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AP Biology: Additional Course Content · Enzymes and Cellular Energetics

Enzyme Structure, Function, and Environmental Effects

You eat a slice of pizza at lunch. The starch in the crust would take years to break down on its own in a test tube at body temperature, yet your body digests it in hours. What speeds it up, and why does the same helper stop working if you get a high fever?

How enzymes work

Chemical reactions need a push to get started. Even a reaction that releases energy overall, an exergonic reaction, first needs reactants to reach an unstable, high-energy state. The energy needed to get there is the activation energy ($E_A$).

An enzyme is a biological catalyst, almost always a protein. It lowers the activation energy, so many more molecules can react per second at body temperature.

  • The reactant an enzyme acts on is the substrate.

  • The substrate binds to a small pocket on the enzyme called the active site.

  • The active site fits the substrate through induced fit: the enzyme changes shape slightly as the substrate binds, which strains bonds and helps the reaction happen.

  • The substrate is converted to products, which are released. The enzyme is unchanged and ready for another substrate.

Energy diagram of a reaction with and without an enzyme: the enzyme lowers activation energy but the overall free energy change stays the same. Free energy Reaction progress Reactants Products Without enzyme With enzyme ΔG (same)

Notice what the enzyme does not change: the energy of the reactants, the energy of the products, and therefore $\Delta G$. It only lowers the hill in the middle.

Practice★☆☆Not started
Define substrate*, active site*, and activation energy*. Then explain in one or two sentences how an enzyme speeds up a reaction without being used up.

Define substrate, active site, and activation energy. Then explain in one or two sentences how an enzyme speeds up a reaction without being used up.

Solve

Temperature and pH

An enzyme works because of its three-dimensional shape, which is held together by hydrogen bonds, ionic bonds, and other weak interactions. Anything that disrupts those interactions changes the shape of the active site.

Temperature. As temperature rises, molecules move faster and collide more often, so the rate goes up. Past the optimum temperature, the enzyme's bonds break, the protein unfolds, and the active site loses its shape. This is denaturation. A denatured enzyme no longer binds its substrate, so the rate drops sharply, usually for good.

pH. Changing pH changes the charges on amino acid R groups. Ionic bonds and hydrogen bonds that hold the folded protein together are disrupted, and the active site changes shape. Each enzyme has an optimum pH. Pepsin in the stomach works best near pH 2, while trypsin in the small intestine works best near pH 8.

Two curves showing enzyme activity versus pH: a stomach enzyme peaking at acidic pH and a small intestine enzyme peaking at basic pH. Activity pH Stomach enzyme Intestinal enzyme 2 4 6 8 10
Practice★☆☆Not started
Most human enzymes work best near 37 °C and a pH near 7.4, while pepsin in the stomach works best near pH 2. Explain what happens to the shape and function of a typical…

Most human enzymes work best near 37 °C and a pH near 7.4, while pepsin in the stomach works best near pH 2. Explain what happens to the shape and function of a typical human enzyme if it is heated well above its optimum temperature. Name the term used for this change.

Solve
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An enzyme's activity is measured at different temperatures, with all other conditions held constant. | Temperature (°C) | Rate ($\mu$mol product/min) | |---|---| | 10 |…

An enzyme's activity is measured at different temperatures, with all other conditions held constant.

Temperature (°C) Rate ($\mu$mol product/min)
10 2
20 4
30 7
40 10
50 4
60 0

(a) Identify the approximate optimum temperature. (b) Explain why the rate rises from 10 °C to 40 °C. (c) Explain why the rate falls after 40 °C.

Solve
Practice★★☆Not started
Two enzymes were tested at different pH values. Relative activity (% of maximum) is shown. | pH | Enzyme X | Enzyme Y | |---|---|---| | 2 | 100 | 0 | | 4 | 60 | 5 | | 6…

Two enzymes were tested at different pH values. Relative activity (% of maximum) is shown.

pH Enzyme X Enzyme Y
2 100 0
4 60 5
6 10 40
8 2 100
10 0 30

One enzyme comes from the stomach and the other from the small intestine. Decide which is which, and explain at the molecular level why a change in pH changes enzyme activity.

Solve

Substrate concentration

Suppose you have a fixed amount of enzyme and keep adding substrate.

  • Low substrate: many active sites are empty. Each added substrate molecule finds an enzyme quickly, so the rate rises almost in a straight line.

  • High substrate: nearly every active site is occupied at every moment. The enzyme is saturated, and the rate levels off at a maximum, $V_{max}$.

Reaction rate versus substrate concentration: the rate rises and then levels off at the maximum rate when the enzyme is saturated. Rate Substrate concentration Vmax Rate limited by substrate Saturated

Adding more substrate cannot raise the rate above $V_{max}$. To raise $V_{max}$, you need more enzyme, because more enzyme means more active sites. Doubling the enzyme roughly doubles $V_{max}$.

Practice★★☆Not started
A fixed amount of enzyme is mixed with different concentrations of substrate. | Substrate (mM) | Rate ($\mu$mol/min) | |---|---| | 0 | 0 | | 1 | 20 | | 2 | 40 | | 4 | 70…

A fixed amount of enzyme is mixed with different concentrations of substrate.

Substrate (mM) Rate ($\mu$mol/min)
0 0
1 20
2 40
4 70
8 90
16 100
32 100

(a) Explain why the rate increases at low substrate concentrations. (b) Explain why the rate levels off at 100. (c) Predict what would happen to the maximum rate if the amount of enzyme were doubled.

Solve

Inhibitors

An inhibitor is a molecule that slows an enzyme.

Type Where it binds Effect on the enzyme Can more substrate overcome it?
Competitive The active site Blocks the substrate (competes for the site) Yes. At high substrate, $V_{max}$ is still reached
Noncompetitive (allosteric) A different site (allosteric site) Changes the shape of the active site No. Lowers $V_{max}$ because some enzymes are disabled
Three enzymes: one with substrate bound, one with a competitive inhibitor in the active site, and one with a noncompetitive inhibitor at an allosteric site that distorts the active site. Substrate Normal Inhibitor Competitive Allosteric inhibitor Noncompetitive

Think of it like a parking spot. A competitive inhibitor is a car parked in the spot, but it can leave if a better-fitting car arrives. A noncompetitive inhibitor is like a flat tire on the spot's owner: the spot is there, but the car cannot use it.

Practice★☆☆Not started
Compare competitive and noncompetitive inhibitors. For each, state where it binds on the enzyme and whether adding more substrate can overcome its effect.

Compare competitive and noncompetitive inhibitors. For each, state where it binds on the enzyme and whether adding more substrate can overcome its effect.

Solve
Practice★★★Not started
A researcher measures reaction rate ($\mu$mol/min) at several substrate concentrations with no inhibitor, with inhibitor A, and with inhibitor B. The same amount of…

A researcher measures reaction rate ($\mu$mol/min) at several substrate concentrations with no inhibitor, with inhibitor A, and with inhibitor B. The same amount of enzyme is used each time.

Substrate (mM) No inhibitor Inhibitor A Inhibitor B
1 20 8 10
2 33 14 17
4 50 25 25
8 67 40 33
16 80 57 40
32 89 73 44

(a) Identify which inhibitor is competitive and which is noncompetitive, citing evidence from the data. (b) Explain, using the structure of the enzyme, why a very high substrate concentration nearly overcomes one inhibitor but not the other. (c) Predict which kind of inhibitor an allosteric site would produce.

Solve

What an enzyme changes and does not change

An enzyme lowers $E_A$ and speeds up how fast equilibrium is reached. It does not change $\Delta G$, the equilibrium position, or the equilibrium constant, because the energies of reactants and products stay the same. For an exergonic reaction with $\Delta G = -20$ kJ/mol, the products are lower in energy than the reactants with or without the enzyme. The forward and reverse reactions are both sped up equally.

Designing an enzyme experiment

Experimental design. Say you test how temperature affects amylase, which breaks down starch. Iodine solution turns blue-black with starch, so loss of color shows starch is gone.

  • Independent variable: temperature (for example 10, 25, 37, 50, 70 °C).

  • Dependent variable: time for the blue-black color to disappear, or the color intensity after a set time.

  • Controlled variables: amount and concentration of amylase and starch, pH, volume, and time.

  • Control: boiled (denatured) amylase with starch. It should show no starch breakdown, which proves that the active enzyme caused the change.

Predicted results: starch disappears fastest near the optimum (about 37 °C for human amylase), more slowly at low temperatures, and not at all at high temperatures where the enzyme is denatured.

Practice★★★Not started
An exergonic reaction has an activation energy of 75 kJ/mol without a catalyst and 40 kJ/mol with an enzyme. The overall free energy change is $-20$ kJ/mol. (a) Explain…

An exergonic reaction has an activation energy of 75 kJ/mol without a catalyst and 40 kJ/mol with an enzyme. The overall free energy change is $-20$ kJ/mol. (a) Explain what the enzyme changes and what it does not change about this reaction (consider activation energy, $\Delta G$, and the equilibrium position). (b) A student plans to test how temperature affects the enzyme amylase using starch and iodine solution. Describe the independent variable, the dependent variable, two variables to hold constant, and one appropriate control (for example, one using boiled enzyme). (c) Predict the results at 0 °C, 37 °C, and 90 °C and justify them.

Solve

Back to the start: your body digests pizza because amylase lowers the activation energy for breaking down starch at 37 °C. A high fever is dangerous because heat can disrupt the shape of enzymes, and without the right shape the active sites stop working.

Summary

  • Enzymes are protein catalysts. They bind substrates at the active site (induced fit) and lower activation energy. They are not used up and do not change $\Delta G$.

  • Enzyme function depends on shape. Heat or extreme pH denatures the enzyme and the rate falls.

  • Rate increases with substrate until the enzyme is saturated at $V_{max}$. More enzyme raises $V_{max}$.

  • Competitive inhibitors bind the active site and can be overcome with more substrate. Noncompetitive (allosteric) inhibitors bind elsewhere and lower $V_{max}$.

  • A good enzyme experiment changes one variable, keeps the others constant, and includes a control such as boiled enzyme.

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