Motors, generators and transformers
The electricity in your home has traveled a very long way: it may have been born in a generator at Hoover Dam turned by falling water, traveled hundreds of miles at very high voltage, and reached your outlet after passing through several transformers. Motor, generator and transformer are three sides of the same coin: electromagnetic induction.
The electric motor: a couple that turns
If you connect a loop of copper wire to a battery and place it between the poles of a magnet, the loop gives a sudden jerk and lines up with the field, then stops: how do we make it keep turning continuously instead of stopping there, so that it can drive machinery?
Power and efficiency
A motor does not turn all the electrical power it absorbs into useful mechanical power. Its efficiency compares the two: $\text{efficiency} = \dfrac{P_{out}}{P_{in}}\times 100\%$, where $P_{in} = V\cdot I$.
The rest becomes thermal energy: Joule heating ($I^2R$) in the copper windings, friction in the bearings and brushes, and eddy currents (small circulating currents induced in the iron core).
The rectangular loop of a DC motor is between the poles of a magnet and carries a current. a) Draw the magnetic forces on the two sides of the loop perpendicular to the…
The rectangular loop of a DC motor is between the poles of a magnet and carries a current.
- a) Draw the magnetic forces on the two sides of the loop perpendicular to the field in your notebook and explain why they form a couple that makes the loop rotate.
- b) What role does the split-ring commutator play? What would happen to the loop upon reaching the dead center if it did not exist?
You can do it on paper and send a photo with your answer.
The loop of a toy motor measures $10\ \text{cm}$ in length and $5\ \text{cm}$ in width, carries a current of $3\ \text{A}$ and is in a field of $0.4\ \text{T}$…
The loop of a toy motor measures $10\ \text{cm}$ in length and $5\ \text{cm}$ in width, carries a current of $3\ \text{A}$ and is in a field of $0.4\ \text{T}$ perpendicular to its axis of rotation, as shown in the figure.
- a) Calculate the magnetic force on each of the long sides of the loop, $F = I \times l \times B$.
- b) Explain why these two forces, acting in opposite directions, form a couple that rotates the loop instead of translating it.
- c) What happens to the couple when the plane of the loop is perpendicular to the field (dead center) and how does the split-ring commutator solve this?
A drill connected to $230\ \text{V}$ draws a current of $2\ \text{A}$ and delivers a useful mechanical power of $400\ \text{W}$. a) Calculate the electrical power it…
A drill connected to $230\ \text{V}$ draws a current of $2\ \text{A}$ and delivers a useful mechanical power of $400\ \text{W}$.
- a) Calculate the electrical power it absorbs from the power line.
- b) Calculate its efficiency, as a percentage.
- c) Name two mechanisms by which a real motor loses energy and briefly explain them.
Generators: AC generator (alternator) and DC generator (dynamo)
a) Explain the fundamental difference between an alternator and a dynamo: what type of current each produces and which connecting element (slip rings or split-ring…
- a) Explain the fundamental difference between an alternator and a dynamo: what type of current each produces and which connecting element (slip rings or split-ring commutator) determines it.
- b) What physical phenomenon are both devices based on?
When a loop rotates at a constant angular speed in a uniform magnetic field, an alternating current is generated, as shown in the figure. a) Explain, based on how the…
When a loop rotates at a constant angular speed in a uniform magnetic field, an alternating current is generated, as shown in the figure.
- a) Explain, based on how the magnetic flux through the loop varies, why the emf continually changes value.
- b) Reason why the emf changes sign every half turn.
In a bicycle with a dynamo, the light turns on when pedaling. a) Explain how the dynamo generates the current that powers the bulb. b) According to Lenz's law, the…
In a bicycle with a dynamo, the light turns on when pedaling.
- a) Explain how the dynamo generates the current that powers the bulb.
- b) According to Lenz's law, the induced current opposes the rotation of the dynamo: explain where the energy consumed by the bulb ultimately comes from, and why more resistance is felt when pedaling with the dynamo connected.
The transformer
If you wind two separate coils around the same iron ring and connect one of them to the alternating current from a wall outlet, the second coil lights a lamp with no electrical contact between the two: how does the energy travel, and what does the voltage received by the lamp depend on?
A transformer has two coils wound on the same iron core. Explain, based on Faraday's law, why connecting the primary to a constant direct current produces no voltage in…
A transformer has two coils wound on the same iron core. Explain, based on Faraday's law, why connecting the primary to a constant direct current produces no voltage in the secondary, whereas connecting it to alternating current does.
The primary of a transformer has $N_1 = 1000$ turns and is connected to $V_1 = 230\ \text{V}$. The secondary has $N_2 = 50$ turns. a) Write the turns ratio,…
The primary of a transformer has $N_1 = 1000$ turns and is connected to $V_1 = 230\ \text{V}$. The secondary has $N_2 = 50$ turns.
- a) Write the turns ratio, $\frac{V_1}{N_1} = \frac{V_2}{N_2}$.
- b) Calculate the secondary voltage and state whether the transformer is step-up or step-down.
Wall outlet voltage, $230\ \text{V}$, needs to be transformed to $12\ \text{V}$ to power a model circuit. a) Calculate the required turns ratio, $\frac{N_1}{N_2}$. b) If…
Wall outlet voltage, $230\ \text{V}$, needs to be transformed to $12\ \text{V}$ to power a model circuit.
- a) Calculate the required turns ratio, $\frac{N_1}{N_2}$.
- b) If the secondary has $30$ turns, how many turns must the primary have?
An ideal transformer has $N_1 = 460$ turns in the primary and $N_2 = 40$ in the secondary. The primary is connected to $230\ \text{V}$. Observe the diagram: a) Calculate…
An ideal transformer has $N_1 = 460$ turns in the primary and $N_2 = 40$ in the secondary. The primary is connected to $230\ \text{V}$. Observe the diagram:
- a) Calculate the secondary voltage.
- b) A current of $2.3\ \text{A}$ flows through the secondary circuit: calculate the power delivered by the transformer.
- c) In an ideal transformer, the primary power is equal to the secondary power: calculate the current drawn by the transformer from the power line.
Real transformers and wireless charging
An ideal transformer wastes nothing, but your phone charger gets warm: where does the missing energy go, and how can a charger work with no iron core at all?
A wireless charger works like a transformer without a shared core. A transmitter coil with alternating current creates a changing flux, and part of it crosses the receiver coil in the phone and induces an emf. Since the coils are separated by air, only a fraction of the flux links them. By Faraday's law the induced emf grows with $\Delta\Phi/\Delta t$, so a very high frequency makes the flux change faster and compensates for the weak coupling.
A toy electric train operates at $18\ \text{V}$ with a current of $2.5\ \text{A}$, using an ideal transformer connected to the $230\ \text{V}$ wall outlet. a) Calculate…
A toy electric train operates at $18\ \text{V}$ with a current of $2.5\ \text{A}$, using an ideal transformer connected to the $230\ \text{V}$ wall outlet.
- a) Calculate the turns ratio of the transformer.
- b) Calculate the power consumed by the train.
- c) Calculate the current drawn by the transformer from the wall outlet.
A laptop charger delivers $19\ \text{V}$ and $38\ \text{W}$ to the laptop, and its transformer has an efficiency of $95\%$. The charger is connected to the…
A laptop charger delivers $19\ \text{V}$ and $38\ \text{W}$ to the laptop, and its transformer has an efficiency of $95\%$. The charger is connected to the $230\ \text{V}$ wall outlet.
- a) Calculate the current flowing through the secondary.
- b) Calculate the power drawn by the charger from the wall outlet and the corresponding primary current.
- c) Calculate the power lost inside the charger.
- d) Explain the two main causes of losses in a real transformer: eddy currents in the core (which is why it is made of stacked, insulated laminations) and the Joule effect in the windings.
A wireless charger has a transmitter coil of $20$ turns powered at $12\ \text{V}$ with alternating current of $100\ \text{kHz}$; the cell phone's coil has $15$ turns.…
A wireless charger has a transmitter coil of $20$ turns powered at $12\ \text{V}$ with alternating current of $100\ \text{kHz}$; the cell phone's coil has $15$ turns. Observe the diagram:
- a) Calculate the induced voltage in the cell phone's coil assuming ideal coupling, using the relationship $\frac{V_1}{N_1} = \frac{V_2}{N_2}$.
- b) Explain how this system resembles a transformer and what fundamental difference there is regarding the core compared to a conventional one.
- c) Reason, based on Faraday's law, why such a high frequency is used instead of the $50\ \text{Hz}$ mains frequency: what happens to $\frac{\Delta \Phi}{\Delta t}$ and to the required size of the coils?
Transmitting energy: why at high voltage
In 1882, Thomas Edison's Pearl Street Station in New York City sent low-voltage current through wires that could serve customers only within about a mile: farther away, the wires wasted too much energy as heat. What physical trick allows us today to send power from Hoover Dam to Southern California, hundreds of miles away, losing only a small fraction on the way?
That is why at a power plant the voltage is stepped up before transmission (with a step-up transformer next to the generators) and stepped down again close to where it is consumed (with a step-down transformer next to the city): the combination of alternating current and transformers is what makes it feasible to transmit electricity hundreds of miles with reasonable losses.
Back to the start: the power from Hoover Dam is stepped up to hundreds of kilovolts for the trip to Southern California, and then stepped down in several stages (the last one is the transformer on the utility pole) until it reaches the 120 V outlet in your home.
Electric utility companies transport energy at voltages of hundreds of kilovolts. a) Write the relationship between power, voltage and current, $P = V \times I$, and…
Electric utility companies transport energy at voltages of hundreds of kilovolts.
- a) Write the relationship between power, voltage and current, $P = V \times I$, and explain why, to transport the same power, a high voltage implies a low current.
- b) The power lost due to the Joule effect in the wires is $I^2 \times R$: explain why it is so important for the transported current to be small.
A town consumes $50\ \text{kW}$ and the supply line feeding it has a total resistance of $2\ \Omega$. a) If transmission were carried out at $1000\ \text{V}$, calculate…
A town consumes $50\ \text{kW}$ and the supply line feeding it has a total resistance of $2\ \Omega$.
- a) If transmission were carried out at $1000\ \text{V}$, calculate the current through the line and the power lost in it, and express this loss as a percentage of the transmitted power.
- b) Repeat the calculations assuming transmission is carried out at $10\ \text{kV}$.
- c) Draw a conclusion as to why it is advantageous to transmit energy at high voltage.
A power plant generates electricity at $6\ \text{kV}$. A step-up transformer increases it to $132\ \text{kV}$ for transmission and, in the city, another transformer…
A power plant generates electricity at $6\ \text{kV}$. A step-up transformer increases it to $132\ \text{kV}$ for transmission and, in the city, another transformer steps it down to $230\ \text{V}$ for consumption. Observe the diagram:
- a) Calculate the turns ratio $\frac{N_2}{N_1}$ of the step-up transformer.
- b) Calculate the turns ratio $\frac{N_1}{N_2}$ of the city step-down transformer.
- c) Explain why the step-up transformer is installed next to the power plant and the step-down transformer next to the points of consumption, and not the other way round.
A wind farm generates $10\ \text{MW}$ and transmits it at $220\ \text{kV}$ over a line with a total resistance of $40\ \Omega$. a) Calculate the current flowing through…
A wind farm generates $10\ \text{MW}$ and transmits it at $220\ \text{kV}$ over a line with a total resistance of $40\ \Omega$.
- a) Calculate the current flowing through the line.
- b) Calculate the power dissipated in the line and express it as a percentage of the generated power.
- c) Repeat the calculations assuming transmission were carried out at $25\ \text{kV}$.
- d) Explain the dual role played by transformers (and therefore alternating current) in making long-distance electrical power transmission viable.
A popular science article proposes "transporting electricity directly at $230\ \text{V}$ to save the cost of transformers". A city requires a power of $1\ \text{MW}$ and…
A popular science article proposes "transporting electricity directly at $230\ \text{V}$ to save the cost of transformers". A city requires a power of $1\ \text{MW}$ and the line would have a resistance of $1\ \Omega$.
- a) Calculate the current that would have to be transmitted.
- b) Calculate the power that would be lost in the line and compare it with the power intended for transmission.
- c) In light of the result, explain why the proposal is unfeasible and how the combination of alternating current and transformers solves the problem.