.40$ eV. (a) Find the energy of the emitted photon in eV. (b) Convert it to joules, using $1\ \text{eV} = 1.60 \times 10^{-19}$ J. (c) Find the photon's wavelength.

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A sodium streetlight emits strong yellow light at a wavelength of $589$ nm. (a) Find the frequency of this light. (b) Find the energy of one photon in joules. (c) The…

A sodium streetlight emits strong yellow light at a wavelength of $589$ nm. (a) Find the frequency of this light. (b) Find the energy of one photon in joules. (c) The lamp emits $2.0 \times 10^{19}$ of these photons each second. Find the power carried by this light.

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Counting lines and reading spectra

With more than two levels, an atom has more possible drops. An atom with levels 1, 2 and 3 can emit photons for $3 \to 2$, $2 \to 1$ and $3 \to 1$. Three drops, three lines, each with its own energy. A two-step path ($3 \to 2$ then $2 \to 1$) gives two photons, each matching its own line.

The biggest gap gives the highest-energy photon, the shortest wavelength. The smallest gap gives the longest wavelength.

Reading a spectrum. Matching a sample's lines with the known lines of an element identifies the element. Astronomers do this for starlight and nebulae, for example with telescopes in Arizona. Helium was first noticed this way, from a line in sunlight, before it was found on Earth.

A hot, thin gas gives bright lines on a dark background (emission). A cooler gas in front of a hot, bright source absorbs photons at those same wavelengths and leaves dark lines on a continuous background (absorption). The same gaps in energy levels are involved either way.

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A student's spectrometer shows a gas emitting lines at $410$ nm, $434$ nm, $486$ nm and $656$ nm. (a) Find the photon energy of each line in eV, using…

A student's spectrometer shows a gas emitting lines at $410$ nm, $434$ nm, $486$ nm and $656$ nm.

(a) Find the photon energy of each line in eV, using $hc = 1240\ \text{eV·nm}$. (b) Explain why a continuous-spectrum model of light could not account for these separate lines, but a photon model with energy levels can. (c) Suppose all four lines end on the same lower level. Argue whether the $656$ nm line comes from the highest or the lowest of the upper levels involved.

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Astronomers at an observatory in Arizona photograph the light from a distant nebula and see bright lines at the same wavelengths as laboratory hydrogen, including $656$…

Astronomers at an observatory in Arizona photograph the light from a distant nebula and see bright lines at the same wavelengths as laboratory hydrogen, including $656$ nm. They also see a bright line at $501$ nm that they attribute to another element.

(a) Explain how the lines identify the elements in the nebula. (b) Find the photon energy of the $501$ nm line in eV, using $hc = 1240\ \text{eV·nm}$. (c) Explain why the nebula shows bright lines on a dark background, while a cooler gas cloud in front of a hot star produces dark lines on a bright background. (d) Describe what must be true of the energy levels for the dark and bright lines of the same element to occur at the same wavelengths.

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Back to the start: a gas glows in only a few exact colors because its electrons have only certain energy levels, so photons can only carry certain energies. Astronomers match those lines to elements to read the makeup of a nebula.

Summary

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